Module 4_Mo Hinh May Bien AP

  • Upload
    hoanggo

  • View
    218

  • Download
    0

Embed Size (px)

Citation preview

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    1/17

    MODULE 4: M HNH MY BIN P TRANG 53

    TrngH SPhm KThut TP.HCM

    MODULE 4

    M HNH MY BIN P

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    2/17

    TRANG 54 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    Ni dung thc hnh

    1. Tm hiu nguyn l hot ng ca cc thit b c trong m hnh.2. Kho st b ngun cung cp.3. Kho st cc dng co.4. Kho st m hnh my bin p 1 pha 3 pha ch khng ti.5. Kho st m hnh my bin p 3 pha mang ti tr.6. Kho st m hnh my bin p 3 pha mang ti cm.7. Kho st m hnh my bin p 3 pha mang ti dung.8. Kho st m hnh my bin p ch ngn mch.

    Cc thit b c trong m hnh:

    1. Variac 3 pha.

    Hnh: M hnh my kho st my bin p

    1

    4

    3 32

    5

    6

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    3/17

    MODULE 4: M HNH MY BIN P TRANG 55

    TrngH SPhm KThut TP.HCM

    2. My bin p 3 cun dy.3. ng ha nng MFM384C4. Ti thun tr.5. Ti thun cm.6. Ti thun dung.

    BI 4.1: KHO ST CC THIT B V DNG CO

    A. MC TIUSau khi hc xong bi ny, sinh vin c kh nng:

    - Xc nh c cc thit b c trong m hnh my bin p.- Trnh by c nguyn l hot ng ca cc thit b c trong m hnh.- Hnh thnh tc phong cng nghip, m bo v sinh v an ton lao ng.B. NI DUNGI. Varia 3 pha

    To ngun 3 pha dao ng t 0 400 V cho m hnh th nghim.

    Trnh t thao tc:

    1. Vn nm xoay (2) theo ngc chiu kim ng h v gi tr zero.

    Hnh 4.1.1: Variac 3 pha 0 400 V

    1 2

    3

    4

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    4/17

    TRANG 56 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    2. Bt khi CB (1) cp ngun cho variac 3 pha3. Vn nm xoay (2) theo cng chiu kim ng h tng dn gi tr

    in p. ng thi quan st ch s hin th trn cm ng h (3) cho

    ph hp vi yu cu bi thc hnh.

    4. Khi t c gi tr mong mun, nhn nt Start a ngun ncc u cc L1, L2, L3, N.

    5. Khi kt thc th nghim, nhn nt Stop, vn nm xoay (2) v gi trzero v tt khi CB cp ngun cho variac

    II. ng ha nng MFM384CXem bi 1.1

    III. Ti tr- Ti cm Ti dungCung cp cc ti c tnh cht tr- tnh cm tnh dung cho bi thc hnh.

    C. CU HI N TP1. Nu tn, thng s v chc nng ca cc thit b c trong m hnh my bin p?

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    5/17

    MODULE 4: M HNH MY BIN P TRANG 57

    TrngH SPhm KThut TP.HCM

    BI 4.2: KHO ST MY BIN P CH KHNG TI

    I. MC TIUSau khi hc xong bi ny, sinh vin c kh nng:

    Xc nh c cc thit b c trng m hnh my bin p. Trnh by c nguyn l hot ng ca cc thit b c trong m hnh. Thc hnh lp rp m hnh, o ly thng s v nhn xt kt qu. Xc nh t s bin i in p ca my bin p vn hnh ch khng ti. Xc nh mc tiu th cng sut tc dng v cng sut phn khng ca my

    bin p ch khng ti.

    Hnh thnh tc phong cng nghip, m bo v sinh v an ton lao ng.II. NI DUNG THC HINBc 1: Nhn bit cc thit b cn thit cho m hnh th nghim. Cc thit b cho trong

    bng sau:

    Thit b S lng

    Variac 3 pha in p 0 400V 1My bin th 3 pha 1

    ng ha nng MFM384C 2

    B ni dy an ton cc mu xanh, , vng,

    en, xanh lc

    B cu ni an ton

    Bc 2: B tr cc thit b theo th t nh hnh 4.2.1.

    Variac 3 pha

    0 400VMFM384C

    My bin th

    ba phaMFM384C

    Hnh 4.2.1. S khi btr cc thit b bi 4.2

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    6/17

    TRANG 58 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    Bc 3: S! dng cc dy ni v cu ni an ton lp rp bi thc hnh theo s"

    ni dy hnh 4.2.2.

    Bc 4: Vn hnh m hnh, tin hnh o cc thng s v ly kt qu

    Cc php o u tin c thc hin trn mt pha ca my bin th, sau nycc kho st s#c thc hin trn 3 pha.

    t ngun in p cho Variac 3 pha ti gi tr 220V v gi$ mc gi tr nykhng thay i trong sut thi gian th nghim.

    MFM384C

    MFM384C

    VARIAC3PHA

    04

    00V

    Hnh4.2.2:Mchkhostch

    khngticamybinth(u1pha)

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    7/17

    MODULE 4: M HNH MY BIN P TRANG 59

    TrngH SPhm KThut TP.HCM

    S! dng cu ni la chn in p cho nh$ng gi tr pha th cp ca mybin th: UN + 5%, UN, UN 5%, UN 10%, UN 15%

    Lu : Ngt ngun khi thao tc thay i cc nc la chn in p.

    o khng ti in p U2 trn cun th cp v xc nh t l bin i thch hp.UN + 5% UN UN 5% UN 10% UN 15%

    U1 (V)

    U2 (V)

    t = U1/U2

    Ghi ch: T l bin i in p ghi trn mt ca my bin th ch p dng cho ti vi

    dng in 1A pha th cp, v vy khng ph hp vi nh$ng gi tro khng ti.

    Tnh ton t s t phn nh gi tr xp x t l s vng dy W1/W2 ti v tr m bi nc

    ang s! dng.

    Khng thay i bt k mi quan h no trn cun s"cp, s! dng vn k cho cun dy

    pha th cp xc nh in p trn cun dy th ba ( ti nh$ng u ra 3U1 3U2).

    U3 = V

    Thc hin o dng in khng ti v cng sut tc dng tiu th bi my bin th.

    Loi b vn k trn cun th cp hn ch sai s ca kt quo.

    U1 = V I10 = A P10 = W

    V dng in thp trong my bin th chy ch khng ti, nn gn nh khng c

    tn tht ng no xut hin. Nh vy, cng sut thc tiu th gn nh ch bao gm tn

    tht st. Xc nh coso trn cun s"cp vi biu thc:

    xc nh:

    IFe = I10.cos0

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    8/17

    TRANG 60 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    Lu : c th s! dng cos0 b%ng ng ho (chp nhn sai s khi o). in trst

    t v in khng t ha c thc tnh ton b%ng cch s! dng ph"ng trnh sau:

    coso =

    IFe = A

    I = A

    RFe =

    Xh =

    Thc hin li th nghim khng ti trn nhng i v tr MBA (s"cp thnh th cp

    v ngc li nh hnh 4.2.3

    UN + 5% UN UN 5% UN 10% UN 15%

    U1 (V)

    U2 (V)

    t' = U1/U2

    1/t

    V

    V

    V

    ARIAC3PHA0-400V

    L1

    L2

    L3

    NPE

    Hnh 4.2.3:o tsbin thc thtrn cun thcp

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    9/17

    MODULE 4: M HNH MY BIN P TRANG 61

    TrngH SPhm KThut TP.HCM

    Kt lun iu g t cc t s my bin th t"ng ng ?

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    Phn th nghim tip theo dnh cho c 3 pha ca my bin th, c thc hin

    t"ng t cc bc nh th nghim 1 pha . &y ch c cun s"cp c s! dng

    cho vic cp in v thao tc ti gi tr UN trn cun th cp.

    Mrng mch nh hnh 4.2.4 v o hai in p U1 v U2, Dng in khng ti I10 (sau

    khi tch ri vn k trn cun th cp), mc tiu th cng sut tc dng P10.

    U1 = V

    U2 = V

    I10 = A

    P10 = W

    III. NI DUNG BO CO1. C kt lun g t nh$ng t l bin i t"ng ng ?

    ...........................................................................................................................................

    ...........................................................................................................................................

    VARIA

    C3PHA0-400V

    L1

    L2

    L3

    NPE

    Hnh 4.2.4: S th nghim cho php o in p, dng in v cng sutch

    khng ti ni sao trn cun scp

    V

    MFM384C

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    10/17

    TRANG 62 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    2. So snh nh$ng gi tro c trong mch 3 pha vi mch 1 pha ?

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    11/17

    MODULE 4: M HNH MY BIN P TRANG 63

    TrngH SPhm KThut TP.HCM

    BI 4.3: KHO ST MY BIN P CH NGN MCH

    I. MC TIUSau khi hc xong bi ny, sinh vin c kh nng:

    Trnh by c s" nguyn l v cch kho st m hnh my bin p chngn mch.

    Thc hnh lp rp m hnh, o ly thng s v nhn xt kt qu. Hnh thnh tc phong cng nghip, m bo v sinh v an ton lao ng.

    II. NI DUNG THC HINBc 1: Nhn bit cc thit b cn thit cho m hnh th nghim. Cc thit b cho trong

    bng sau:

    Thit b S lng

    Variac 3 pha in p 0 400V 1

    My bin th 3 pha 1

    ng ho dng in 1

    ng ha nng MFM384C 1B ni dy an ton cc mu xanh, , vng,

    en, xanh lc

    B cu ni an ton

    Bc 2: B tr cc thit b theo th t nh hnh 4.3.1

    Bc 3: S! dng cc dy ni v cu ni an ton lp rp bi thc hnh theo s"

    ni dy hnh 4.3.2.

    Bc 4: Vn hnh m hnh, tin hnh o cc thng s v ly kt qu.

    Variac 3 pha

    0 400VMFM384C

    My bin th

    ba pha

    Hnh 4.3.1. S btr cc thit b bi 4.3

    A

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    12/17

    TRANG 64 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    Lu : Vn nm xoay ca variac ba pha v gi tr zero trc khi tin hnh th nghim.

    S! dng cu ni chn nc iu p trn cun th nh ti in p danh nh v nin vi u ra.

    Tng gi trin p ca variac ba pha bt u ti zero cho n khi dng inmy bin th danh nh t n 1,2A trn cun s"cp. o in p U1kv cng

    sut P1ktiu th ca mch.

    U1k=V I1 = A P1k= W

    Xc nh h s cos, cc in p ngn mch t"ng i c'ng nh thnh phn doin trv do trkhng ngn mch sinh ra theo ph"ng trnh sau:

    ur = uk.cos

    ux = uk.sin

    VARIAC3PHA0

    -400V

    L1

    L2

    L3

    NPE

    Hnh 4.3.2: Ch vn hnh ca my bin thtrng thi ngn mch (kt ni 1 pha)

    A

    MFM384C

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    13/17

    MODULE 4: M HNH MY BIN P TRANG 65

    TrngH SPhm KThut TP.HCM

    cosk=

    uk= %

    ur = %

    ux = %

    R1k=

    X1k=

    (Trong cc php o ngn mch nh$ng hiu ng ca in cm t ha Xh v in trtn

    tht st l khng ng k)

    Khng thay i bt k mi quan h no trn cun s" cp, o dng in ngnmch trong cun dy pha th cp (ti v triu p UN) v s! dng thng s

    ny hnh thnh t l bin i dng in.

    I1 = A

    I2 = A

    I1/I2 =

    So snh iu ny vi t s bin i in p t"ng ng t php o khng ti

    Tr li: ..............................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    M rng mch nh hnh 4.3.3 v tng in p bt u t zero n khi dng in

    danh nh l 1,2A

    o in p U1kv mc tiu th cng sut thc P1k

    U1k= V

    I1 = A

    P1k= W

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    14/17

    TRANG 66 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    III. NI DUNG BO CO1. So snh nh$ng gi tro c vi cc gi trmch 1 pha ?

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................

    2. V# mt s" mch (pha "n) t"ng "ng y ca my bin th v ghi y

    tt c cc i lng o c hoc tnh ton ?

    I1 =. R1 =. X1 =.

    I =.

    X =.

    X2' =. R2 =. I2 =.

    IFE =.

    RFE =.

    U1 =. U2 =.U1N =.

    Hnh 4.3.4: S mch mt pha ca my bin thtng ng sdng trong th

    nghim (my bin thni sao)

    VARIAC3PHA0

    -400V

    L1

    L2

    L3

    NPE

    Hnh 4.3.3: Php o U,I,P v ni Y trn cun scp v ngn mch cun thcp

    MFM384C

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    15/17

    MODULE 4: M HNH MY BIN P TRANG 67

    TrngH SPhm KThut TP.HCM

    BI 4.4: KHO ST MY BIN P CH MANG TI

    I. MC TIUSau khi hc xong bi ny, sinh vin c kh nng:

    Trnh by c s" nguyn l v cch vn hnh m hnh my bin p ch mang ti.

    Thc hnh lp rp m hnh, o ly thng s v nhn xt k qu. Hnh thnh tc phong cng nghip, m bo v sinh v an ton lao ng.

    II. NI DUNG THC HINBc 1: Nhn bit cc thit b cn thit cho m hnh th nghim. Cc thit b cho trong

    bng sau:

    Thit b S lng

    Variac 3 pha in p 0 400V 1

    My bin th 3 pha 1

    ng ho dng in 1

    Ti tr 1Ti cm 1

    Ti dung 1

    ng ha nng MFM384C 1

    B ni dy an ton cc mu xanh, , vng,

    en, xanh lc

    B cu ni an ton

    Bc 2: B tr cc thit b theo t t nh hnh 4.4.1

    Bc 3: S! dng dy ni v cu ni an ton lp rp bi thc hnh theo s" ni

    dy hnh 4.4.2.

    Bc 4: Vn hnh m hnh, tin hnh o cc thng s v ly kt qu.

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    16/17

    TRANG 68 MODULE 4: M HNH MY BIN P

    TrngH SPhm KThut TP.HCM

    Tt c cc php o c thc hin vi my bin th ni sao sao. Trc ht chng ta

    s# kho st trng hp ti thun tr.

    VARIAC

    3PHA0-400V

    L1

    L2

    L3

    NPE

    MFM384C

    MFM384CPE

    Hnh 4.4.2. S kt ni mch kho st ch my bin p c ti thay i.

    Variac 3 pha

    0 400V MFM384C

    My bin th

    ba pha MFM384C

    Hnh 4.4.1. S btr cc thit b bi 4.4

    Ti tr Ti dung Ti cm

  • 7/29/2019 Module 4_Mo Hinh May Bien AP

    17/17

    MODULE 4: M HNH MY BIN P TRANG 69

    TrngH SPhm KThut TP.HCM

    III. NI DUNG BO CO1. in kt quo c bc 4 vo bng sau:R U20(V) U2(V) U (V) I2(A) P1(W) P2(W) P(W) (%)

    1

    2

    3

    4

    5

    6

    72. Lp mch t"ng t th nghim trn nhng thay ti tr b%ng ti cm. o ly

    thng s v in vo bng sau:

    L (H) U20(V) U2 (V) U (V) I2(A)

    6.0

    4.8

    2.4

    1.2

    1.0

    3. Lp mch t"ng t th nghim trn nhng thay ti tr b%ng ti dung. o lythng s v in vo bng sau:

    C () U20(V) U2 (V) U (V) I2(A)

    2.0

    4.0

    8.0

    16.0

    4. Nhn xt kt qu vi ti thun tr, ti cm v ti dung ?...........................................................................................................................................

    ...........................................................................................................................................

    ...........................................................................................................................................