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8/14/2019 Meat Juice Lab (Anna Peskin, C5)
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
ISOLATION AND CHARACTERIZATION OF LACTATE DEHYDROGENASE
OBJECTIVE :
The objective of this experiment was to purify and characterize a protein of interest. In this lab, lactate
dehydrogenase (LDH) was the protein of interest. LDH has various isozymes made of heart or muscle LDH (H4, M3H,
H2M2, HM3, and M4). This lab looked specifically at porcine muscle, but both heart and muscle LDH are expressed in
muscle. The protein was first purified on an affinity column. Afterwards, a BCA assay was used to determine the
amount of protein that was purified. The reaction that is catalyzed by LDH (lactate + NAD+pyruvate + NADH + H+)was run while observed in a spectrophotometer and LDH activity was measured by observing NADH formation. SDS-
PAGE was then used to measure to observe the purity of the purifiedprotein. Finally, a spectrophotometer was used to
run kinetic analysis of the reaction catalyzed by LDH in order to determine kinetic constants of the reaction.
PROCDURE :
The first step of this experiment was to prepare a lipid-free sample of porcine muscle (prepared by the TA).
This homogenized sample was run through an Affigel Blue affinity column, washed with various buffers, and collected
into several fractions (F1-10). The expected contents of these fractions are in table 1, below. The fractions were then
dialyzed to remove NaCl, NAD, and NADH. These molecules would otherwise interfere with assays performed later on
in this experiment.
Native gel electrophoresis was then run on each fraction. The H and M subunits differ in net chargethe heart
subunits are negative while the muscle subunits are slightly positive. Native gel electrophoresis uses this to its advantage
as it separates the subunits based on charge and allows experimenters to see the relative amount of each isozyme in each
fraction.
Afterwards, a BCA Assay was run to determine the total amount of protein in each fraction. BCA works
because peptide bonds (and thus proteins) reduce Cu+2to Cu+1. Cu+1binds to BCA and forms a colored complex. This
color can be measured with absorbance and thus the amount of protein in each sample can be quantified.The amount of LDH activity in each fraction was determined by adding the LDH containing fraction to lactate
and NAD and catalyzing the reaction: lactate + NAD+pyruvate + NADH + H+(this reaction is catalyzed by LDH).
A spectrophotometer measured absorbance at 340nm, where NADH absorbs while NAD does not absorb. The formation
of NADH was representative of the activity of LDH in each sample.
SDS-PAGE was used to separate proteins based their size. The SDS-PAGE of our fractions was compared to
known contaminants as well as the known size for LDH. The SDS-PAGE allowed for experimenters to visually
observe purity in each fraction as well as see if LDH was present in each fraction.
Finally, kinetic constants for LDH were calculated by running the reaction catalyzed by LDH while observing
NADH formation in a spectrophotometer. This was done while varying NAD or lactate concentrations one at a time.
From here, kinetic constants could be calculated.
F1: crude homogenate F6: column washed with NAD, expect to see heart LDH
F2: homogenate ran through column, no LDH F7: column washed with NAD, expect to see heart LDH
F3: homogenate ran through column, no LDH F8: column washed with NADH, expect to see muscle LDH
F4: homogenate ran through column, no LDH F9: column washed with NADH, expect to see muscle LDH
F5: column washed with NAD, expect to see heart LDH F10: column washed with NADH, expect to see muscle LDH
Table 1, expected contents of various fractions.
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
RESULTS AND CONCLUSION :
ACTIVITY AND RECOVERY OF LACTATE DEHYDROGENASE :
Fraction Volume (mL) Dilution? Volume
Assayed (L)
Absorbance
/ minute
[NADH] in the cuvette
after 1 minute (mol/mL)
units LDH
in 10 mL
Activity
(units)
F1 2.7 1:5 10 0.38 0.061 31 84
F2 2.7 n/a 10 0.018 0.0030 0.30 0.81
F3 2.9 n/a 10 0.0060 0.00097 0.096 0.28
F4 3.3 n/a 10 0.0014 0.00022 0.023 0.075
F5 4.2 n/a 10 0.0028 0.00045 0.045 0.19
F6 3.2 n/a 10 0.0096 0.0015 0.15 0.49
F7 4.1 n/a 10 -0.00080 -0.00013 -0.013 -0.052
F8 3.1 n/a 10 0.60 0.096 9.6 30.
F9 3.0 n/a 10 0.64 0.10 10. 31
F10 3.8 n/a 10 0.11 0.018 1.8 6.7
Table 2, activity of all of the fractions. Note: volume amounts were measured with a pipette after dialysis. Negative units are
indicative of so little LDH that it was barely measureable.
Sample Activity Calculation for F1:
Absorbance at 0sec: .11
Absorbance at 30sec: .30
abs / 30 sec = (Absorbance30sec - Absorbance0sec) / 30 sec
= (.30 - .11) / 30 sec
= .19 / 30 sec
abs / 1 min = (abs / 30 sec) * (60 sec / 1 min)
= (.19 / 30 sec) * (60 sec / 1 min)
= .38 / minute
[NADH] in the cuvette after 1 minute (mol/L)use A1/ C1= A2/ C2 (the molar extinction coefficient which is
6220M-1cm-1 for NADH)
(6220M-1cm-1)/ 1M = (abs / 1 min) / x
x = .38 / (6220M-1cm-1 / 1M)
x= 6.1*10-5 mol/L
Convert units to mol/mL:
6.1*10-5 mol 106 mol 1 L = .061 mol/mL
1 L 1 mol 103 mL
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
Account for dilution : .061 mol/mL * 5 (dilution factor) = .31 mol/mL
Units LDH in 10 L: .31 units LDH 1.0*103L = 31 units / mL
10. L 1 mL
Activity = (units / mL) * (mL fraction)
= 31 units / mL * 2.7 mL
= 84 units
Percent Recovery :
Fraction Percent Recovery
F2 0.96 %
F3 0.33 %
F4 0.089 %
F5 0.22 %
F6 0.58 %
F7 -0.062 %
F8 36 %
F9 37 %
F10 7.9 %
Total Recovery 82 %
Table 3, percent recovery of the various fractions. Negative percent recovery is indicative of negative LDH units (explained
in table 2).
Sample Percent Recovery Calculation for F8:
Percent Recovery F8 = (LDH Activity in F8 / LDH Activity in F1 (crude homogenate)) * 100%
= (30 / 84) * 100%
= 36 %
It is expected that the NAD and NADH buffers will elute LDH from the column. NAD has a high affinity for
heart isozyme and NADH has a high affinity for muscle isozyme. Because of this, it is expected that NAD will elute
heart isozyme and NADH will elute muscle isozyme. This assay was run on porcine muscle and thus it is expected the
majority of the LDH isozyme to be muscle isozyme. Because of this, the NADH is eluting most of the product off of the
column.
These results showed that the LDH that was applied to the column did indeed bind to the resin. The fraction
that did not go through the column (F1) had a high activity (84 activity units) which is indicative of a lot of LDH present
in the fraction. The fractions that went through the column but were not washed with an elution buffer (F2, F3, and F4)
had a very low activity (.81, .28, and .075respectively) which indicates that little to no LDH was present in these
fractions. The fractions that were washed with NAD (in which it was expected to see heart isozyme (F5, F6, and F7) also
had low activitynone of these activities surpassed 1 unit. This is not surprising because porcine muscle does not have
a high amount of heart LDH isozyme. Thus, there was not a large amount of LDH in the fractions and the activity was
low. It is expected to see the most LDH recovered in F8, F9, and F10 because those were washed with NADH and
NADH has a high affinity for muscle LDH isozyme. This turned out to be truethe activity in F8F10 was much
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
higher (reaching up to 31 activity units) than all of the other fractions that passed through the column. Out of these 3
fractions, F10 had the lowest activity. This is due to the fact that most of the LDH likely washed off into F8 and F9. This
data supports the conclusion that LDH was bound to the resin and was later eluted with NADH.
Overall, 82% of the LDH was recovered. A majority of the LDH was recovered when the column was washed
with NADH. This supports the conclusion that a majority of the LDH present was muscle LDH (because muscle LDH
has a high binding affinity for NADH). 18% of the LDH was not recovered. It may have stuck to the column and not
washed off with the elution buffers. Alternatively, since this experiment was done over the course of a few weeks it
might have denatured over time and thus would not be active.
PROTIEN DETERMINATION:
Figure 1, protein determination by BCA. The lighter lines represent 1 standard deviation from the mean.
Fraction Concentration
(Sample 1, mg/mL)
Concentration
(Sample 2, mg/mL)
Concentration
(Average, mg/mL)
Specific
Activity
F1 7.8 8.3 8.1 1.4
F2 0.27 0.46 0.36 0.30
F3 1.7 2.2 1.9 0.017
F4 1.6 1.6 1.6 0.0042
F5 0.45 0.45 0.45 0.024
F6 0.17 0.21 0.19 0.26
F7 0.14 0.10 0.12 -0.026
F8 0.20 0.17 0.19 16
y = 0.43x + 0.080
R = 0.98
y = 0.43x + 0.040
y = 0.43x + 0.12
0
0.2
0.4
0.6
0.8
1
1.2
0 0.5 1 1.5 2 2.5A
bsorbance(absorbanceunits)
Protein Concentration (mg/mL)
PROTEIN DETERMINATION BYBCA
: Protein Determination: Standard Curve : 1 Standard Deviation
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
F9 0.32 0.28 0.30 12
F10 0.13 0.15 0.14 3.4
Table 4, total protein concentration as determined by BCA-Assay and specific activity of fractions.
Based on the specific activity of LDH in each fraction, the recovered LDH is more pure then the crudehomogenate (F1). In F8, F9, and F10, each mg/mL of protein has 16, 12, and 3.4 (respectively) units of LDH activity.
This can be compared to F1 where there was only 1.4 units of LDH activity for each mg/mL of protein. From this, it can
be concluded that the recovered LDH was much more pure then the starting material.
BCA-Assay Absorbance Results
Table 5, BCA-Assay absorbance results. S1-S11 were standards of known concentrations made with BSA.
Sample Concentration Calculation for F1:
Equation from linear regression: y= .43x + .080 ; y= absorbance, x=concentration
Concentration = (absorbance - .080)/.43
= (.75 - .080)/.43
= 1.6 mg/mL
S1 S2 S3 S4 S5 S6 S7 S8 S9 S10 S11
F1 F1, 1:5 F1, 1:25 F2 F2, 1:5 F2, 1:25 F3 F3, 1:5 F3, 1:25
F4 F5 F6 F7 F8 F9 F10
S1 S2 S3 S4 S5 S6 S7 S8 S9 S10 S11
F1 F1, 1:5 F1, 1:25 F2 F2, 1:5 F2, 1:25 F3 F3, 1:5 F3, 1:25
F4 F5 F6 F7 F8 F9 F10
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
Account for dilution 1.6 * 5.0 (dilution factor)
= 7.8 mg/mL
Sample Specific Activity Calculation for F1:
mg total protein = volume fraction (from dialysis) * concentration
= 2.7 mL * 8.1 mg/mL
= 22 mg
Specific Activity = Units LDH (from table 2) / mg total protien
= 31 / 22 mg
= 1.4 activity units
Standard Deviation Calculations:
xi yi yl*
(yi-yl) (yi-yl)
2
0.00 0.12 0.080 0.039 0.0015
0.00 0.12 0.080 0.038 0.0014
0.20 0.20 0.17 0.028 0.00081
0.20 0.17 0.17 -0.051 0.0026
0.40 0.25 0.25 0.0010 1.1*10-6
0.40 0.26 0.25 0.0110 0.00012
0.60 0.33 0.34 -0.014 0.00021
0.60 0.39 0.34 0.046 0.0021
0.80 0.43 0.43 0.0073 5.3*10-5
0.80 0.31 0.43 -0.12 0.0131.0 0.52 0.51 0.0089 7.9*10-6
1.0 0.50 0.51 -0.017 0.00029
1.2 0.60 0.60 0.00052 2.7*10-7
1.2 0.58 0.60 -0.015 0.00024
1.4 0.66 0.68 -0.021 0.00044
1.4 0.68 0.68 -0.0019 3.5*10-6
1.6 0.77 0.77 -0.0042 1.8*10-5
1.6 0.74 0.77 -0.027 0.00074
1.8 0.88 0.86 0.025 0.00064
1.8 0.83 0.86 -0.030 0.00088
2.0 1.0 0.94 0.088 0.0077
2.0 0.95 0.94 0.0030 9.0*10-6
SUM = 0.033
SD
*21 = (number of samples -1)
= (0.033/ 21)
= 0.040
Table 6, standard deviation calculations for protein concentration as determined by a BCA-Assay.
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*ylis the absorbance that is expected based on the linear regression. To calculate, the x values were plugged into the
equation y=.43x+.080 and y was solved for.
Example calculation for xi = 0:
yl = .43x+.080
= .43(0)+.080
= .080
Expected absorbance (yl) for 0 protein concentration = .080
Actual absorbance (yi) for 0 protein concentration: 0.12
(yi-yl) = 0.12 - .080
= 0.039
(yi-yl)2 = 0.0392
=0.0015
NATIVE GEL
Figure 2, native gel showing amounts of LDH in various fractions.
The heart LDH seemed to be more prominent in the fractions. Heart LDH was prominent in every fraction
other than F2 and F10. Muscle LDH was only present in F1, F8, F9, and F10. As expected, F8 (which was washed with
a NADH buffer to elute M4LDH) had the highest abundance of muscle LDH. F9 and F10 were also washed with NADH
F1 F2 F3 F4 F5 F6 F7 F8 F9 F10 F1
H4
M4
M3H
M2H2
MH3
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
so it is expected to see muscle isozyme in F9 and F10. The native gel shows dimmer smears in the F9 column and by
F10 they are virtually nonexistent other than a light marking that represents the muscle isozyme. This is because most of
the muscle LDH got eluted off into fractions 8 and 9.
The native gel confirms that heart isozyme has a higher affinity for NAD while muscle isozyme has a higher
affinity for NADH. Fractions 5, 6, and 7 were washed with NAD buffer. These bands are dark and appear where it is
expected to see H4and maybe MH3isozymes. On the other hand, fractions 8, 9, and 10 were washed with NADH buffer.
F8 and F9 contain darker smears where it is expected to see M4isozyme which confirms the affinity of M4for NADH.
Also, light M4bands are seen in the F10 column (which was also washed with NADH), but it is reasonable to conclude
that these bans are light because by the 10thfraction almost all of the LDH has been washed out.
SDS-PAGE
Figure 3, SDS-PAGE gel showing presence of LDH as well as the purity of various fractions.
From the SDS-PAGE, it can be concluded that the final preparation was pure. Bands for other proteins (such as
ovalbumin or lysozyme) clearly showed up in the crude homogenate F1 and the wash fraction (F3). Bands for other
proteins were faint, but nevertheless present in F5, F6, and F7. This lab was concerned with muscle isozyme (which was
expected in F8-F10), and these bands were absent by the time that F8 was eluted. This is indicative of purity in F8 and
F9.
The gel pattern agreed with the LDH standard. It was expected that LDH was seen in F5-F7 (heart LDH) and
F8-F9 (muscle isozyme). There is a clear, thick band in the LDH standard column which also shows up in the F8
column. This band is also present in F5-F7 and F9, although it is much fainter. This faint band suggests that a majority
of the LDH that was present was indeed muscle LDH that had mostly eluded off into F8.
F1 F2 F3 F5 F6 F7 F8 F9 MW std LDH std
Carbonic anhydrase (31 kDa)
Phos hor lase B 97 kDa Serum albumin (66 kDa)
Ovalbumin (45 kDa)
Trypsin inhibitor (21 kDa)
Lysozyme (14 kDa)
LDH
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
Figure 5, a graph of the y-intercepts found in the Lineweaver-Burke plot (figure 4).
Note that 25mM lactate data was excluded because there was likely a problem with dilution due to pipetting accuracy. The intercept
of the 25mM lactate data was inconsistent with the rest of the data and thus excluded.
Figure 6, a graph of the slopes found in the Lineweaver-Burke plot (figure 4).
Note that 25mM lactate data was excluded because there was likely a problem with dilution due to pipetting accuracy. The slope of
the 25mM lactate data was inconsistent with the rest of the data and thus excluded.
y = 26x + 2.2
R = 0.97
0
0.5
1
1.5
2
2.5
3
3.5
0 0 .005 0 .01 0 . 015 0 .02 0 .025 0 .03
Intercept
1/Lactate (mM-1)
INTERCEPT REPLOT (EXCLUDING 25MM
LACTATE)
y = 15x + 0.20
R = 0.98
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0 0 . 0 0 5 0 . 0 1 0 . 0 1 5 0 . 0 2 0 . 0 2 5 0 . 0 3
Slope
1/Lactate (mM-1
)
SLOPE REPLOT (EXCLUDING 25MM
LACTATE)
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Anna Peskin (1020425) Biochemistry 426
Lab Partner: Anthony Cho (Group C5) November 13, 2013
CALCULATIONS EXCLUDING 25MMLACTATE
Kiafor NAD = -(1/x value of interception) = -(1/-1.7) = 0.59 mM
Intercept Replot Equation: y = 26x+2.2
Y-intercept (Vmax-1) = 2.2
NAD Vmax(max rate of product formation)
= 2.2-1
= 0.45 units/30 sec
X-intercept (-Kb-1) = -0.083
Kbfor lactate
(Michaelis constant for lactate)
= (-1.0)(-0.083-1)
= 12 mM
Slope Replot Equation: y = 15x + 0.20
NAD Ka(Michaelis constant for NAD)
= y-intercept of slope replot * Vmax
= 0.20 * .45
= 0.093 mM
DISCUSSION :
The column seemed to work well in general. The activity of LDH was significantly higher in the fractions
which were washed with NADH to elute muscle LDH (when compared to all of the other fractions that were washed
through the column). A high activity in this fraction when compared to other fractions shows that the column efficiently
allowed for separating of muscle LDH. Also, the SDS-PAGE showed no bands that represented contaminate proteins in
F8 and F9. It did, however, show lines that indicated the presence of LDH. From these results, it can be concluded that
the column worked well to purify muscle LDH.
The LDH is purer at the end that in the pure homogenate. Comparing F8F10 to the crude homogenate shows
how many fold the increase in purity was after the homogenate was applied to the column.
F8 16 / 1.4 = 11 fold
F9 12 / 1.4 = 8.6 fold
F10 3.4 / 1.4 = 2.4 fold
It is important to note that throughout this lab F2 showed low activity, low LDH concentrations, and even low
contamination on the SDS-PAGE. It is suspected that F2 was mostly wash buffer left over in the column from when the
column was created rather than actual fraction.
There were some inconsistencies in the data. For example, one of the lines (the line representing 25mM lactate)
on the Lineweaver-Burk plot did not intersect and gave an inconsistent slope and y-intercept. That line was excluded
from the calculations. It is likely that error occurred with that sample because the pipets that were used had less than
perfect accuracy. This caused error to occur when working with very small, diluted samples. It would be ideal to redo
the kinetics experiment for 25mM lactate with a more accurate pipet and see if results differ.
Also, all of the assays showed a low LDH activity in F3-F7. However, the native gel showed dark bands for
heart LDH in F3-F7. This was unexpected for two reasons. First of all, F3-F7 had otherwise consistently showed low
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