Upload
vuongxuyen
View
243
Download
1
Embed Size (px)
Citation preview
9/12/2013
1
Neamen Microelectronics, 4e Chapter 2-1McGraw-Hill
Microelectronics Circuit Analysis and Design
Donald A. Neamen
Chapter 2
Diode Circuits
Neamen Microelectronics, 4e Chapter 2-2McGraw-Hill
In this chapter, we will:
Determine the operation and characteristics of diode rectifier circuits, which is the first stage of the process of converting an ac signal into a dc signal in the electronic power supply.
Apply the characteristics of the Zener diode to a Zener diode voltage regulator circuit.
Apply the nonlinear characteristics of diodes to create waveshaping circuits known as clippers and clampers.
Examine the techniques used to analyze circuits that contain more than one diode.
Neamen Microelectronics, 4e Chapter 2-3McGraw-Hill
Block Diagramfor ac to dc Converter
The diode rectifier, filter, and voltage regulator are diode circuits.
Neamen Microelectronics, 4e Chapter 2-4McGraw-Hill
Problem-Solving Technique: Diode Circuits
1. Determine the input voltage condition such that the diode is conducting (on).
a. Find the output signal for this condition.
2. Determine the input voltage such that the diode is not conducting (off).
a. Find the output signal for this condition.
9/12/2013
2
Neamen Microelectronics, 4e Chapter 2-5McGraw-Hill
Half-Wave Rectifier
Voltage Transfer Characteristics
Neamen Microelectronics, 4e Chapter 2-6McGraw-Hill
Signals of Half Wave Rectifier
Input voltage Output voltage
Diode voltage
Neamen Microelectronics, 4e Chapter 2-7McGraw-Hill
Half-Wave Rectifier as Battery Charger
Diode conducts for
− > = (
) & = 180° − ! = −
360°Neamen Microelectronics, 4e Chapter 2-8
McGraw-Hill
Half-Wave Rectifier with Filter
$%& = ($%&) − $'( = $%&)*/,-
9/12/2013
3
Neamen Microelectronics, 4e Chapter 2-9McGraw-Hill
Half-Wave Rectifier with Filter
ForRC>>T’andif:;≅ : = =>Then$'( = $%&)*/,- ≅ $%& 1 − 1
ABCD = $%& − $'( = $%&
=,-
%B FFG = $%& − $'($%&
H100%
%B FFG = 1ABC H100%
Neamen Microelectronics, 4e Chapter 2-10McGraw-Hill
Full-Wave Rectifier
Voltage transfer characteristics
Input and output waveforms
Neamen Microelectronics, 4e Chapter 2-11McGraw-Hill
Full-Wave Bridge Rectifier
When vS is positive, D1 and D2 are turned on (a). When vS is negative, D3 and
D4 are turned on (b).
In either case, current flows through R in the same direction, resulting in an
output voltage, vO, shown in (c).
Neamen Microelectronics, 4e Chapter 2-12McGraw-Hill
Output Voltage of Full-Wave Rectifier with RC Filter
9/12/2013
4
Neamen Microelectronics, 4e Chapter 2-13McGraw-Hill
Output Voltage of Full-Wave Rectifier with RC Filter
The ripple on the ‘dc’ output isP
Mr
Tf
fRC
VV
2
1 where
2==
%IJ = 1:′/2M N OP
);/
Q≅ 2
R NThe average ‘dc’ output is
Neamen Microelectronics, 4e Chapter 2-14McGraw-Hill
Output Voltage of Full-Wave Rectifier with RC Filter
Diode conducts current for only a small portion of the period.
Neamen Microelectronics, 4e Chapter 2-15McGraw-Hill
Demodulation of AMSignal
Modulated input signal
Detector circuit
Demodulated output
signal
Neamen Microelectronics, 4e Chapter 2-16McGraw-Hill
Voltage Regulator
The characteristics of the Zener diode determines VL.
LIZ
i
ZPSI
L
ZL
III
R
VVI
R
VI
−=
−=
=
9/12/2013
5
Neamen Microelectronics, 4e Chapter 2-17McGraw-Hill
Design DC Power Supply Circuit
Neamen Microelectronics, 4e Chapter 2-18McGraw-Hill
Example
Zener diode voltages range from 2.0 to 25 volts, at
power rating from 0.3 to 5 watts.
0 < TU < 0.1W
Select a diode and resistor to supply a steady 9 V to a radio
which draws 0 to 0.1 A. The source is an unsteady 12V supply.
Neamen Microelectronics, 4e Chapter 2-19McGraw-Hill
Example
1. Choose a zener diode voltage:
Select 9V zener for this example.
2. Determine max. circuit current:
The load requires 100mA, plus we need at least 10 mA
for the zener diode. Since the supply is unstable, we
can add 20-50% margin to obtain a safe value. Let’s
choose Imax = 200mA.
3. Select zener diode power rating:
Pz = Vz*Imax = 9*0.2 = 1.8W
=> select 1.8W or higher rated zener
Neamen Microelectronics, 4e Chapter 2-20McGraw-Hill
Example
4. Select the resistor:
XY = Z[\]^_Z`a]^_ = bc.de
f.g = gcΩ
5. Select the resistor power rating:
Pr = Vr * Imax = 3.6 * 0.2 = 0.72W
=> select 0.72W or higher rated resistor.
-------------------------------------------------------------
Would the circuit be adequate if the source voltage varied up to
15.5V?
9/12/2013
6
Neamen Microelectronics, 4e Chapter 2-21McGraw-Hill
The Zener diode begins to conduct when VPS = VZ.
When VPS ≥ VZ: VL = VZ
IL = VZ/RL,, but VZ ≠ constant
I1 = (VPS – VZ)/Ri
IZ = I1 - IL
Voltage Rectifier with nonzero Zener resistance
Neamen Microelectronics, 4e Chapter 2-22McGraw-Hill
Single Diode Clipper
ijk < + the diode is open and Q = kijk ≥ + the diode conducts and Q = +
Neamen Microelectronics, 4e Chapter 2-23McGraw-Hill
Additional Diode Clipper Circuits
Neamen Microelectronics, 4e Chapter 2-24McGraw-Hill
Parallel-Based Diode Clipper Circuit
9/12/2013
7
Neamen Microelectronics, 4e Chapter 2-25McGraw-Hill
Series-Based Diode Clipper
Circuits
Neamen Microelectronics, 4e Chapter 2-26McGraw-Hill
Diode Clamper Circuit
The clamper circuit shifts the entire signal voltage by a DC level.
nis clamped to . The output is a shifted replica of input.
n = k − o = N( O − 1)assume
ideal diode
n clamped to 0V.
Neamen Microelectronics, 4e Chapter 2-27McGraw-Hill
Diode Clamper Circuit with Voltage Source
The clamper circuit shifts the entire signal voltage by a DC level.
nis clamped to + ( = 0pjO).
o pqrjN − . ⇒ n= − o
Neamen Microelectronics, 4e Chapter 2-28McGraw-Hill
2 Diode Circuit
Voltage transfer characteristics
1. tjAA&tj ⇒ n = − TB2. tj&tj ⇒ n =k3. tj&tjAA ⇒ n =
9/12/2013
8
Neamen Microelectronics, 4e Chapter 2-29McGraw-Hill
Problem-Solving Technique: Multiple Diode Circuits
1. Assume the state of the diode. a. If assumed on, VD = Vγ
b. If assumed off, ID = 0.
2. Analyze the ‘linear’ circuit with assumed diode states.
3. Evaluate the resulting state of each diode.
4. If any initial assumptions are proven incorrect, make new assumption and return to Step 2.
Neamen Microelectronics, 4e Chapter 2-30McGraw-Hill
Exercise problem
D1 is not on.
D2 is on.
This pins VO to -0.6V
Neamen Microelectronics, 4e Chapter 2-31McGraw-Hill
Diode Logic Circuits:2-Input OR Gate
V1 (V) V2 (V) VO (V)
0 0 0
5 0 4.3
0 5 4.3
5 5 4.3
Vγ = 0.7V
Neamen Microelectronics, 4e Chapter 2-32McGraw-Hill
Diode Logic Circuits:2-Input AND Gate
V 1
( V )V 2
( V )V O
( V )
0 0 0.7
5 0 0.7
0 5 0.7
5 5 5.0
Vγ = 0.7V