Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

Sep 22­9:04 AM

Review for Module 1 Lesson 1-11 Test

HWStudy for Module 1 Lesson 1-11

Test Tomorrow

Do Now:Write the converse of the conditional statement:

If parallel lines are cut by a transversal then alternate interior angles are equal

Sep 24­2:48 PM

Do Now:Write the converse of the conditional statement:

Conditional: If parallel lines are cut by a transversal then alternate interior angles are equal

Converse: If alternate interior angles are equal then there are parallel lines cut by a transversal

Module 1 Lesson 1­11 Review.notebook

2

September 26, 2016

Sep 22­9:04 AM

1. Construct circle A, center A radius AB

2. Construct circle B, center B, radius AB

3. Label one point of intersection as C

4. Draw segments AC and BC

Sep 22­9:04 AM

1. Create a circle with the center at the stake, and the radius of Bailey's leash

2. Create a circle with the center at the stake, and the radius of Daisy's leash

3. Put X's at point of intersection

0°

122

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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Tina is correct because the cirlces at centers D

and G with radius DG do not intersect at point O.

Sep 22­9:04 AM

1. Create circle B, any radius

2. Label points of intersection as E and D

3. Create circles with center E and center D, radius DE

4. Label the point of intersection as F

5. Draw ray BF

1. Create circle A, any radius

2. Label points of intersection as C and B

3. Draw ray FE

4. Draw circle F radius BC

5. Label points of intersection as H and G

6. Draw circle G radius BC

Module 1 Lesson 1­11 Review.notebook

4

September 26, 2016

Sep 22­9:05 AM

1. Construct circle A, center A radius AB

2. Construct circle B, center B, radius AB

3. Label one point of intersection as C and D

4. Draw segment CD

Sep 22­9:05 AM

1. Construct circle P any radius such that it intersects line ST twice.2. Construct circle A, center A radius AB

3. Construct circle B, center B, radius AB

4. Label one point of intersection as C and D

5. Draw segment CD that passes through point P

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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Altitudes

Angle Bisectors

Medians

Perpendicular Bisectors

False (only 1 right angle created, perpendicular lines have 4True ( C is the midpoint)True ( C is the midpoint)True (Both are right angles)

Sep 22­9:05 AM

x and y are supplementary anglesy + x = 180y + 103 = 180 -103 -103

y = 77

x = 103 because Vertical angles are

equal to one another

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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3,4 4,5 5,6 3,6 1,2

3,4 4,5 5,6 3,6 1,2

6,4 3,5

Sep 22­9:06 AM

x and <ABC are supplementary anglesx + 110 = 180 -110 -110

x = 70

<ABD = 70 because <ABD and <x equal one another <ABD + x + <DBC = 180

70 + 70 + <DBC = 180 140 + <DBC = 180 -140 -140 <DBC = 40

y and 115 are supplementary anglesy + 115 = 180 -115 -115

y = 65

65 + 2x + 65 - 10 = 180 120 + 2x =180 -120 -120 2x = 60 2 2 x = 30

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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<1 and <2 are Same side interior supplementary angles <1 + <2 =180 7x - 36 + 5x + 12 = 180 12x - 24 = 180 + 24 +24 12x = 204 12 12

x = 17

Sep 22­9:06 AM

y = 30 because of alternate interior angles

z = 80 because of vertical angles

x + y + z = 180

x + 30 + 80 = 180

x + 110 = 180

-110 -110

x = 70

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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<RTQ = 63 because of alternate interior angles

<2 + 90 + 63 = 180

<2 + 153 = 180

-153 -153

<2 = 27

Sep 22­9:06 AM

opposite interior angle + opposite interior angle = exterior angle

x + 40 + 4x - 5 = 6x + 20 5x + 35 = 6x + 20 -5x -5x 35 = x + 20 -20 - 20

15 = x

<QPT = 6x + 20 <QPT= 6(15) + 20<QPT = 90 + 20

<QPT = 110

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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Consecutive Angles on a straight line sum to 180 x + 40 + 90 = 180 x + 130 = 180 - 130 -130 x = 50

Supplementary angles sum to 180 y + 40 = 180 -40 -40 y = 140

Sep 22­9:07 AM

<a = 48 because of alternate interior angles

Supplementary angles sum to 180180 - 118 = 62

<b = 62 because of alternate interior angles

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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<1 = 70, corresponding angles<2 = 55, alternate interior angles

<x = <1 + <2 = 70 + 55 = 125

<x = 125 degrees

Sep 22­9:07 AM

43Alternate interior angles are equal

94 + 43 + e =180 137 + e = 180 -137 -137 e = 43

43Angles in a triangle sum to 180

43 + 43 + k =180 86 + k = 180 -86 -86 k = 94

94Consecutive Angles on a straight line sum to 180

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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<1 + 98 = 180 same side supplementary

- 98 -98

<1 = 82 <2 = 46, alternate interior angles

<x = <1 + <2 vertical angles<x = 82 + 46<x = 128

128

Vertical angles are equal to one another

Sep 22­9:08 AM

a

a + 110 = 180 -110 -110 a = 70

70

Linear Pairs form supplementary angles

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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70b + 70 + 90 = 180

b + 160 = 180

-160 -160

b = 20

20

Angles in a triangle sum to 180 degrees

Sep 22­9:08 AM

Linear pairs form supplementary angles

Linear pairs form supplementary angles

Angles in a triangle sum to 180 degrees

Substitution Property of Equality

Module 1 Lesson 1­11 Review.notebook

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September 26, 2016

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1. Given1. AB ll CD

2. AB ll L, L ll CD 2. Auxillary line L drawn in through G

3. <x = <13. If parallel lines are cut by a transversal then corresponding angles are equal

4. <w = <24. If parallel lines are cut by a transversal then corresponding angles are equal

6. <x + <w = <15. <1 + <2 = <y

6. Substitution Property of Equality

5. Angle Addition Postulate

Sep 22­9:09 AM

1. <a = <1 1. Vertical Angles are equal to one another

2. <1 + <b + <c = 180

3. <a + <b + <c = 180

2. Consecutive angles on a straight line sum to 180 degrees

3. Substitution Property of Equality