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No Warm-Up today. You have a Quiz Clear your desk of everything but a calculator and something to write with.

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No Warm-Up today. You have a Quiz  Clear your desk of everything but a calculator and something to write with. . Unit 2 Day 5. Basic probability. Definitions. Experiment – process that gives definite results Outcomes – results of an experiment Sample space – set of all possible outcomes. - PowerPoint PPT Presentation

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Page 1: No Warm-Up today.  You have a  Quiz

No Warm-Up today.

You have a Quiz

Clear your desk of everything but a calculator

and something to write with.

Page 2: No Warm-Up today.  You have a  Quiz

BASIC PROBABILITY

Unit 2 Day 5

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Definitions• Experiment – process that gives definite results• Outcomes – results of an experiment• Sample space – set of all possible outcomes

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Examples• Experiment – Tossing a coin–Outcomes: Heads or Tails–Sample space: S = {H, T}

• Experiment – Rolling a die–Outcomes: 1, 2, 3, 4, 5, and 6–Sample space: S = {1, 2, 3, 4, 5, 6}

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ExampleConsider this dartboard. Assume that the experiment is

“throwing a dart” once and that the dart hits the board. Find each of the following.a) The outcomesb) The sample space

Solution:a) The outcomes are hitting white (W), purple (P), or yellow (Y).b) The sample space is {hitting white, hitting purple, hitting

yellow}, which can be stated as {W, P, Y}.

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Definition of an EventIf S is a sample space of an experiment, then an event

is any subset of the sample space.

Examples…1. Die showing an even number2. Picking an ace from a deck of cards

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ExampleIf an experiment consists of tossing a coin three times and recording the results in order, find the sample space. (Find all possible outcomes)

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

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ExampleThe event E of showing “exactly two heads” is the

subset of S that consists of all outcomes with two heads. Write out that possible event.

E = {HHT, HTH, THH}

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ExampleWhat is the event F of showing “at least two heads”?

F = {HHH, HHT, HTH, THH}

What is the event G of showing “no heads”?

G = {TTT}

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Types of Probability• Experimental Probability–Based on trials and observations

• Theoretical Probability–Calculated by analyzing a situation

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Experimental ProbabilitySociological Survey. The

authors of this text conducted an experimental survey to determine the number of people who are left-handed, right-handed, or both. The results are shown in the graph.a) Determine the probability that a person is right-handed.b) Determine the probability that a person is left-handed.

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Solutions:a) The number of right-handed is 82, the number of left-handed is 17, the number of ambidextrous is 1. The total number of observations is 82 + 17 + 1 = 100.The probability that a person is right-handed is

P = 82/100 = .82 = 82%

b) The probability that a person is left-handed is P, where

P = 17/100 = .17 = 17%

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Probability Facts• P(E) is a number between 0 and 1,

0 ≤ P(E) ≤ 1• If an event is certain to occur, then

P(E) = 1• If an event is impossible, then

P(E) = 0• The closer the probability of event is to 1, the more

likely the event is to happen.

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Examples• If you flip a coin, what is the theoretical

probability that it lands with heads up?– ½ or 50%

• If you flip a coin, what is the theoretical probability that it lands with tails up?– ½ or 50%

• How would you find experimental probability?

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Examples• If you roll a standard die, what is the

theoretical probability that it lands with the 3 facing up?– 1/6

• If you roll a standard die, what is the theoretical probability that it lands with the 3 or the 4 facing up?– 2/6 or 1/3

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ExampleSuppose we select, without looking, one marble

from a bag containing 4 red and 9 purple marbles. What is the probability of selecting a red marble?

Solution: There are 13 equally likely ways of selecting any marble, and 4 ways of selecting red.

P(selecting a red marble) = 4/13

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Example

What is the probability of getting a sum of 5 on a roll of a pair of dice?

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Rolling a Pair of Dice

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SolutionOn each die, there are 6 possible outcomes. The outcomes are paired so there are 6(6) or 36 possible ways in which the two can fall.

There are 4 ways to roll a total of 5:(1, 4) (4, 1) (2, 3) and (3, 2).

P(sum of 5) = 4/36 = 1/9

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Your Turn!• What is the probability of choosing, at random, the

ace of spades from a deck of 52 cards?• What is the probability of choosing any ace from a

deck of 52 cards?• What is the probability of drawing a red card from a

deck of 52 cards?• What is the probability of drawing a club from a

deck of 52 cards?

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Solutions• What is the probability of choosing, at random, the

ace of spades from a deck of 52 cards? 1/52• What is the probability of choosing any ace from a

deck of 52 cards? 4/52 = 1/13• What is the probability of drawing a red card from a

deck of 52 cards? 26/52 = 1/2• What is the probability of drawing a club from a

deck of 52 cards? 13/52 = 1/4

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ExampleA five-card poker hand is drawn from a standard deck

of 52 cards. What is the probability that all five cards are spades?

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= picking 5 spades picking 5 cards

= 13(12)(11)(10)(9) 52(51)(50)(49)(48)

= 0.000495 or 0.0495 %

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Solution• How many different ways can we choose five spades

from 13 spades?

• Probability of drawing five spades is

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ExampleA bag contains 20 tennis balls, of which four are

defective. If two balls are selected at random from the bag, what is the probability that both are defective?

= pick a defected tennis ball picking any two tennis balls

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Solution

= 4(3) 20(19)

= 0.8316 or 83.16 %

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HomeworkProbability WS