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Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 1
NAME OF THE SUBJECT : Engineering Mathematics – I
SUBJECT CODE : MA2111
NAME OF THE METERIAL : Formula Material
MATERIAL CODE : JM08AM1001
(Scan the above Q.R code for the direct download of this material)
Unit – I (Matrices)
1. The Characteristic equation of matrix A is
a) 2
1 20S S if A is 2 X 2 matrix
1
2
Where Sum of the main diagonal elements.S
S A
b) 3 2
1 2 30S S S if A is 3 X 3 matrix
1
2
3
Where Sum of the main diagonal elements.
Sum of the minors of the main diagonal elements.
S
S
S A
2. To find the eigenvectors solve 0A I X .
3. Property of eigenvalues:
Let A be any matrix then
a) Sum of the eigenvalues = Sum of the main diagonal.
b) Product of the eigenvalues = A
c) If the matrix A is triangular then diagonal elements are eigenvalues.
d) If is an eigenvalue of a matrix A, the 1
is the eigenvalue of 1
A .
e) If 1 2, , ...
n are the eigenvalues of a matrix A, then
1 2, , ...
n
m m m are
eigenvalues of mA .( m being a positive integer)
f) The eigenvalues of A & TA are same.
4. Cayley-Hamilton Theorem:
Every square matrix satisfies its own characteristic equation. (ie) 0A I .
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 2
5. Matrix of Q.F
1
2
3
2
1 2 1 3
2
2 1 2 3
2
3 1 3 2
1 1( ) ( ) ( )
2 2
1 1( ) ( ) ( )
2 2
1 1( ) ( ) ( )
2 2
coeff x coeff x x coeff x x
coeff x x coeff x coeff x x
coeff x x coeff x x coeff x
6. Index = p = Number of positive eigenvalues
Rank = r = Number of non-zero rows
Signature = s = 2p-r
7. Diagonalisation of a matrix by orthogonal transformation (or) orthogonal
reduction:
Working Rules:
Let A be any square matrix of order n.
Step:1 Find the characteristic equation.
Step:2 Solve the characteristic equation.
Step:3 Find the eigenvectors.
Step:4 Form a normalized model matrix N, such that the eigenvectors are orthogonal.
Step:5 Find TN .
Step:6 Calculate TD=N AN .
Note:
We can apply orthogonal transformation for symmetric matrix only. If any two eigenvalues are equal then we must use a, b, c method for third eigenvector.
Unit – II (Three Dimensional Analytical Geometry)
1. Equation of the sphere, general form 2 2 22 2 2 0x y z ux vy wz d ,
centre
, ,2 2 2
x coefficient y coefficient z coefficient
,
2
x coefficientu
2
y coefficientv
2
z coefficientw
radius 2 2 2r u v w d .
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 3
2. Equation of the sphere with centre , ,a b c , radius r is
2 2 2 2
x a y b z c r .
3. Equation of the sphere with centre origin and radius r is 2 2 2 2x y z r .
4. Equation of circle:
The curve of intersection of a sphere by a plane is a circle. So, a circle can be represented by two equations, one being the equation of a sphere and the
other that of a plane. Thus, the equation 2 2 22 2 2 0,x y z ux vy wz d
x my nz p taken together represent a circle.
5. Tangent plane:
Equation of tangent plane of sphere at the point 1 1 1, ,x y z is
1 1 11 1 10u x x v y y w z z dxx yy zz .
6. Condition for the plane x my nz p to be a tangent plane to the sphere
2 2 2 2 2 2 2
u mv nw p m n u v w d .
7. Condition for the spheres to cut orthogonally1 2 1 2 1 2 1 2
2 2 2u u v v w w d d .
8. Equation of Right Circular Cone is
2 2 2 22 2 2 2
cosx m y n z m n x y z
9. Equation of Right Circular Cylinder is
2 2 2
2 2 2 2n y m z z n x m x y r m n
If radius is not given
2
2 2 22
2 2 2
x m y n zr x y z
m n
.
Unit – III (Differential Calculus)
1. Curvature of a circle = Reciprocal of it’s radius
2. Radius of curvature with Cartesian form
3
2 21
2
1 y
y
3. Radius of curvature if1
y ,
3
2 21
2
1 x
x
, where 1
dxx
dy
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 4
4. Radius of curvature in implicit form
3
2 22
2 22
x y
xx y xy x y yy x
f f
f f f f f f f
5. Radius of curvature with paramatic form
3
2 2 2x y
x y x y
6. Centre of curvature is ,x y .
7. Circle of curvature is 2 2 2
x x y y .
where 2
1 1
2
1y yx x
y
,
2
1
2
1 yy y
y
8. Evolute: The locus of centre of curvature of the given curve is called evolute of
the curve. 2
1 1
2
1y yx x
y
,
2
1
2
1 yy y
y
9. Envelope: The envelope is a curve which meets each members of a family of
curve.
If the given equation can be rewrite as quadratic equation in parameter, (ie)
20A B C where , , A B C are functions of x and y then the envelope is
24 0B AC .
10. Evolute as the envelope of normals.
Equations Normal equations
24y ax 3
2y xt at at
24x ay 3
2x yt at at
2 2
2 21
x y
a b
2 2
cos sin
ax bya b
2 2
2 21
x y
a b
2 2
sec tan
ax bya b
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 5
2 2 2
3 3 3x y a cos sin cos 2x y a
2xy c 2 3c
y xt ctt
Unit – IV (Functions of several variables)
1. Euler’s Theorem:
If f is a homogeneous function of x and y in degree n , then
(i) f f
x y nfx y
(first order)
(ii) 2 2 2
2 2
2 22 1
f f fx xy y n n f
x x y y
(second order)
2. If ( , , )u f x y z , 1 2 3( ), ( ), ( )x g t y g t z g t then
du u dx u dy u dz
dt x dt y dt z dt
3. If 1 2
( , ), ( , ), ( , )u f x y x g r y g r then
(i) u u x u y
r x r y r
(ii)
u u x u y
x y
4. Maxima and Minima :
Working Rules:
Step:1 Find x
f and y
f . Put 0x
f and 0y
f . Find the value of x and y.
Step:2 Calculate , ,xx xy yy
r f s f t f . Now 2rt s
Step:3 i. If 0 , then the function have either maximum or minimum.
1. If 0r Maximum
2. If 0r Minimum
ii. If 0, then the function is neither Maximum nor Minimum, it is
called Saddle Point.
iii. If 0, then the test is inconclusive.
5. Maxima and Minima of a function using Lagrange’s Multipliers:
Let ( , , )f x y z be given function and ( , , )g x y z be the subject to the condition.
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 6
Form ( , , ) ( , , ) ( , , )F x y z f x y z g x y z , Putting 0x y z
F F F F and
then find the value of x,y,z. Next we can discuss about the Max. and Min.
6. Jacobian:
Jacobian of two dimensions: , ( , )
, ( , )
u v u vJ
x y x y
u u
x y
v v
x y
7. The functions u and v are called functionally dependent if( , )
0( , )
u v
x y
.
8. ( , ) ( , )
1( , ) ( , )
u v x y
x y u v
9. Taylor’s Expansion:
2 2
3 2 2 3
1 1( , ) ( , ) ( , ) ( , ) ( , ) 2 ( , ) ( , )
1! 2!
1 ( , ) 3 ( , ) 3 ( , ) ( , ) ...
3!
x y xx xy yy
xxx xxy xyy yyy
f x y f a b hf a b kf a b h f a b hkf a b k f a b
h f a b h kf a b hk f a b k f a b
where h x a and k y b
Unit – V (Multiple Integrals)
1. 0
( , )b x
af x y dxdy x : a to b and y : o to x (Here the first integral is w.r.t. y)
2. 0
( , )b y
af x y dxdy x : 0 to y and y : a to b (Here the first integral is w.r.t. x)
3. Area R
dxdy (or) R
dydx
To change the polar coordinate
cos
sin
x r
y r
dxdy rdrd
4. Volume V
dxdydz (or)V
dzdydx
GENERAL:
Engineering Mathematics 2013
Prepared by Mr.C.Ganesan, M.Sc.,M.Phil., (Ph: 9841168971) Page 7
1. 1
2 2sin
dx x
aa x
(or) 1
2sin
1
dxx
x
2. 2 2
2 2log
dxx a x
a x
(or) 2
2log 1
1
dxx x
x
3. 1
2 2
1tan
dx x
a x a a
(or) 1
2tan
1
dxx
x
4. 2
2 2 2 2 1 sin
2 2
x a xa x dx a x
a
5. /2 /2
0 0
1 3 2sin cos . ... .1 if is odd and 3
2 3
n n n nx dx x dx n n
n n
6. /2 /2
0 0
1 3 1sin cos . ... . if is even
2 2 2
n n n nx dx x dx n
n n
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 1
SUBJECT NAME : Engineering Mathematics – II
SUBJECT CODE : MA 2161
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08AM1003 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch:
Unit – I (Ordinary Differential Equation) 1. ODE with constant coefficients: Solution C.F + P.Iy
Complementary functions:
Sl.No. Nature of Roots C.F
1. 1 2
m m ( )mx
Ax B e
2. 1 2 3
m m m 2 mxAx Bx c e
3. 1 2
m m 1 2m x m xAe Be
4. 1 2 3
m m m 31 2 m xm x m xAe Be Ce
5. 1 2 3
, m m m 3( )m xmx
Ax B e Ce
6. m i ( cos sin )x
e A x B x
7. m i cos sinA x B x
Particular Integral:
Type-I If ( ) 0f x
then . 0P I
Type-II
If ( )ax
f x e
1.
( )
axP I e
D
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 2
Replace D by a . If ( ) 0D , then it is P.I. If ( ) 0D , then diff. denominator
w.r.t D and multiply x in numerator. Again replace D by a . If you get denominator
again zero then do the same procedure.
Type-III
Case: i If ( ) sin ( ) cosf x ax or ax
1
. sin (or) cos( )
P I ax axD
Here you have to replace only for 2D not for D . 2
D is replaced by 2a . If the
denominator is equal to zero, then apply same procedure as in Type – I.
Case: ii If 2 2 3 3( ) (or) cos (or) sin (or) cosf x Sin x x x x
Use the following formulas 2 1 cos 2
2
xSin x
, 2 1 cos 2
cos2
xx
,
x x x 3 3 1sin sin sin 3
4 4, x x x 3 3 1
cos cos cos 34 4
and separate 1 2
. & .P I P I
Case: iii If ( ) sin cos ( ) cos sin ( ) cos cos ( ) sin sinf x A B or A B or A B or A B
Use the following formulas:
1( ) in cos ( ) sin( )
2
1(ii) cos sin ( ) sin( )
2
1( ) cos cos cos( ) cos( )
2
1( ) sin sin cos( ) cos( )
2
i s A B sin A B A B
A B Sin A B A B
iii A B A B A B
iv A B A B A B
Type-IV
If ( ) mf x x
1
.( )
mP I xD
1
1 ( )
mxg D
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 3
1
1 ( ) mg D x
Here we can use Binomial formula as follows:
i) 1 2 31 1 ...x x x x
ii) 1 2 31 1 ...x x x x
iii) 2 2 31 1 2 3 4 ...x x x x
iv) 2 2 31 1 2 3 4 ...x x x x
v) 3 2 3(1 ) 1 3 6 10 ...x x x x
vi) 3 2 3(1 ) 1 3 6 10 ...x x x x
Type-V
If ( ) axf x e V where sin ,cos , mV ax ax x
1
.( )
axP I e VD
First operate axe by replacing D by D+a.
1
( )
axe VD a
Type-VI
If ( ) nf x x V where sin ,cosV ax ax
sin I.P of
cos R.P of
iax
iax
ax e
ax e
Type-VII (Special Type Problems) If ( ) sec (or) cosec (or) tanf x ax ax ax
1
. ( ) ( )ax axP I f x e e f x dxD a
1. ODE with variable co-efficient: (Euler’s Method)
The equation is of the form 2
2
2( )
d y dyx x y f x
dx dx
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 4
Implies that 2 2( 1) ( )x D xD y f x
To convert the variable coefficients into the constant coefficients
Put logz x implies zx e
2 2
3 3
( 1)
( 1)( 2)
xD D
x D D D
x D D D D
where d
Ddx
and d
Ddz
The above equation implies that ( 1) 1 ( )D D D y f x which is O.D.E
with constant coefficients.
2. Legendre’s Linear differential equation:
The equation if of the form 2
2
2( ) ( ) ( )
d y dyax b ax b y f x
dx dx
Put log( )z ax b implies ( ) zax b e
2 2 2
3 3 3
( )
( ) ( 1)
( ) ( 1)( 2)
ax b D aD
ax b D a D D
ax b D a D D D
where d
Ddx
and d
Ddz
3. Method of Variation of Parameters:
The equation is of the form d y dy
a b cy f xdx dx
2
2( )
1 2.C F Ay By and
1 2.P I Py Qy
where 2
1 2 1 2
( )y f xP dx
y y y y
and
1
1 2 1 2
( )y f xQ dx
y y y y
Unit – II (Vector Calculus)
1. Vector differential operator is / / /i x j y k z
2. Gradient of / / /i x j y k z
3. Divergence of F F
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 5
4. Curl of F
1 2 3
/ / /
i j k
XF x y z
F F F
5. If F is Solenoidal vector then 0F
6.
7. If F is Irrotational vector the 0XF
8. Maximum Directional derivative
9. Directional derivative of in the direction of a a
a
10. Angle between two normals to the surface 1 2
1 2
cosn n
n n
Where 1 1 1
1 1 ( , , )at x y zn &
2 2 22 2 ( , , )at x y z
n
11. Unit Normal vector, n
12. Equation of tangent plane 1 1 1( ) ( ) ( ) 0l x x m y y n z z
Where l, m,n are coefficient of , ,i j k in .
13. Equation of normal line
1 1 1x x y y z z
l m n
14. Work Done = C
F dr , where dr dxi dyj dzk
15. If .C
F dr be independent of the path is that curl 0F
16. In the surface integral ˆ.
dxdydS
n k ,
ˆ.
dydzdS
n i ,
ˆ.
dzdxdS
n j & ˆdS ndS
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 6
17. Green’s Theorem:
If , , ,u v
u vy x
are continuous and one-valued functions in the region R enclosed
by the curve C, then C R
v uudx vdy dxdy
x y
.
18. Stoke’s Theorem:
Let F be the vector point function, around a simple closed curve C and over the
open surface S having as its boundary, then ˆxC S
F dr F nds
19. Gauss Divergence Theorem:
Let F be a vector point function in a region R bounded by a closed surface S,
then ˆS V
F nds Fdv
Unit – III (Analytic Function)
1. Necessary condition for f(z) is analytic function
Cauchy – Riemann Equations: & u v v u
x y x y
(C-R equations)
2. Polar form of Cauchy-Riemann Equations: 1 1
& u v v u
r r r r
3. Condition for Harmonic function: 2 2
2 20
u u
x y
4. If the function is harmonic then it should be either real or imaginary part of a
analytic function.
5. Milne – Thomson method: (To find the analytic function f(z))
i) If u is given ( ) ( ,0) ( ,0)x yf z u z iu z dz
ii) If v is given ( ) ( ,0) ( ,0)y xf z v z iv z dz
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 7
6. To find the analytic function
i) ( ) ; ( )f z u iv if z iu v adding these two
We have ( ) ( ) (1 ) ( )u v i u v i f z
then ( )F z U iV where , & ( ) (1 ) ( )U u v V u v F z i f z
Here we can apply Milne – Thomson method for F(z).
7. Bilinear transformation:
1 2 3 1 2 3
1 2 3 1 2 3
w w w w z z z z
w w w w z z z z
Unit – IV (Complex Integration)
1. Cauchy’s Integral Theorem:
If f(z) is analytic and ( )f z is continuous inside and on a simple closed curve C,
then ( ) 0c
f z dz .
2. Cauchy’s Integral Formula:
If f(z) is analytic within and on a simple closed curve C and 0z is any point inside
C, then ( )
2 ( )C
f zdz if a
z a
3. Cauchy’s Integral Formula for derivatives:
If a function f(z) is analytic within and on a simple closed curve C and a is any
point lying in it, then
2
1 ( )( )
2C
f zf a dz
i z a
Similarly
3
2! ( )( )
2C
f zf a dz
i z a
, In general
( )
1
! ( )( )
2
n
n
C
n f zf a dz
i z a
4. Cauchy’s Residue theorem:
If f(z) be analytic at all points inside and on a simple closed cuve c, except for a
finite number of isolated singularities 1 2 3, , ,... nz z z z inside c, then
( ) 2 (sum of the residues of ( ))C
f z dz i f z .
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 8
5. Critical point:
The point, at which the mapping w = f(z) is not conformal, (i.e) ( ) 0f z is called
a critical point of the mapping.
6. Fixed points (or) Invariant points:
The fixed points of the transformation az b
wcz d
is obtained by putting w = z in
the above transformation, the point z = a is called fixed point.
7. Re { ( )} ( ) ( )z a
s f z Lt z a f z
(Simple pole)
8. 1
1
1Re { ( )} ( )
( 1)!
mm
mz a
ds f z Lt z a f z
m dz
(Multi Pole (or) Pole of order m)
9. ( )
Re { ( )}( )z a
P zs f z Lt
Q z
10. Taylor Series:
A function ( )f z , analytic inside a circle C with centre at a, can be expanded in
the series
2 3( )( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ... ( ) ...1! 2! 3! !
nnz a z a z a z a
f z f a f a f a f a f an
Maclaurin’s Series:
Taking a = 0, Taylor’s series reduce to
2 3
( ) (0) (0) (0) (0) ...1! 2! 3!
z z zf z f f f f
11. Laurent’s Series: 0 1
( ) ( )( )
n nn n
n n
bf z a z a
z a
where 1
1
1 ( )
2 ( )n n
C
f za dz
i z a
& 2
1
1 ( )
2 ( )n n
C
f zb dz
i z a
, the integrals being
taken anticlockwise.
12. Isolated Singularity:
A point 0z z is said to be isolated singularity of ( )f z if ( )f z is not analytic at
0z z and there exists a neighborhood of 0z z containing no other singularity.
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 9
Example: 1
( )f zz
. This function is analytic everywhere except at 0z .
0z is an isolated singularity.
13. Removable Singularity:
A singular point 0z z is called a removable singularity of ( )f z if
0
lim ( )f z
z z
exists finitely.
Example: sin
lim ( ) lim 1
0 0
zf z
z
z z
(finite) 0z is a removable
singularity.
14. Essential Singularity:
If the principal part contains an infinite number of non zero terms, then 0z z is
known as a essential singularity.
Example:
21 1/1/( ) 1 ...
1! 2!z
zzf z e has 0z as an essential
singularity.
CONTOUR INTEGRATION:
15. Type: I
The integrals of the form 2
0(cos ,sin )f d
Here we shall choose the contour
as the unit circle : 1 or ,0 2iC z z e . On this type 2 1
cos2
z
z
,
2 1sin
2
z
iz
and
1d dz
iz .
16. Type: II
Improper integrals of the form ( )
( )
P xdx
Q x
, where P(x) and Q(x) are polynomials
in x such that the degree of Q exceeds that of P at least by two and Q(x) does not
vanish for any x. Here ( ) ( ) ( )
R
C R
f z dz f x dx f z dz
as ( ) 0R f z dz
.
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 10
17. Type: III
The integrals of the form ( ) cos (or) ( )sinf x mxdx f x mxdx
where
( ) 0 as f x x .
Unit – V (Laplace Transform)
1. Definition: 0
( ) ( )stL f t e f t dt
2.
Sl.No
1. 1L 1
s
2. nL t
1 1
! ( 1)n n
n n
s s
3. atL e
1
s a
4. atL e
1
s a
5. sinL at 2 2
a
s a
6. cosL at 2 2
s
s a
7. sinhL at 2 2
a
s a
8. coshL at 2 2
s
s a
3. Linear Property: ( ) ( ) ( ) ( )L af t bg t aL f t bL g t
4. First Shifting property:
If ( ) ( )L f t F s , then
i) ( ) ( )at
s s aL e f t F s
ii) ( ) ( )at
s s aL e f t F s
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 11
5. Second Shifting property:
If ( ) ( )L f t F s , ( ),
( )0,
f t a t ag t
t a
then ( ) ( )asL g t e F s
6. Change of scale:
If ( ) ( )L f t F s , then 1
( )s
L f at Fa a
7. Transform of derivative:
If ( ) ( )L f t F s , then ( ) ( )d
L tf t F sds
, 2
2
2( ) ( )
dL t f t F s
ds ,
In general ( ) ( 1) ( )n
n n
n
dL t f t F s
ds
8. Transform of Integral;
If ( ) ( )L f t F s , then 1
( ) ( )s
L f t F s dst
9. Initial value Theorem:
If ( ) ( )L f t F s , then ( ) ( )
0 s
Lt f t Lt sF s
t
10. Final value Theorem:
If ( ) ( )L f t F s , then ( ) ( )
s 0
Lt f t Lt sF s
t
11.
Sl.No
1. 1 1
Ls
1
2. 1 1
Ls a
ate
3. 1 1
Ls a
ate
4. 1
2 2
sL
s a
cos at
5. 1
2 2
1L
s a
1
sin ata
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 12
6. 1
2 2
sL
s a
cosh at
7. 1
2 2
1L
s a
1
sinh ata
8. 1 1
nL
s
1
( 1)!
nt
n
12. Deriative of inverse Laplace Transform:
1 11( ) ( )L F s L F s
t
13. Colvolution of two functions: 0
( ) ( ) ( ) ( )
t
f t g t f u g t u du
14. Covolution theorem:
If f(t) & g(t) are functions defined for 0t then ( ) ( ) ( ) ( )L f t g t L f t L g t
15. Convolution theorem of inverse Laplace Transform:
1 1 1( ) ( ) ( ) ( )L F s G s L F s L G s
16. Solving ODE for second order differential equations using Laplace Transform
i) ( ) ( ) (0)L y t sL y t y
ii) 2( ) ( ) (0) (0)L y t s L y t sy y
iii) 3 2( ) ( ) (0) (0) (0)L y t s L y t s y sy y take ( )y L y t
17. Solving integral equation: 0
1( ) ( )
t
L y t dt L y ts
18. Inverse Laplace Transform by Contour Integral method
1 1( ) ( )
2
st
c
L F s F s e dsi
19. Periodic function in Laplace Transform:
If f(x+T) = f(x), then f(x) is periodic function with period T.
0
1( ) ( )
1
Tst
sTL f t e f t dt
e
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SUBJECT NAME : Transforms and Partial Diff. Eqns.
SUBJECT CODE : MA2211
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08AM3005 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch: Unit – I (Fourier Series)
1) Dirichlet’s Conditions:
Any function ( )f x can be expanded as a Fourier
series 0
1 1
cos sin2
n n
n n
aa nx b nx
where 0, ,
n na a b are constants provided the
following conditions are true. ( )f x is periodic, single – valued and finite.
( )f x has a finite number of discontinuities in any one period.
( )f x has at the most a finite number of maxima and minima.
2) The Fourier Series in the interval (0,2π):
0
1 1
( ) cos sin2
n n
n n
af x a nx b nx
Where 2
0
0
1( )a f x dx
,
2
0
1( )cos
na f x nxdx
,
2
0
1( )sin
nb f x nxdx
3) The Fourier Series in the interval (-π,π):
0
1 1
( ) cos sin2
n n
n n
af x a nx b nx
Where 0
0
2( )a f x dx
,
0
2( )cos
na f x nxdx
,
0
2( )sin
nb f x nxdx
In this interval, we have to verify the function is either odd function or
even function. If it is even function then find only 0 and
na a ( 0
nb ). If it is odd
function then find only n
b (0
0n
a a ).
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If the function is neither odd nor even then you should find
0, and
n na a b by using the following formulas
0
1( )a f x dx
,
1( )cos
na f x nxdx
, 1
( )sinn
b f x nxdx
.
4) The half range Fourier Series in the interval (0,π):
The half range Cosine Series in the interval (0,π):
0
1
( ) cos2
n
n
af x a nx
Where 0
0
2( )a f x dx
,
0
2( )cos
na f x nxdx
The half range Sine Series in the interval (0,π):
1
( ) sinn
n
f x b nx
Where 0
2( )sin
nb f x nxdx
5) The Parseval’s Identity in the interval (0,2π): 2 2
2 2 20
10
1[ ( )] [ ]
4n n
n
af x dx a b
6) The Parseval’s Identity in the interval (-π,π): 2
2 2 20
10
2[ ( )] [ ]
4n n
n
af x dx a b
7) The Parseval’s Identity for half range cosine series in the interval (0,π): 2
2 20
10
2[ ( )]
4n
n
af x dx a
8) The Parseval’s Identity for half range sine series in the interval (0,π):
2 2
10
2[ ( )]
n
n
f x dx b
Change of interval:
9) The Fourier Series in the interval (0,2ℓ):
0
1 1
( ) cos sin2
n n
n n
a n x n xf x a b
Where 2
0
0
1( )a f x dx ,
2
0
1( )cos
n
n xa f x dx
,
2
0
1( )sin
n
n xb f x dx
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10) The Fourier Series in the interval (-ℓ, ℓ):
0
1 1
( ) cos sin2
n n
n n
a n x n xf x a b
Where 0
0
2( )a f x dx ,
0
2( )cos
n
n xa f x dx
,
0
2( )sin
n
n xb f x dx
In this interval, you have to verify the function is either odd function or even
function. If it is even function then find only 0 and
na a ( 0
nb ). If it is odd
function then find only n
b (0
0n
a a ).
11) The half range Fourier Series in the interval (0, ℓ):
The half range Cosine Series in the interval (0, ℓ):
0
1
( ) cos2
n
n
a n xf x a
Where 0
0
2( )a f x dx ,
0
2( )cos
n
n xa f x dx
The half range Sine Series in the interval (0, ℓ):
1
( ) sinn
n
n xf x b
Where 0
2( )sin
n
n xb f x dx
12) The Parseval’s Identity in the interval (0,2ℓ):
2 2
2 2 20
10
1[ ( )] [ ]
4n n
n
af x dx a b
13) The Parseval’s Identity in the interval (-ℓ,ℓ): 2
2 2 20
10
2[ ( )] [ ]
4n n
n
af x dx a b
14) The Parseval’s Identity for half range cosine series in the interval (0,ℓ): 2
2 20
10
2[ ( )]
4n
n
af x dx a
15) The Parseval’s Identity for half range sine series in the interval (0,ℓ):
2 2
10
2[ ( )]
n
n
f x dx b
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16) Harmonic Analysis: The method of calculation of Fourier constants by means of numerical
calculation is called as Harmonic analysis.
0
1 1
( ) cos sin2
n n
n n
af x a nx b nx
where
0 1 2 3
2 2 2 2 , cos , cos 2 , cos 3 , ...a y a y x a y x a y x
n n n n
1 2 3
2 2 2sin , b sin 2 , b sin 3 , ...b y x y x y x
n n n
When the values of x is given as numbers the is calculated by 2 x
T
.
Where T is period, n is the number of values given. If the first and last y values are same we can omit one of them.
Complex form of Fourier Series: 17) The Complex form of Fourier Series in the interval (0,2π):
( )inx
n
n
f x c e
where2
0
1( )
2
inx
nc f x e dx
18) The Complex form of Fourier Series in the interval (-π,π):
( )inx
n
n
f x c e
where1
( )2
inx
nc f x e dx
19) The Complex form of Fourier Series in the interval (0,2ℓ):
( )
in x
n
n
f x c e
where2
0
1( )
2
in x
nc f x e dx
20) The Complex form of Fourier Series in the interval (-ℓ,ℓ):
( )
in x
n
n
f x c e
where1
( )2
in x
nc f x e dx
Unit – II (Fourier Transforms)
1) Fourier Integral theorem
The Fourier integral theorem of ( )f x in the interval , is
0
1( ) ( )cos ( )f x f x t dxd
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2) Convolution Theorem If [ ]F s and [ ]G s are the Fourier transform of the functions ( )f x and
( )g x respectively, then [ ( )* ( )] .F f x g x F s G s
3) The Fourier Transform of a function ( )f x is given by [ ( )]F f x is denoted by
[ ]F s .
4) Fourier Transform 1
[ ] [ ( )] ( )2
isxF s F f x f x e dx
5) Inverse Fourier Transform 1
( ) [ ]2
isxf x F s e ds
6) The Fourier transforms and Inverse Fourier transforms are called Fourier transforms pairs.
7) Fourier Sine Transform 0
2[ ] [ ( )] ( )sin
s sF s F f x f x sx dx
8) Fourier Cosine Transform 0
2[ ] [ ( )] ( )cos
c cF s F f x f x sx dx
9) If ( )ax
f x e then the Fourier Cosine and Sine transforms as follows
a) 2 2
2[ ( )]
c
aF f x
a s
b) 2 2
2[ ( )]
s
sF f x
a s
10) Property
a) [ ( )] [ ( )]s c
dF xf x F f x
ds
b) [ ( )] [ ( )]c s
dF xf x F f x
ds
11) Parseval’s Identity
a) 2 2
( ) ( )F s ds f x dx
b) 0 0
( ) ( ) ( ) ( )c c
F s G s ds f x g x dx
(Or) 2 2
0 0
( ) ( )c
F s ds f x dx
12) Condition for Self reciprocal [ ( )] ( )F f x f s
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Unit – III (Partial Differential Equation) 1) Lagrange’s Linear equation
The equation of the form Pp Qq R
then the subsidiary equation is dx dy dz
P Q R
2) Homogeneous Linear Partial Differential Equation of higher order with constant
coefficients:
The equation of the form 2 2 2
2 2( , )
z z za b c f x y
x x y y
The above equation can be written as
2 2( , )aD bDD cD z f x y …………………………….. (1)
where2
2
2 , D D
x x
and 2
2
2 , D D
y y
The solution of above equation is z = C.F + P.I Complementary Function (C.F) :
To find C.F consider the auxiliary equation by replacing D by m and D by
1.The equation (1) implies that 20am bm c , solving this equation
we get two values of m. The following table gives C.F of the above equation.
Sl.No. Nature of m Complementary Function
1 1 2m m
1 1 2 2C.F = ( ) ( )f y m x f y m x
2 1 2m m
1 2C.F = ( ) ( )f y mx xf y mx
3 1 2 3m m m
1 1 2 2 3 3C.F = ( ) ( ) ( )f y m x f y m x f y m x
4 1 2 3m m m 2
1 2 3C.F = ( ) ( ) ( )f y mx xf y mx x f y mx
5 1 2 3, is differentm m m
1 2 3 3C.F = ( ) ( ) ( )f y mx xf y mx f y m x
Particular Integral (P.I) :
To find P.I consider 2 2( , )D D aD bDD cD .
Type: 1 If ( , ) 0f x y , then P.I 0 .
Type: 2 If ( , )ax by
f x y e
1.
( , )
ax byP I e
D D
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Replace D by a and D by b. If ( , ) 0D D , then it is P.I.
If ( , ) 0D D , then diff. denominator w.r.t D and multiply x in
numerator. Again replace D by a and D by b. If again denominator equal to zero then continue the same procedure.
Type: 3 If ( , ) sin( ) (o ) cos( )f x y ax by r ax by
1. sin( ) (o ) cos( )
( , )P I ax by r ax by
D D
Here replace 2D by 2
a , 2D by 2
b and DD by ab . Do not replace for and D D . If the denominator equal to zero, then apply the same producer as in Type: 2.
Type: 4 If ( , )m n
f x y x y
1.
( , )
m nP I x y
D D
1
1 ( , )
m nx y
g D D
1
1 ( , )m n
g D D x y
Here we can use Binomial formula as follows:
i) 1 2 3
1 1 ...x x x x
ii) 1 2 3
1 1 ...x x x x
iii) 2 2 3
1 1 2 3 4 ...x x x x
iv) 2 2 3
1 1 2 3 4 ...x x x x
v) 3 2 3(1 ) 1 3 6 10 ...x x x x
vi) 3 2 3(1 ) 1 3 6 10 ...x x x x
Type: 5 If ( , ) Vax by
f x y e , where
V=sin( ) (or) cos( ) (or) m n
ax by ax by x y
1. V
( , )
ax byP I e
D D
First operate ax bye
by replacing D by D a and Dby D a .
1. V
( , )
ax byP I e
D a D b
, Now this will either Type: 3 or
Type: 4.
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Type: 6 If ( , ) sin (or) cosf x y y ax y ax
1. sin
( , )P I y ax
D D
1 2
1 siny ax
D m D D m D
2y c m x
2
1
1 sin c m x ax dx
D m D
(Apply Bernouili’s method)
3) Solution of Partial Differential Equations:
Standard Type: 1 Equation of the form ( , ) 0f p q
Assume that z ax by c be the solution the above
equation.put and p a q b in equation (1), we get
( , ) 0f a b . Now, solve this, we get ( )b a .
( )z ax a y c which is called Complete solution.
Standard Type: 2 Equation of the form ( , )z px qy f p q (Clairaut’s form)
The Complete solution is ( , )z ax by f a b . To find
Singular integral diff. partially w.r.t a & b , equate to zero
and eliminate a and b .
Standard Type: 3 Equation of the form 1 2( , ) ( , )f x p f y q
The solution is z pdx qdy .
Standard Type: 4 Equation of the form ( , , ) 0f z p q
In this type put u x ay , then ,dz dz
p q adu du
Unit – IV (Application of Partial Differential Equation) 1) The One dimensional Wave equation:
2 2
2
2 2
y ya
t x
The three solutions of the above equation are
i) ( , )px px pat pat
y x t Ae Be Ce De
ii) ( , ) cos sin cos siny x t A px B px C pat D pat
iii) ( , )y x t Ax B Ct D
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But the correct solution is ii),
( , ) cos sin cos siny x t A px B px C pat D pat .
2) The One dimensional Heat flow equation: 2
2
2
u u
t x
2 k
c
where
Thermal Conductivity
Density
Specific Heat
k
c
The three solutions of the above equation are
i) 2 2
( , )px px p t
u x t Ae Be Ce
ii) 2 2
( , ) cos sinp t
u x t A px B px Ce
iii) ( , )u x t Ax B C
But the correct solution is ii), 2 2
( , ) cos sinp t
u x t A px B px Ce
3) The Two dimensional Heat flow equation: 2 2
2 20
u u
x y
The three solutions of the above equation are
i) ( , ) cos sinpx px
u x y Ae Be C py D py
(Applicable when given value is parallel to y-axies)
ii) ( , ) cos sinpy py
u x y A px B px Ce De
(Applicable when given value is parallel to x-axies)
iii) ( , )u x y Ax B Cy D (Not applicable)
Unit – V (Z - Transform)
1) Definition of Z-transform:
Let ( )f n be the sequence defined for all the positive integers n such that
0
( ) ( )n
n
Z f n f n z
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2)
Sl.No ( )Z f n [ ]F z
1. 1Z 1
z
z
2. ( 1)n
Z 1
z
z
3. n
Z a z
z a
4. Z n
21
z
z
5. 1Z n
2
21
z
z
6. 1
Zn
log1
z
z
7. sin2
nZ
2
1
z
z
8. cos2
nZ
2
21
z
z
3) Statement of Initial value theorem:
If ( ) [ ]Z f n F z , then 0
[ ] ( )z nLt F z Lt f n
4) Statement of Final value theorem:
If ( ) [ ]Z f n F z , then 1
( ) ( 1) ( )n zLt f n Lt z F z
5) ( ) ( )n
zz
a
Z a f n Z f n
6) ( ) ( )d
Z nf n z Z f ndz
7) Inverse Z-transform
Sl.No 1( )Z F z
( )f n
1. 1
1
zZ
z
1
2. 1
1
zZ
z
( 1)
n
3. 1 z
Zz a
n
a
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4. 1 z
Zz a
na
5.
1
21
zZ
z
n
6.
1
2
zZ
z a
1nna
7.
1
2
zZ
z a
1n
n a
8.
2
1
21
zZ
z
cos
2
n
9.
2
1
2 2
zZ
z a
cos
2
n na
10. 1
21
zZ
z
sin2
n
11. 1
2 2
zZ
z a
1
sin2
n na
8) Inverse form of Convolution Theorem
1 1 1[ ( ). ( )] [ ( )] [ ( )]Z F z G z Z F z Z G z
and by the defn. of Convolution of two functions 0
( ) ( ) ( ) ( )n
r
f n g n f r g n r
9) a) [ ( )] ( )Z y n F z
b) [ ( 1)] ( ) (0)Z y n zF z zy
c) 2 2[ ( 2)] ( ) (0) (1)Z y n z F z z y zy
d) 3 3 2[ ( 3)] ( ) (0) (1) (2)Z y n z F z z y z y zy
----All the Best----
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SUBJECT NAME : Numerical Methods
SUBJECT CODE : MA 2262
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08AM1015 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch:
UNIT – 1
1. Regula Falsi method: 1
( ) ( )
( ) ( )
af b bf ax
f b f a
2. Newton’s method (0r) Newton-Raphson method:1 /
( )
( )n
n n
n
f xx x
f x
3. Fixed point iteration (or) Iterative formula (or) Simple iteration method
( )1
x g xn n
, ( )where x g x
4. The rate of convergence in N-R method is of order 2.
5. Condition for convergence of N-R method is 2// /( ) ( ) ( )f x f x f x
6. Condition for the convergence of iteration method is /( ) 1g x
7. Gauss elimination & Gauss-Jordon are direct methods and Gauss-Seidal and
Gauss-Jacobi are iterative methods.
8. Power method, To find numerically largest eigen value 1n nY AX
UNIT – 2
1. Lagrange’s interpolation formula is
0 2 0 1 11 20 1
0 1 0 2 0 1 0 1 2 1 0 1 1
( )( )...( ) ( )( )...( )( )( )...( )( ) ...
( )( )...( ) ( )( )...( ) ( )( )...( )n nn
n
n n n n n n
x x x x x x x x x x x xx x x x x xy f x y y y
x x x x x x x x x x x x x x x x x x
2. Inverse of Lagrange’s interpolation formula is
0 2 0 1 11 20 1
0 1 0 2 0 1 0 1 2 1 0 1 1
( )( )...( ) ( )( )...( )( )( )...( )( ) ...
( )( )...( ) ( )( )...( ) ( )( )...( )n nn
n
n n n n n n
y y y y y y y y y y y yy y y y y yx f y x x x
y y y y y y y y y y y y y y y y y y
3. Newton’s divided difference interpolation formula is 2
( ) ( ) ( ) ( ) ( )( ) ( ) ...0 0 0 0 1 0f x f x x x f x x x x x f x
4. Newton’s forward difference formula is
2 3
0 0 0 0
( 1) ( 1)( 2)( ) ...
1! 2! 3!
u u u u u uy x y y y y
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where 0x xu
h
5. Newton’s backward difference formula is
2 3( 1) ( 1)( 2)( ) ...
1! 2! 3!n n n n
v v v v v vy x y y y y
where x xnvh
6. Interpolation with a cubic spline
1 1 1 12
64 2i i i i i iM M M y y y
h
23 3
1 1 1 1
1 1( ) ( ) ( ) ( )
6 6i i i i i i i
hS x x x M x x M x x y M
h h
2
1
1( )
6i i i
hx x y M
h
1,2,...( 1) and xi-1for i n x xi
UNIT – 3
1. Newton’s forward formula to find the derivatives 2
2 3
0 0 0
1 2 1 3 6 2...
2 6
dy u u uy y y
dx h
2 22 3 4
0 0 02 2
1 6 18 11( 1) ...
12
d y u uy u y y
dx h
3
3 4
0 03 3
1 12 18...
12
d y uy y
dx h
where 0x x
uh
2. Newton’s forward formula to find the derivatives at 0x x
2 3
0 00
0
1...
2 3X X
y ydyy
dx h
22 3 4
0 0 02 2
0
1 11...
12X X
d yy y y
dx h
33 4
0 03 3
0
1 3...
2X X
d yy y
dx h
3. Newton’s backward formula to find the derivatives 2
2 31 2 1 3 6 2...
2 6n n n
dy v v vy y y
dx h
2 22 3 4
2 2
1 6 18 11( 1) ...
12n n n
d y v vy v y y
dx h
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33 4
3 3
1 12 18...
12n n
d y vy y
dx h
where nx x
vh
4. Newton’s backward formula to find the derivatives at nx x
2 31...
2 3n n
n
X Xn
dy y yy
dx h
22 3 4
2 2
1 11...
12n n n
X Xn
d yy y y
dx h
33 4
3 3
1 3...
2n n
X Xn
d yy y
dx h
5. Trapezoidal Rule
0
0 1 2 3
0
( ) 2 ...2
x nh
n
x
hf x dx y y y y y
6. Simpson’s 1/3rd Rule
0
0 1 3 5 2 4 6
0
( ) 4 ... 2 ...3
x nh
n
x
hf x dx y y y y y y y y
7. Simpson’s 3/8th Rule
0
0 1 2 4 5 7 3 6 9
0
3( ) 3 ... 2 ...
8
x nh
n
x
hf x dx y y y y y y y y y y
8. Romberg’s formula for 1 2 & is
2 12
3
9. Error is the Trapezoidal formula is of the order 2h and in the Simpson formula is
of the order4h .
10. Two points Gaussian Quadrature formula 1
1
1 1( )
3 3f x dx f f
11. Three points Gaussian Quadrature formula 1
1
5 3 3 8( ) (0)
9 5 5 9f x dx f f f
12. If the range is not 1 ,1 then the idea to solve the Gaussian Quadrature
problem is 2 2
b a b ax z
UNIT – 4
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1. Taylor Series method 2 3
/ // ///
1 0 0 0 0 0( ) ...1! 2! 3!
h h hy y x h y y y y
and 2 3
/ // ///
2 1 1 1 1 1( ) ...1! 2! 3!
h h hy y x h y y y y
2. Euler’s method
If 0 0( , ); ( )
dyf x y y x y
dx
then 0 0 0 0( ) ( , )y x h y hf x y
and 1 1 1 1( ) ( , )y x h y hf x y
3. Modified Euler’s method
If 0 0( , ); ( )
dyf x y y x y
dx
then ( ) , ( , )0 0 0 00 0 2 2 h h
y x h y h x y f x yf
And ( ) , ( , )1 1 1 11 1 2 2 h h
y x h y h x y f x yf
4. Runge-kutta method of fourth order
First formula:
1 0 0( , )k hf x y 23 0 0,
2 2
h kk hf x y
12 0 0,
2 2
h kk hf x y
4 0 0 3,k hf x h y k
and 1 2 3 4
12 2
6y k k k k & 0 0( )y x h y y
For the second formula, replace 0 by 1 in the above formula.
5. Milne’s Predictor formula: / / /
1 3 2 1
42 2
3n n n n n
hy y y y y
6. Milne’s Corrector formula: / / /
1 1 1 143
n n n n n
hy y y y y
7. Adams-Bashforth method:
Adam’s Predictor formula:/ / / /
1 1 2 355 59 37 924
n n n n n n
hy y y y y y
Adam’s Corrector formula:/ / / /
1 1 1 29 19 524
n n n n n n
hy y y y y y
UNIT – 5
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1. Solving ordinary diff. Eqn. by finite diff. method
The given eqn. // /( ) ( ) ( ) ( ) ( ) ( )y x f x y x g x y x x
// 1 12
2( ) i i i
i
y y yy x
h
& / 1 1( )
2i i
i
y yy x
h
2. Solving one dimensional heat eqn. by Bender –Schmidt’s method [Explicit
method]
The given equation
2
2
u ua
x t
then , 1 1, , 1,(1 2 )i j i j i j i ju u u u , where 2
k
ah
for 1
2 the above equation becomes,
, 1 1, 1,
1
2i j i j i ju u u
, where 2
2
ak h
3. Solving one dimensional heat eqn. by Crank-Nicolson’s method [Implicit
method]
The given equation
2
2
u ua
x t
then 1, 1 1, 1 , 1 , 1, 1,2( 1) 2( 1) ( )i j i j i j i j i j i ju u u u u u
where 2
k
ah
for 1 the above equation becomes,
, 1 1, 1 1, 1 1, 1,
1
4i j i j i j i j i ju u u u u
, where 2k ah
4. Solving one dimensional wave eqn.
The given equation
2 22
2 2
u ua
t x
then 2 2 2 2
, 1 , 1, 1, , 12 1 ( )i j i j i j i j i ju a u a u u u ,
where k
h
for 2 2 1a , the above equation becomes,
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, 1 1, 1, , 1i j i j i j i ju u u u , where h
ka
5. Solving two dimensional Laplace equation
The given eqn.
2 2
2 20
u u
x y
(or)
2 0u
The Standard five point formula: [SFPF]
, 1, 1, , 1 , 1
1
4i j i j i j i j i ju u u u u
Diagonal five point formula: [DFPF]
, 1, 1 1, 1 1, 1 1, 1
1
4i j i j i j i j i ju u u u u
Liebamann’s iteration process:
( 1) ( 1) ( ) ( ) ( 1)
, 1, 1, , 1 , 1
1
4
n n n n n
i j i j i j i j i ju u u u u
6. Solving two dimensional Poisson equation
The given eqn.
2 2
2 2( , )
u uf x y
x y
(or)
2 ( , )u f x y
To solve the above equation, we use the following formula
2
1, 1, , 1 , 1 ,4 ( , )i j i j i j i j i ju u u u u h f ih jh
---- All the Best ----
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 1
SUBJECT NAME : Probability & Queueing Theory
SUBJECT CODE : MA 2262
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08AM1007 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch:
UNIT-I (RANDOM VARIABLES)
1) Discrete random variable: A random variable whose set of possible values is either finite or countably infinite is called discrete random variable. Eg: (i) Let X represent the sum of the numbers on the 2 dice, when two dice are thrown. In this case the random variable X takes the values 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. So X is a discrete random variable. (ii) Number of transmitted bits received in error.
2) Continuous random variable: A random variable X is said to be continuous if it takes all possible values between certain limits. Eg: The length of time during which a vacuum tube installed in a circuit functions is a continuous random variable, number of scratches on a surface, proportion of defective parts among 1000 tested, number of transmitted in error.
3)
Sl.No. Discrete random variable Continuous random variable 1
( ) 1i
i
p x
( ) 1f x dx
2 ( )F x P X x ( ) ( )
x
F x P X x f x dx
3 Mean ( )i i
i
E X x p x Mean ( )E X xf x dx
4 2 2( )
i i
i
E X x p x 2 2( )E X x f x dx
5 2
2Var X E X E X
22
Var X E X E X
6 Moment = r r
i i
i
E X x p Moment = ( )
r rE X x f x dx
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Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 2
7 M.G.F
( )tX tx
X
x
M t E e e p x
M.G.F
( )tX tx
XM t E e e f x dx
4) E aX b aE X b
5) 2Var VaraX b a X
6) 2 2Var VaraX bY a X b Var Y
7) Standard Deviation Var X
8) ( ) ( )f x F x 9) ( ) 1 ( )p X a p X a
10)
/p A B
p A Bp B
, 0p B
11) If A and B are independent, then p A B p A p B .
12) 1st Moment about origin = E X = 0
Xt
M t
(Mean)
2nd Moment about origin = 2E X =
0X
t
M t
The co-efficient of !
rt
r = r
E X (rth Moment about the origin)
13) Limitation of M.G.F: i) A random variable X may have no moments although its m.g.f exists.
ii) A random variable X can have its m.g.f and some or all moments, yet the m.g.f does not generate the moments.
iii) A random variable X can have all or some moments, but m.g.f does not exist except perhaps at one point.
14) Properties of M.G.F: i) If Y = aX + b, then bt
Y XM t e M at .
ii) cX XM t M ct , where c is constant.
iii) If X and Y are two independent random variables then
X Y X YM t M t M t
.
15) P.D.F, M.G.F, Mean and Variance of all the distributions: Sl.No.
Distribution
P.D.F ( ( )P X x ) M.G.F Mean Variance
1 Binomial x n x
xnc p q
n
tq pe
np npq
2 Poisson
!
xe
x
1
te
e
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3 Geometric 1xq p
(or) xq p
1
t
t
pe
qe
1
p
2
q
p
4 Negative Binomial 1
( 1)k x
kx k C p p
1
k
t
p
qe
kq
p
2
kq
p
5 Uniform 1
, ( )
0, otherwise
a x bf x b a
( )
bt ate e
b a t
2
a b
2( )
12
b a
6 Exponential
, 0, 0( )
0, otherwise
xe x
f x
t
1
2
1
7 Gamma 1
( ) , 0 , 0( )
xe x
f x x
1
(1 )t
8 Weibull 1( ) , 0, , 0
xf x x e x
16) Memoryless property of exponential distribution
/P X S t X S P X t .
UNIT-II (RANDOM VARIABLES)
1) 1ij
i j
p (Discrete random variable)
( , ) 1f x y dxdy
(Continuous random variable)
2) Conditional probability function X given Y, ,
/( )
i i
P x yP X x Y y
P y .
Conditional probability function Y given X , ,
/( )
i i
P x yP Y y X x
P x .
,
/( )
P X a Y bP X a Y b
P Y b
3) Conditional density function of X given Y, ( , )
( / )( )
f x yf x y
f y .
Conditional density function of Y given X, ( , )
( / )( )
f x yf y x
f x .
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4) If X and Y are independent random variables then
( , ) ( ). ( )f x y f x f y (for continuous random variable)
, .P X x Y y P X x P Y y (for discrete random variable)
5) Joint probability density function , ( , )
d b
c a
P a X b c Y d f x y dxdy .
0 0
, ( , )
b a
P X a Y b f x y dxdy
6) Marginal density function of X, ( ) ( ) ( , )X
f x f x f x y dy
Marginal density function of Y, ( ) ( ) ( , )Y
f y f y f x y dx
7) ( 1) 1 ( 1)P X Y P X Y
8) Correlation co – efficient (Discrete): ( , )
( , )X Y
Cov X Yx y
1( , )Cov X Y XY XY
n , 2 21
XX X
n , 2 21
YY Y
n
9) Correlation co – efficient (Continuous): ( , )
( , )X Y
Cov X Yx y
( , ) ,Cov X Y E X Y E X E Y , ( )X
Var X , ( )Y
Var Y
10) If X and Y are uncorrelated random variables, then ( , ) 0Cov X Y .
11) ( )E X xf x dx
, ( )E Y yf y dy
, , ( , )E X Y xyf x y dxdy
.
12) Regression for Discrete random variable:
Regression line X on Y is xyx x b y y ,
2xy
x x y yb
y y
Engineering Mathematics 2013
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Regression line Y on X is yxy y b x x ,
2yx
x x y yb
x x
Correlation through the regression, .XY YX
b b Note: ( , ) ( , )x y r x y
13) Regression for Continuous random variable:
Regression line X on Y is ( ) ( )xy
x E x b y E y , x
xy
y
b r
Regression line Y on X is ( ) ( )yx
y E y b x E x , y
yx
x
b r
Regression curve X on Y is / / x E x y x f x y dx
Regression curve Y on X is / / y E y x y f y x dy
14) Transformation Random Variables:
( ) ( )Y X
dxf y f x
dy (One dimensional random variable)
( , ) ( , )UV XY
x x
u vf u v f x y
y y
u v
(Two dimensional random variable)
15) Central limit theorem (Liapounoff’s form)
If X1, X2, …Xn be a sequence of independent R.Vs with E[Xi] = µi and Var(Xi) = σi2, i
= 1,2,…n and if Sn = X1 + X2 + … + Xn then under certain general conditions, Sn
follows a normal distribution with mean 1
n
i
i
and variance 2 2
1
n
i
i
as
n .
16) Central limit theorem (Lindberg – Levy’s form)
If X1, X2, …Xn be a sequence of independent identically distributed R.Vs with E[Xi]
= µi and Var(Xi) = σi2, i = 1,2,…n and if Sn = X1 + X2 + … + Xn then under certain
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 6
general conditions, Sn follows a normal distribution with mean n and variance
2n as n .
Note: nS n
zn
( for n variables),
Xz
n
( for single variables)
UNIT-III (MARKOV PROCESSES AND MARKOV CHAINS)
1) Random Process:
A random process is a collection of random variables {X(s,t)} that are
functions of a real variable, namely time ‘t’ where s Є S and t Є T.
2) Classification of Random Processes:
We can classify the random process according to the characteristics of time t
and the random variable X. We shall consider only four cases based on t and X
having values in the ranges -∞< t <∞ and -∞ < x < ∞.
Continuous random process
Continuous random sequence
Discrete random process
Discrete random sequence
Continuous random process:
If X and t are continuous, then we call X(t) , a Continuous Random Process.
Example: If X(t) represents the maximum temperature at a place in the
interval (0,t), {X(t)} is a Continuous Random Process.
Continuous Random Sequence:
A random process for which X is continuous but time takes only discrete values is
called a Continuous Random Sequence.
Example: If Xn represents the temperature at the end of the nth hour of a day, then
{Xn, 1≤n≤24} is a Continuous Random Sequence.
Discrete Random Process:
If X assumes only discrete values and t is continuous, then we call such random
process {X(t)} as Discrete Random Process.
Example: If X(t) represents the number of telephone calls received in the interval
(0,t) the {X(t)} is a discrete random process since S = {0,1,2,3, . . . }
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Discrete Random Sequence:
A random process in which both the random variable and time are discrete is
called Discrete Random Sequence.
Example: If Xn represents the outcome of the nth toss of a fair die, the {Xn : n≥1} is a
discrete random sequence. Since T = {1,2,3, . . . } and S = {1,2,3,4,5,6}
3) Condition for Stationary Process: ( ) ConstantE X t , ( ) constantVar X t .
If the process is not stationary then it is called evolutionary.
4) Wide Sense Stationary (or) Weak Sense Stationary (or) Covariance Stationary: A random process is said to be WSS or Covariance Stationary if it satisfies the
following conditions.
i) The mean of the process is constant (i.e) ( ) constantE X t .
ii) Auto correlation function depends only on (i.e)
( ) ( ). ( )XX
R E X t X t
5) Property of autocorrelation:
(i) 2
( ) lim
XXE X t R
(ii) 2( ) 0
XXE X t R
6) Markov process: A random process in which the future value depends only on the present value and not on the past values, is called a markov process. It is symbolically
represented by 1 1 1 1 0 0
( ) / ( ) , ( ) ... ( )n n n n n n
P X t x X t x X t x X t x
1 1( ) / ( )
n n n nP X t x X t x
Where 0 1 2 1
...n n
t t t t t
7) Markov Chain:
If for all n , 1 1 2 2 0 0
/ , , ...n n n n n n
P X a X a X a X a
1 1/
n n n nP X a X a
then the process n
X , 0,1, 2, ...n is called the
markov chain. Where 0 1 2, , , ... , ...
na a a a are called the states of the markov chain.
8) Transition Probability Matrix (tpm): When the Markov Chain is homogenous, the one step transition probability is denoted by Pij. The matrix P = {Pij} is called transition probability matrix.
9) Chapman – Kolmogorov theorem: If ‘P’ is the tpm of a homogeneous Markov chain, then the n – step tpm P(n) is
equal to Pn. (i.e) ( )n
n
ij ijP P .
10) Markov Chain property: If 1 2 3, , , then P and
1 2 31 .
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11) Poisson process: If ( )X t represents the number of occurrences of a certain event in (0, )t ,then
the discrete random process ( )X t is called the Poisson process, provided the
following postulates are satisfied.
(i) 1 occurrence in ( , )P t t t t O t
(ii) 0 occurrence in ( , ) 1P t t t t O t
(iii) 2 or more occurrences in ( , )P t t t O t
(iv) ( )X t is independent of the number of occurrences of the event in any
interval.
12) Probability law of Poisson process:
( ) , 0,1, 2, ...!
nte t
P X t n nn
Mean ( )E X t t , 2 2 2( )E X t t t , ( )Var X t t .
UNIT-IV (QUEUEING THEORY)
n – Number of customers in the system.
– Mean arrival rate.
– Mean service rate.
nP – Steady State probability of exactly n customers in the system.
qL – Average number of customers in the queue.
sL – Average number of customers in the system.
qW – Average waiting time per customer in the queue.
sW – Average waiting time per customer in the system.
Model – I (M / M / 1): (∞ / FIFO)
1) Server Utilization
2) 1n
nP (P0 no customers in the system)
3) 1
sL
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4) 2
1q
L
5)
1
1s
W
6) 1
qW
7) Probability that the waiting time of a customer in the system exceeds t is
( )( )
t
sP w t e
.
8) Probability that the quue size exceeds “t” is 1nP N n where 1n t
.
Model – II (M / M / C): (∞ / FIFO)
1) s
2)
11
0
0 ! ! 1
n ss
n
s sP
n s
3)
1
02
1
. ! 1
s
q
sL P
s s
4) s q
L L s
5) q
q
LW
6) s
s
LW
7) The probability that an arrival has to wait: 0
! 1
ss
P N s Ps
8) The probability that an arrival enters the service without waiting = 1 – P(an
arrival hat to wait) = 1 P N s
9) ( 1 )
0
( ) 11
!(1 )( 1 )
s t s s
ts e
P w t e Ps s s
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Model – III (M / M / 1): (K / FIFO)
1)
2) 0 1
1
1k
P
(No customer)
3) 01 P (effective arrival rate)
4) 1
1
1
1 1
k
s k
kL
5) q s
L L
6) s
s
LW
7) q
q
LW
8) 0a customer turned away
k
kP P P
Model – IV (M / M / C): (K / FIFO)
1) s
2)
11
0
0 ! !
n ss k
n s
n n s
s sP
n s
3)
0
0
, !
, !
n
n n
n s
sP n s
nP
sP s n k
s s
4) Effective arrival rate: 1
0
s
n
n
s s n P
5)
1
02
1
! 11
s k s k s
q
s k sL P
s
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6) s q
L L
7) q
q
LW
8) s
s
LW
UNIT-V (NON – MARKOVIAN & QUEUEING NETWORK)
1) Pollaczek – Khintchine formula:
22( ) ( )
( )2 1 ( )
S
Var t E tL E t
E t
(or)
2 2 2
2 1S
L
2) Little’s formulas:
2 2 2
2 1S
L
q SL L
S
S
LW
q
q
LW
3) Series queue (or) Tandem queue:
The balance equation
00 2 01P P
1 10 00 2 11P P P
01 2 01 1 10 2 1bP P P P
1 11 2 11 01P P P
2 1 1 11bP P
Engineering Mathematics 2013
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Condition 00 10 01 11 1
1b
P P P P P
4) Open Jackson networks:
i) Jackson’s flow balance equation 1
k
j j i ij
i
r P
Where k – number of nodes, rj – customers from outside
ii) Joint steady state probabilities
1 2
1 2 1 1 2 2, , ... 1 1 ... 1knn n
k k kP n n n
iii) Average number of customers in the system
1 2
1 2
...1 1 1
k
S
k
L
iv) Average waiting time of a customers in the system
S
S
LW
where
1 2...
kr r r
5) Closed Jackson networks:
In the closed network, there are no customers from outside, therefore 0j
r
then
i) The Jackson’s flow balance equation 1
k
j i ij
i
P
0j
r
(or)
11 12 1
221 22
1 2 1 2
1 2
...
... ... ...
...
k
k
k k
k k kk
P P P
PP P
P P P
ii) If each nodes single server
1 2
1 2 1 2, , ... ... knn n
k N kP n n n C
Where 1 2
1 2
1
1 2
...
... k
k
nn n
N k
n n n N
C
iii) If each nodes has multiple servers
Engineering Mathematics 2013
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1 2
1 2
1 2
1 2
, , ... ...knn n
k
k N
k
P n n n Ca a a
Where 1 2
1 2
1 1 2
... 1 2
...k
k
nn n
k
N
n n n N k
Ca a a
! ,
! ,i i
i i i
i n s
i i i i
n n sa
s s n s
---- All the Best ----
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 1
SUBJECT NAME : Probability & Random Process
SUBJECT CODE : MA 2261
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08AM1007 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch:
UNIT-I (RANDOM VARIABLES)
1) Discrete random variable: A random variable whose set of possible values is either finite or countably infinite is called discrete random variable. Eg: (i) Let X represent the sum of the numbers on the 2 dice, when two dice are thrown. In this case the random variable X takes the values 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. So X is a discrete random variable. (ii) Number of transmitted bits received in error.
2) Continuous random variable: A random variable X is said to be continuous if it takes all possible values between certain limits. Eg: The length of time during which a vacuum tube installed in a circuit functions is a continuous random variable, number of scratches on a surface, proportion of defective parts among 1000 tested, number of transmitted in error.
3)
Sl.No. Discrete random variable Continuous random variable 1
( ) 1i
i
p x
( ) 1f x dx
2 ( )F x P X x ( ) ( )
x
F x P X x f x dx
3 Mean ( )i i
i
E X x p x Mean ( )E X xf x dx
4 2 2( )
i i
i
E X x p x 2 2( )E X x f x dx
5 2
2Var X E X E X
22
Var X E X E X
6 Moment = r r
i i
i
E X x p Moment = ( )
r rE X x f x dx
Engineering Mathematics 2013
Prepared by C.Ganesan, M.Sc., M.Phil., (Ph: 9841168917) Page 2
7 M.G.F
( )tX tx
X
x
M t E e e p x
M.G.F
( )tX tx
XM t E e e f x dx
4) E aX b aE X b
5) 2Var VaraX b a X
6) 2 2Var VaraX bY a X b Var Y
7) Standard Deviation Var X
8) ( ) ( )f x F x 9) ( ) 1 ( )p X a p X a
10)
/p A B
p A Bp B
, 0p B
11) If A and B are independent, then p A B p A p B .
12) 1st Moment about origin = E X = 0
Xt
M t
(Mean)
2nd Moment about origin = 2E X =
0X
t
M t
The co-efficient of !
rt
r = r
E X (rth Moment about the origin)
13) Limitation of M.G.F: i) A random variable X may have no moments although its m.g.f exists.
ii) A random variable X can have its m.g.f and some or all moments, yet the m.g.f does not generate the moments.
iii) A random variable X can have all or some moments, but m.g.f does not exist except perhaps at one point.
14) Properties of M.G.F: i) If Y = aX + b, then bt
Y XM t e M at .
ii) cX XM t M ct , where c is constant.
iii) If X and Y are two independent random variables then
X Y X YM t M t M t
.
15) P.D.F, M.G.F, Mean and Variance of all the distributions: Sl.No.
Distribution
P.D.F ( ( )P X x ) M.G.F Mean Variance
1 Binomial x n x
xnc p q
n
tq pe
np npq
2 Poisson
!
xe
x
1
te
e
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3 Geometric 1xq p
(or) xq p
1
t
t
pe
qe
1
p
2
q
p
4 Uniform 1
, ( )
0, otherwise
a x bf x b a
( )
bt ate e
b a t
2
a b
2( )
12
b a
5 Exponential
, 0, 0( )
0, otherwise
xe x
f x
t
1
2
1
6 Gamma 1
( ) , 0 , 0( )
xe x
f x x
1
(1 )t
7 Normal 21
21( )
2
x
f x e
2 2
2
tt
e
2
16) Memoryless property of exponential distribution
/P X S t X S P X t .
17) Function of random variable: ( ) ( )Y X
dxf y f x
dy
UNIT-II (RANDOM VARIABLES)
1) 1ij
i j
p (Discrete random variable)
( , ) 1f x y dxdy
(Continuous random variable)
2) Conditional probability function X given Y ,
/( )
i i
P x yP X x Y y
P y .
Conditional probability function Y given X ,
/( )
i i
P x yP Y y X x
P x .
,
/( )
P X a Y bP X a Y b
P Y b
3) Conditional density function of X given Y, ( , )
( / )( )
f x yf x y
f y .
Conditional density function of Y given X, ( , )
( / )( )
f x yf y x
f x .
4) If X and Y are independent random variables then
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( , ) ( ). ( )f x y f x f y (for continuous random variable)
, .P X x Y y P X x P Y y (for discrete random variable)
5) Joint probability density function , ( , )
d b
c a
P a X b c Y d f x y dxdy .
0 0
, ( , )
b a
P X a Y b f x y dxdy
6) Marginal density function of X, ( ) ( ) ( , )X
f x f x f x y dy
Marginal density function of Y, ( ) ( ) ( , )Y
f y f y f x y dx
7) ( 1) 1 ( 1)P X Y P X Y
8) Correlation co – efficient (Discrete): ( , )
( , )X Y
Cov X Yx y
1( , )Cov X Y XY XY
n , 2 21
XX X
n , 2 21
YY Y
n
9) Correlation co – efficient (Continuous): ( , )
( , )X Y
Cov X Yx y
( , ) ,Cov X Y E X Y E X E Y , ( )X
Var X , ( )Y
Var Y
10) If X and Y are uncorrelated random variables, then ( , ) 0Cov X Y .
11) ( )E X xf x dx
, ( )E Y yf y dy
, , ( , )E X Y xyf x y dxdy
.
12) Regression for Discrete random variable:
Regression line X on Y is xyx x b y y ,
2xy
x x y yb
y y
Regression line Y on X is yxy y b x x ,
2yx
x x y yb
x x
Correlation through the regression, .XY YX
b b Note: ( , ) ( , )x y r x y
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13) Regression for Continuous random variable:
Regression line X on Y is ( ) ( )xy
x E x b y E y , x
xy
y
b r
Regression line Y on X is ( ) ( )yx
y E y b x E x , y
yx
x
b r
Regression curve X on Y is / / x E x y x f x y dx
Regression curve Y on X is / / y E y x y f y x dy
14) Transformation Random Variables:
( ) ( )Y X
dxf y f x
dy (One dimensional random variable)
( , ) ( , )UV XY
x x
u vf u v f x y
y y
u v
(Two dimensional random variable)
15) Central limit theorem (Liapounoff’s form)
If X1, X2, …Xn be a sequence of independent R.Vs with E[Xi] = µi and Var(Xi) = σi2, i
= 1,2,…n and if Sn = X1 + X2 + … + Xn then under certain general conditions, Sn
follows a normal distribution with mean 1
n
i
i
and variance 2 2
1
n
i
i
as
n .
16) Central limit theorem (Lindberg – Levy’s form)
If X1, X2, …Xn be a sequence of independent identically distributed R.Vs with E[Xi]
= µi and Var(Xi) = σi2, i = 1,2,…n and if Sn = X1 + X2 + … + Xn then under certain
general conditions, Sn follows a normal distribution with mean n and variance
2n as n .
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Note: nS n
zn
( for n variables),
Xz
n
( for single variables)
UNIT-III (MARKOV PROCESSES AND MARKOV CHAINS)
1) Random Process:
A random process is a collection of random variables {X(s,t)} that are
functions of a real variable, namely time ‘t’ where s Є S and t Є T.
2) Classification of Random Processes:
We can classify the random process according to the characteristics of time t
and the random variable X. We shall consider only four cases based on t and X
having values in the ranges -∞< t <∞ and -∞ < x < ∞.
Continuous random process
Continuous random sequence
Discrete random process
Discrete random sequence
Continuous random process:
If X and t are continuous, then we call X(t) , a Continuous Random Process.
Example: If X(t) represents the maximum temperature at a place in the
interval (0,t), {X(t)} is a Continuous Random Process.
Continuous Random Sequence:
A random process for which X is continuous but time takes only discrete values is
called a Continuous Random Sequence.
Example: If Xn represents the temperature at the end of the nth hour of a day, then
{Xn, 1≤n≤24} is a Continuous Random Sequence.
Discrete Random Process:
If X assumes only discrete values and t is continuous, then we call such random
process {X(t)} as Discrete Random Process.
Example: If X(t) represents the number of telephone calls received in the interval
(0,t) the {X(t)} is a discrete random process since S = {0,1,2,3, . . . }
Discrete Random Sequence:
A random process in which both the random variable and time are discrete is called
Discrete Random Sequence.
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Example: If Xn represents the outcome of the nth toss of a fair die, the {Xn : n≥1} is a
discrete random sequence. Since T = {1,2,3, . . . } and S = {1,2,3,4,5,6}
3) Condition for Stationary Process: ( ) ConstantE X t , ( ) constantVar X t .
If the process is not stationary then it is called evolutionary.
4) Wide Sense Stationary (or) Weak Sense Stationary (or) Covariance Stationary: A random process is said to be WSS or Covariance Stationary if it satisfies the
following conditions.
i) The mean of the process is constant (i.e) ( ) constantE X t .
ii) Auto correlation function depends only on (i.e)
( ) ( ). ( )XX
R E X t X t
5) Time average:
The time average of a random process ( )X t is defined as1
( ) 2
T
T
T
X X t dtT
.
If the interval is 0,T , then the time average is 0
1( )
T
TX X t dt
T .
6) Ergodic Process:
A random process ( )X t is called ergodic if all its ensemble averages are
interchangeable with the corresponding time averageT
X .
7) Mean ergodic:
Let ( )X t be a random process with mean ( )E X t and time averageT
X ,
then ( )X t is said to be mean ergodic if T
X as T (i.e)
( )T
TE X t Lt X
.
Note: var 0T
TLt X
(by mean ergodic theorem)
8) Correlation ergodic process:
The stationary process ( )X t is said to be correlation ergodic if the process
( )Y t is mean ergodic where ( ) ( ) ( )Y t X t X t . (i.e) ( )T
TE Y t Lt Y
.
Where T
Y is the time average of ( )Y t .
9) Auto covariance function:
( ) ( ) ( ) ( )XX XX
C R E X t E X t
10) Mean and variance of time average:
Mean: 0
1( )
T
TE X E X t dt
T
Variance: 2
2
1( ) ( )
2
T
T XX XX
T
Var X R C dT
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11) Markov process: A random process in which the future value depends only on the present value and not on the past values, is called a markov process. It is symbolically
represented by 1 1 1 1 0 0
( ) / ( ) , ( ) ... ( )n n n n n n
P X t x X t x X t x X t x
1 1( ) / ( )
n n n nP X t x X t x
Where 0 1 2 1
...n n
t t t t t
12) Markov Chain:
If for all n , 1 1 2 2 0 0
/ , , ...n n n n n n
P X a X a X a X a
1 1/
n n n nP X a X a
then the process n
X , 0,1, 2, ...n is called the
markov chain. Where 0 1 2, , , ... , ...
na a a a are called the states of the markov chain.
13) Transition Probability Matrix (tpm): When the Markov Chain is homogenous, the one step transition probability is denoted by Pij. The matrix P = {Pij} is called transition probability matrix.
14) Chapman – Kolmogorov theorem: If ‘P’ is the tpm of a homogeneous Markov chain, then the n – step tpm P(n) is
equal to Pn. (i.e) ( )n
n
ij ijP P .
15) Markov Chain property: If 1 2 3, , , then P and
1 2 31 .
16) Poisson process: If ( )X t represents the number of occurrences of a certain event in (0, )t ,then
the discrete random process ( )X t is called the Poisson process, provided the
following postulates are satisfied.
(i) 1 occurrence in ( , )P t t t t O t
(ii) 0 occurrence in ( , ) 1P t t t t O t
(iii) 2 or more occurrences in ( , )P t t t O t
(iv) ( )X t is independent of the number of occurrences of the event in any
interval.
17) Probability law of Poisson process:
( ) , 0,1, 2, ...!
xte t
P X t x xx
Mean ( )E X t t , 2 2 2( )E X t t t , ( )Var X t t .
UNIT-IV (CORRELATION AND SPECTRAL DENSITY)
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XXR - Auto correlation function
XXS - Power spectral density (or) Spectral density
XYR - Cross correlation function
XYS - Cross power spectral density
1) Auto correlation to Power spectral density (spectral density):
i
XX XXS R e d
2) Power spectral density to Auto correlation:
1
2
i
XX XXR S e d
3) Condition for ( )X t and ( )X t are uncorrelated random process is
( ) ( ) ( ) ( ) 0XX XX
C R E X t E X t
4) Cross power spectrum to Cross correlation:
1
2
i
XY XYR S e d
5) General formula:
i) 2 2cos cos sin
ax
ax ee bx dx a bx b bx
a b
ii) 2 2sin sin cos
ax
ax ee bx dx a bx b bx
a b
iii) 2 2
2
2 4
a ax ax x
iv) sin2
i ie e
i
v) cos2
i ie e
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UNIT-V (LINEAR SYSTEMS WITH RANDOM INPUTS)
1) Linear system:
f is called a linear system if it satisfies
1 1 2 2 1 1 2 2( ) ( ) ( ) ( )f a X t a X t a f X t a f X t
2) Time – invariant system:
Let ( ) ( )Y t f X t . If ( ) ( )Y t h f X t h then f is called a time –
invariant system.
3) Relation between input ( )X t and output ( )Y t :
( ) ( ) ( ) Y t h u X t u du
Where ( )h u system weighting function.
4) Relation between power spectrum of ( )X t and output ( )Y t :
2( ) ( ) ( )
YY XXS S H
If ( )H is not given use the following formula ( ) ( ) j t
H e h t dt
5) Contour integral:
2 2
imxm ae
ea x a
(One of the result)
6) 1
2 2
1
2
ae
Fa a
(from the Fourier transform)
---- All the Best ----
Engineering Mathematics Material 2012
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SUBJECT NAME : Statistics
MATERIAL NAME : Formula & Problems
MATERIAL CODE : JM08AM1003
Name of the Student: Branch:
UNIT – I (Testing of Hypothesis)
1. Write the application of ‘F’ - test and – test and ‘t’ – test.
Application of – test
i) To test the goodness of fit.
ii) To test the “independence of attributes”.
iii) To test the significance of discrepancy between experimental values and the
theoretical values.
Application of ‘F’ – test i) To test whether there is any significant difference between two estimates of
population variance.
ii) To test if the two samples have come from the same population.
Application of ‘t’ – test i) Test of Hypothesis about the population mean.
ii) Test of Hypothesis about the difference between two means.
iii) Test of Hypothesis about the difference between two means with dependent
samples.
iv) Test of Hypothesis about the observed sample correlation coefficient and sample
regression coefficient.
2. Define Type – I and Type – II errors and critical region.
Type – I Error
The hypothesis is true but our test rejects it.
Type – II Error
The hypothesis is false but our test accepts it.
Critical region
A region in the sample space which amounts to rejection of H0 is termed as
critical region or rejection.
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3. Define F – variate.
Greater VarianceF
Smaller Variance
2
2
1
11
x xS
n
and
2
2
2
21
y yS
n
Here 2
1S and 2
2S are Variance
and 1S and 2
S are S.D.
4. Write down any two properties of chi – Square distribution.
i) The mean and variance of the chi – Square distribution are n and 2n respectively.
ii) As n → , Chi – Square distribution approaches a normal distribution.
iii) The sum of independent Chi – Square variates is also a Chi – Square variate.
5. What are the assumptions for Student’s ‘t’ test?
i) The parent population from which the sample drawn is normal.
ii) The sample observations are independent.
iii) The population standard deviation is unknown.
UNIT – I (Testing of Hypothesis) There are two types of samples in Testing of Hypothesis
i) Small Sample (n <30)
ii) Large Sample (n >30)
Small Sample: (n <30)
Type 1 Student’s ‘t’ test
Single Mean (S.D given directly)
Single Mean (S.D is not given directly)
Difference of Means
Type 2 F – test
Type 3 – test
Goodness of fit
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Independence of attributes
Large Sample: (n >30)
Type 1 Single Mean
Type 2 Single Proportion
Type 3 Difference of Mean
Type 4 Difference of Proportion
Small Sample: (n <30)
Student’s ‘t’ test:
Single Mean (S.D given directly)
√
Where Sample Mean
Population
n Sample size
S.D Standard deviation
Degree of freedom = n – 1
Single Mean (S.D is not given directly)
√
Where ∑( )
Degree of freedom = n – 1
Difference of Means
√
Where
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[∑( )
∑( )
]
(or)
Where 2 2
2 1 1 2 2
1 22
n s n ss
n n
Degrees of freedom 1 22n n
F - test: Greater Variance
FSmaller Variance
2
2
1
11
x xS
n
and
2
2
2
21
y yS
n
Here 2
1S and 2
2S are Variance and
1S and 2
S are S.D. (Capital S mention Population S.D and Small s mention Sample S.D)
Chi – Square test :
Goodness of fit:
2
2O E
E
Where O – Observed frequency
E – Expected frequency, Degree of freedom 1n
Independence of attributes:
a b a + b
c d c + d
a + c b + d N
The expected frequencies are given by ( )( )
( )( )
a + b
( )( )
( )( )
c + d
a + c b + d N
Degree of freedom 1 1r s
Where r – number of rows
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S – number of columns
Large Sample: (n >30)
Single Mean (or) x x
zs
n n
Difference of Mean 1 2 1 2
2 2 2 2
1 2 1 2
1 2 1 2
(or) x x x x
zs s
n n n n
Single Proportion
p Pz
PQ
n
where p – Sample proportion, P – Population proportion, Q = 1 – P
Difference of Proportion
1 2
1 2
1 1
p pz
pqn n
where 1 1 2 2
1 2
n p n pp
n n
and 1q p
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SUBJECT NAME : Discrete Mathematics
SUBJECT CODE : MA 2265
MATERIAL NAME : Formula Material
MATERIAL CODE : JM08ADM009 (Scan the above Q.R code for the direct download of this material)
Name of the Student: Branch:
Unit – I (Logic and Proofs) 1) Truth Table:
Conjunction Disjunction Conditional Biconditional
p
q
p q
p
q
p q
p
q
p q
p
q
p q
T T T T T T T T T T T T
T F F T F T T F F T F F
F T F F T T F T T F T F
F F F F F F F F T F F T
Negation
p p
T F
F T
2) Tautology and Contradiction:
A Compound proposition 1 2, , ...
nP P P P where
1 2, , ...
nP P P variables are called
tautology if it is true for every truth assignment for 1 2, , ...
nP P P .
P is called a Contradiction if it is false for every truth assignment for 1 2, , ...
nP P P .
If a proposition is neither a tautology nor a Contradiction is called contingency.
3) Laws of algebra of proposition:
Name of Law Primal form Dual form
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Idempotent law p p p p p p
Identity law p F p p T p
Dominant law p T T p F F
Complement
law p p T p p F
Commutative
law p q q p p q q p
Associative law p q r p q r p q r p q r
Distributive law p q r p q p r p q r p q p r
Absorption law p p q p p p q p
Demorgan’s law p q p q p q q p
Double
Negation law
p p
4) Equivalence involving Conditionals:
Sl.No. Propositions
1. p q p q
2. p q q p
3. p q p q
4. p q p r p q r
5. p r q r p q r
5) Equivalence involving Biconditionals:
Sl.No. Propositions
1. p q p q q p
2. p q p q
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3. p q p q p q
4. p q p q
6) Tautological Implication:
A B if and only if A B is tautology. (i.e) To prove A B , it enough to prove
A B is tautology.
7) The Theory of Inferences:
The analysis of the validity of the formula from the given set of premises by using
derivation is called “theory of inferences”
8) Rules for inferences theory:
Rule P:
A given premise may be introduced at any stage in the derivation.
Rule T:
A formula S may be introduced in a derivation if S is tautologically implied by one or
more of the preceding formulae in the derivation.
Rule CP:
If we can drive S from R and a set of given premises, then we can derive R S from
the set of premises alone. In such a case R is taken as an additional premise (assumed
premise). Rule CP is also called the deduction theorem.
9) Indirect Method of Derivation:
Whenever the assumed premise is used in the derivation, then the method of derivation
is called indirect method of derivation.
10) Table of Logical Implications:
Name of Law Primal form
Simplification
p q p
p q q
Addition
p p q
q p q
Disjunctive Syllogism
p p q q
q p q p
Modus Ponens p p q q
Modus Tollens p q q p
Hypothetical Syllogism p q q r p r
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p q q p
Unit – II (Combinatorics) 1) Principle of Mathematical Induction:
Let ( )P n be a statement or proposition involving for all positive integers n.
Step 1: (1)P is true.
Step2: Assume that ( )P k is true.
Step3: We have to prove ( 1)P k is true.
2) Principle of Strong induction.
Let ( )P n be a statement or proposition involving for all positive integers n.
Step 1: (1)P is true.
Step2: Assume that ( )P n is true for all integers 1 n k .
Step3: We have to prove ( 1)P k is true.
3) The Pigeonhole Principle:
If n pigeons are assigned to m pigeonholes and m n , than at least one pigeonhole
contains two or more pigeons.
4) The Extended Pigeonhole Principle:
If n pigeons are assigned to m pigeonholes than one pigeonhole must contains at least
11
n
m
pigeons.
5) Recurrence relation:
An equation that expressesn
a , the general term of the sequence na in terms of one or
more of the previous terms of the sequence, namely0 1 1, , ...
na a a
, for all integers n is
called a recurrence relation for na or a difference equation.
6) Working rule for solving homogeneous recurrence relation:
Step 1: The given recurrence relation of the form
0 1 1( ) ( ) ... ( ) 0
n n k n kC n a C n a C n a
Step 2: Write the characteristic equation of the recurrence relation
0 1 1... 0
n k k nn kC r C r C r
Step 3: Find all the roots of the characteristic equation namely1 2, , ...
kr r r .
Step 4:
Case (i): If all the roots are distinct then the general solution is
1 1 2 2...
n n n
n k ka b r b r b r
Case (ii): If all the roots are equal then the general solution is
2
1 2 3...
n
na b nb n b r
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Unit – III (Graph Theory) 1) Graph:
A graph G=(V,E) consists of two sets 1 2, , ...V v v v , called the set of vertices and
1 2, , ...E e e e
, called the set of edges of G.
2) Simple graph: A graph is said to be simple graph if it has no loops and parallel edges. Otherwise it is
multi graph.
3) Regular graph: If every vertex of a simple graph has the same degree, then the graph is called a regular
graph. If every vertex in a regular graph has degree n, then the graph is called n-regular. 4) Complete graph:
A simple graph in which each pair of distinct vertices is joined by an edge is called a
complete graph. The complete graph on “n” vertices is denoted byn
K .
5) Pendent vertex and Pendent edge:
A vertex with degree one is called a pendent vertex and the only edge which is incident
with a pendent vertex is called the pendent edge.
6) Matrix representation of a graph:
There are two ways of representing a graph by a matrix namely adjacent matrix and
incidence matrix as follows:
Adjacency matrices:
Let G be a graph with n vertices, then the adjacency matrix, G ijA A defined
by 1, if , are adjacent
0, otherwise
i j
ij
u vA
.
Incidence matrix:
Let G be a graph with n vertices, then the incidence matrix of G is an n x e matrix
G ijB B defined by
1, if edge is incident on the vertex
0, otherwise
th th
ij
j iB
7) Bipartite graph:
A graph G=(V,E) is called a bipartite graph if its vertex set V can be partitioned into two
subsets 1
V and 2
V such that each edge of G connects and vertex of 1
V to a vertex of 2
V .
In other words, no edge joining two vertices, in 1
V or two vertices in 2
V .
8) Isomorphism of a graph:
The simple graphs 1 1 1,G V E and 2 2 2
,G V E are isomorphic if there is a one to
one and onto function f from 1
V to 2
V with the property that a and b are adjacent in
1G if and only if ( )f a and ( )f b are adjacent in
2G , for all a and b in
1V .
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9) Complementary and Self complementary graph:
Let G be a graph. The complement G of G is defined by any two vertices are adjacent
in G if and only if they are not adjacent inG .
G is said to be a self complementary graph if G is isomorphic toG .
10) Connected graph:
A graph G is said to be connected if there is at least one path between every pair of
vertices in G. Otherwise G is disconnected. A disconnected graph consists of two or
more connected sub graphs and each of them is called a component. It is denoted by
( )G .
11) Strongly Connected and Weakly Connected graph:
12) Cut edge:
A cut edge of a graph G is an edge “e” such that ( ) ( )G e G . (i.e) If G is
connected and “e” is a cut edge of G, then G e is disconnected.
13) Cut vertex:
A cut vertex of a graph G is a vertex “v” such ( ) ( )G v G . (i.e) If G is connected
and “v” is a cut vertex of G, then G v is disconnected.
14) Define vertex connectivity.
The connectivity ( )G of G is the minimum “k” for which G has a k-vertex cut. If G is
either trivial or disconnected then ( ) 0G .
15) Define edge connectivity.
The edge connectivity ( )G of G is the minimum “k” for which G has a k-edge cut. If G
is either trivial or disconnected then ( ) 0G
16) Define Eulerian graph.
A path of graph G is called an Eulerian path, if it includes each edge of G exactly once. A
circuit of a graph G is called an Eulerian circuit, if it includes each edge of G exactly one.
A graph containing an Eulerian circuit is called an Eulerian graph.
17) Define Hamiltonian graph.
A simple path in a graph G that passes through every vertex exactly once is called a
Hamilton path. A circuit in a graph G that passes through every vertex exactly once is
called a Hamilton circuit. A graph containing a Hamiltonian circuit.
Unit – IV (Algebraic Structures) 1) Semi group:
If G is a non-empty set and * be a binary operation on G, then the algebraic system
,*G is called a semi group, if G is closed under * and * is associative.
Example: If Z is the set of positive even numbers, then ,Z and ,Z are semi
groups.
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2) Monoid:
If a semi group ,*G has an identity element with respect to the operation *, then
,*G is called a monoid. It is denoted by ,*,G e .
Example: If N is the set of natural numbers, then ,N and ,N are monoids with
the identity elements 0 and 1 respectively. ,Z and ,Z are semi groups with
out monoids, where Z is the set of all positive even numbers 3) Sub semi groups:
If ,*G is a semi group and H G is called under the operation *, then ,*H is
called a sub semi group of ,*G .
Example: If the set E of all even non-negative integers, the ,E is a sub semi group
of the semi group ,N , where N is the set of natural numbers. 4) Semi group homomorphism:
If ,*G and ,G are two semi groups, then a mapping :f G G is called a semi
group homomorphism, if for any ,a b G , ( * ) ( ) ( )f a b f a f b . A homomorphism f
is called isomorphism if f is 1-1 and onto. 5) Group:
If G is a non-empty set and * is a binary operation of G , then the algebraic system
,*G is called a group if the following conditions are satisfied.
(i) Closure property
(ii) Associative property
(iii) Existence of identity element
(iv) Existence of inverse element
Example: ,Z is a group and ,Z is not a group.
6) Abelian group: A group ,*G , in which the binary operation * is commutative, is called a
commutative group or abelian group.
Example: The set of rational numbers excluding zero is an abelian group under the
multiplication. 7) Coset:
If H is a subgroup of a group G under the operation *, then the set aH, where a G ,
define by * /aH a h h H is called the left coset of H in G generated by the
element a G . Similarly the set Ha is called the right coset of H in G generated by the
element a G .
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Example: 1, 1, ,G i i be a group under multiplication and 1, 1H is a
subgroup of G. The right cosets are 1 1, 1H , 1 1,1H , ,iH i i and
,iH i i . 8) Lagrange’s theorem:
The order of each subgroups of a finite group is a divisor of a order of a group. 9) Cyclic group:
A group ,*G is said to be cyclic, if and element a G such that every element of
G generated by a. (i.e) 21, , , ...
nG a a a a e .
Example: 1, 1, ,G i i is a cyclic group under the multiplication. The generator is
i , because 4 2 31, 1, , i i i i i .
10) Normal subgroup: A subgroup H of the group G is said to be normal subgroup under the operation *, if for
any a G , aH Ha . 11) Kernel of a homomorphism:
If f is a group homomorphism from ,*G and ,G , then the set of element of G ,
which are mapped into e , the identity element of G , is called the kernel of the
homomorphism f and denoted by ker f . 12) Fundamental theorem of homomorphism:
If f is a homomorphism of G on to G with kernel K, then /G K is isomorphic to G . 13) Cayley’s theorem:
Every finite group of order n is isomorphic to a permutation group of degree n . 14) Ring:
An algebraic system , ,S is called a ring if the binary operations and on S
satisfy the following properties.
(i) ,S is an abelian group
(ii) ,S is a semi group
(iii) The operation is distributive over .
Example: The set of all integers Z , and the set of all rational numbers R are rings
under the usual addition and usual multiplication. 15) Commutative ring:
16) Integral domain: A commutative ring without zero divisor is called Integral domain.
Example: (i) , ,R is an integral domain, since ,a b R such that
0, 0a b then 0ab . (ii) 10 10 10, ,Z is not an integral domain,
Engineering Mathematics 2013
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because 10
2,3 Z and 10
2 5 0 . Therefore 2 and 5 are zero divisors.
17) Field:
A commutative reing , ,S which has more than one element such that every non-
zero element of S has a multiplicative inverse in S is called a field.
Example: The ring of rational numbers , ,Q is a field since it is a commutative ring
and each non-zero element is inversible.
Unit – V (Lattices and Boolean algebra) 1) Partially ordered set (Poset):
A relation R on a set A is called a partial order relation, if R is reflexive, antisymmetric
and transitive. The set A together with partial order relation R is called partially ordered
set or poset.
Example: The greater than or equal to relation is a partial ordering on the set of
integers Z . 2) Lattice:
A lattice is a partially ordered set ,L in which every pair of elements ,a b L has a
glb and lub. 3) Sub-lattice:
4) General formula:
i) glb , *a b a b a b
ii) l b ,u a b a b a b
iii) *
& *
a b a
a b b
&
a b a
a b b
iv) If *
a b a b a
a b b
5) Properties:
Name of Law Primal form Dual form
Idempotent law *a a a a a a
Commutative
law * *a b b a a b b a
Associative law * * * *a b c a b c a b c a b c
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Distributive law * * *p q r p q p r * *p q r p q p r
Absorption law *a a b a *a a b a
Complement * 0a a 1a a
Demorgan’s law *a b a b *a b a b
Double
Negation law
p p
6) Complemented Lattices:
A Lattice ,*,L is said to be complemented if for any a L , there exist a L ,
such that * 0a a and 1a a .
7) Demorgan’s laws:
Let ,*,L be the complemented lattice, then *a b a b and
*a b a b .
8) Complete Lattice: A lattice ,*,L is complete if for all non-empty subsets of L, there exists a glb and
lub.
9) Lattice Homomorphism: Let ,*,L and , ,S be two lattices. A mapping :g L S is called lattices
homomorphism if ( * ) ( ) ( )g a b g a g b and ( ) ( ) ( )g a b g a g b . 10) Modular Lattice:
A lattice ,*,L is said to be modular if for any , ,a b c L
i) * *a c a b c a b c
ii) * *a c a b c a b c
11) Chain in Lattice: Let ,L be a Chain if
i) or a b a c and ii) and a b a c
12) Condition for the algebraic lattice: A lattice ,*,L is said to be algebraic if it satisfies Commutative Law, Associative
Law, Absorption Law and Existence of Idempotent element. 13) Isotone property:
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Let ,*,L be a lattice. The binary operations * and are said to possess isotone
property if * *
b c a b a c
a b a c
.
14) Boolean Algebra:
A Boolean algebra is a lattice which is both complemented and distributive. It is denoted
by ,*,B .
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