MATHEMATICAL LITERACY GRADE 11 TERM 2 JUNE EXAM …

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GRADE 11 TERM 2 MATHEMATICAL LITERACY JUNE EXAM PAPER 1

Duration: 2 hours Marks: 100

Instructions:• Answer ALL the questions in this paper.• Show all calculations.• Where necessary, round off answers to 2 decimal places (unless otherwise stated).• A non-programmable scientific calculator may be used.• Write in BLUE pen only.

QUESTION 11.1. Peter’s Pizzas has a special on Wednesdays where all pizzas are 20% off and all pastas are 1

3 off.

1.1.1. If a Margarita pizza usually sells for R68, how much would you pay for it on a Wednesday? (2)

1.1.2. If a portion of Alfredo pasta sells for R56, how much would you pay for it on a Wednesday? (2)

1.1.3. Susan buys one Margarita and one portion of Alfredo on a Thursday. Calculate how much money she could have saved if she had bought the food on Wednesday. (3)

1.2. Jason got a holiday job doing gardening. He spent a total of 2.5 hours working in one garden. During that time he spent 40 minutes mowing the lawn, 20 minutes trimming hedges, 30 minutes weeding and the rest of the time watering the plants.

1.2.1. How much time (in minutes) was spent watering the plants? (2)

1.2.2. What fraction (in simplest form) of the time was spent trimming hedges? (2)

1.2.3. What percentage of the time was spent mowing the lawn? Round your answer to the nearest whole. (2)

1.3. Debbie has been asked to bake 50 chocolate chip muffins for a school function. Below is the recipe she will use:

Choc chip muffins(makes 36)

700g cake flour200g chocolate chips50ml baking powder

70ml oil800ml milk

4 tbs cocoa powder

Calculate how much of each of the following ingredients Debbie will need to make 50 muffins:

1.3.1. Cake flour (2)

1.3.2. Chocolate chips (2)

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The total cost of ingredients for all 50 muffins is R118.

1.3.3. Calculate the cost price per muffin. (2)

1.3.4. The school wishes to add a 75% mark-up to each muffin. Calculate the selling price of each muffin, to the nearest rand. (2)

1.3.5. Calculate how much profit the school will make if all 50 muffins are sold. (3)

1.4. Lebo and Andrew saw how well the muffins sold at the school function and decide to sell them at the school tuck shop. They calculate their fixed monthly expenses as shown in table 1 below: Table 1

Fixed monthly expensesWater R360Cleaning materials R120Miscellaneous costs R150

1.4.1. Calculate Lebo and Andrew’s fixed monthly costs. (2)

Table 2 below shows the cost of ingredients to make 36 muffins.

Table 2 Ingredients costs for 36 muffins

Flour R22Chocolate chips R17Baking powder R2,10Oil R8,20Milk R9,60Cocoa powder R3,70

They have calculated that they use 5 units (kWh) of electricity to bake 36 muffins. Each unit of electricity costs R1,10.

1.4.2. Calculate the total cost of ingredients for baking 36 muffins. (3)

1.4.3. Calculate the cost of ingredients PER MUFFIN. (2)

1.4.4. Calculate the cost of electricity (in RAND) PER MUFFIN. (2)

1.4.5. Now calculate the total cost per muffin. (2)

Lebo and Andrew decide to sell the muffins for R4,50 each.

1.4.6. How much profit will they make per muffin? Use the formula: profit = selling price – cost price (2)

1.4.7. Calculate this profit per muffin as a percentage. Use the formula: profit per muffin

cost per muffin x 100 = % profit (3)

1.4.8. How many giant muffins must Lebo and Andrew sell to cover their costs and break even? Round off your answer to the nearest whole. Use the formula: total fixed monthly expenses

profit per muffin = number of muffins (3)

[43]



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QUESTION 2Mrs Green’s daughter, Ashleigh, is going to grade 2 at a new school. Below is a map of the school.

2.1. Ashleigh is going to be in Ms Wilson’s class.

2.1.1. On which side of the school is her classroom? (1)

2.1.2. Give Ashleigh directions to her classroom if she enters the school through the front entrance. (2)

2.1.3. Measure the length and breadth of Ashleigh’s classroom, on the map, in centimetres (rounded to the nearest whole). (2)

2.1.4. Use the given scale to calculate the length and breadth (in METRES) of the real life classroom. (4)

2.1.5. Calculate the area of Ashleigh’s classroom in m2. Use the formula A = l x b (2)

2.1.6. How many windows are there in the school? (1)

2.2. Ashleigh starts school at 7:30 am and finishes at 1:00 pm each day. She has two breaks during the school day; first break is 30 minutes long and second break is 20 minutes long. Each lesson is 35 minutes long.

2.2.1. How many hours is the school day? (2)

2.2.2. Convert your previous answer to minutes. (2)

2.2.3. How much time (in minutes) is spent on lessons only? (2)

2.2.4. Now find how many lessons Ashleigh will have in a single day. (3)



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2.3. Ashleigh lives 16km from the school. It takes 20 minutes to get there.

2.3.1. Calculate the average speed at which Ashleigh travels to school. Use the formula. speed = distance

time (3)

2.3.2. At what time should Ashleigh leave her house if she has to be at school at least 15 minutes before lessons begin? (2)

2.3.3. Ashleigh’s mom finds a new route to school with no traffic. She can drive at a steady 80km/h. It takes 15 minutes to get there. Calculate the distance of the new route, using the formula. speed = distance

time (4)

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QUESTION 3

Hennie lives in Cradock and he often travels to Cookhouse and Kommadagga for work.

3.1. Name the national route Hennie uses to travel between Cradock, Cookhouse and Kommadagga. (2)

3.2. How many kilometres does Hennie travel from Cradock to Cookhouse? (2)

3.3. If Hennie continues on to Kommadagga, how many more kilometres does he drive? (2)

3.4. Calculate the total distance Hennie travels on a return journey. (3)



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3.5. In which direction is Jansenville from Cradock? (2)

3.6. If Hennie turns west when he reaches Cradock, what is the first town he will reach? (2)

3.7. There are roadworks between Cookhouse and Middleton which have caused the road to be shut down. Hennie is in Cookhouse and needs to get to his client in Kommadagga. Give him directions for the easiest alternate route from Cookhouse to Kommadagga. (4)

3.8. A distance between two points on the map is 3cm. The real-life distance between these two points is 18km.

3.8.1. Determine the scale used in the form 1: (3)

3.8.2. Use your scale to determine the distance in km between two points with a map distance of 5cm. (3)

3.8.3. If the distance between two places is 48km, calculate what the map distance between these two places would be (in cm). (4)

[27]

GRAND TOTAL: [100]



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MEMORANDUMMarks: 100 Time: 2 hours

Key: M Method

MA Method with accuracyC CalculationS Substitution

SF SimplificationA Answer

RA Rounded answerJ Justification

Question Solution Explanation Marks

1.1.1 0,2 x 68 = R13,60 off 60 – 13,60 = R46,40 for the pizza

1 C

1 A(2)

1.1.2 13 x 56 = R18, 67 off 56 – 18,67 = R37,33

1 C

1 A(2)

1.1.3

Thursday: 68 + 56 = R124

If she had bought Wednesday: 46,40 + 37,33 = R83,73

124 – 83,73 = R40,27 savings

1 A

1 A

1 A

(3)

1.2.12.5 x 60 = 150 minutes total.

150 – 40 – 20 – 30 = 60 minutes watering

1 C

1 A(2)

1.2.2 20150 = 2

15 1 A

1 SF(2)

1.2.340

150 x 100 = 26,66666667

≈ 27%

1 C

1 RA(2)

1.3.1 700 ÷ 36 x 50 = 972 g 1 M

1 A(2)

1.3.2 200 ÷ 36 x 50 = 278 g1 M

1 A(2)

1.3.3 118 ÷ 50 = R2,361 C

1 A(2)

1.3.42,36 + (2,36 x 0,75) = R4,13

≈ R4

1 M

1 RA(2)



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1.3.5

Profit per muffin: 4 – 2,36 = R1,641,64 x 50 = R82 total profit

OR

Total cost: R118 (given)Total income: 50 x 4 = R200 income 200 – 118 = R82 total profit

1 M1 C 1 A

1 M1 C1 A

(3)

(3)

1.4.1 360 + 120 + 150 = R630 1 C

1 A(2)

1.4.2 (22 + 17 + 2,10 + 8,20 + 9,60 + 3,70) = R62,60 for 36 muffins

1 M

1 C

1 A

(3)

1.4.3 62,60 ÷ 36 = R1,74 1 C

1 RA(2)

1.4.45 x 1,1 = R5,50 for all muffins.

5,50 ÷ 36 = R0,15

1 M

1 RA(2)

1.4.5 R1,74 + R0,15 = R1,89 1 C

1 A(2)

1.4.6 Profit = 4,50 – 1,89 = R2,61 1 C

1 A(2)

1.4.72,611,89 x 100 = 138,0952381

≈ 138% profit

1 S

1 C

1 RA

(3)

1.4.86302,61 = 241,3793103

≈ 242 muffins

1 S

1 A

1 RA

(Answer cannot be rounded down, as they will not then break even)

(3)

2.1.1 South side 1 A (1)

2.1.2Turn left at the secretary’s office

Ms Wilson’s classroom is the 3rd on the left 2 A (2)

2.1.3Length: 3,1 cm ≈ 3 cm

Breadth: 2,1 cm ≈ 2 cm

1 RA

1 RA(2)



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2.1.4

3 x 400 = 1 200 cm

1 200 100 = 12 m length

2 x 400 = 800 cm

800 100 = 8 m breadth

1 M

1 A

1 M

1 A

(4)

2.1.5 A = 12 x 8

= 96 m2

1 S

1 A(2)

2.1.6 54 windows 1 A (1)

2.2.1 5 12 hours 2 A (2)

2.2.2 5,5 x 60 = 330 minutes 1 M

1 A(2)

2.2.3 330 – 30 – 20 = 280 minutes 1 M

1 A(2)

2.2.4 280 ÷ 35 = 8 lessons in a day

1 M

1 C

1 A

(3)

2.3.1 speed = 1613

= 48 km / hour

1 S

1 M (time converted to hours)

1 A

(3)

2.3.2 She wants to arrive by 7:15. 7:15 – 20 minutes = 6:55 am

1 M

1 A(2)

2.3.3

distance = speed x time

Distance = 80 x 1560

= 20 km

1 M (correct formula)

1 M (changing time to hours)

1 C

1 A

(4)

3.1. N10 2 A (2)

3.2 36 + 26 + 7 + 13 = 82 km 1 C

1 A(2)

3.3 11 + 37 = 48 km further1 C

1 A(2)

3.4 82 + 48 = 130 km one way

130 x 2 = 260 km total

1 C

1 M

1 A

(3)

3.5 SW 2 A (2)



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3.6 Pearston OR Somerset East 2 A (2)

3.7

Head west to Somerset east.

There, turn south on road 335 to reach Bracefield.

Turn east on road 400.

4 A (can be presented differently, but this is the only route)

(4)

3.8.1

18 x 100 000 = 1 800 000 cm

3:1 800 000

1: 600 000

1 M

1 M

1 A

(3)

3.8.25 x 600 000 = 3 000 000 cm

3 000 000 100 000 = 30 km

1 M

1 C

1 A

(3)

3.8.348 x 100 000 = 4 800 000 cm

4 800 000 600 000 = 8 cm on the map

1 M

1 M

1 C

1 A

(4)


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MATHEMATICAL LITERACY GRADE 11 TERM 2 JUNE EXAM …