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Name: MOHD SHEREEN BIN ZAINUDDIN Matric no: A136646 INTRODUCTION Nowadays, the application of rubber bearing is really important to reduce vibration risk due to earthquake or vibration from human activity. For bridge applications this rubber bearing is used to protect structural elements from the effects of strong-ground motion. Rubber bearing with steel reinforcement are mostly common rubber bearing are used in superstructure application. For this analysis, CST software is used to determine the formation of the deformation of the rubber block with and without steel laminated at the middle of the rubber block.

MOHD SHEREEN BIN ZAINUDDIN

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2D STRESS ANALYSIS USING CST NO MATRIC: A 136646UKM

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  • Name: MOHD SHEREEN BIN ZAINUDDIN

    Matric no: A136646

    INTRODUCTION

    Nowadays, the application of rubber bearing is really important to reduce vibration risk due to

    earthquake or vibration from human activity. For bridge applications this rubber bearing is used

    to protect structural elements from the effects of strong-ground motion. Rubber bearing with

    steel reinforcement are mostly common rubber bearing are used in superstructure application.

    For this analysis, CST software is used to determine the formation of the deformation of the

    rubber block with and without steel laminated at the middle of the rubber block.

  • Before we proceed with the calculation by using CST, here are some information related with the

    acronyms:

    NN: Number of node

    NE: Number of elements

    NM: Number of different materials

    NDIM: Number of coordinates per node (2D = 2 or 3D = 3)

    NEN: N Number of node per elements

    ND: Number of degree of freedom along which displacement is specified. (Boundary condition)

    NL: Number of applied component loads (along degree of freedom)

    NMPC: Number of Multipoint Constrains

    Nu: Poissons ratio

    CASE 1:

    Rubber block without steel laminated deformation analysis.

    Rubber block analysis:

    Thickness: 300mm

    Dimension: 100 mm X 80 mm

    Material: Rubber.

  • Answer:

    Node# X-Displ (mm) Y-Displ (mm)

    1 -1.70077E-06 -3.70928E-06

    2 6.03003E-07 -4.8504E-06

    3 1.51156E-06 -4.37135E-06

    4 -0.059250339 -0.16026537

    5 0.031269896 -0.139690352

    6 0.136115145 -0.238519185

    7 -0.030993938 -0.375223348

    8 0.074256736 -0.296143672

    9 0.267747217 -0.508297224

    Elem# SX SY Txy S1 S2 S3

    1 -26.70966247 -53.42024646 -4.93746 -25.8262 -54.3037 -10.1447

    2 0.857812273 -34.49246932 3.977442 1.299808 -34.9345 6.341018

    3 -23.28067469 -46.5617128 2.605806 -22.9926 -46.8498 6.309005

    4 -11.79373582 -65.52557143 4.754214 -11.3763 -65.943 5.017608

    5 -11.68760037 -59.5832946 3.726368 -11.3994 -59.8715 4.422247

    6 1.991293218 -38.11768335 8.854215 3.858931 -39.9853 11.91092

    7 1.883179886 -38.17174002 -3.00635 2.107567 -38.3961 -4.26851

    8 6.634455171 -64.12728202 -3.17423 6.776559 -64.2694 -2.56331

    DOF# Reaction

    1 197288.9441 N

    2 430276.6238 N

    3 -69948.29141 N

    4 562646.7523 N

    5 -175340.6527 N

    6 507076.6238 N

  • Result:

    Displacement of the node:

    From the picture above, it is the form of deformation of the rubber block. The resultant force are

    more toward to the right direction. The deformation happened at the entire portion of the

    element.

  • CASE 2:

    Steel laminated rubber block analysis:

    Thickness: 300mm

    Dimension: 100 mm X 80 mm

    Material: Rubber and steel

  • Answer:

    Node# X-Displ (mm) Y-Displ (mm)

    1 -3.89101E-08 -1.12083E-07

    2 1.50991E-08 -1.93563E-07

    3 3.78997E-08 -1.34624E-07

    4 0.002013544 -0.134005283

    5 0.021987199 -0.120650501

    6 0.041988278 -0.163685533

    7 -0.000689064 -0.137619293

    8 0.025582289 -0.123865518

    9 0.050385789 -0.168204464

    10 -0.021151996 -0.309906591

    11 0.037200266 -0.229298178

    12 0.203999529 -0.406731079

    Elem# SX SY Txy S1 S2 S3

    1 -25.52477999 -51.04958159 0.191764 -25.5233 -51.051 0.430423

    2 -17.65470284 -43.29886792 2.984336 -17.312 -43.6416 6.551153

    3 -22.98100492 -45.96201896 2.094021 -22.7918 -46.1513 5.164099

    4 -25.84454997 -59.68953154 1.129878 -25.8069 -59.7272 1.909923

    5 63.96764559 -53.08992242 -0.24347 63.96815 -53.0904 -0.11917

    6 94.28056554 -36.01616334 48.8142 110.5394 -52.275 18.4217

    7 66.71891879 -44.28465736 -38.5532 78.79522 -56.361 -17.3925

    8 79.23122218 -66.60925688 -3.61752 79.3209 -66.6989 -1.42004

    9 -25.81093374 -62.13040893 -1.03193 -25.7816 -62.1597 -1.62618

    10 -4.521808037 -32.38452108 6.480368 -3.08834 -33.818 12.47308

    11 -13.46814476 -36.85768945 -1.84946 -13.3228 -37.003 -4.49327

    12 -0.953837837 -68.62738054 2.80102 -0.8381 -68.7431 2.366088

    DOF# Reaction

    1 132566.8625 N

    2 381865.0992 N

    3 -51442.50217 N

    4 659469.8016 N

    5 -129124.3603 N

    6 458665.0992 N

  • The deformation of the rubber mostly happened at the top layer of the laminated rubber block.

  • DISCUSSION

    1. The displacement of the nodes for case 1 (rubber block without steel laminated) are much

    higher compared to the rubber block with steel laminated.

    2. Besides that, the reaction forces for case 1 are higher compared to the steel laminated

    rubber block.

    3. Steel laminated rubber block give out minimum deformation and stabilize the shape of the

    block, which is important to maintain the shape of the structure in application area.

    4. The deformation of the rubber block without steel laminated give out major shape changing

    when force being applied to its surface.

    CONCLUSION

    As conclusion, for steel laminated rubber block, the deformation happen mostly at the top of the

    surface of the laminated area. But for the rubber block without steel laminated, we can see that,

    the entire area of the surface undergoes serious deformation.