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CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
1
TYPES OF FACTOR EXAMPLES OF REACTION EFFECT OF FACTOR ON THE RATE OF
REACTION
SIZE OF REACTANT /
TOTAL SURFACE AREA
A reaction between calcium
carbonate and hydrochloric acid
CaCO3 + 2HCl → CaCl2 + H2O + CO2
1. When the size of reactant become
smaller, the total surface area becomes
larger
2. Thus, the rate of reaction higher
ACTIVITY
Set 1 Excess calcium carbonate powder + 50 cm3 of 0.2M hydrochloric acid
Set 2 Excess calcium carbonate granulated + 50 cm3 of 0.2M hydrochloric acid
Volume of CO2 gas (cm3)
Set 1
Set 2
Time (s)
The gradient of the curve Set 1 is steeper than curve Set 2.
The rate of reaction in Set 1 is higher than rate of reaction in Set 2.
Because: The total surface area of calcium carbonate powder is larger than
calcium carbonate granulated.
The quantities of calcium carbonate and hydrochloric acid used, in mole in both
Set 1 and Set 2 are same.
Thus, the maximum volume of carbon dioxide gas collected in both Set 1 and Set
2 also the same.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
2
TYPES OF FACTOR EXAMPLES OF REACTION EFFECT OF FACTOR ON THE RATE OF
REACTION
CONCENTRATION OF
SOLUTION (REACTANT)
A reaction between sodium
thiosulphate, Na2S2O3 solution and
sulphuric acid, H2SO4
Na2S2O3 + H2SO4 → Na2SO4 + SO2 +
H2O + S
Ionic equation:
S2O32- + 2H+ → SO2 + H2O + S
1. When concentration of Na2S2O3 solution
increases, the number of S2O22- ion per
unit volume increase.
2. Thus, rate of reaction higher.
OBSERVATION:
When the concentration of Na2S2O3 solution increases, the time taken for the ‘X’ mark
disappears from view become shorter. (yellow sulphur precipitate is formed)
Concentration of Na2S2O3
(mol dm-3)
Time
(s)
The higher the concentration, the
shorter the time taken for ‘X’ mark
disappears from view.
Thus, the rate of reaction is higher.
Concentration of Na2S2O3
(mol dm-3)
1/t
(s-1)
Concentration of Na2S2O3 is directly
proportional to rate of reaction.
The higher the concentration, the
rate of reaction is higher.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
3
ACTIVITY
Set 1 Excess zinc powder + 20 cm3 of 0.4M sulphuric acid
Set 2 Excess zinc powder + 40 cm3 of 0.2M sulphuric acid
Volume of H2 gas (cm3)
Set 1
Set 2
Time (s)
The gradient of the curve Set 1 is steeper than curve Set 2.
The rate of reaction in Set 1 is higher than rate of reaction in Set 2.
Because: The concentration of sulphuric acid in Set I is higer than Set 2.
The quantities of zinc powder and sulphuric acid used, in mole in both Set 1 and
Set 2 are same.
Thus, the maximum volume of hydrogen gas collected in both Set 1 and Set 2 also
the same.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
4
TYPES OF FACTOR EXAMPLES OF REACTION EFFECT OF FACTOR ON THE RATE OF
REACTION
TEMPERATURE A reaction between sodium
thiosulphate, Na2S2O3 solution and
sulphuric acid, H2SO4
Na2S2O3 + H2SO4 → Na2SO4 + SO2 +
H2O + S
Ionic equation:
S2O32- + 2H+ → SO2 + H2O + S
1. When temperature of a solution increase,
the kinetic energy of S2O32- ions
increases.
2. S2O32- ions move faster and have more
energy.
3. Thus, the rate of reaction higher.
OBSERVATION:
When the temperature of Na2S2O3 solution increases, the time taken for the ‘X’ mark
disappears from view become shorter. (yellow sulphur precipitate is formed)
Temperature (°C)
Time
(s)
The higher the temperature, the
shorter the time taken for ‘X’ mark
disappears from view.
Thus, the rate of reaction is higher.
Temperature (°C)
1/t
(s-1)
Temperature of Na2S2O3 is directly
proportional to rate of reaction.
The higher the temperature, the rate
of reaction is higher.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
5
ACTIVITY
Set 1 1 g of CaCO3 chips + 50 cm3 of 0.5M HCl at 60.0 °C
Set 2 1 g of CaCO3 chips + 50 cm3 of 0.5M HCl at 30.0 °C
Volume of CO2 gas (cm3)
Set 1
Set 2
Time (s)
The gradient of the curve Set 1 is steeper than curve Set 2.
The rate of reaction in Set 1 is higher than rate of reaction in Set 2.
Because: The temperature of HCl in Set I is higer than Set 2.
The quantities of CaCO3 and HCl used, in mole in both Set 1 and Set 2 are same.
Thus, the maximum volume of CO2 gas collected in both Set 1 and Set 2 also the
same.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
6
TYPES OF FACTOR EXAMPLES OF REACTION EFFECT OF FACTOR ON THE RATE OF
REACTION
CATALYST a. Decomposition of hydrogen
peroxide
In the presence of a catalyst
(manganese (IV) oxide, MnO4)
2H2O2 → 2H2O + O2
b. Reaction between zinc and
sulphuric acid
Zn + H2SO4 → ZnSO4 + H2
The rate of reaction higher when:
1. There is presence of catalyst in the
reaction
NOTE:
A catalyst – A substance which can alter the rate of reaction while its remains
chemically unchanged at the end of the reaction.
Classified into 2 types:
Positive catalyst – a catalyst that increase the rate of reaction
Negative catalyst (inhibitors) – a catalyst that lower the rate of reaction
A catalyst does not change the quantity of the products formed.
The characteristic of a catalyst:
It remains chemically unchanged at the end of the reaction.
It does not change the quantities of products formed.
The amount of catalyst remains unchanged before and after the reaction.
Most catalyst is transition element.
Only a small amount of catalyst used will increase the rate of reaction.
ACTIVITY 1
Set 1 2 g of granulated Zn + 25 cm3 of 0.1M HCl + CuSO4 solution
Set 2 2 g of granulated Zn + 25 cm3 of 0.1M HCl
Volume of H2 gas (cm3)
Set 1
Set 2
Time (s)
The gradient of the curve Set 1 is steeper than curve Set 2.
The rate of reaction in Set 1 is higher than rate of reaction in Set 2.
Because: The Set 1 is using the catalyst and Set 2 is without catalyst.
The quantities of Zn and HCl used, in mole in both Set 1 and Set 2 are same.
Thus, the maximum volume of H2 gas collected in both Set 1 and Set 2 also the
same.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
7
ACTIVITY 2
Set 1 50 cm3 of 20-volume H2O2 + 0.2 g of manganese(IV) oxide, MnO4
Set 2 50 cm3 of 20-volume H2O2 + 0.8 g of manganese(IV) oxide, MnO4
Volume of O2 gas (cm3)
Set 2
Set 1
Time (s)
The gradient of the curve Set 2 is steeper than curve Set 1.
The rate of reaction in Set 2 is higher than rate of reaction in Set 1.
Because: The Set 2 is using more amount of catalyst than Set 1.
The quantities of H2O2 used, in mole in both Set 1 and Set 2 are same.
Thus, the maximum volume of O2 gas collected in both Set 1 and Set 2 also the
same.
TYPES OF FACTOR EXAMPLES OF REACTION EFFECT OF FACTOR ON THE RATE OF
REACTION
PRESSURE
Only reactions that involve
gaseous reactants
Reaction of hydrogen peroxide
2H2O2 → 2H2O + O2
1. When the pressure of the gas increase,
H2O2 particle per unit volume increase.
2. The reaction occurs faster.
3. Thus, the rate of reaction higher
ACTIVITY
Volume of O2 gas (cm3)
Set 1
Set 2
Time (s)
The gradient of the curve Set 1 is steeper than curve Set 2.
The rate of reaction in Set 1 is higher than rate of reaction in Set 2.
Because: The pressure in Set 1 is higher than in Set 2.
CHAPTER 1: RATE OF REACTION FACTORS AFFECTING THE RATE OF REACTION
8
APPLICATION OF THE FACTORS AFFECTING THE RATE OF REACTION IN DAILY LIFE AND IN INDUSTRIAL
PROCESS
1. APPLIED IN DAILY LIFE
a. Burning of charcoal
Why food can be cooked faster when smaller pieces of
charcoal are used compared to bigger pieces of
charcoal?
ANSWER:
Smaller pieces of charcoal have bigger total
exposed surface area.
It can burn faster to produce more heat.
Thus, the food is cooked faster.
b. Storing food in a refrigerator
Why food stored in the refrigerator last longer than
the food stored in the kitchen cabinet?
ANSWER:
The temperature inside the refrigerator is lower
than kitchen cabinet.
Bacteria are not active at low temperature.
The growth of bacteria in food can be reduced.
The rate of decomposition of food is lower.
Thus, the food can be stored longer.
c. Cooking food in a pressure cooker
Why cooking of food in a pressure cooker save energy
and time (cooked faster) compared to the normal
cooker?
ANSWER:
In a pressure cooker, the high pressure raises the
boiling point of water to a temperature above 100
°C.
Thus, cooking is carried out at a temperature
higher than 100 °C in the pressure cooker.
The food can be cooked faster.
d. Cooking solid food in different sizes
Why meat cut into small pieces can be cooked faster
compare with meat in big chunks?
ANSWER:
Meat in small pieces has larger total surface than
meat in big chunks.
A total surface area exposed to heat during
cooking is increases.
More heat can be absorbed faster.
Meats in small pieces take shorter time to cook
compare to big chunks.
2. APPLIED IN INDUSTRIAL PROCESS
Name of process Haber process Contact process Ostwald process Hydrogenation
Catalyst Iron powder, Fe Vanadium(V) oxide,
V2O5 Platinum, Pt Nickel, Ni
Temperature 450 – 550 °C 450 °C 850 °C 180 °C
Pressure 200 – 300 atm 1 – 3 atm 2 – 5 atm 1 atm
Product Ammonia gas, NH3 Sulphuric acid, H2SO4 Nitric acid, HNO3 Margarine (from
palm oil)