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Math 141, Jagodina Chapter 1 Notes Math lab may help
Math 141
Chapter 1: Equations andInequalities
Notes
Name...............................................
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.1 The Coordinate Plane
Graphing Regions in the Coordinate Plane
1. Example: Sketch the region given by the set
(a) {(x, y)|x = −3}
(b) {(x, y)|y = 4}
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Math 141, Jagodina Chapter 1 Notes Math lab may help
(c) {(x, y)| − 2 < x ≤ 2}
(d) {(x, y)|x > 3 and y ≤ 3}
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Distance Formula
2. Example: Consider the points (5, 0) and (0, 4).
(a) Plot the points in the coordinate plane.
(b) Find the distance between the points.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Midpoint Formula
3. Example: Find the midpoint of the segment that joins (5, 0) and (0, 8).
4. Example: If M(3,4) is the midpoint of the line segment AB and if A has coordinates(-1,2), find the coordinates of B.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Shifting the Coordinate Plane
5. Example: Suppose that each point in the coordinate plane is shifted 4 units to theright and 3 units downward.
(a) The point (3,2) is shifted to what new point?
(b) The point (a, b) is shifted to what new point?
Reflecting in the Coordinate Plane
6. Example: Suppose that the y-axis acts as a mirror that reflects each point to theright of it into a point to the left of it.
(a) The point (1,3) is reflected to what point?
(b) The point (a, b) is reflected to what point?
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.2 Graphs and Equations in TwoVariables
Graphing Equations by Plotting Points
1. Example: Sketch the graph of 3x− y = 5. Plot 5 points.
2. Example: Sketch the graph of y = x2 − 3. Plot 5 points.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
3. Example: Sketch the graph of y = |x|. Plot 5 points.
Intercepts
4. Example: Find the x− and y−intercepts of y = x2 − 3.
5. Example: Find the x− and y−intercepts ofx2
16+
y2
25= 1 Graph the equation.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
6. Example: Find the intercepts of the equation whose graph is shown.
−2 −1 1 2 3 4 5 6 7
−3
−2
−1
1
2
3
4
0
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Circles Standard form of an equation of the circle with center (h, k) and radius r:
Standard form of an equation of the circle with center (0, 0) and radius r:
7. Example: Graph x2 + y2 = 9
8. Example: Graph (x− 2)2 + (y + 1)2 = 4
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Math 141, Jagodina Chapter 1 Notes Math lab may help
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Math 141, Jagodina Chapter 1 Notes Math lab may help
9. Example: Find an equation of the circle with radius 10 and center (1,-3)
10. Example: Show that the equation x2 + y2 − 2x + 6y − 15 = 0 represents a circle.Find the center and radius of the circle.
Symmetry
Symmetry with respect to the y-axis
Test: The equation must be unchanged when x is replaced with −x
Graph:
Symmetry with respect to the x-axis
Test: The equation must be unchanged when y is replaced with −y
Graph:
Symmetry with respect to the origin
Test: The equation must be unchanged when (x, y) is replaced with (−x,−y)
Graph:
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Math 141, Jagodina Chapter 1 Notes Math lab may help
11. Example: Test y = x5 − 9x3 for symmetry.
12. Example: Test y = x2 + 2x for symmetry.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.3 Lines
Slope of a line
Point-Slope Form
Slope-Intercept Form
1. Example: Find the slope of each line.
(a) The line passes through (1,2) and (5,8)
(b) y = −3
2x + 4
(c) y = 4
(d) x = 5
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Math 141, Jagodina Chapter 1 Notes Math lab may help
2. Example: Find an equation of the line through (-3,1) and (-4,3).
Parallel Lines
Two nonvertical lines are parallel if and only if they have the same .
3. Example: Find an equation of the line through (2,5) that is parallel to the line6x + 4y + 5 = 0
Perpendicular Lines
Two lines with defined slopes are perpendicular if and only if their slopes are.
A vertical line is to a horizontal line.
4. Example: Find the equation of the line that is perpendicular to the line 6x+4y+5 =0 and passes through (1,1).
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.5 Modeling with Equations
Investement Problems
Interest=Principle × Interest Rate × Time (in years)I = Prt
1. Example: Melissa won $60,000 on a slot machine in Las Vegas. She invested partat 2% simple interest and the rest at 3%. In one year she earned a total of $1,600in interest. How much was invested at each rate?
Solution:Define a variable. Let x=
Organize relevant data into a table or a chart
principal × rate = interest1st account2nd account
Together
Equation:
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Mixture Problems
2. Example: A chemist needs 180 ml of a 55% solution but has only 22% and 76%solutions available. Find how many ml of each should be mixed to get the desiredsolution.
Solve this problem by using only one variable.
Solution:
Define a variable. Let x=
Organize relevant data into a table.
Percent × ml = Amount of So-lution
Solution 1 (high %)Solution 2 (low %)Mixture (middle %)
Equation:
Solve!
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Work Problems
The standard equation that will be needed for these problems is
Portion of job done in given time=work rate × time spent working
When two or more objects are working, the setup becomes
work rate of object 1 + work rate of object 2 =one job done× ×time spent working time spent working
or
time together
time apart+time together
time apart=one job done
3. Example: An office has two envelope stuffing machines. Machine A can stuff abatch of envelopes in 5 hours, while Machine B can stuff a batch of envelopes in 3hours. How long would it take the two machines working together to stuff a batchof envelopes?
Solution:
Define a variable. Let t
time together
time apart+time together
time apart=one job done
Equation:
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Math 141, Jagodina Chapter 1 Notes Math lab may help
4. Example: Mary can clean an office complex in 5 hours. Working together John andMary can clean the office complex in 3.5 hours. How long would it take John toclean the office complex by himself?
Solution:
Define a variable. Let t
Motion Problems
The standard formula that we’ll be using here is
Distance=Rate × Time
5. Example: Two cars are 500 miles apart and moving directly towards each other.One car is moving at a speed of 100 mph and the other is moving at 70 mph. As-suming that the cars start moving at the same time how long does it take for thetwo cars to meet?
Solution:
Draw a diagram.
Define a variable. Let t
Organize relevant data into a table.
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Rate Time DistanceCar 1Car 2Total
Equation:
Solve!
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.6 Quadratic Equations
Solving using factoring
The zero factor property:If ab = 0 then either a = 0 and/or b = 0
1. Example: Solve by factoring
(a) 4m2 − 1 = 0 (b) 10z2 + 19z + 6 = 0 (c) 5x2 = 2x
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Completing the Square
If you start with x2 + bx and add
(b
2
)2
, you’ll get a factorable trinomial:
x2 + bx +
(b
2
)2
factors as
(x +
b
2
)2
This process is called completing the square.
2. Example: Use completing the square to solve each equation.
(a) x2 + 6x + 1 = 0 (b) 2x2 + 7x + 2 = 0
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Quadratic Formula
If ax2 + bx + c = 0, then
x =−b±
√b2 − 4ac
2a.
3. Example: Solve1
3x2 +
5
3x = 1 using the quadratic formula.
Applications of Quadratic Equations
4. Example: An object is thrown or fired straight upward at an initial speed of v0 ft/swill reach a height of h feet after t seconds, where h and t are related by the formula
h(t) = −16t2 + v0t.
Suppose that a bullet is shot straight upward with an initial speed of 800 ft/s.
(a) When does the bullet fall back to ground level?
(b) When does the bullet reach a height of 6,400 ft?
(c) When does it reach a height of 1 miles?
(d) How high is the highest point the bullet reaches?
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.7 Solving Other Types of Equations
Polynomial Equations
1. Example: Solve x3 = 16x
2. Example: Solve 5x3 − 5x2 − 10x = 0
3. Example: Solve 2x3 + x2 − 18x− 9 = 0
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Rational equations
4. Example: Solve.10
x− 12
x− 3= −4
5. Example: Solve.
x
2x + 7− x + 1
x + 3= 1
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Radical Equations
6. Example: Solve each equation.
(a)√
4− 6x = 2x
(b)√x + 1 + 2x = 8
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Equations quadratic in form
7. Example: Solve each equation.
(a) x4 − 5x2 + 4 = 0
Equations with Fractional Powers
8. Example: Solve each equation.
(a) x43 = 4 (b) x
43 − 5x
23 + 6 = 0
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.8 Solving Inequalities
To solve an inequality, we must isolate the variable on one side of the inequalitysymbol. When both sides of an inequality are multiplied or divided by a negativenumber, the direction of the inequality symbol reverses.
1. Example: Solve each inequality. Give the solution set in set-builder notation andinterval notation.
(a) −3t + 11 < −1
(b)1
4z − 1
2≥ 2z
3+ 2
(c) 2 < 3x− 4 ≤ 9
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Quadratic Inequalities
2. Example: Solve 2x2 − x > 1
3. Example: Solve (x− 3)2(x + 3)3 < 0
Rational Inequalities
4. Example: Solvex + 1
x + 4≥ 0
5. Example: Solve3 + x
3− x> 1
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Math 141, Jagodina Chapter 1 Notes Math lab may help
1.9 Absolute Value Equations andInequalities
Equations
Rule: |expression| = a⇒ expression=a or expression=−a where a ≥ 0
Before you can use the rule above, you must isolate the absolute value on the leftside.
1. Example: Solve each equation.
(a) |x + 2| = 4
(b) 3|2x + 1|+ 2 = 8
(c) |x + 2| = |2x− 1|
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Math 141, Jagodina Chapter 1 Notes Math lab may help
Absolute value inequalities
Rule: |x| > c→ x > c OR x < −c
This rule applies to |x| ≥ c as well.
Rule: |x| < c→ −c < x < c
This rule applies to |x| ≤ c as well.
2. Example: Solve each inequality. Give the solution set in interval notation.
(a) |x + 1| > 4 (b) |2x− 3| ≤ 4 (c) |x + 1| ≥ −3
(d) |x + 3| < −2 (e) |2x + 1| ≤ 0
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