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Name Date _ 40 Inheritance of Sex-linked Traits BACKGROUND The body cells of humans have 46 chromosomes in their nuclei. There aretwenty-nvo pairs of homolog()us chromosomes. These chromosomes are called autosomes, and they detennine most of the traits of the individual. The other two chromosomes are the sex chromosomes, which detennine the sex of the individual. There aretwo different sex chromosomes. X and Y._~. A female hastwo X chromosomes; amale has one X and one Y chromosome. Traits controlled bygenes carried on the sex chromosomes are said to be sex-li1lked. Hu- mans are known to have more than 40 sex-linked traits. The Y chromosome is considerably smaller and has fewer genes than the X chromosome. Almost all human sex-linked traits are carried on the X chromosome. Among the sex-linked traits in humans are color blindness arid hemophilia. OBJECTIVES ;I In this activity you will learn about the pattem of inheritance of two sex-linked traits in humans. PROCEDURES AND OBSERVATIONS In humans, red-green color blindness isthe re- sult of a recessive gene, c, carried on the X chromosome. Nom1al color vision is produced by the dominant gene, C, also carried on the X chromosome. In predicting the inhelitance of sex-linked traits, use the symbols X and Y to represent the sex chromosomes. "'rite the letter symbol for the trait as a superscript on the appropriate s~x chromosome. For example, an X chromosome with the dominant gene for normal color vision would be '.vrittenXC. An X chromosome with the. recessive gene for color blindness would be writ- ten Xc. a. Determine how to write the genotypes for male and female individuals who either are color blind or have normal color vision. 1. Write the genotype of a male with normal color vision. 2. Write the genotype of a male who is color blind. 3. Write the two possible genotypes of a f2maJe with norma! colct vision. 4. Write the genotype of a female who ha~ normal color vision but who carriesthe gene for color blindness. 5. Write the genotype of a female who is color blind. ~ h. Pun nett squares can be used to determine the probability of inheritance of color blindness. A pedigree chart' can also be used to illustrate the information in a Punnett square. In a pedigree chart, the heterozygous genotype can be shown by shading in only half of the symbol. 6. Using a Punnett square, determine the pos- sible genotypes and phenotypes of the children of a color-blind maleand a female who has normal color vision but carries the recessivegene. genotype: L_~_, _ phenotype;

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Page 1: Name Date 40 Inheritance of Sex-linked - APCSCIENCE.COMapcscience.com/uploads/3/1/4/7/3147682/lab_sexlinked_traits.pdf40 Inheritance of Sex-linked Traits BACKGROUND The body cells

Name Date _

40 Inheritance of Sex-linked Traits

BACKGROUND

The body cells of humans have 46 chromosomes in their nuclei. There are twenty-nvo pairsof homolog()us chromosomes. These chromosomes are called autosomes, and they detenninemost of the traits of the individual. The other two chromosomes are the sex chromosomes,which detennine the sex of the individual. There are two different sex chromosomes. X and Y._~.A female has two X chromosomes; a male has one X and one Y chromosome.Traits controlled by genes carried on the sex chromosomes are said to be sex-li1lked. Hu-

mans are known to have more than 40 sex-linked traits. The Y chromosome is considerablysmaller and has fewer genes than the X chromosome. Almost all human sex-linked traits arecarried on the X chromosome. Among the sex-linked traits in humans are color blindness aridhemophilia.

OBJECTIVES

;I

In this activity you will learn about the pattem of inheritance of two sex-linked traits inhumans.

PROCEDURES AND OBSERVATIONSIn humans, red-green color blindness is the re-

sult of a recessive gene, c, carried on the Xchromosome. Nom1al color vision is produced bythe dominant gene, C, also carried on the X

chromosome.In predicting the inhelitance of sex-linked

traits, use the symbols X and Y to represent thesex chromosomes. "'rite the letter symbol for thetrait as a superscript on the appropriate s~xchromosome. For example, an X chromosomewith the dominant gene for normal color visionwould be '.vrittenXC. An X chromosome with the.recessive gene for color blindness would be writ-ten Xc.

a. Determine how to write the genotypes for maleand female individuals who either are color blindor have normal color vision.

1. Write the genotype of a male with normal

color vision.

2. Write the genotype of a male who is colorblind.

3. Write the two possible genotypes of a

f2maJe with norma! colct vision.

4. Write the genotype of a female who ha~

normal color vision but who carries the

gene for color blindness.

5. Write the genotype of a female who iscolor blind. ~

h. Pun nett squares can be used to determine theprobability of inheritance of color blindness. Apedigree chart' can also be used to illustrate theinformation in a Punnett square. In a pedigreechart, the heterozygous genotype can be shownby shading in only half of the symbol.

6. Using a Punnett square, determine the pos-

sible genotypes and phenotypes of the

children of a color-blind male and a female

who has normal color vision but carries the

recessive gene.

genotype:

L_~_, _

phenotype;

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7. Draw a pedigree chart illustrating the cross

in question 6.

8. Using a Punnelt square, determine the pos-

sible genotypes and phenotypes of the

children of a color-blind female and a malewith normal color vision.

9. Draw a pedigree chart illustrating the cross

in question 8.

174

Like color blindness, the inheritance 0'

hemophilia in humans is also controlled by sex·linked genes. The dominant gene. H. is carriec"on the X chromosome. It causes the production 0'

substance5 that allo\V the blood to clot 110nnalhafter an injury. An individual with the recessi\-~gene, h, on the X chromosome lack,:; certain ofth.:substances in the blood that alla\,- it to clot normally. In extreme cases, a hemophiliac can bleec-to death from a minor injury_

c. Punnett squares can be used to determine thEchance of inheritance of hemophilia.

10. Using a Punnett square, determine thE

possible genotypes and phenotypes of thE

children of a normal male and a femalE

who carries the recessive gene fOI

hemophilia.

11. Draw a pedigree chart illustrating the cross

in question 10.

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Name Date. _

CONCLUSIONS AND APPLICATIONS liiiiiiiiiiiiiiiiiiiiiil .... _

1. What is the probability that a daughter of a color-blind female and a male with normal color visionwill be color-blind?

2. Explain why males are affected by color blindness and hemophilia much mox:e frequently thanfemales.

3. Is it possible for a male to have normal color vision and carry the gene for color blindness? Explain.

4. A color-blind male and a female with normal color vision produce a color-blind daughter. What is thegenotype of the mother?

5. Can a color-blind female and a male \vith normal color vision have a son with nonnal vision? Explain.

6. Use a Punnett square to detemline the possible genotypes of the children of a male with normal colorvision and a female with normal color vision whose father was color-blind.

175

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7. What genotypes in parents could produce a female with hemophilia?

8. What is the probability that a male with hemophilia and a nomlal female with no e\'icil"'l1ce ofhemophilia in her famih' will produce a hemophiliac son? Expbin.

176