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N1 Engineering Science April 2016 Memorandum

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Page 1: N1 Engineering Science April 2016 Memorandum

Copyright reserved Please turn over

NATIONAL CERTIFICATE

APRIL EXAMINATION

ENGINEERING SCIENCE N1

6 APRIL 2016

This marking guideline consists of 12 pages.

MARKING GUIDELINE

Page 2: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -2- T560(E)(A6)T ENGINEERING SCIENCE N1

Copyright reserved Please turn over

ü= 1 mark. √ = ½ mark. Calculations:

• 1 mark for substitution and conversion of values. • 1 mark for answer and unit. • -½ mark for using the incorrect unit.

QUESTION 1 1.1 1.1.1 C 1.1.2 D 1.1.3 B 1.1.4 A (4 x 1) (4) 1.2

üü Resultant = 52 m,30°ü

(2)

1.3 1.3.1

üü

kms

s

tvstsv

75,93

)6015(375

.

=

´=

=

=

Page 3: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -3- T560(E)(A6)T ENGINEERING SCIENCE N1

Copyright reserved Please turn over

1.3.2

üü

(2 x 2)

(4) 1.4 1.4.1

üüü

(3)

1.4.2

üü

(2) [15]

min122,075,46875,93

%2537575,93

==

=

´=

=

=

thourst

t

t

vst

tsv

2.333,13040

-=

=

D=

sma

a

tva

Page 4: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -4- T560(E)(A6)T ENGINEERING SCIENCE N1

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QUESTION 2 2.1 2.1.1

2.1.2 2.1.3 2.1.4 2.1.5

False False True True False

(5 x 1)

(5)

2.2 2.2.1

üü

2.2.2

üü

(2 x 2)

(4)

mEE

LVRELE

VR

Dist

Dist

DistDist

Dist

Dist

5,105,33

=´=´=

=

NE

E

MALE

ELMA

2205,2

550

=

=

=

=

Page 5: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -5- T560(E)(A6)T ENGINEERING SCIENCE N1

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2.3

üüü

OR

Page 6: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -6- T560(E)(A6)T ENGINEERING SCIENCE N1

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By calculations Consider both A and B up

A B 125N x - A cos 400 = -0,766A B Cos 500 = 0,643B 0 Y A sin 400 = 0,643 B sin 500 = 0.766B -125

B = 1.191A 1

0,643A + 0,766B = 7,5 2 1 in 2 0,643A + 0,766 x 1,191A = 7,5 A = 4.823N Therefore B = 1.191 x 4,823 = 5,744 kN üüü

(3)

2.4

üü

(2)

NP

P

PRMLM

333,833212521253

=

´=

´=´=

Page 7: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -7- T560(E)(A6)T ENGINEERING SCIENCE N1

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2.5

üü Equilibrant = 2500N East 32°Northü OR By calculations

(3) [17]

QUESTION 3 3.1 3.1.1 B 3.1.2 A 3.1.3 B 3.1.4 A 3.1.5 B (5 x 1) (5) 3.2

üü

(2)

kJWWW

sFW

105000105200525

==

´=´=

Page 8: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -8- T560(E)(A6)T ENGINEERING SCIENCE N1

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3.3 3.3.1

üüü

(3)

3.3.2

üü

(2) [12]

QUESTION 4 4.1 4.1.1

4.1.2 4.1.3 4.1.4 4.1.5

Higher Lower Removed Radiation pyrometer Joule

(5 x 1)

(5)

4.2

üüü

(3)

kJWJW

WsFW

6500650105006

==

´=´=

Page 9: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -9- T560(E)(A6)T ENGINEERING SCIENCE N1

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4.3 4.3.1

4.3.2 4.3.3

Conduction Convection Convection/radiation

(3 x 1)

(3)

4.4

üü

(2)

4.5 4.5.1

4.5.2

ü

ü

(2 x 1)

(2)

4.6 4.6.1

4.6.2 4.6.3

Heat is transferred between the lead and water. The law of conservation of energy. The temperature of both materials is the same.

(3 x 1)

(3) [18]

QUESTION 5 5.1 5.1.1

5.1.2 5.1.3 5.1.4 5.1.5

Atom Matter Molecule Melting Condensation

(5 x 1)

(5)

5.2 Gas: particles far from each other

Liquid: particles not far from each other Solid: particles close to each other

(3)

5.3 Electron – negative

Neutrons – neutral Proton – positive

(3)

MJQJQ

QtcmQ

87,4100700418

)1555(4187250

==

-´´=D´´=

mmlml

llll fo

895895,0

105,3536

=D=D

-=D

-=D

Ctt

ttt fo

!602585

=D

-=D

-=D

Page 10: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -10- T560(E)(A6)T ENGINEERING SCIENCE N1

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5.4 When an atom has gained or lost an electron. ü (1) [12]

QUESTION 6 6.1 6.1.1

6.1.2 6.1.3 6.1.4 6.1.5

C D A E B

(5 x 1) (5) 6.2 6.2.1

6.2.2 6.2.3 6.2.4

Insulator – is a material that prevents the flow of electrical current. Resistance – is a material that resists the flow of electrical current. Potential difference – is the electrical pressure required to overcome the resistance in order for a current to flow. Joule's Law – the quantity of heat generated by an electrical current is directly proportional to ???? Is something not missing here?

(4 x 1) (4) 6.3 6.3.1

üü

6.3.2

üü

6.3.3

OR OR üü

(3 x 2) (6)

80,986ΩRR

RRR

t

t

t

=

+=

+=

2301

12511

111

21

mAIAI

I

RVI

296296,0986,8024

==

=

=

WPP

IVP

104,7296,024

=´=´=

WPP

RIP

096,7986,80296,0 2

2

=´=

=

WP

P

RVP

112,7986,80242

2

=

=

=

Page 11: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -11- T560(E)(A6)T ENGINEERING SCIENCE N1

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6.4 6.4.1 6.4.2

Resistivity – Different metals have different resistances. Length – The longer the conductor, the higher the resistance.

(2 x 1) (2) 6.5 6.5.1

6.5.2

Alloys – no change in resistance.ü Insulators – The resistance decreases with the rise in temperature.ü

(2 x 1) (2) 6.6

üüü

(3)

Page 12: N1 Engineering Science April 2016 Memorandum

MARKING GUIDELINE -12- T560(E)(A6)T ENGINEERING SCIENCE N1

Copyright reserved

6.7

üüüü

(4) [26]

TOTAL: 100