ME606 Lect 7-9

Embed Size (px)

Citation preview

  • 8/6/2019 ME606 Lect 7-9

    1/21

    Chemical Kinetics

    Chemical kinetics gives information about how fast thereaction proceeds. Global reactions, as given below,

    are employed to describe the initial and final states.

    22222188 4798)76.3(5.12 NOHCONOHC p

    In reality, these global reactions take place in several

    steps. An elementary reaction is one which can takeplace in a single step.

  • 8/6/2019 ME606 Lect 7-9

    2/21

    Molecularity of a Reaction

    Molecularity of a reaction is the number of moleculesor atoms taking part in each act leading to chemical

    reaction. It is defined for an elementary reaction only.

    N2O5 N2O4 + O2, a unimolecular reaction2HIH2 + I2, is a bimolecular reaction

    CO2 + H2 CO + H2O, is a bimolecular reaction

    2NO + O2

    2NO2, is a termolecular reactionMost reactions are bimolecular, since there is higher

    probability for two molecules to collide.

  • 8/6/2019 ME606 Lect 7-9

    3/21

    Order of a Reaction

    Order of a reaction is the power index of concentrationthat determines the reaction rate.

    Molecularity gives insight into the mechanism of a

    reaction.For the uni-molecular reaction N2O5 N2O4 + O2, the

    rate is given by d[N2O5]/dt = -k1 [N2O5], indicating that

    the reaction is first order.In 2NO22NO + O2, the rate is given by d[NO2]/dt = -

    k2[NO2]2, indicating that the reaction is second order.

  • 8/6/2019 ME606 Lect 7-9

    4/21

    Order of a Reaction

    The reaction between methylamine and ethyl bromine,

    (C2H5)3N + C2H5Br (C2H5)4NBr is second order; its

    rate is d[C2H5Br]/dt = -k2 [C2H5Br] [(C2H5)3N].

    The reaction 2NO + O2 2NO2, is third order as the

    reaction rate depends on concentrations of two NO

    molecules and one oxygen molecule.

    The order for global reaction steps may be fractional;

    for example, d[CH3CHO]/dt = -k [CH3CHO]1.5.

    For elementary reactions order and molecularity are

    usually the same.

  • 8/6/2019 ME606 Lect 7-9

    5/21

    Order of a Reaction

    There are also some zero order reactions. The ratesof these reactions do not depend upon the quantity of

    the unconsumed reactants.

    For hydro-carbons burning in oxygen, the overall order

    of the reaction is known to lie between 1.7 to 2.2; the

    order with respect to oxygen is near unity.

    The order of a reaction being equal to 3 or more is

    very rare, as the probability of 3 molecules to collide at

    the same location is very less.

  • 8/6/2019 ME606 Lect 7-9

    6/21

    Collision theory of reactions

    A

    BC

    VA

    (dA+ dB)

    A + B C

  • 8/6/2019 ME606 Lect 7-9

    7/21

    Collision theory of reactions

    )(BAABddd !

    BAABAB

    AB

    ABCCTnnV

    dZ E

    T

    !

    4

    2

    Consider a cylinder ofdiameterdAB around an A particle

    A

    AB Vd

    4

    2TThe volume covered by the A particle in unit time

    BA

    AB nd

    4

    2T

    !No. of collisions for one A particle with B per sec.

    A

    A

    m

    TV

    O3!Velocity of an A particle

    No. of collisions between A andB per unit vol. per sec.

  • 8/6/2019 ME606 Lect 7-9

    8/21

    Collision theory of reactions

    ? A ? A? ABAA CCk

    dtCd !

    All the ZAB collisions are not fruitful. Only those whichcan provide activation energy for creating active radicals

    will be fruitful.

    RT

    Ea

    AB expNumber of fruitful collisions =

    Finally the rate of a reaction A + B C is given as

    The rate constant k E

    R

    T

    EaexpT1/2

  • 8/6/2019 ME606 Lect 7-9

    9/21

    Collision theory of reactions

    Law ofMass Action: The rate of a reaction isproportional to the product of reactant

    concentrations.

    The proportionality constant (k) is known asthe Rate constant. It is actually a strong

    function of the temperature T.

    BABA

    aACCkCC

    RT

    ETa

    dt

    dC!

    ! exp

  • 8/6/2019 ME606 Lect 7-9

    10/21

    Rate Constant From experimental data, k is usually evaluated in a

    form k = a Tm exp{-Ea/RT}

    Here a is called the pre-exponential factor, m is the

    temperature power index and Ea is the activation

    energy

    Ea

    Qcomb

    E

    t

    H2 H + H

    O2 O + O

    Such active species are

    required for combustionreactions to proceed

  • 8/6/2019 ME606 Lect 7-9

    11/21

    Rate Constant

    In Arrhenius type reactions, k = a exp{-Ea/ RT}. Theterm Tm is usually unimportant and its effect can be

    absorbed in the stronger exponential term.

    Only in low temperature pre-combustion reactions,

    the Tm term may have to be considered.

    ln k

    1/T

    Intercept = ln(a)

    Slope = -Ea/R

  • 8/6/2019 ME606 Lect 7-9

    12/21

    Reaction Rate

    DCBADCBA

    RRRR p

    Consider the reaction

    ? A ? A BABA CCk

    RR

    [ !

    y

    ? A ? A BABA

    D

    D

    C

    C

    B

    B

    A

    A CCkRR

    R

    [

    R

    [

    R

    [

    R

    [

    [ !!!

    !

    !

    yyyy

    y

    For the reactants, the reaction rate is negative and

    for the products it is positive

  • 8/6/2019 ME606 Lect 7-9

    13/21

    Concentration variation with time

    For a first order reaction A B, the rate of

    consumption of A

    ? A ? AAkdtAd ! ? A

    ? Adtk

    A

    Ad !

    ? A ? A }exp{0 ktAA !

    kkt

    693.02ln2/1 !!

    t

    A0

  • 8/6/2019 ME606 Lect 7-9

    14/21

  • 8/6/2019 ME606 Lect 7-9

    15/21

    Concentration variation with time

    For a second order reaction A + B C, let

    there be x moles of C formed. Also, let a

    and b be the initial number of moles of A

    and B present. Then we can write

    dtkxbxa

    dx!

    ))((

    ? A? A? A )()( xbxakBAk

    dt

    dx

    dt

    Cd!!!

    dtkdxxb

    Cdx

    xa

    C!

    )()(21

    Where C1 = -C2 = 1/(b-a)

    321 )ln()ln( CktxbCxaC !

  • 8/6/2019 ME606 Lect 7-9

    16/21

    Concentration variation with time

    For a third order reaction A + B + C D, let

    there be x moles of D formed. Also, let

    a,b and c be the initial number of moles

    of A,B and C present. Then we can write

    dtkxcxbxa

    dx ! ))()((

    ? A? A? A? A ))(()( xcxbxakCBAk

    dt

    dx

    dt

    Dd!!!

    The above equation can be solved using the

    method of partial fractions

  • 8/6/2019 ME606 Lect 7-9

    17/21

    Multi-step Reactions

    OHHOH

    OHHO

    OOO

    HHH

    k

    k

    kk

    kk

    bf

    bf

    2

    ,

    2

    ,2

    4

    3

    22

    11

    p

    p

    pn

    pn

    ? A? A ? A ? A? A ? A? AHOHHOHbHf

    H CCkCCkCkCkdt

    Cd43

    2

    11 22 2 !

  • 8/6/2019 ME606 Lect 7-9

    18/21

    Multi-step Reactions

    For multi-step reactions, a particular species may be

    consumed or produced from more than one reaction

    step and so it is necessary to find the net rate of

    production of each species. For the set of reaction steps shown for the hydrogen-

    oxygen system, six species (H2, O2, H, O, OH and

    H2O) are present and hence a set of six coupled

    ordinary differential equations can be formulated. The coupled set of ODEs can be solved numerically

    by time- marching methods like the Runge- Kutta

    schemes.

  • 8/6/2019 ME606 Lect 7-9

    19/21

    Quasi- steady state assumption

    ReactantsProducts

    Intermediates

    C

    t

    Many intermediate species

    have a short life time and

    they may reach a quasi-

    steady state. That is, thenet reaction rate is equal

    to zero for these species.

    With quasi- steady assumption, the temporal variation of an

    intermediate species can be determined in terms of the other

    species concentrations, by taking the net rate as zero.

  • 8/6/2019 ME606 Lect 7-9

    20/21

    Multi-step Reactions

    A multi- step reaction scheme can be categorized

    as chain- initiation, chain- branching or chain-

    propagation and chain- termination steps.

    Steps like H2 2H are chain initiation steps.

    Steps like H + O OH are chain- branching.

    Steps like OH + H are chain- terminating.

    If the rate at which active species are formed isfaster than chain- termination, an explosive reaction

    will result.

  • 8/6/2019 ME606 Lect 7-9

    21/21

    Chemical Equilibrium

    Consider HHHbf kk pn 11 ,2

    Forward reaction rate ? A2,1 HkR ff !

    Backward reaction rate ? A2

    ,1 HkR bb !

    At chemical equilibrium, forward rate = backward rate

    ? A2,1 HkR ff ! = ? A2

    ,1 HkR bb !

    ? A

    ? A2

    2

    ,1

    ,1

    H

    H

    k

    kK

    b

    f

    eq !! Keq = f(T) only