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METO 621 CHEM Lesson 1

METO 621 CHEM

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METO 621 CHEM. Lesson 1. CHEMICAL FORMULA. Each atom is given a symbol, N stands for nitrogen, O for oxygen, Cl for chlorine. For molecules, the number of atoms is placed as a subscript, for example Nitrogen Dioxide is written as NO 2 , and contains one nitrogen atom and two oxygen atoms. - PowerPoint PPT Presentation

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Page 1: METO 621 CHEM

METO 621 CHEM

Lesson 1

Page 2: METO 621 CHEM

CHEMICAL FORMULA• Each atom is given a symbol, N stands for nitrogen, O for oxygen, Cl

for chlorine.• For molecules, the number of atoms is placed as a subscript, for

example Nitrogen Dioxide is written as NO2, and contains one nitrogen atom and two oxygen atoms.

• We will deal with the simplest reactions, e.g.

NO + O3 → NO2 + O2

Nitric oxide (NO) reacts with Ozone (O3) to give Nitrogen Dioxide (NO2) plus molecular oxygen (O2)

• The number of atoms for a particular species must be the same on both sides of the equation.

Page 3: METO 621 CHEM

Photochemical Change

• A quantum of radiative energy is called a photon, and is given the symbol hHence in a chemical equation we write:

O3 + h→O2 + O• The energy of a photon in terms of its wavelength is

E=119625/kJ mol-1 or 1239.8/ eV • To get enough energy to break up a molecule (dissociation)

the wavelength must be in or below the ultraviolet. Thus dissociation typically occurs as the result of electronic transitions

• Small, light chemical species generally have electronic transitions at wavelengths shorter than those for more complex compounds, e.g. <200 nm for O2 but <300 nm for O3

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Photochemical Change• Atmospheres tend to act as filters cutting out short wavelength

radiation, since the absorptions of their major constituents are generally strong at the short wavelengths.

• As a result, photochemically active radiation that penetrates into an atmosphere is of longer wavelengths, and the chemistry is characterized by lower energies. For example, the dissociation of molecular oxygen, the ultimate source of ozone in the stratosphere, is limited to altitudes above 30 km.

• Absorption of a photon of photochemically active radiation leads to electronic excitation, represented as

AB + h →AB*

• If the excited molecule then breaks apart, the quantum yield of such a reaction is defined as the number of reactant molecules decomposed for each quantum of radiation absorbed

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Photochemical Change

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Photodissociation• Two main mechanisms are recognized for dissociation, optical dissociation and pre-dissociation. These processes will be illustrated in the O2 and O3 molecules.

• Optical dissociation occurs within the electronic state to which the dissociation first occurs. The absorption spectrum leading to dissociation is a continuum.

• At some longer wavelength the spectrum shows vibrational bands. The bands get closer together as the limit is approached – the restoring force for the vibration gets weaker.

•The absorption from the ‘X’ to the ‘B’ state in O2 , is an example.

Page 7: METO 621 CHEM

Photodissociation

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Photodissociation

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Photodissociation

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Photodissociation• Note that when the B state dissociates, one of the two atomic

fragments is excited. One atom is left in the ground state (3P) and the other in an excited state (1D).

• Some fragmentation occurs in the B→X (Schumann-Runge) system before the dissociation limit. This occurs because a repulsive state crosses the B electronic state and a radiationless transition takes place. The repulsive state is unstable and dissociation takes place. Note that both atomic fragments are 3P.

• Although molecular oxygen has many electronic states, not all of the possible transitions between the states are allowed. The magnitude of the photon energy is not the only criteria

• Consideration of things such as the need to conserve quantum spin and orbital angular momentum indicate if the transition is possible.

Page 11: METO 621 CHEM

Photodissociation

• Let us take the reactionO3 + h→ O2 + O

• The O2 molecule and atom can be left in several states if we consider energy alone, because any ‘extra’ energy can be used for kinetic energy of the products.

• For wavelengths about 310 nm or less, spin conservation allows the transition

O3 + h→ O2(1g) + O(1D)• The O(1D) atom formed in this reaction plays a major role in

atmospheric chemistry, for exampleO(1D) + H2O → OH + OH

• OH, the hydroxyl radical, can break down hydrocarbons.

Page 12: METO 621 CHEM

Wavelength Threshold for Dissociation of Ozone

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Quantum yield for Ozone

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Quantum yield for Ozone

• Note that the onset of dissociation is not abrupt. • The shape of the curve can be explained if the

internal energy of the molecule (vibration and rotation) can be added to the photon energy to induce transitions.

• Transitions from vibrationally excited states can be important in the atmosphere.

• The solar spectrum shows a rapid increase above 310 nm, so any extension of the absorption cross section above this limit can lead to a significant increase in say the quantum yield of O1D

Page 15: METO 621 CHEM

Potential Energy Surface• We have already considered the potential energy diagram for a

diatomic surface, which can be represented as a two dimensional surface.

• But for a polyatomic molecule we must consider a three dimensional potential energy surface.

• The next figure represents the potential energy surface for the reaction

A + BC → ABC* → AB + C• The symbol * indicating that ABC has energy above that of

the reactants A and BC, and therefore ABC* is unstable.• ABC* will either drop back to A + BC or drop down to AB +

C

Page 16: METO 621 CHEM

Potential Energy Surface

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Chemical Kinetics• A reaction

A + B → products proceeds at a rate proportional to the concentrations raised to

some power

][][][][ BAkdtBd

dtAdRate

• k is the rate coefficient (rate constant). The powers and are the order of the reaction with respect to the reactants i.e.

A + B → products

• If for example then the reaction is called a second order reaction () .

Page 18: METO 621 CHEM

Chemical Kinetics

• If the concentration of B is very much greater then A then [B] can be considered a constant.

• One can now combine [B] with k to form a first order reaction rate

][]}[][{][ 12 AkABkdtAdRate

• k1 is called a pseudo first order rate coefficient

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Bimolecular reactions

• As two reactants approach each other closely enough, the energy of the reaction system rises ( see the previous figure).

• The contours of the surface show that there is a valley that provides the lowest energy approach of the reactants, the dotted line in the figure is that lowest path.

• There comes a point , marked ‘*’ beyond which the energy starts to decrease again, and so product formation is now energetically favorable.

• The next figure shows the energy of the ABC system as a function of distance traveled along the lowest path for an exothermic reaction.

Page 20: METO 621 CHEM

Bimolecular reactions

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Bimolecular reactions

• In principle, if the potential surface is known, it is possible to calculate the rate coefficient, but in practice this a difficult problem.

• Two simplifications are adopted. The first is the collision theory, the second the Transition State theory.

• In the collision theory two conditions must be met, a collision between the reactants must occur, and the energy of collision along the line of centers must equal or exceed the energy required to overcome the energy barrier. The rate of reaction becomes

)/exp( RTEcnndt

dndt

dnccBCA

BCA

Page 22: METO 621 CHEM

Bimolecular reactions

• The rate coefficient then becomes

)/exp( expression Arrhenius

thefollow tofound are constants rateorder -secondMany )/exp(

RTEAk

RTEck

a

cc

c andA between difference theis tellingMore

• In this expression A is a constant whereas the mean velocity used in the collision theory depends on the square root of the temperature. So the two equations do not agree exactly.

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Bimolecular reactions

• For typical molecular reactants, with collision radii of 400 picometers, and relative masses of ~30, c is ~3E-10 cm-3 molecule-1 s-1 at 300K.

• This product is called the collision frequency factor. Except for the simplest systems, A is always less than this factor.

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Transition State Theory• For this theory we write the rate coefficient as

)/exp(* kTEqq

qh

kTk cBCA

ABC

• The q’s are statistical thermodynamic terms or partition functions. Basically the internal motions neglected in the collision theory are specifically taken into account.

•The q’s for AB and BC are obtained from spectroscopic constants. However this cannot be done for ABC*. Informed guess.

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Transition State Theory

)/exp(' RTETAk cn

The partition functions may each have a different temperature dependence but the over all temperature dependence can be expressed as a power law.

Where A’ is the temperature-independent part of the pre-exponential function, and n is the exponent for the temperature dependence.

Page 26: METO 621 CHEM

Liquid Phase Reactions

• In such areas as the formation of acid rain, reactions that take place within a droplet are extremely important.

• Henry’s Law will determine the rate at which the reactant gases enter the droplet.

• Droplets are much denser then the surrounding air, and reactants have to squeeze past solvent molecules in order to react

• Liquid-phase kinetics can be viewed in two ways• First, the rate determining process is the diffusion of the

reactants through the solvent – a diffusion controlled reaction.• Second, the kinetics are controlled by the rate of reaction

within the droplet – an activation controlled reaction.

Page 27: METO 621 CHEM

Heterogeneous Reactions• These are reactions that occur at the interface between condensed and gaseous phases, i.e. the surface

• In liquids, the reactions tend to be inside the particle. In solids, the diffusion from the surface is extremely small, and the reactions are confined to the surface. We now need to consider the case when two different species X and Y are absorbed on the surface and reactIf we assume that all surface sites are equivalent, and that there are no interactions between similar molecules, i.e. the number of sites ‘filled’ is small compared to the total number of sites, then we can apply the Langmuir adsorption isotherm

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Heterogeneous Reactions

• It can be shown that the surface coverage, X, is given by

X=bpX/(1+pX)• b is the ratio of rate coefficients for adsorption onto the surface

and desorption from it. p is the partial pressure of the gas.• In general the value of pX is much smaller that 1. Hence we can

write

YYXXLYXL pbpbkk rate