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May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law

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May 1, 2013

AGENDA:1 – Bell Ringer & Part.

Log2 – Review HW3 – Demo: Boyle’s

Law4 - CN: Charles’ Law5 – Practice Problems6 – Demo: Charles’

Law7 – Work Time

Today’s Goal:Students will be able to

calculate using Charles’ Law.

Homework1. Charles’ Law2. Work from Week 32 is

due by Friday.3. Make up Week 32

Quiz by Friday.

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

5 minutes!

4 MINUTES REMAINING…

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

4 minutes!

3 MINUTES REMAINING…

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

3 minutes!

2 MINUTES REMAINING…

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

2 minutes!

1minute Remaining…

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

1 minute!!!

30 Seconds Remaining…

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

30 seconds!!!

BELL-RINGER TIME IS

UP!

May 1, 2013

AGENDA:1 – Bell Ringer & Part.

Log2 – Review HW3 – Demo: Boyle’s

Law4 - CN: Charles’ Law5 – Practice Problems6 – Demo: Charles’

Law7 – Work Time

Today’s Goal:Students will be able to

calculate using Charles’ Law.

Homework1. Charles’ Law2. Work from Week 32 is

due by Friday.3. Make up Week 32

Quiz by Friday.

Wednesday, May 1

Objective: Students will be able to calculate using Charles’ Law.

Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.

REVIEW

REVIEW HOMEWORK

Kinetic Molecular Theory and Boyle’s Law

Demonstrations of Boyle’s Law

Stay Puft Marshmallow Man in a vacuum… http://www.youtube.com/watch?v=27yqJ9vJ5kQ

What happens to lungs when diving underwater? Underwater demo:

http://www.youtube.com/watch?v=t8wFIMbMJvs Lab explanation demo:

http://www.youtube.com/watch?v=hXnkJNk45Ek

Discussion: How do yourlungs work?

Topic: Charles’ Law Date: 5/1/2013

Charles’ Law = For a given amount of gas at a constant pressure, the VOLUME of the gas is directly related to TEMPERATURE.

So if: T ↑ = V ↑ T ↓ = V ↓

T α V

1. Compare2. Formulat

e3. Support

Temperature

VolumeConsta

nt Pressur

e

Temper-ature

Volu

me

Topic: Charles’ Law Date: 5/1/2013

Variables & Units: V = Volume (mL, L) T = Temperature (K = Kelvin) You must convert °C to K before you calculate further!

To convert degrees Celsius to Kelvin: Temp. in K = °C + 273 Example: What is 25°C in K

temp.?Temp. in K = 25°C + 273Temp. in K = 298 K

1. Compare2. Formulat

e3. Support

Topic: Charles’ Law Date: 5/1/2013

Equation:1. Compare2. Formulat

e3. Support

V1 = V2

T1 T2

V1T2 = V2T1

Notice subscriptsare different on each

side!

Practice Problem

A balloon is at RT (25°C). The volume of the balloon is 2.0L. The balloon is then taken outside to a temperature of -5°C. What is the new volume of the balloon?

3rd Calculate:V1T2 = V2T1

(2)(268)=(V2)(298)

536 = V2(298) 298 298V2 = 536/298

V2 = 1.8L

2nd Determine Variables:V1 =T1 =V2 =T2 =

1st Predict: If T ↓, then V↓.

25°C2.0L

-5°C? = x

+273=298K

+273=268K

Convert to K!

Demonstrations of Charles’ Law Balloon fun with liquid nitrogen…

http://www.youtube.com/watch?v=ZgTTUuJZAFs

Balloon fun with boiling water… http://www.youtube.com/watch?v=GcCmalm

LTiU

Discussion: How do hot air balloons work?