Name: MOHD SHEREEN BIN ZAINUDDIN

Matric no: A136646

Before we proceed with the calculation by using CST, here are some information related with the

acronyms:

NN: Number of node

NE: Number of elements

NM: Number of different materials

NDIM: Number of coordinates per node (2D = 2 or 3D = 3)

NEN: N Number of node per elements

ND: Number of degree of freedom along which displacement is specified. (Boundary condition)

NL: Number of applied component loads (along degree of freedom)

NMPC: Number of Multipoint Constrains

Nu: Poissons ratio

Rubber block deformation analysis.

Rubber block analysis:

Thickness: 300mm

Dimension: 100 mm X 80 mm

Material: Rubber.

NN NE NM NDIM NEN NDN

9 8 1 2 3 2

ND NL NMPC

6 6 0

Node# X Y

1 0 0

2 50 0

3 100 0

4 0 40

5 50 40

6 100 40

7 0 80

8 50 80

9 100 80

Elem# N1 N2 N3 Mat# Thickness Temp Rise

1 1 2 4 1 300 0

2 5 4 2 1 300 0

3 2 3 5 1 300 0

4 6 5 3 1 300 0

5 4 5 7 1 300 0

6 8 7 5 1 300 0

7 5 6 8 1 300 0

8 9 8 6 1 300 0

DOF# Displacement

1 0

2 0

3 0

4 0

5 0

6 0

DOF# Load

13

1.60E+0

4

14

-

5.00E+0

5

15

1.60E+0

4

16

-

5.00E+0

5

17

1.60E+0

4

18

-

5.00E+0

5

MAT# E Nu Alpha

1

1.00E+0

4 0.25 1.20E-05

B1 i B2 j B3

(Multi-

point constr.

B1*Qi+B2*Qj=B3

)

Answer:

Node# X-Displ (mm)Y-Displ (mm)

1 -9.36E-07 -4.0362E-06

2 6.5299E-07 -6.2743E-06

3 7.6691E-07 -4.8104E-06

4 -0.0202804 -0.19411691

5 0.02507255 -0.1669478

6 0.07106639 -0.24027858

7 -0.0065359 -0.42198613

8 0.05092381 -0.32429449

9 0.16999272 -0.50129108

Elem# SX SY Txy S1 S2 S3

1 -12.940519 -51.7633471 -2.02813 -12.8349 -51.869 -2.98234

2 -1.4541391 -42.0989166 4.680718 -0.92207 -42.631 6.485176

3 -11.129411 -44.5177346 2.507307 -10.9422 -44.705 4.270724

4 -6.2062327 -61.6200017 1.2401 -6.17849 -61.6477 1.281362

5 -5.5159852 -58.3463011 3.547974 -5.27878 -58.5835 3.824973

6 1.76830109 -38.8945962 10.40046 4.274044 -41.4003 13.5459

7 -0.6777601 -39.5061115 -3.28134 -0.40241 -39.7815 -4.79666

8 8.00053468 -63.2529911 -4.26709 8.255164 -63.5076 -3.41495

DOF# Reaction

1 92854.053 N

2 400393.855 N

3 -64776.839 N

4 622412.29 N

5 -76077.214 N

6 477193.855 N

Result:

Displacement of the node:

From the picture above, it is the form of deformation of the rubber block. The resultant force are

more toward to the right direction.

Conclusion:

Deformation happened at the entire portion of the element.

Steel laminated rubber block analysis:

NN NE NM NDIM NEN NDN

12 12 2 2 3 2

ND NL NMPC

6 6 0

Node# X Y

1 0 0

2 50 0

3 100 0

4 0 35

5 50 35

6 100 35

7 0 45

8 50 45

9 100 45

10 0 80

11 50 80

12 100 80

Elem# N1 N2 N3 Mat# Thickness

Temp

Rise

1 1 2 4 1 300 0

2 5 4 2 1 300 0

3 2 3 5 1 300 0

4 6 5 3 1 300 0

5 4 5 7 2 300 0

6 8 7 5 2 300 0

7 5 6 8 2 300 0

8 9 8 6 2 300 0

9 7 8 10 1 300 0

10 11 10 8 1 300 0

11 8 9 11 1 300 0

12 12 11 9 1 300 0

DOF# Displacement

1 0

2 0

3 0

4 0

5 0

6 0

DOF# Load

19 1.60E+04

20 -5.00E+05

21 1.60E+04

22 -5.00E+05

23 1.60E+04

24 -5.00E+05

MAT# E Nu Alpha

1 1.00E+04 0.25 1.20E-05

2 2.00E+05 0.25 1.20E-05

B1 i B2 j B3

(Multi-

point constr. B1*Qi+B2*Qj=B3)

Answer:

Node# X-Displ (mm)Y-Displ (mm)

1 -1.743E-08 -1.11125E-07

2 1.2911E-08 -2.08747E-07

3 1.9054E-08 -1.34382E-07

4 0.00885918 -0.162864543

5 0.01913444 -0.153034029

6 0.02838085 -0.190734361

7 0.00714629 -0.165821491

8 0.02236942 -0.155603138

9 0.0357172 -0.194418824

10 0.00242336 -0.367859271

11 0.03415642 -0.279248756

12 0.13620939 -0.429752272

Elem# SX SY Txy S1 S2 S3

1 -12.408712 -49.63487288 1.012472 -12.3812 -49.6624 1.556789

2 -9.4676654 -46.09086497 2.973233 -9.22786 -46.3307 4.611281

3 -11.659718 -46.6388782 2.186797 -11.5235 -46.7751 3.563476

4 -12.559563 -57.63538395 0.227497 -12.5584 -57.6365 0.289162

5 28.0706981 -52.12127545 2.025699 28.12184 -52.1724 1.446097

6 51.25011 -38.56964846 42.22925 67.98605 -55.3056 21.61899

7 25.749458 -44.94481147 -34.4406 39.7539 -58.9493 -22.1279

8 37.3000485 -64.36426462 -3.41431 37.41459 -64.4788 -1.92134

9 -12.145753 -60.76151843 0.277704 -12.1442 -60.7631 0.327272

10 -2.650899 -35.99004428 8.435926 -0.63787 -38.0031 13.42124

11 -6.5730924 -36.97059263 -1.75817 -6.47174 -37.0719 -3.29928

12 3.84113333 -66.27784467 -0.55546 3.845533 -66.2822 -0.45384

DOF# Reaction

1 57552.1957 N

2 366946.066 N

3 -42632.444 N

4 689307.867 N

5 -62919.752 N

6 443746.066 N

Conclusion:

As conclusion the deformation of the rubber mostly happened at the top layer of the laminated

rubber block.