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Mendelian Genetics Laws of Inheritance

Mendelian Genetics

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Mendelian Genetics. Laws of Inheritance. Terms. Phenotype: the appearance of the trait in the organism Genotype : the genetic make-up of an organism Genetics : biology dealing with the principles of variation and inheritance in animals and plants. - PowerPoint PPT Presentation

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Page 1: Mendelian  Genetics

Mendelian Genetics

Laws of Inheritance

Page 2: Mendelian  Genetics

Terms

Phenotype: • the appearance of the trait in the organismGenotype: • the genetic make-up of an organismGenetics: • biology dealing with the principles of variation and

inheritance in animals and plants. • gives us greater understanding of how we can determine

the likelihood of inheriting certain phenotypes.

Page 3: Mendelian  Genetics

History• Since 460 B.C.E philosophers, physicians and scientists have

been theorizing heredity

• Most believed inheritance involved a “mixing” of genetic information from the mother and father

• During the 19th century the “blending theory” of genetics was quite popular.

-offspring’s phenotypes were a blend of the parents’

• Didn’t understand how phenotypes were expressed, or WHY some phenotypes in the P generation were NOT expressed in their offspring’s generation

Page 4: Mendelian  Genetics

Gregor Mendel (1822-1884)

• Austrian monk

• Developed principles that became genetics through 8 yrs of conducting experiments on pea plants

Why the pea plant?• Commercially available• Easy to grow, and matures quickly• Sexual organs (re: reproductive organs) entirely enclosed in

the flower – meaning plants self-pollinate so Mendel could control reproduction

Page 5: Mendelian  Genetics

Mendel’s Experiments• introduced pollen from the flower of one pea plant to the

pistil (ovaries) of another flower• resulted in a variety of different, easily distinguishable

phenotypes• examined seven of the resulting phenotypes – each of which

only had two possible variations

Page 6: Mendelian  Genetics

Experiment #1 – F1 Generation• obtained plant “purebreds” (P* – parent generation) *only use this notation if purebred

• crossed each P generation with its opposite-ex: tall P plant is crossed with a short P

• this produced the F1* generation (1st filial) -hybrids since a cross between two different purebreds *only use this notation if hybrid offspring of 2 purebreds

• called a Monohybrid Cross (only 1 trait was selected – plant height

Page 7: Mendelian  Genetics

Results:• all F1 plants were tall• concluded the trait for tall plants must be dominant • trait for short plants must be recessive

Dominant:• a phenotype that is always expressed

Recessive: • a characteristic that is always latent (present but inactive) • not usually expressed in an individual

Principle of Dominance: • When individuals with contrasting traits are crossed, the offspring

will express only the dominant trait

Page 8: Mendelian  Genetics

F1 Results

Page 9: Mendelian  Genetics

Experiment #2 – F2 Generation• Crossed F1 generations• produced F2 generationResults:• 3 were tall, 1 was short• ratio of 3:1 is known as the Mendelian ratio

Page 10: Mendelian  Genetics

Mendel’s Law of Segregation1. Each parent has 2 copies of each gene

Gene – part of the chromosome that controls expression of a certain trait

2. Genes can exist in different forms, known as alleles.• Alleles for pea seed shape include round and wrinkled.

3. Offspring inherit one allele of a gene from each parent.• If both alleles are the same = homozygous for that gene.• If alleles are different = heterozygous for that gene.

4. Alleles can be dominant or recessive.• Dominant alleles are expressed in heterozygous offspring.• Recessive alleles are only expressed in homozygous offspring.

5. Each gamete carries only one allele for each trait.

Page 11: Mendelian  Genetics
Page 12: Mendelian  Genetics

Genotypes & Phenotypes• Capital letters used for dominant allele• lowercase of the same letter used for recessive• ex. round seeds are dominant over wrinkled.• R = round, r = wrinkledGenotype • the alleles for an individual, ex. for seeds:

- RR (homozygous round)- rr (homozygous wrinkled)- Rr (heterozygous round)

Phenotype• the expressed trait for an individual (what is seen) ex. for seeds:

- round- wrinkled

• Heterozygous genotypes (Rr) always have the phenotype of the dominant allele.

Page 13: Mendelian  Genetics

Plant Height Experiments• F1 genotype:- 4 Tt (heterozygous)• F1 phenotype:- 4 tall• F2 genotypes:- 1 TT (homozygous dominant)- 2 Tt (heterozygous)- 1 tt (homozygous recessive)- ratio 1:2:1• F2 phenotypes:- 3 tall- 1 short- ratio 3:1

tt

P Generation

F1 Generation

F2 Generation

True-breeding parents

Tall = dominant = TShort = recessive = t

TT tt

Hybrid offspringAll heterozygous

all Tt

Monohybrid crossfrom F1 generation

TT Tt Tt

Tall

all Tall

TallTall Tall

short

short

Genotypes1 TT : 2 Tt : 1 tt

Phenotypes3 Tall :1 short

Page 14: Mendelian  Genetics

Probability & Punnet SquaresProbability – the likelihood of an outcomePunnett square - used to determine the probabilities of allele combinations when the genotypes of the parents are known

Page 15: Mendelian  Genetics

Making Punnet Squares

Page 16: Mendelian  Genetics

Practice Problem #1• A geneticist crosses two pea plants. One of the plants is heterozygous

for the dominant inflated pea pod trait, and the other plant has constricted pea pods. What would be the expected genotypic and phenotypic proportions of the offspring?

Given• inflated pod (I) - dominant • constricted pod (i) - recessive• II or Ii = Inflated pods• ii = constricted pods• heterozygous inflated x constricted = Ii x iiRequired• Punnet square• gametes from the cross• expected proportions of F1 plants with genotypes II, Ii, and ii• expected proportions of phenotypes (inflated pods and constricted)

Page 17: Mendelian  Genetics

Solution• The Ii parent produces

gametes I and i.• The ii parent produces

gametes i and i.

I i

i Ii ii

i Ii ii

Paraphrase1/2 of the offspring would be heterozygous (Ii) and 1/2 would be ii. Therefore, 1/2 of the offspring would have inflated pods, and 1/2 would have constricted pods.

Page 18: Mendelian  Genetics

Solutions #2- 42. Solution• The Aa parent produces gametes A and a.• The aa parent produces gametes a and a. Paraphrase• ½ the offspring would be heterozygous (Aa) and ½ would be

aa. Therefore, ½ of the offspring would be brown, and ½ would be albino

3. Solution• The DD parent produces gametes D and D.• The Dd parent produces gametes D and d. Paraphrase• ½ of the offspring would be heterozygous (Aa) and ½ would

be homozygous (AA). Therefore, all of the offspring would have dimples.

4. Solution• The Tt parents produce gametes T and t. Paraphrase• ½ of the offspring would be heterozygous (Tt), ¼ would be

homozygous dominant (TT) and ¼ would be homozygous recessive (tt). Therefore, ¾ of the offspring would taste PTC, and ¼ would not.

A aa Aa aaa Aa aa

D DD DD DDd Dd Dd

T t

T TT Tt

t Tt tt

Page 19: Mendelian  Genetics

Test Crosses• how genotype can be determined from phenotype

• breed an individual with the dominant phenotype with a homozygous recessive

• If offspring are all dominant phenotype, the parent was homozygous dominant

• If offspring are half dominant phenotype, and half recessive phenotype, the parent was heterozygous dominant.