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Practice Midterm Exam W4315 Fall 2011 Name: 1. Consider a regression where the explanatory variable is time: t o t t Y 1 for t=1,….n where the i are uncorrelated with E( i )=0 and 2 ( i )= 2 . (a) Compute the least squares estimate of 0 and 1 . (b) Show that the estimate is unbiased. (c) Compute the variance of the estimate. 2. Show that in the simple linear regression model, the relationship between the F- statistic and R 2 is given by 2 2 1 ) 2 ( R R n F 3. Show that the matrix (1/n)J, where J is the unit matrix, is idempotent. 4. Consider the multiple regression model: i i i i X X Y 2 2 1 1 for i=1,….n where the i are uncorrelated with E( i )=0 and 2 ( i )= 2 . Derive the least squares estimators of 1 and 2 .

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A plumbing fixture used for washing the middle part of the body, especially genitals. It is also known as the Sitz Bath

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  • Practice Midterm Exam W4315 Fall 2011

    Name:

    1. Consider a regression where the explanatory variable is time:

    tot tY 1 for t=1,.n

    where the i are uncorrelated with E(i)=0 and 2(i)=

    2.

    (a) Compute the least squares estimate of 0 and 1. (b) Show that the estimate is unbiased. (c) Compute the variance of the estimate.

    2. Show that in the simple linear regression model, the relationship between the F-statistic and R2 is given by

    2

    2

    1

    )2(

    R

    RnF

    3. Show that the matrix (1/n)J, where J is the unit matrix, is idempotent.

    4. Consider the multiple regression model:

    iiii XXY 2211 for i=1,.n

    where the i are uncorrelated with E(i)=0 and 2(i)=

    2.

    Derive the least squares estimators of 1 and 2.

  • 5. The Tri-City Office Equipment Corporation sells an imported copier on a franchise basis and performs preventive maintenance and repair service on this copier. Data was collected from 45 recent calls to perform routine preventive maintenance service; for each call, X is the number of copiers serviced and Y is the total number of minutes spent by the service person.

    A simple linear regression model is fit and the output is shown below:

    > results = lm(Time ~ Copiers) > results Call: lm(formula = Time ~ Copiers) Coefficients: (Intercept) Copiers -0.5802 15.0352 > summary(results) Call: lm(formula = Time ~ Copiers) Residuals: Min 1Q Median 3Q Max -22.7723 -3.7371 0.3334 6.3334 15.4039 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -0.5802 2.8039 -0.207 0.837 Copiers 15.0352 0.4831 31.123