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Function Operations

Module 2 topic 2 notes

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Page 1: Module 2 topic 2 notes

Function Operations

Page 2: Module 2 topic 2 notes

We all know that the faster you drive the farther you will travel while reacting to an obstacle and while braking to complete that stop. The reaction distance and braking distance depend on the speed of the vehicle at the moment the obstacle is observed.

The functions below represent speed, x, in miles per hour to the reaction distance, R(x), and the braking distance B(x), both in feet.

2

191

)(

1011

)(

xxB

xxR

Page 3: Module 2 topic 2 notes

You can relate speed, x, to the total stopping distance s, as a sum of R and B.

2

191

)(

1011

)(

xxB

xxR

2

191

1011

)(

)()()(

xxxS

xBxRxS

Functions can also be represented by subtraction, multiplication and division.

Page 4: Module 2 topic 2 notes

Operations with Functions

0)()()(

))((

)()())((

)()())((

)()())((

xgxgxf

xgf

xgxfxgf

xgxfxgf

xgxfxgf

Page 5: Module 2 topic 2 notes

.5)(4)( 2 xxgandxxfLet

Let’s try some examples:

Write an expression for each function. State any restrictions.

))((.

))((.

))((.

))((.

xgfD

xfg

C

xfgB

xgfA

Page 6: Module 2 topic 2 notes

2054

)(

)5)(4(

))((.

!

!445

)4()5(

))((.

1

,

)4()5(

))((.

9

)5()4(

))((.

23

2

2

2

2

2

2

2

xxx

FOILDistribute

xx

xgfD

furtheranySimplifiedbeCannot

zerobydivideCannotxxx

xx

xfg

C

xx

TermsLikeAddthenSignNegativetheDistribute

xx

xfgB

TermsLikeAdd

xx

xx

xgfA

Solutions:

Page 7: Module 2 topic 2 notes

More examples:

A craftsmen makes and sells antique chests.

The function represents his cost in dollars to produce x chest.

The function represents the income in dollars form selling x chest.

Write and simplify a function P(x) that represents the profit from selling x chest.Find P(50), the profit earned when he makes and sells 50 chest.(Remember: Profit = Income – Cost)

xxC 550)(

xxI 250)(

Solutions:P(x) = I(x) – C(x) = (250x) – (50 + 5x) = 255x – 50; P(50) = 255(50) – 50 = 12,700

Page 8: Module 2 topic 2 notes

Domain and Range

The domain of the sum, difference, product and quotient functions consist of the x-values such that are in the domains of BOTH f and g.

However, the domain of a quotient function does not contain any x-value for which g(x) = 0.Follow this link to review Domain and Range:http://www.algebasics.com/3way12.htmlClick on “Domain and Range” at the upper left for a tutorial.

Page 9: Module 2 topic 2 notes

The domain for f(x) is all real numbers because there are no values of x such that the function will not be defined.

The domain for g(x) is all real numbers.

Therefore, the domain for (f + g)(x) is all real numbers.

Examples:

F(x) = x + 4 and G(x) = 2x

(f + g)(x) = (x + 4) + (2x) = 3x + 4

Page 10: Module 2 topic 2 notes

The domain for f(x) is all real numbers because there are no values of x such that the function will not be defined.

The domain for g(x) is all real numbers.

Therefore, the domain for (f - g)(x) is all real numbers.

Examples:

f(x) = x + 4 and g(x) = 2x

(f - g)(x) = (x + 4) - (2x) = -x + 4

Page 11: Module 2 topic 2 notes

The domain for f(x) is all real numbers because there are no values of x such that the function will not be defined.

The domain for g(x) is all real numbers.

Therefore, the domain for (f • g)(x) is all real numbers.

Examples:

f(x) = x + 4 and g(x) = 2x

(f • g)(x) = (x + 4)(2x) = 2x2 + 8x

Remember to Distribute!

Page 12: Module 2 topic 2 notes

The domain for f(x) is all real numbers because there are no values of x such that the function will not be defined.

The domain for g(x) is all real numbers.

However, the domain of a quotient function does not contain any x-value for which g(x) = 0.

If the value for x in 2x cannot produce 0, then x cannot equal zero.

Therefore, the domain for (f ÷ g)(x)is all real numbers except 0.

Examples:

f(x) = x + 4 and g(x) = 2x

(f ÷ g)(x) = (x + 4)÷(2x) = x

x2

4

Page 13: Module 2 topic 2 notes

Another example:

An airplane travels at a constant speed of 265 miles per hour in still air. During a particular portion of the flight, the wind speed is 35 miles per hour in the same direction the plane is flying.

a. Write a function f(x) for the distance traveled by the airplane in still air for x hours.

Solution: f(x) = 265x

b. Write a function g(x) for the effect of the wind on the airplane for x hours.

Solution: g(x) = 35x

c. Write an expression for the total speed of the airplane flying with the wind.

Solution: f(x) + g(x) = 265x + 35x = 300x

Page 14: Module 2 topic 2 notes

Helpful Links:

http://www.purplemath.com/modules/fcnops.htm

http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut30b_operations.htm