50
More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g) 2CuO (s) ould the coefficients be of much use in the lab????

More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g) 2CuO (s) Would the coefficients be of much use in the lab?????

Embed Size (px)

Citation preview

Page 1: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

More about reactions!!!Coefficients…..again

2Cu (s) + O2 (g) 2CuO (s)

Would the coefficients be of much use in the lab?????

Page 2: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

There are units on the coefficientscalled the ‘mole’

2Cu (s) + O2 (g) 2CuO (s)

Chemists say:2 moles of Cu react with 1 mole of O2 to produce

2 moles of CuO

Page 3: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So…. When chemists talk about a “mole,” what exactly

are they talking about???

Cute… but no…

Not quite…

Ummm… I don’t think so...

6.02 x 1023 THAT’S IT!

Page 4: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

That’s right, in chemistry, a “mole” is a number!

Just like a “dozen” is 12 and a “gross” is 144, a “mole” is simply a word that stands for a number:

6.02 x 1023

It is also called Avogadro’s number named for the chemist who discovered it

Page 5: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So… What is so special about the number 6.02 x 1023?For one thing, it represents a very, very, VERY large quantity.

If written out, it would be: 602,000,000,000,000,000,000,000.

That’s 602 million, million, billion!That’s big!

Page 6: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

How big you ask…Consider the following examples.(And come up with your own if you want. They’re really not that hard to do…)

Page 7: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

This computer has a remarkably fast processor: 1.83 GHz.

That means, for example, that it is capable of counting to 1,830,000,000 every second!

So… at that rate, how long do you think it would take this computer to count to 1 mole???

Page 8: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

At 1,830,000,000 per second, it would take this computer a little over ten million years to count to 1 mole!!

(That’s a lot of counting!)

By the way, factor label makes this calculation fairly simple:

6.02 x 1023counts1sec

1.83x109countsX

1min

60 secX

1 year

365 dayX

1 day

24 hrX

1hr

60 minX

= 1.04 x 107 years= 10.4 million years

Page 9: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

A grain of rice is pretty small.

It takes about fifty grains of rice to fill a tiny one-milliliter box!

Even still, one mole of rice grains would be HUGE…

Take a guess: How much space would be taken up by one mole of rice grains?

Page 10: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

One mole of rice – that’s 6.02 x 1023 grains – would cover the entire planet Earth…And… in case you were wondering how this was calculated:

6.02 x 1023 grains

Earth’s radius = 6400 km = 6.4 x 106 m

Surface area of a sphere = 4r2

Surface area of Earth = 4(6.4 x 106m)2 = 5.1 x 1014 m2

= 1.2 x 1016 m3

Height =Volume

Area= 23.5 m

1 mL

50 grainsX

1 m3

1 x 106 mLX

1.2 x 1016 m3

5.1 x 1014 m2=

over 23 meters deep!

Volume of all that rice

Area that rice has to cover

Page 11: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

That’s so important, it’s worth repeating:

The mole provides a simple way for us to “count out” atoms and molecules by weighing them.

Page 12: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

But why is a mole such a big number?????

Because atoms are so small……..remember noone has ever seen an atom.

Page 13: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

To understand how this works, let’s take a look at the periodic table:Take Cu for example

We can see that the average mass

for a Cu atom is 63.546.

29

Cu63.546

29

Cu63.546

Page 14: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So how much would a mole of Cu weigh?

29

Cu63.546

The mass of one mole of Cu is simply Cu’s atomic mass expressed in grams.

1 mole Cu = 63.546 g = 6.02 x 1023 atoms Cu

Page 15: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

And does this neat little trick work for every element in the table?Let’s try neon.

We can see that the average mass

for a neon atom is 20.180.10

Ne20.180

10

Ne20.180

Page 16: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So how much would a mole of Ne weigh?

It tells us that one mole of Ne weighs 20.180 grams.

How convenient is that!

10

Ne20.180

Page 17: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So now, take out a periodic table and try answering the following questions.

As you figure out the answers, record them on the Mole Powerpoint and Video Notesheet available on Kdocs. Copy it to your notebook!

Page 18: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

1. How much would one mole of He weigh? Click on the right answer.

1 g 2 g 4.003 g 6.02x1023 g

Page 19: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

1. How much would one mole of He weigh?

1 g 2 g 4.003 g 6.02x1023 g

Sorry, try again

Page 20: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

1. How much would one mole of He weigh?

1 g 2 g 4.003 g 6.02x1023 g

Sorry, try again

Page 21: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

1. How much would one mole of He weigh?

1 g 2 g 4.003 g 6.02x1023 g

CORRECT!One mole of He would weigh 4.003 g

Write that answer on your worksheet, and then try the next question.

Page 22: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

2. How much would one mole of Ca weigh?

40.08 g1 g 12 g 6.02x1023 g

Page 23: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

2. How much would one mole of Ca weigh?

1 g 12 g 40.08 g 6.02x1023 g

Sorry, try again

Page 24: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

2. How much would one mole of Ca weigh?

1 g 12 g 40.08 g 6.02x1023 g

Sorry, try again

Page 25: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

2. How much would one mole of Ca weigh?

1 g 12 g 40.08 g 6.02x1023 g

CORRECT!One mole of Ca would weigh 40.08 g.

Write that answer on your worksheet, and then try the next question.

Page 26: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

3. How many atoms would be present in one mole of He?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Page 27: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

3. How many atoms would be present in one mole of He?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Sorry, try again

Page 28: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

3. How many atoms would be present in one mole of He?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Sorry, try again

Page 29: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

3. How many atoms would be present in one mole of He weigh?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

CORRECT!In one mole of He there would be 6.02x1023

atoms present.Write that answer on your worksheet,

and then try the next question.

Page 30: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

4. How many atoms would be present in one mole of Ca?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Page 31: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

4. How many atoms would be present in one mole of Ca?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Sorry, try again

Page 32: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

4. How many atoms would be present in one mole of Ca?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

Sorry, try again

Page 33: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

4. How many atoms would be present in one mole of Ca?

1 atom 2 atoms 4.003 atoms 6.02x1023 atoms

CORRECT!In one mole of Ca there would be 6.02x1023

atoms present.Write that answer on your worksheet,

and now let’s return to the tutorial.

Page 34: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

So what have we learned so far?1) One mole of any element weighs its

atomic mass in grams as shown on the Periodic Table.

(thus one mole of C weighs 12.011 g)

2) One mole of any element contains 6.02 x 1023 atoms.

(thus one mole of C contains 6.02 x 1023 atoms)

Page 35: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

But what about compounds like water (H2O), carbon dioxide (CO2) and propane (C3H8)…

Does the mole apply to them too?ABSOLUTELY! But there is a difference…

When we talk about 1 mole of an element like C, we are talking about 6.02x1023 atoms of C…

That’s 6.02x1023 of these:

But when we talk about 1 mole of a compound like H2O, for example, we are talking about 6.02x1023 molecules of H2O…

That’s 6.02x1023 of these: OH H

CCCCCCCCCCCCCCCCCCCCCCCCCCC

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH H

OH

OH

C

Page 36: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

How much would one mole of water H2O

weigh? HINT: use the Periodic Table.

If you were thinking 18.014 g, then good job!2(1.0079 grams) + 1(15.999 grams) = 18.014 grams

How much would one mole of CF4 weigh?

That’s one C and four F’s: 1(12.011 grams) + 4(18.998 grams) = 88.003 grams

And one mole of CF4 would weigh 88.003 g

Page 37: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

Again, using a periodic table (and perhaps a calculator if you need one), try answering the following questions?

As you figure out the answers, record them on the mole tutorial work sheet.

Page 38: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

5. How much would one mole of CO2 weigh?

40.0 g22.0 g 28.0 g 44.0 g

Page 39: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

5. How much would one mole of CO2 weigh?

40.0 g22.0 g 28.0 g 44.0 g

Sorry, try again

Page 40: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

5. How much would one mole of CO2 weigh?

40.0 g22.0 g 28.0 g 44.0 g

Sorry, try again

Page 41: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

CORRECT!One mole of CO2 would weigh 44.0 g.

Write that answer on your worksheet, and then try the next question.

40.0 g22.0 g 28.0 g 44.0 g

5. How much would one mole of CO2 weigh?

Page 42: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

6. What would one mole of (NH4)2S weigh?

54.1 g38.0 g 50.1 g 68.1 g

Page 43: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

6. What would one mole of (NH4)2S weigh?

54.1 g38.0 g 50.1 g 68.1 g

Sorry, try again

Page 44: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

6. What would one mole of (NH4)2S weigh?

54.1 g38.0 g 50.1 g 68.1 g

Sorry, try again

Page 45: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

CORRECT!One mole of (NH4)2S would weigh 68.1 g.

Write that answer on your worksheet, and then try the next question.

54.1 g38.0 g 50.1 g 68.1 g

6. What would one mole of (NH4)2S weigh?

Page 46: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

There is one more important bit of information we need to consider:Seven elements on the periodic tableAre not normally found as individual atoms like this:

9

F19.00

17

Cl35.45

35

Br79.90

53

I126.9

8

O16.00

7

N14.01

1

H1.008Instead, they

always bonded together into pairs like this:

Page 47: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

These seven elements are said to be “diatomic.” And when we write their symbols, we include a subscript “2” after them. Bromine, for example, would not just be “Br.”

Instead, it would be “Br2.”

Likewise, oxygen would be “O2.”

9

F19.00

17

Cl35.45

35

Br79.90

53

I126.9

8

O16.00

7

N14.01

1

H1.008

To help remember these seven diatomic elements, just think of the word:Br I N Cl H O F(pronounced “Brinklehof.”)

Br Br

O O

Page 48: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

The reason that this is important to mention here is that when we talk of “a mole of oxygen,” for example, we are not talking about 6.02x1023 individual O atoms like thisInstead, we are talking about 6.02x1023 diatomic O2 molecules, like this

9

F19.00

17

Cl35.45

35

Br79.90

53

I126.9

8

O16.00

7

N14.01

1

H1.008

O O O O O O O

OO

OO

OO

OO

OO

OO

OO

1 2 3 4 5 6 7…

1 2 3 4 5 6 7…

Page 49: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

That means that one mole of oxygen would not weigh 15.999 g. It would weigh twice that: 31.998 g.

9

F19.00

17

Cl35.45

35

Br79.90

53

I126.9

8

O16.00

7

N14.01

1

H1.008

8

O16.00

Likewise, one mole of nitrogenwould not weigh 14.007 g. It would weigh twice that: 28.014 g.

7

N14.01

It’s important to keep this in mind when dealing with these seven elements.

Page 50: More about reactions!!! Coefficients…..again 2Cu (s) + O 2 (g)  2CuO (s) Would the coefficients be of much use in the lab?????

Now try problems 7-18 on the mole notesheet. The answers are listed in the margin, so check them off as you do them to make sure you are on the right track.