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7/27/2019 Mws Che Nle Txt Newton Examples
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Chapter 03.04Newton-Raphson Method of Solving a NonlinearEquation More ExamplesChemical Engineering
Example 1
You have a spherical storage tank containing oil. The tank has a diameter of . You are
asked to calculate the height h to which a dipstick 8 ft long would be wet with oil when
immersed in the tank when it contains of oil.
ft6
3ft6
h
r
Spherical Storage Tank
Dipstick
Figure 1 Spherical storage tank problem.
The equation that gives the height h of the liquid in the spherical tank for the given volume
and radius is given by 08197.39 23 hhhf
Use the Newton-Raphson method of finding roots of equations to find the height to which
the dipstick is wet with oil. Conduct three iterations to estimate the root of the aboveequation. Find the absolute relative approximate error at the end of each iteration and the
number of significant digits at least correct at the end of each iteration.
h
03.04.1
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03.04.2 Chapter 03.04
Solution
8197.39 23 hhhf hhhf 183 2
Let us take the initial guess of the root of 0hf as 10 h .
Iteration 1
The estimate of the root is
0
001
hf
hfhh
11813
8197.31911
2
23
15
1803.41
2786901 .
721310.
The absolute relative approximate error a at the end of Iteration 1 is
1001
01
h
hha
100721310
1721310
.
.
%636.38
The number of significant digits at least correct is 0, as you need an absolute relative
approximate error of or less for one significant digit to be correct in your result.%5
Iteration 2The estimate of the root is
1
112
hf
hfhh
721310187213103
8197.37213109721310721310
2
23
..
...
423.11
48764.0721310
.
042690.0721310 .678620.
The absolute relative approximate error a at the end of Iteration 2 is
1002
12
h
hha
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Newton-Raphson Method More Equations: Chemical Engineering 03.04.3
100678620
72131067862.0
.
.
%2907.6
The number of significant digits at least correct is 0.
Iteration 3The estimate of the root is
2
223
hf
hfhh
6786201867862.03
8197.3678620967862067862.0
2
23
.
..
834.10
012536.0678620
.
0011572.0678620 .
677470.The absolute relative approximate error a at the end of Iteration 3 is
1003
23
h
hha
100677470
678620677470
.
..
%17081.0
Hence the number of significant digits at least correct is given by the largest value of for
which
m
m
a
2
105.0 m
2105.017081.0
m
21034162.0
m 234162.0log 4665.234162.0log2 mSo
2m
The number of significant digits at least correct in the estimated root 0.67747 is 2.
NONLINEAR EQUATIONSTopic Newton-Raphson Method-More ExamplesSummary Examples of Newton-Raphson Method
Major Chemical Engineering
Authors Autar KawDate August 7, 2009
Web Site http://numericalmethods.eng.usf.edu
http://c/Documents%20and%20Settings/sgarapat/http://c/Documents%20and%20Settings/sgarapat/http://c/Documents%20and%20Settings/sgarapat/