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METO 621 LESSON 7

METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

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Page 1: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

METO 621

LESSON 7

Page 2: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Vibrating Rotator• If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be the sum of the two energies. But there is, and we get

• The wavenumber of a spectral line is given by the difference of the term values of the two states

22

200

)1()1(

)2/1()2/1(),(

JJDJJB

vxvhc

JvE

vv

e

Page 3: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Energy levels of a vibrating rotator

Page 4: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Selection rules• Not all transitions are allowed - selection rules, e.g. in rotational transitions changes in J are restricted to 0, and 1

•The complete set of rotational transitions between two vibrational levels is known as a ‘band’

•A band normally consists of three separate sequences; if J=0 we have the Q branch, J=1 the R branch, J=-1 the P branch

Page 5: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Selection rules

Page 6: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Fine structure in HCl

Page 7: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Line strengths• Earlier we defined the line strength for an isolated line, S. In the case of a vibration-rotation band we define a band strength

• To determine the line strength of a individual transition we need to determine the population of the lowest level for each vibration/rotation level. As the electronic levels have a large energy difference, nearly all molecules are in the so-called ‘ground’ state.

Page 8: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Line strengths

30

0

cmper molecules ofnumber total theis where

)(exp)(

N

Tk

vGNvN

B

• The population of the vibrational levels is governed by the Boltzmann distribution

• For rotational levels we have the complication that each level is ‘degenerate’. For each rotational number J there are (2J+1) levels.

Tk

JEJ

Tk

hcBNJN

BB

v )(exp)12()( 0

Page 9: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Relative populations of rotational levels in HCl

Figure 2.3 in binder

J

Page 10: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Intensity distribution in bands of HCl

Page 11: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Potential energy diagram for a typical diatomic molecule

Page 12: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Dissociation• The previous slide shows a potential energy diagram for a

typical diatomic molecule.• The x axis is the inter-nuclear separation r, and the y axis

is the potential energy.• As the two atoms come together the electrons of each

overlap and produce a binding force which stabilizes the molecule.

• Hence the ‘potential well’.• The shaded area represents energies for which the

molecule can be broken apart. When this occurs the molecule is not restricted to absorbing discrete energies as any additional energy can be taken away by the atoms as kinetic energy which is not quantized.

• The shaded area is referred to as a dissociation continuum.

Page 13: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Franck-Condon principle

• The time for a transition is extremely small, and in this time the atoms within a molecule can be assumed not to move.

• Franck and Condon therefore postulated that on a potential energy diagram the most likely transitions would be vertical transitions

Page 14: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Franck-Condon principle

Page 15: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Electronic levels

• In molecules we have two opposing forces - the repelling force of the nuclei, and the binding force of the electrons.

• If the orbit of the electrons change then the binding force will change, i.e. the net potential energy of the molecule will change.

• This means that the inter-atomic distance will change

• Different electronic levels will have different rotational and vibrational constants

Page 16: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Photodissociation

• The fragmentation of a chemical species following the absorption of light is most important in atmospheric chemistry

• Optical dissociation occurs from the electronic state to which absorption takes place

• Absorption leading to dissociation gives rise to a continuum, as additional energy can be taken away by the fragments as kinetic energy, which is not quantized.

• The atomic products can be in an excited state.

Page 17: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Photochemical Change

Page 18: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Photodissociation

• Two main mechanisms are recognized for dissociation, optical dissociation and pre-dissociation. These processes will be illustrated in the O2 molecule.

• Optical dissociation occurs within the electronic state to which the dissociation first occurs. The absorption spectrum leading to dissociation is a continuum.

• At some longer wavelength the spectrum shows vibrational bands. The bands get closer together as the limit is approached – the restoring force for the vibration gets weaker.

•The absorption from the ‘X’ to the ‘B’ state in O2 , is an example.

Page 19: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Photodissociation

Page 20: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Discrete absorption in molecular oxygen, ( Schumann-Runge bands)

Page 21: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Absorption continuum in molecular oxygen (Schumann-Runge continuum)

Page 22: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Photodissociation• Note that when the B state dissociates, one of the two atomic

fragments is excited. One atom is left in the ground state (3P) and the other in an excited state (1D).

• Some ‘pre-dissociation’ occurs in the B→X (Schumann-Runge) system before the dissociation limit. This occurs because a ‘repulsive’ state crosses the B electronic state and a radiationless transition takes place. The repulsive state is unstable and dissociation takes place. Note that both atomic fragments are 3P.

• Although molecular oxygen has many electronic states, not all of the possible transitions between the states are allowed. The magnitude of the photon energy is not the only criteria

• Consideration of things such as the need to conserve quantum spin and orbital angular momentum indicate if the transition is possible.

Page 23: METO 621 LESSON 7. Vibrating Rotator If there were no interaction between the rotation and vibration, then the total energy of a quantum state would be

Predissociation