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Momentum and Momentum Conservation Momentum Impulse Conservation of Momentum Collision in 1-D Collision in 2-D

Momentum and Momentum Conservation

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Momentum and Momentum Conservation. Momentum Impulse Conservation of Momentum Collision in 1-D Collision in 2-D. So What’s Momentum ?. Momentum = mass x velocity This can be abbreviated to : . momentum = mv - PowerPoint PPT Presentation

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Page 1: Momentum and  Momentum Conservation

Momentum and Momentum Conservation

• Momentum • Impulse• Conservation of Momentum• Collision in 1-D• Collision in 2-D

Page 2: Momentum and  Momentum Conservation

So What’s Momentum ?• Momentum = mass x velocity

• This can be abbreviated to : . momentum = mv

• Or, if direction is not an important factor : . . momentum = mass x speed

• So, A really slow moving truck and an extremely fast roller skate can have the same momentum.

Page 3: Momentum and  Momentum Conservation

Question :• Under what circumstances would the roller

skate and the truck have the same momentum ?

• The roller skate and truck can have the same momentum if the ratio of the speed of the skate to the speed of the truck is the same as the ratio of the mass of the truck to the mass of the skate.

• A 1000 kg truck moving at 0.01 m/sec has the same momentum as a 1 kg skate moving at 10 m/sec. Both have a momentum of 10 kg m/sec. ( 1000 x .01 = 1 x 10 = 10 )

Page 4: Momentum and  Momentum Conservation

Linear Momentum• A new fundamental quantity, like force, energy• The linear momentum p of an object of mass

m moving with a velocity is defined to be the product of the mass and velocity:

– The terms momentum and linear momentum will be used interchangeably in the text

– Momentum depend on an object’s mass and velocity

v

vmp

Page 5: Momentum and  Momentum Conservation

Newton’s Law and Momentum• Newton’s Second Law can be used to relate the

momentum of an object to the resultant force acting on it

• The change in an object’s momentum divided by the elapsed time equals the constant net force acting on the object

tvm

tvmamFnet

)(

netFtp

interval timemomentumin change

Page 6: Momentum and  Momentum Conservation

• If momentum changes, it’s because mass or velocity change.

• Most often mass doesn’t change so velocity changes and that is acceleration.

• And mass x acceleration = force • Applying a force over a time interval to an

object changes the momentum• Force x time interval = Impulse • Impulse = F t or Ft = mv

Impulse and Momentum

Ft = mv

Page 7: Momentum and  Momentum Conservation

Impulse-Momentum Theorem• The theorem states

that the impulse acting on a system is equal to the change in momentum of the system

if vmvmpI

ItFp net

Page 8: Momentum and  Momentum Conservation

FOR

CE

• An object at rest has no momentum, why?• Because anything times zero is zero• (the velocity component is zero for an object at rest)• To INCREASE MOMENTUM,

apply the greatest force possible for as long as possible.

• Examples : • pulling a sling shot • drawing an arrow in a bow all the way back • a long cannon for maximum range• hitting a golf ball or a baseball

. (follow through is important for these !)

TIME

MOMENTUM

Page 9: Momentum and  Momentum Conservation

MOMENTUM• SOME VOCABULARY : • impulse : impact force X time (newton.sec)

. Ft = impulse

• impact : the force acting on an object (N) . usually when it hits something.

• impact forces : average force of impact

Page 10: Momentum and  Momentum Conservation

• Decreasing Momentum • Which would it be more safe to hit in a car ?

• Knowing the physics helps us understand why hitting a soft object is better than hitting a hard one.

MOMENTUM

mv

mv

Ft

Ft

Page 11: Momentum and  Momentum Conservation

• In each case, the momentum is decreased by the same amount or impulse (force x time)

• Hitting the haystack extends the impact time (the time in which the momentum is brought to zero).

• The longer impact time reduces the force of impact and decreases the deceleration.

• Whenever it is desired to decrease the force of impact, extend the time of impact !

MOMENTUM

Page 12: Momentum and  Momentum Conservation

DECREASING MOMENTUM• If the time of impact is increased by 100 times (say from .01

sec to 1 sec), then the force of impact is reduced by 100 times (say to something survivable).

• EXAMPLES :• Padded dashboards on cars• Airbags in cars or safety nets in circuses• Moving your hand backward as you catch a fast-moving ball

with your bare hand or a boxer moving with a punch.• Flexing your knees when jumping from a higher place to the

ground. or elastic cords for bungee jumping• Using wrestling mats instead of hardwood floors.• Dropping a glass dish onto a carpet instead of a sidewalk.

Page 13: Momentum and  Momentum Conservation

EXAMPLES OF DECREASING MOMENTUM

• Bruiser Bruno on boxing …

• Increased impact time reduces force of impact• Barbie on bungee Jumping …

Ft = change in momentum

Ft = change in momentum

Ft = Δmv applies here.mv = the momentum gained before the cord begins to stretch that we wish to change.

Ft = the impulse the cord supplies to reduce the momentum to zero.

Because the rubber cord stretches fora long time the average force on the jumper is small.

Page 14: Momentum and  Momentum Conservation

Questions : • When a dish falls, will the impulse be less if it lands on a

carpet than if it lands on a hard ceramic tile floor ? • The impulse would be the same for either surface

because there is the same momentum change for each. It is the force that is less for the impulse on the carpet because of the greater time of momentum change. There is a difference between impulse and impact.

• If a boxer is able to increase the impact time by 5 times by “riding” with a punch, by how much will the force of impact be reduced?

• Since the time of impact increases by 5 times, the force of impact will be reduced by 5 times.

Page 15: Momentum and  Momentum Conservation

BOUNCING• IMPULSES ARE GREATER WHEN AN OBJECT

BOUNCES• The impulse required to bring an object to a stop

and then to throw it back upward again is greater than the impulse required to merely bring the object to a stop.

• When a martial artist breaks boards,• does their hand bounce?• Is impulse or momentum greater ?

• Example : • The Pelton Wheel.

Page 16: Momentum and  Momentum Conservation

Calculating the Change of Momentum

0 ( )p m v mv

( )

after before

after before

after before

p p p

mv mv

m v v

For the teddy bear

For the bouncing ball

( ) 2p m v v mv

Page 17: Momentum and  Momentum Conservation

How Good Are the Bumpers? In a crash test, a car of mass 1.5103 kg collides with a wall

and rebounds as in figure. The initial and final velocities of the car are vi=-15 m/s and vf = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find

(a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car

Page 18: Momentum and  Momentum Conservation

How Good Are the Bumpers? In a crash test, a car of mass 1.5103 kg collides with a wall

and rebounds as in figure. The initial and final velocities of the car are vi=-15 m/s and vf = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find

(a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car

smkgsmkgmvp ii /1025.2)/15)(105.1( 43

Ns

smkgtI

tpFav

54

1076.115.0

/1064.2

smkgsmkgmvp ff /1039.0)/6.2)(105.1( 43

smkg

smkgsmkg

mvmvppI ifif

/1064.2

)/1025.2()/1039.0(4

44

Page 19: Momentum and  Momentum Conservation

CONSERVATION OF MOMENTUM• To accelerate an object, a force must be applied. • The force or impulse on the object must come

from outside the object.

• EXAMPLES : The air in a basketball, sitting in a car and pushing on the dashboard or sitting in a boat and blowing on the sail don’t create movement.

• Internal forces like these are balanced and cancel each other.

• If no outside force is present, no change in momentum is possible.

Page 20: Momentum and  Momentum Conservation

The Law of Conservation of Momentum

• In the absence of an external force, the momentum of a system remains unchanged.

• This means that, when all of the forces are internal (for EXAMPLE: the nucleus of an atom undergoing . radioactive decay, . cars colliding, or . stars exploding the net momentum of the system before and after the event is the same.

Page 21: Momentum and  Momentum Conservation

Conservation of Momentum• In an isolated and closed

system, the total momentum of the system remains constant in time. – Isolated system: no external forces– Closed system: no mass enters or

leaves– The linear momentum of each

colliding body may change– The total momentum P of the

system cannot change.

Page 22: Momentum and  Momentum Conservation

Conservation of Momentum• Start from impulse-momentum

theorem

• Since

• Then

• So

if vmvmtF 222212

if vmvmtF 111121

tFtF 1221

)( 22221111 ifif vmvmvmvm

ffii vmvmvmvm 22112211

Page 23: Momentum and  Momentum Conservation

QUESTIONS• 1. Newton’s second law states that if no net force is

exerted on a system, no acceleration occurs. Does it follow that no change in momentum occurs?

• No acceleration means that no change occurs in velocity of momentum.

• 2. Newton’s 3rd law states that the forces exerted on a cannon and cannonball are equal and opposite. Does it follow that the impulse exerted on the cannon and cannonball are also equal and opposite?

• Since the time interval and forces are equal and opposite, the impulses (F x t) are also equal and opposite.

Page 24: Momentum and  Momentum Conservation

• ELASTIC COLLISIONS

• INELASTIC COLLISIONS

COLLISIONS

Momentum transfer from one Object to another .

Is a Newton’s cradle like the one Pictured here, an example of an elastic or inelastic collision?

Page 25: Momentum and  Momentum Conservation

Problem Solving #1• A 6 kg fish swimming at 1 m/sec swallows a 2 kg fish

that is at rest. Find the velocity of the fish immediately after “lunch”.

• net momentum before = net momentum after • (net mv)before = (net mv)after • (6 kg)(1 m/sec) + (2 kg)(0 m/sec) = (6 kg + 2 kg)(vafter) • 6 kg.m/sec = (8 kg)(vafter) • vafter = 6 kg.m/sec / 8 kg • 8 kg• vafter = ¾ m/sec

vafter =

Page 26: Momentum and  Momentum Conservation

Problem Solving #2• Now the 6 kg fish swimming at 1 m/sec swallows a 2

kg fish that is swimming towards it at 2 m/sec. Find the velocity of the fish immediately after “lunch”.

• net momentum before = net momentum after • (net mv)before = (net mv)after • (6 kg)(1 m/sec) + (2 kg)(-2 m/sec) = (6 kg + 2 kg)(vafter) • 6 kg.m/sec + -4 kg.m/sec = (8 kg)(vafter) • vafter = 2 kg.m/sec / 8 kg

• 8 kg• vafter = ¼ m/sec

vafter =

Page 27: Momentum and  Momentum Conservation

Problem Solving #3 & #4• Now the 6 kg fish swimming at 1 m/sec swallows a 2

kg fish that is swimming towards it at 3 m/sec. • (net mv)before = (net mv)after • (6 kg)(1 m/sec) + (2 kg)(-3 m/sec) = (6 kg + 2 kg)(vafter) • 6 kg.m/sec + -6 kg.m/sec = (8 kg)(vafter) • vafter = 0 m/sec

• Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 4 m/sec.

• (net mv)before = (net mv)after • (6 kg)(1 m/sec) + (2 kg)(-4 m/sec) = (6 kg + 2 kg)(vafter) • 6 kg.m/sec + -8 kg.m/sec = (8 kg)(vafter) • vafter = -1/4 m/sec

Page 28: Momentum and  Momentum Conservation

The Archer An archer stands at rest on frictionless ice and fires a 0.5-kg

arrow horizontally at 50.0 m/s. The combined mass of the archer and bow is 60.0 kg. With what velocity does the archer move across the ice after firing the arrow?

ffii vmvmvmvm 22112211

fi pp

?,/50,0,5.0,0.60 122121 ffii vsmvvvkgmkgm

ff vmvm 22110

smsmkgkgv

mmv ff /417.0)/0.50(

0.605.0

21

21

Page 29: Momentum and  Momentum Conservation

Types of Collisions• Momentum is conserved in any collision• Inelastic collisions: rubber ball and hard ball

– Kinetic energy is not conserved– Perfectly inelastic collisions occur when the objects

stick together• Elastic collisions: billiard ball

– both momentum and kinetic energy are conserved• Actual collisions

– Most collisions fall between elastic and perfectly inelastic collisions

Page 30: Momentum and  Momentum Conservation

Collision between two objects of the same mass. One mass is at rest.

Collision between two objects. One not at rest initially has twice the mass.

Collision between two objects. One at rest initially has twice the mass.

Simple Examples of Head-On Collisions(Energy and Momentum are Both Conserved)

vmp

Page 31: Momentum and  Momentum Conservation

vmp

Collision between two objects of the same mass. One mass is at rest.

Example of Non-Head-On Collisions

(Energy and Momentum are Both Conserved)

If you vector add the total momentum after collision,you get the total momentum before collision.

Page 32: Momentum and  Momentum Conservation

Collisions Summary• In an elastic collision, both momentum and kinetic

energy are conserved• In an inelastic collision, momentum is conserved but

kinetic energy is not. Moreover, the objects do not stick together

• In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same

• Elastic and perfectly inelastic collisions are limiting cases, most actual collisions fall in between these two types

• Momentum is conserved in all collisions

Page 33: Momentum and  Momentum Conservation

More about Perfectly Inelastic Collisions

• When two objects stick together after the collision, they have undergone a perfectly inelastic collision

• Conservation of momentum

• Kinetic energy is NOT conserved

fii vmmvmvm )( 212211

21

2211

mmvmvmv ii

f

Page 34: Momentum and  Momentum Conservation

An SUV Versus a Compact An SUV with mass 1.80103 kg is travelling eastbound at +15.0

m/s, while a compact car with mass 9.00102 kg is travelling westbound at -15.0 m/s. The cars collide head-on, becoming entangled.

(a) Find the speed of the entangled cars after the collision.

(b) Find the change in the velocity of each car.

(c) Find the change in the kinetic energy of the system consisting of both cars.

Page 35: Momentum and  Momentum Conservation

(a) Find the speed of the entangled cars after the collision.

fii vmmvmvm )( 212211

fi pp smvkgm

smvkgm

i

i

/15,1000.9

/15,1080.1

22

2

13

1

21

2211

mmvmvmv ii

f

smv f /00.5

An SUV Versus a Compact

Page 36: Momentum and  Momentum Conservation

(b) Find the change in the velocity of each car.

smvvv if /0.1011

smvkgm

smvkgm

i

i

/15,1000.9

/15,1080.1

22

2

13

1

smv f /00.5

An SUV Versus a Compact

smvvv if /0.2022

smkgvvmvm if /108.1)( 41111

02211 vmvm

smkgvvmvm if /108.1)( 42222

Page 37: Momentum and  Momentum Conservation

(c) Find the change in the kinetic energy of the system consisting of both cars.

JvmvmKE iii52

22211 1004.3

21

21

smvkgm

smvkgm

i

i

/15,1000.9

/15,1080.1

22

2

13

1

smv f /00.5

An SUV Versus a Compact

JKEKEKE if51070.2

JvmvmKE fff42

22211 1038.3

21

21

Page 38: Momentum and  Momentum Conservation

More About Elastic Collisions• Both momentum and kinetic energy

are conserved

• Typically have two unknowns• Momentum is a vector quantity

– Direction is important– Be sure to have the correct signs

• Solve the equations simultaneously

222

211

222

211

22112211

21

21

21

21

ffii

ffii

vmvmvmvm

vmvmvmvm

Page 39: Momentum and  Momentum Conservation

Elastic Collisions• A simpler equation can be used in place of the KE

equation

iffi vvvv 2211

222

211

222

211 2

121

21

21

ffii vmvmvmvm

))(())(( 2222211111 ififfifi vvvvmvvvvm

)()( 222111 iffi vvmvvm

)()( 22

222

21

211 iffi vvmvvm

ffii vmvmvmvm 22112211

ffii vmvmvmvm 22112211

Page 40: Momentum and  Momentum Conservation

Summary of Types of Collisions• In an elastic collision, both momentum and kinetic

energy are conserved

• In an inelastic collision, momentum is conserved but kinetic energy is not

• In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same

iffi vvvv 2211 ffii vmvmvmvm 22112211

ffii vmvmvmvm 22112211

fii vmmvmvm )( 212211

Page 41: Momentum and  Momentum Conservation

Problem Solving for 1D Collisions, 1• Coordinates: Set up a

coordinate axis and define the velocities with respect to this axis– It is convenient to make your

axis coincide with one of the initial velocities

• Diagram: In your sketch, draw all the velocity vectors and label the velocities and the masses

Page 42: Momentum and  Momentum Conservation

Problem Solving for 1D Collisions, 2• Conservation of

Momentum: Write a general expression for the total momentum of the system before and after the collision– Equate the two total

momentum expressions– Fill in the known values

ffii vmvmvmvm 22112211

Page 43: Momentum and  Momentum Conservation

Problem Solving for 1D Collisions, 3• Conservation of Energy:

If the collision is elastic, write a second equation for conservation of KE, or the alternative equation– This only applies to perfectly

elastic collisions

• Solve: the resulting equations simultaneously

iffi vvvv 2211

Page 44: Momentum and  Momentum Conservation

One-Dimension vs Two-Dimension

Page 45: Momentum and  Momentum Conservation

Two-Dimensional Collisions• For a general collision of two objects in two-

dimensional space, the conservation of momentum principle implies that the total momentum of the system in each direction is conserved

fyfyiyiy

fxfxixix

vmvmvmvm

vmvmvmvm

22112211

22112211

Page 46: Momentum and  Momentum Conservation

Two-Dimensional Collisions• The momentum is conserved in all directions• Use subscripts for

– Identifying the object– Indicating initial or final values– The velocity components

• If the collision is elastic, use conservation of kinetic energy as a second equation– Remember, the simpler equation can only be used

for one-dimensional situations

fyfyiyiy

fxfxixix

vmvmvmvm

vmvmvmvm

22112211

22112211

iffi vvvv 2211

Page 47: Momentum and  Momentum Conservation

Glancing Collisions

• The “after” velocities have x and y components• Momentum is conserved in the x direction and in the

y direction• Apply conservation of momentum separately to each

direction

fyfyiyiy

fxfxixix

vmvmvmvm

vmvmvmvm

22112211

22112211

Page 48: Momentum and  Momentum Conservation

Problem Solving for Two-Dimensional Collisions, 3

• Conservation of Energy: If the collision is elastic, write an expression for the total energy before and after the collision– Equate the two expressions– Fill in the known values– Solve the quadratic equations

• Can’t be simplified

Page 49: Momentum and  Momentum Conservation

Problem Solving for Two-Dimensional Collisions, 4

• Solve for the unknown quantities– Solve the equations simultaneously– There will be two equations for inelastic

collisions– There will be three equations for elastic

collisions• Check to see if your answers are

consistent with the mental and pictorial representations. Check to be sure your results are realistic

Page 50: Momentum and  Momentum Conservation

Collision at an Intersection A car with mass 1.5×103 kg

traveling east at a speed of 25 m/s collides at an intersection with a 2.5×103 kg van traveling north at a speed of 20 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision and assuming that friction between the vehicles and the road can be neglected. ??,/20,/25

105.2,105.1 33

fviycix

vc

vsmvsmvkgmkgm

Page 51: Momentum and  Momentum Conservation

Collision at an Intersection

??,/20,/25105.2,105.1 33

fviycix

vc

vsmvsmvkgmkgm

smkgvmvmvmp cixcvixvcixcxi /1075.3 4

cos)( fvcvfxvcfxcxf vmmvmvmp

cos)1000.4(/1075.3 34fvkgsmkg

smkgvmvmvmp viyvviyvciycyi /1000.5 4

sin)( fvcvfyvcfycyf vmmvmvmp

sin)1000.4(/1000.5 34fvkgsmkg

Page 52: Momentum and  Momentum Conservation

Collision at an Intersection

??,/20,/25105.2,105.1 33

fviycix

vc

vsmvsmvkgmkgm

cos)1000.4(/1075.3 34fvkgsmkg

sin)1000.4(/1000.5 34fvkgsmkg

33.1/1075.3/1000.5tan 4

4

smkgsmkg

1.53)33.1(tan 1

smkg

smkgv f /6.151.53sin)1000.4(

/1000.53

4

Page 53: Momentum and  Momentum Conservation

MOMENTUM VECTORS• Momentum can be analyzed by using vectors• The momentum of a car accident is equal to the

vector sum of the momentum of each car A & B before the collision.

A

B

Page 54: Momentum and  Momentum Conservation

MOMENTUM VECTORS (Continued) • When a firecracker bursts, the vector sum of the momenta

of its fragments add up to the momentum of the firecracker just before it exploded.

• The same goes for subatomic elementary particles. The tracks they leave help to determine their relative mass and type.