----

Pl=O.7 bar, Bend

7Scm

.~ ---rr ' SG;O.8 ~

- h=?Water r10cm,

I=-,

D=15cm iu d=15cm, -~

60c

flgure(Z)Figure(l}

Question (2) IruA steady frictionless water flow occurs in the.pipe shown ill figure 1.Calculate thepressure in the 10 em diameter pipe if the given value bf Hmllx is O.3m. Determine: I-the rate ofdischarge Q, 2-thc Pitot tube reading, h, and 3- Sketch "theT.B.L. and H.G.L. .!tlWater flows through a horizontal bend to discharge into atmosphere as shown in figure 2.when the gauge reads 0.7 bar, the resultant y-direction anchoring force, required to hold thebend in place Fy=2.98 kN. Determine the flow rate Q through the bend and the x-directionanchoring force Fx to hold the bend.Question (3) .!!.)Assume the power to drive a fan P=feD. p, N ,Q} where D is fan diameter, p is density ofair, N is rotational speed and Q is the flow rate. Use 15, D,N as repeating variables todetermine a suitable set of pi- terms. What is the ratioP pIPmifthe model, fan runs at Nn/Np=2:1and Dn! D, = 1:3 in two similar operating conditions. (m denotes model, p denotes prototype)

hlGalcuJate the power required for the pump to operate a horizontal pipe line connecting tworesrvoirs of the same level. The pipe line is cast iron {s=O.25 mm)of diameter =100 rom and alength equals 200 m and delivers 50 litis (0.05 ml/s) of water. (~1000kg/m3, jl=O.OOl Pa.s).Neglect secondary losses. ,.,

..

Answer the following questionsQuestion (1)!lDefine both the laminar and the turbulent flows. Ifthe head loss for laminar flow is givenby the relation: hL=32~ Lv/(pgd2), prove that the Darcy friction F=641R:where R, isReynolds number.g) Glycerin (p=1260kglin3, J.l=1.49Pa.s) flows in 150mm diameter pipewith average velocity of 1.5mls. Calculate the head loss if pipe length is 50 m and calculatethe flow velocities at r = 0, 25 mm . Also detemine the shear stress at the pipe walls.

AIN SHAMS UNIVERSITYASU-CHEP( NEW PROGRAMS)MANUFACTURING ENGINEERING

------------~~--!. ...-.~--___;___~--____;

, ...

"""t ,.... ..~'.~.. /" -.

-,~ .~ ...~ .. ;. ---- .._,- .. - ~" ..' ..

: "

*I-'.

. - ': .", - '.,:..

. .'_'~""'_ ,.10 __ ._ __ _ _._ • ~ .

. (i) Mq(k

. :

. ~.,;,'

• it,

. ',''.~.'.Jl ::.,',~"6. 51:r I.;' . .'(f ' .

, ': I 1'3 == 6'3. Cf Lf' t~ ~.

Guesb'oY1 {2J.a' ifl Ha'fk sGfv-e.YJ: S~

f"(I~+\~Y1Il!'s~flowH .,..",A¥. -:::a>·3 m

.: it. V,,':- h _ ,/" '2 '~r+- ~ = - -c-.» 'rj.

t-------.;.._-

." ' ~,

ew!T- E.,.L. C/y, 'cI.'."".,1P.55 F/60 ,f\'Oi/ ' :0}' '/~ ~ r ..(Il}1t',(k.'_/s

tCD 11

c.,.., Vlf n::? V~2=i5 zj - i Vi!. .

7:j ,_123

Wt\1<{.;; T"':: ,

-L-s 7" , ~. I 1 (.3) I I-~ •~ .1'- D= IS c- 0::.5~ d-:::: to~WI c......

: H,..,~~ "

::: .IfJ~L·< ~(._, -- ,_

Da.h.Ln1 H-GLI

-Iff! ~s. CU 1'1~"k. (jJ_ M~r i«.

'fa) ~(J ,0.163 :d of.s.f/61-

2.)

. , '

. . .....

• .,. e;,.1. " .. ::,'

: •• : t,' '" '. '., . .

. ~.

A'feo. ==0.0093(2) t?')"'t.

"" ... ,., .... "' ~.-

, " . ~...- . ~...--~--. ~ .. ";'"....... ,.

• - t 'I!U"i·'• -I

. ,."

. , :

.. -. . ','

. : ...... .

.. .~...

... ~.. . . "

"

.r~o.tJ25

-

I