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Variables Separated Equations and Finite Simple Groups Mike Fried, UC Irvine, Talk at Idaho S. U. 10/02/08 [UMSt] www.math.uci.edu/˜mfried/paplist-cov/UMStory.html. Algebraic equations in separated variables: (*) f (x) g (y )=0. Defines a projective nonsingular algebraic curve X f,g with two projections to the (Riemann sphere) z -line P 1 z = C ∪ {∞}: f : P 1 x P 1 z and g : P 1 y P 1 z . Two problems from the 60s (Davenport’s and Shinzel’s) solved by the monodromy method . I explain that and the associated Genus 0 Problem. Another genus 0 problem, related to John Thompson, connects the Monster simple group to genus 0 modular curves. Both influenced by the same conference – Santa Cruz (proceedings in 1980). – Typeset by Foil T E X 1

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Page 1: mich03-26-07 rootmfried/talklist-cov/ISU-Dav-Thomp10-02-08.pdfVariables Separated Equations and Finite Simple Groups Mike Fried, UC Irvine, Talk at Idaho S. U. 10/02/08 ... conference

Variables Separated Equations and Finite Simple Groups

Mike Fried, UC Irvine, Talk at Idaho S. U. 10/02/08

[UMSt] www.math.uci.edu/˜mfried/paplist-cov/UMStory.html.

Algebraic equations in separated variables: (*) f(x)−g(y) = 0.

Defines a projective nonsingular algebraic curve Xf,g with two

projections to the (Riemann sphere)

z-line P1z = C ∪ {∞}: f : P1

x → P1z and g : P1

y → P1z.

Two problems from the 60s (Davenport’s and Shinzel’s)

solved by the monodromy method . I explain that and the

associated Genus 0 Problem. Another genus 0 problem,

related to John Thompson, connects the Monster simple group

to genus 0 modular curves. Both influenced by the same

conference – Santa Cruz (proceedings in 1980).

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§I. Abel and Dihedral functions

To integrate cos(θ)n, 1st year calc. uses the nth

Chebychev polynomial (with Tn(cos(θ)) = cos(nθ)):Tn : P1

w = Cw ∪ {∞} → P1z = Cz ∪ {∞}.

It is branched over {z1, z2, z3} = {−1,+1,∞}.The trick : Find T ∗

n(w) = 2Tn(w/2) so

T ∗n(x+1/x) = xn+1/xn inductively, using degrees.

Then substitute x �→ e2πiθ.

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§I.A. The dihedral group with observationsTn (n odd) is a dihedral function:

with a b(ranch)c(ycle)d(escription):σ1 = (2n)(3 n−1) · · · (n+1

2n+3

2 )σ2 = (1n)(2 n−1) · · · (n−1

2n+3

2 )σ∞ = (n n−1 · · · 1)

• (generation) 〈σ1, σ2〉=Dn = {( ±1 b

0 1

)}b∈Z/n, order

2n dihedral group; C2, involution conj. class

⇔ −1 in (1,1) position).• (conjugacy classes) σi, i = 1, 2, are in C2, σ∞ is

an n-cycle (n−12 conjugacy classes of these).

• (product-one) σ1σ2σ∞ = 1.

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Two dihedral function questions

• Q1: From whence the (σ1, σ2, σ∞)?Answer: Use App. A: With r = 3. Always get an

n-cycle at ∞ for polynomial f with deg(f) = n.

• Q2: If another function f : P1w → P1

z with similar

bcd, how related to Tn?

Answer: ∃ Mobius transforms. α1, α2 ∈ PGL2(C)with f = α2 ◦ Tn ◦ α−1

1 (w): f ∼Mobius Tn.

Historical generalization: Abel used more general

dihedral Mobius classes.

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§I.B. r = 4 (not 3) branch dihedral functions

Denote distinct elements of (P1z)

4 by U 4. S4 (sym-

metries on {1, 2, 3, 4}) permutes coordinates of U 4.

Instead of (σ1, σ2, σ∞) take ∼Mobius classes of

functions with bcds among 4-tuples, Ni(Dn,C24)(Nielsen classes), in C24 with generation and product-

one — branched over any

zzz = {z1, . . . , z4} ∈ U 4/S4def= U4

def= U4,z.

One element of Ni(Dn,C24): (σ1, σ−11 , σ2, σ

−12 ).

Here’s another: (σ1, σ−11 σ2σ1, σ

−11 , σ−1

2 ).

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Why such f : P1w → P1

z exists

• App. A gives compact surface cover f : X → P1z.

• R(iemann)-H(urwitz) (App. B) =⇒ X hasgenus0.

• R(iemann)-R(och) =⇒ X analytically P1w.

• Each zi has a unique unramified wi �→ zi

(wi corresponds to length 1 disjoint cycle in σi):f ↔ (www,zzz) ∈ U4,w × U4,z �→ [∼Mobius]

PGL2(C)\U4,w × U4,z/PGL2(C) = (P1jw

\∞) × (P1jz\∞).

Image is the modular curve called X0(n).

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§II. Davenport and Schinzel Problems

Separated Variables Equations

Consider polynomial pairs (f, g): degrees m and

n (> 0). Unless said, exclude g(x) = f(ax + b).Separated Variables Equation: (*) f(x) − g(y) = 0.

Davenport’s Problem: For what (f, g) over Q are

ranges on Z/p (p a prime) equal for almost all p.

For K a number field, there is an the analog.

Schinzel’s Problem: When is (*) reducible?

Indecomposability condition: We will assume f is

not a composition of lower degree polynomials.

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§II.A. Splitting variables

Initial step: Separated variables ⇒ introduce z:

f(x) − z = 0 and g(y) − z = 0. Express by covers:

(*2) f : P1x → P1

z and g : P1y → P1

z (we added ∞).

Note: Problem not changed by replacing (f, g) by

(α◦f ◦β, α◦g◦γ) with α, β, γ affine transformations.

The fiber product P1x ×P1

zP1

y consists of the

{(x′, y′) | f(x′) = g(y′)}, but we want the non-

singular model (normalization) of this.

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§II.B. Introducing Galois groups

f has a Galois closure cover f : Xf → P1z (resp. g :

Xg→ P1z): connected component of m-fold (resp. n-

fold) fiber product of f (resp. g), minus fat diagonal.

Symmetric group Sm permutes the coordinates:

Galois group Gf , subgroup of Sm fixing Xf ;

Denote the permutation representation by Tf .

Combine Galois closures: Fiber product of f and

g over the maximal cover Z → P1z through which

they both factor. Gives

Gf,g = Gf ×G(Z/P1z) Gg

projecting to Gf and Gg, inducing reps. Tf and Tg.

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§II.C. Translating Davenport to Group Theory

This starts the monodromy method . As expected,

particular problems require an expert to translate:

Use Chebotarev Density Theorem.

Equivalent to (f, g) a Davenport pair: ∀ σ ∈ Gf,g,

(*3) Tf(σ) fixes an integer ⇔ Tg(σ) fixes an integer.

Two serious general problems:

Group Problem P1: What groups, and permutation

pairs, give such a Gf,g; what has this to do with the

classification of simple groups?

Converse Problem P2: Even answering P1, from

whence polynomials (f, g) satisfying Davenport?

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§III. Primitivity, cycles and the Classification

• Primitive ⇔ no group properly between Gf and

Gf(1) = {g ∈ Gf | Tf(g)(1) = 1}.• DoublyTransitive⇔Gf(1)transitive on {2, . . . , m}.

[A-O-S85]: Primitive group template of 5 patterns: 4

from (almost) simple groups; rest from affine groups.

Classifying Doubly transitive groups is easier. Also,

if you can’t assume a group is primitive, even the

classification has yet to be helpful.

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III.A. Translating Primitivity for f : X → P1z

• Gf primitive ⇔ f factors through no proper cover.

• Gf doubly transitive ⇔ X ×P1zX has exactly two

irreducible components (one the diagonal).

For f a rational function:

• Primitive ⇔ can’t decompose f as f1 ◦ f2 with

both deg(fi)s exceeding 1.

• DoublyTransitive ⇔(f(x)−f(y)/(x−y)irreducible.

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III.B. Further Group translation of DavenportKey Observations:

1. Polynomial (of degree m) branch cycles (p. 4) include an

n-cycle σ∞ at ∞.

2. If Tf primitive, then Tf doubly transitive unless f is (Mobius

equivalent to) Chebychev (p. 2) or cyclic (x �→ xn) [Fr70].

Representation Thm: For (f, g) a Davenport pair:1. deg(f) = deg(g), Xf = Xg, so Gf = Gg; and

2. Tf = Tg as group representations, but not as

permutation representations.

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Equal degree argument

Get branch cycle σ∞ in Gf,g (p. 4) with Tf(σ∞)(resp. Tg(σ∞)) an m-cycle (resp. n-cycle). Suppose

(m, n) = d < m. Consider σ′ = σm∞.

Then Tf(σ′) fixes all integers, while Tg(σ′) moves

each integer. This contradicts (*3) on p. 10. A

fancier version of this gives Xf = Xg and Gf = Gg.

(*4) Another Version: Zeros {xi}ni=1 of f(x) − z are

functions of zeros {yi}ni=1 of g(y)−z (and vice-versa).

Normalize numbering: σ∞ cycles xis and yis.

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III.C. Double Transitivity and Difference sets

Since Tf is doubly transitive, representation theory

gives this much stronger conclusion:

(*5) x1 = y1 + yα2 + · · · + yαk, 2 ≤ k ≤ (n − 1)/2:

The representation space is the same for xs and ys.

Multiplier Thm: Write R1 = {1, α2, . . . , αk} mod n

1. Among nonzero differences from R1, each integer

{1, . . . , n− 1} occurs u = k(k− 1)/(n− 1) times.2. The expression for yis in xjs gives the different set

(up to translation) −R1.

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Argument for # 1

Acting by σ∞ – translating subscripts – gives

collections Ri, i = 1, . . . , n. The # times u mod n

appears as a (nonzero) difference from R1 equals

# times {1, u + 1} appears in the union of the Ris.

That is, normalize its appearance as a difference with

1st integer is a ”1.”

Double transitivity of Tf is equivalent to Gf(1)transitive on {2, . . . , n}: no dependence on u on the

appearances of {1, u + 1} in all the Ris.

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§IV. What groups give Davenport pairs and how?

How this pointed to all Genus 0 MonodromyThis is the start of the Brumer-McLaughlin-Misera-Feit-

Thompson-Guralnick-Saxl-Muller interactions told in [UMSt].

Story to show how to use the power of group theory, vs how to

study groups. I answer these points from p. 10:

• P1: What groups could possibly arise as Gf with (f, g) a

D(avenport)P(air).

• P2: From those, how to produce all Davenport pairs.

• Genus 0 Problem: What are the monodromy groups of

rational functions?

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§IV.A. Projective Linear Groups

Finite field Fq (with q = pt, p prime). For v ≥ 2, Fqv+1 is a

dimension v + 1 vector space over Fq. Then,

PGLv+1(Fq) = GLv+1(Fq)/(Fq)∗ acts on lines through origin:

on the n = (qv+1 − 1)(q − 1) points of projective v-space.

PGLv+1(Fq) has two (inequivalent) doubly transitive

permutation representations: On points and on hyperplanes.

An incidence matrix conjugates between them: Equiv. reps.

Euler’s Thm. gives a cyclic generator, γq, of F∗qv+1. Multiplying

by γq on Fqv+1 = F v+1q induces an n-cycle in PGLv+1(Fq).

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§IV.B.Punchlines onDavenport (f indecomposable)1. Davenport’s Original Question: ∃ DPs over Q? From

Mult. Thm #2 (p. 15) =⇒ g is complex conjugate

to f . So, the answer is “No!”

2. Answer to Schinzel’s Problem: If f(x) − h(y) factors (over

C), then h = g(h2(y)) with (f, g) a Davenport pair over

some field.

3. Degrees of DPs: n = 7, 11, 13, 15, 21, 31. For each n, we

know exactly what fields carry DPs.

4. Two equivalent doubly transitive reps. and n-cycle: Except

for one of deg 11, all are PGLv+1 s (from classification).

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§IV.C. From #3, Hints at the Genus 0 Problem

For the cases n = 7, 13, 15 there are non-trivial

Mobius equivalence (p. 4) families of Davenport

pairs. For n = 7 = 1 + 2 + 22, Gf = PGL3(Z/2).Example branch cycles: (σ1, σ2, σ3, σ4) with

σ1, σ2, σ3 involutions, each fixing the 3 points, on

some hyperplane, and σ4 is a 7-cycle. R(iemann)-

H(urwitz) (App. B) says any cover with these branch

cycles has genus ggg7 = 0:

(*5) 2(7+ggg7 -1)=∑4

i=1 ind(σi) = 3 ·2+6 =⇒ ggg7=0.

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Comments on the three families n = 7, 13, 15• Their Mobius equivalence classes form a genus 0 j-line cover.

Each has definition field Q, but is not a modular curve.

• These form approximately half of the genus 0 families

of polynomials whose monodromy groups aren’t close to

dihedral or Alternating groups as determined by Muller [Mu].

• Data from other problems [Fr80] also gave something akin

to the result here: Only polynomials of finitely many degrees

have (close to) projective linear groups as monodromy group.

Genus 0: Excluding groups related to An , Sn , Dn and

Z/n s, rational functions have only finitely other possible

monodromy groups.

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•••

• ••

z0

z1

zi

zr

σi ↗ σr↘

σ0↗

σ1↘

δ1↗

δi↗ ←δr

b1↗

bi↗

←br

a1↗

ai↘←ar

App. A: Punctured Sphere Classical Generators:

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Pieces in the figure

Ordered closed paths δiσiδ−1i = σi, i = 1, . . . , r,

are classical generators of π1(Uzzz, z0).Discs, i = 1, . . . , r: Di with center zi; all disjoint,

each excludes z0; bi be on the boundary of Di.

Clockwise orientation: Boundary of Di is a path

σi with initial and end point bi; δi a simple simplicial

path: initial point z0 and end point bi. Assume δi

meets none of σ1, . . . , σi−1, σi+1, . . . , σr, and it meets

σi only at its endpoint.

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Meeting Boundary of D0

D0 intersections: D0 with center z0; disjoint from

each D1, . . . , Dr. Consider ai, first intersection of δi

and boundary σ0 of D0.

Crucial ordering: Conditions on δ1, . . . , δr:

• pairwise nonintersecting, except at z0; and

• a1, . . . , ar are in order clockwise around σ0.

Since paths are simplicial, last condition is

independent of D0, for D0 sufficiently small.

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App. B: R(iemann)-H(urwitz)R-H: Computes the genus gX of a degree n cover

ϕ : X → P1z from these ingredients.

• zzzϕ are the branch points, and (σ1, . . . , σr) are

classical generators (App.A1) of π1(Uzzzϕ).

• X0 = ϕ−1(Uzzzϕ). So, ϕ0 : X0 → Uzzz is unramified,

giving ϕ∗ : π1(Uzzzϕ) → Sn.

• ϕ∗(σ1, . . . , σr) = (σ1, . . . , σr).

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Branch cycles and the genus

With ind(σi) = n − |σi orbits|,

2(n+gX−1)=r∑

i=1

ind(σi).

Then, (g1, . . . , gr) are branch cycles of ϕ.

Exercise:Compute genus of a cover with branch

cycles ggg ∈ Ni(Dpk+1,C24)abs in §I.B (p. 5). Same for

ggg ∈ Ni(Dpk+1,C24)in.

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App.C. Dragging a function by its branch points

Continuity on the space of such f s: You can drag

the classical generators on Uzzz0 = P1z \ zzz0 along any

path P (t), t ∈ [0, 1] based at zzz0 ∈ Ur to classical

generators on UP (t).

Upshot: You can drag f0 to ft by its branch

points. If P is closed, representing [P ] ∈ π1(Ur,zzz0),

then f1 (usually) has a different bcd, denoted (ggg)q[P ],

(relative to the original classical generators).

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Bibliography[A-O-S] M. Aschbacher and L. Scott, Maximal subgroups of finite groups, J. Algebra 92 (1985), 44-80.

[CoCa99] J.-M. Couveignes and P. Cassou-Nogues, Factorisations explicites de g(y)-h(z), Acta Arith. 87(1999), no. 4, 291-317.

[CKS76] C.W. Curtis, W.M. Kantor and G.M. Seitz, The 2-transitive permutation representations of thefinite Chevalley groups, TAMS 218 (1976), 1-59.

[DL63] H. Davenport and D.J. Lewis, Notes on Congruences (I), Qt. J. Math. Oxford (2) 14 (1963), 51–60.

[Fr73] M. Fried, The field of definition of function fields and a problem in the reducibility of polynomials intwo variables, Ill. J. Math. 17 (1973), 128-146.

[Fr87] M. Fried, Irreducibility results for separated variables equations, J. Pure and Appl. Alg. 48 (1987), 9-22.

[Fr99] M. Fried, Variables Separated Polynomials and Moduli Spaces, No. Th. in Prog., eds. K. Gyory,H. Iwaniec, J.Urbanowicz, Schinzel Festschrift, Sum. 1997,WalterdeGruyter,Berlin-NY (Feb. 1999),169-228.

[Fr05] M. Fried, Relating two genus 0 problems of John Thompson, Volume for John Thompsons 70thbirthday, in Progress in Galois Theory, H. Voelklein and T. Shaska editors 2005 Springer Science, 51-85.

[GLS] D. Gorenstein, R. Lyons, R. Solomon, The Classification of Finite Simple Groups, Number 3,Mathematical Surveys and Monographs, 40 ISBN:0821803913.

[LPS] M. Liebeck, C. Praeger, J. Saxl, The maximal factorizations of the finite simple groups and theirautomorphism groups, Mem. AMS 86 #432 (1990).

[Mu95] P. Mller, Primitive monodromy groups of polynomials, Proceedings of the Recent developments inthe Inverse Galois Problem conference, vol. 186, 1995, AMS Cont. Math series, pp. 385401.

[Sc71] A. Schinzel, Reducibility of Polynomials, Int. Cong. Math. Nice 1970 (1971), Gauthier-Villars, 491-496.

[So01] R. Solomon, ABrief History of the Classification of Finite Simple Groups, BAMS38 (3) (2001), 315-352.

[UMSt] http://www.math.uci.edu/˜mfried/paplist-cov/UMStory.html.

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