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multiplication above the base Vinay Nair SCHOOL OF VEDIC MATHS

multiplication above the base

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multiplication above the base. Vinay Nair S CHOOL OF V EDIC M ATHS. sutra used:. Meaning: A ll from nine and the last from ten. 12 104 1015 x13 x103 x1010___ above the above the above the base 10 base 100 base 1000. What is a ‘Base’? - PowerPoint PPT Presentation

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Page 1: multiplication above the base

multiplication above the base Vinay Nair SCHOOL OF VEDIC MATHS

Page 2: multiplication above the base

sutra used: Meaning: All from nine and the last from ten

Page 3: multiplication above the base

12 104 1015x13 x103 x1010___

above the above the above thebase 10 base 100 base 1000

Page 4: multiplication above the base

What is a ‘Base’?

Powers of 10 i.e. 10, 100, 1000 and so on, are called ‘base’ numbers.

Page 5: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 6: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 7: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 8: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 9: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 10: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 11: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 12: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 13: multiplication above the base

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 14: multiplication above the base

replay proceed

12 + 2 104 + 4 1015 + 15x13 + 3 x103 + 3 x1010 + 10__ 15 | 6 107 | 12 1025 | 150

Page 15: multiplication above the base

problems of type ii

14 110 1200x16 x115 x1011___

Page 16: multiplication above the base

the number of digits on the right side of the answer will be equal to the number of zeros in the base.

Base 10

14+4x16+6 20| 4 2

14x16 224replay proceed

Page 17: multiplication above the base

the number of digits on the right side of the answer will be equal to the number of zeros in the base.

Base 1 0 0

110+10 x115+15 125| 50 1

110 x11512650

replay proceed

Page 18: multiplication above the base

the number of digits on the right side of the answer will be equal to the number of zeros in the base.

Base 1 0 0 0

1200+200 x1011+ 11 1211| 200 2

1200 x1011 1213200

replay proceed

Page 19: multiplication above the base

replay proceed

Base 10 Base 1 0 0 Base 10 0 0

14+4 110+10 1200+200x16+6 x115+15 x1011+ 11 20| 4 125| 50 1211| 200 2 1 2

14+4 110+10 1200+200x16+6 x115+15 x1011+ 11 224 12650 1213200

Page 20: multiplication above the base

practise problems

12 14 112 107x13 x11 x101___ x108156 154 11312 11556

19 117 125 1035x11 x102x103x1010209 11934 12875 1045350

Page 21: multiplication above the base

problems of type iii

102 104 1003x103 x101 x1012___

Page 22: multiplication above the base

the number of digits on the right side of the answer will be equal to the number of zeros in the base.

Base 1 0 0 Base 1 0 0 Base 1 0 0 0

102+2 104+4 1003+3x103+3 x101+1 x1012+12 105| 0 6 105| 0 4 1015| 0 3 6

102+2 104+4 1003+3x103+3 x101+1 x1012+12 10506 10504 1015036

Page 23: multiplication above the base

practise problems

19 114 103 115x14 x110 x103___ x108266 12540 10609 12420

125 1002 1004 1250x120 x1007 x1002 x1010150001009014 1006008 1262500

Page 24: multiplication above the base

hari om!