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Mathematics
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FORMULAEFORMULAE
A relation (equation) A relation (equation) between two or more between two or more quantities is called a quantities is called a formulaformula
Literals are used to Literals are used to represent the quantities represent the quantities in a formulain a formula
EXERCISE 6AEXERCISE 6A1)Form a formula for each of the 1)Form a formula for each of the
following:-following:-
(i) Khushi’s weight is 5 kg more (i) Khushi’s weight is 5 kg more than thrice that of Poojathan thrice that of Pooja
SOLUTION:SOLUTION:
Let Khushi weight be a and and Let Khushi weight be a and and Pooja’s weight bPooja’s weight b
Therefore the formula is, a= 5+3b Therefore the formula is, a= 5+3b
(ii) The volume (v) of a cube is (ii) The volume (v) of a cube is equal to the cube of its side (a) equal to the cube of its side (a)
SOLUTION:SOLUTION:
The volume of a cube = the cube The volume of a cube = the cube of its sides of its sides
v = a*a*av = a*a*a
Therefore v = aTherefore v = a33
(iii) The speed (s) of a body equals (iii) The speed (s) of a body equals the distance covered (d) divided the distance covered (d) divided by time (t).by time (t).
SOLUTION:SOLUTION:
We all know that Speed = distanceWe all know that Speed = distance
________________________________________________________________
timetime
Therefore s = d Therefore s = d _______ _______
t t
2)Express each of the following 2)Express each of the following statement in the form of a statement in the form of a formula :-formula :-
(i) A number (p) multiplied by itself (i) A number (p) multiplied by itself twice is equal to another number twice is equal to another number (q)(q)
SOLUTION:SOLUTION:
p*p*p = qp*p*p = q
Therefore ,pTherefore ,p33 = q = q
((ii) A number (a) exceeds ii) A number (a) exceeds another number (b) by 10.another number (b) by 10.
SOLUTION:SOLUTION:
a exceeds b by 10a exceeds b by 10
Therefore, a=b+10Therefore, a=b+10
(iii) The sum of a number (a) (iii) The sum of a number (a) and 1675 is four times and 1675 is four times another number (b)another number (b)
SOLUTION:SOLUTION:
a + 1675 = b+b+b+ba + 1675 = b+b+b+b
Therefore ,a + 1675 =4bTherefore ,a + 1675 =4b
(iv)Vinay is twice as old as (iv)Vinay is twice as old as VijayVijay
SOLUTION:SOLUTION:
Vinay’s age = xVinay’s age = x
Vijay’s age = yVijay’s age = y
Therefore ,a=2y Therefore ,a=2y
3)Make the given variables 3)Make the given variables the subject of the formula:-the subject of the formula:-
(i) C=5 (F – 32(i) C=5 (F – 32)) ______________
99
SOLUTION:SOLUTION:
9/5 C = F9/5 C = F
Therefore ,Therefore ,
F = 9/5 C +32F = 9/5 C +32
(ii) A = P+ PRT(ii) A = P+ PRT ____________________________
100100
Multiply both the sides by 100Multiply both the sides by 100
A-P=PRTA-P=PRT ______________________________
100100
100(A-P)=PRT100(A-P)=PRT
So,R= 100*(A-P)So,R= 100*(A-P) ____________________________________________________________________________
PTPT