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8/12/2019 Materials c
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Crystallographic Points, Directions, and Planes.
ISSUES TO ADDRESS...
• How to define points, directions, planes, as well as
linear, planar, and volume densities
– Define basic terms and give examples of each:
• Points (atomic positions)
• Vectors (defines a particular direction - plane normal )
• Miller Indices (defines a particular plane)
• relation to diffraction
• 3-index for cubic and 4-index notation for HCP
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
a
b
c
Points, Directions, and Planes in Terms of Unit Cell Vectors
All periodic unit cells may be described viathese vectors and angles, if and only if • a, b, and c define axes of a 3D coordinate system.
• coordinate system is Right-Handed!
But, we can define points, directions and
planes with a “triplet” of numbers in uni ts
of a , b , and c unit cell vectors.
For HCP we need a “quad” of numbers, as
we shall see.
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
POINT Coordinates
To define a point within a unit cell….
Express the coordinates uvw as fractions of unit cell vectors a , b , and c
(so that the axes x, y, and z do not have to be orthogonal).
a
b
c
origin
pt. coord.
x (a ) y (b ) z (c )
0 0 0
1 0 0
1 1 1
1/2 0 1/2
pt.
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Crystallographic Directions
Procedure:
1. Any line (or vector direction) is specified by 2 points.
• The first point is, typically, at the origin (000).
2. Determine length of vector projection in each of 3 axes in
units (or fractions) of a, b, and c.• X (a), Y(b), Z(c)
1 1 0
3. Multiply or divide by a common factor to reduce the
lengths to the smallest integer values, u v w.
4. Enclose in square brackets: [u v w]: [110] direction.
ab
c
DIRECTIONS will help define PLANES (Miller Indices or plane normal ).
[ 1 1 0]5. Designate negative numbers by a bar• Pronounced “bar 1”, “bar 1”, “zero” direction.
6. “Family” of [110] directions is designated as <110>.
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Self-Assessment Example 1: What is crystallographic direction?
ab
c Along x: 1 a
Along y: 1 b
Along z: 1 c
[1 1 1]DIRECTION =
Magnitude alongX
Y
Z
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Self-Assessment Example 2:
(a) What is the lattice point given by point P?
(b) What is crystallographic direction
for the origin to P?
The lattice direction [132] from the origin.
Example 3: What lattice direction does the lattice point 264 correspond?
[ 1 12]
112
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Symmetry Equivalent Directions
Note: for some crystal structures, differentdirections can be equivalent.
e.g. For cubic crystals, the directions are all
equivalent by symmetry:
[1 0 0], [ 0 0], [0 1 0], [0 0], [0 0 1], [0 0 ]111
Families of crystallographic directions
e.g. <1 0 0>
Angled brackets denote a family of crystallographic directions.
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Families and Symmetry: Cubic Symmetry
x
y
z
(100)
Rotate 90o about z-axis
x
y
z
(010)
x
y
z
(001)Rotate 90o about y-axis
Similarly for other
equivalent directions
Symmetry operation can
generate all the directions
within in a family.
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Designating Lattice Planes
Why are planes in a lattice important?
(A) Determining crystal structure * Diffraction methods measure the distance between parallel lattice planes of atoms.
• This information is used to determine the lattice parameters in a crystal.
* Diffraction methods also measure the angles between lattice planes.
(B) Plastic deformation
* Plastic deformation in metals occurs by the slip of atoms past each other in the crystal.
* This slip tends to occur preferentially along specific crystal-dependent planes.
(C) Transport Properties
* In certain materials, atomic structure in some planes causes the transport of electrons
and/or heat to be particularly rapid in that plane, and relatively slow not in the plane.
• Example: Graphite: heat conduction is more in sp2
-bonded plane.
• Example: YBa2Cu3O7 superconductors: Cu-O planes conduct pairs of electrons
(Cooper pairs) responsible for superconductivity, but perpendicular insulating.
+ Some lattice planes contain only Cu and O
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How Do We Designate Lattice Planes?
Example 1
Planes intersects axes at:• a axis at r= 2
• b axis at s= 4/3
• c axis at t= 1/2
How do we symbolically designate planes in a lattice?
Possibility #1: Enclose the values of r, s, and t in parentheses (r s t)
Advantages:
• r, s, and t uniquely specify the plane in the lattice, relative to the origin.
• Parentheses designate planes, as opposed to directions given by [...]
Disadvantage:
• What happens if the plane is parallel to --- i.e. does not intersect--- one of the axes?
• Then we would say that the plane intersects that axis at ∞ !
• This designation is unwieldy and inconvenient.
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How Do We Designate Lattice Planes?
Planes intersects axes at:• a axis at r= 2
• b axis at s= 4/3• c axis at t= 1/2
How do we symbolically designate planes in a lattice?
Possibility #2: THE ACCEPTED ONE
1. Take the reciprocal of r, s, and t.
• Here: 1/r = 1/2 , 1/s = 3/4 , and 1/r = 2
2. Find the least common multipl e that converts all reciprocals to integers.
• With LCM = 4, h = 4/r = 2 , k= 4/s = 3 , and l= 4/r = 8
3. Enclose the new triple (h,k,l) in parentheses: (238)
4. This notation is called the Miller Index.
* Note: If a plane does not intercept an axes (I.e., it is at ∞ ), then you get 0.
* Note: All parallel planes at similar staggered distances have the same Miller index.
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Self-Assessment Example
What is the designation of this plane in Miller Index notation?
What is the designation of the top face of the unit cell
in Miller Index notation?
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z
x
y
Look down this direction
(perpendicular to the plane)
Crystallographic Planes in FCC: (100)
d 100 aDistance between (100) planes
Distance to (200) plane d 200 a
2
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Crystallographic Planes in FCC: (110)
d 110 a 2
2
Distance between (110) planes
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Crystallographic Planes in FCC: (111)
z
x
y
Look down this direction(perpendicular to the plane)
d 111 a 3
3Distance between (111) planes
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Note: similar to crystallographic directions, planes that are parallel to
each other, are equivalent
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Comparing Different Crystallographic Planes
-1
1
For (220) Miller Indexed planes you are getting planes at 1/2, 1/2, ∞.
The (110) planes are not necessarily (220) planes!
For cubic crystals: Miller Indices provide you easy
measure of distance between planes.
d 110 a
1212
02
a
2
a 2
2
Distance between (110) planes
For any vector, v
cos(vx)+cos(vy)+cos(vz)=1
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Directions in HCP Crystals
1. To emphasize that they are equal, a and b is changed to a1 and a2.
2. The unit cell is outlined in blue.
3. A fourth axis is introduced (a3) to show symmetry.• Symmetry about c axis makes a3 equivalent to a1 and a2.
• Vector addition gives a3 = –( a1 + a2).
4. This 4-coordinate system is used: [a1 a2 –( a1 + a2) c]
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Directions in HCP Crystals: 4-index notation
Example What is 4-index notation for vector D?
• Projecting the vector onto the basal plane, it lies
between a1 and a2 (vector B is projection).
• Vector B = (a1 + a2), so the direction is [110] in
coordinates of [a1 a2 c], where c-intercept is 0.
• In 4-index notation, because a3 = –( a1 + a2), the
vector B is since it is 3x farther out.
• In 4-index notation c = [0001], which must be
added to get D (reduced to integers) D = [1123]
Self-Assessment Test: What is vector C?
Easiest to remember: Find the coordinate axes that straddle the vector
of interest, and follow along those axes (but divide the a1, a2 , a3 part of vector
by 3 because you are now three times farther out!).
1
3[112 0]
Check w/ Eq. 3.7
or just use Eq. 3.7
a2
–
2a3 B without 1/3
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Directions in HCP Crystals: 4-index notation
Example
What is 4-index notation for vector D?• Projection of the vector D in units of [a1 a2 c] gives
u’=1, v’=1, and w’=1. Already reduced integers.
• Using Eq. 3.7:
[112 3]
[1
3
1
3
2
3 1]
Check w/ Eq. 3.7: a dot-product projection in hex coords.
u 13
[2u 'v ' ] v 13
[2v 'u ' ] w w '
u
1
3[2(1)1]
1
3v
1
3[2(1)1]
1
3w w '1
• In 4-index notation:
• Reduce to smallest integers:
After some consideration, seems just using Eq. 3.7 most trustworthy.
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Miller Indices for HCP Planes
As soon as you see [1100], you will know
that it is HCP, and not [110] cubic!
4-index notation is more important for planes in HCP, in order
to distinguish similar planes rotated by 120o.
1. Find the intercepts, r and s, of the plane with any two
of the basal plane axes (a1, a2, or a3), as well as the
intercept, t , with the c axes.
2. Get reciprocals 1/r, 1/s, and 1/t.
3. Convert reciprocals to smallest integers in same ratios.
4. Get h, k, i , l via relation i = - (h+k ), where h isassociated with a1, k with a2, i with a3, and l with c.
5. Enclose 4-indices in parenthesis: (h k i l ) .
Find Miller Indices for HCP:
r s
t
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
Yes, Yes….we can get it without a3!
1. The plane’s intercept a1, a2 and c
at r=1, s= –1/2 and t= ∞, respectively.
2. The reciprocals are 1/r = 1, 1/s = –2, and 1/t = 0.
3. They are already smallest integers.
4. We can write (h k i l ) =
5. Using i = - (h+k ) relation , i=1 .
6. Miller Index is (12 10)
(12 ?0)
But note that the 4-index notation is unique….Consider all 4 intercepts:
• plane intercept a1, a2, a3 and c at 1, –1/2, 1, and ∞, respectively.
• Reciprocals are 1, –2, 1, and 0.
• So, there is only 1 possible Miller Index is (12 10)
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
a1
a2
a3
• Parallel to a1, a2 and a3 • So, h = k = i = 0
• Intersects at z = 1
Name this plane…
Basal Plane in HCP
plane (0001)
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
z
a1
a2
a3
(1 1 0 0) plane
+1 in a1
-1 in a2
h = 1, l = 0i = -(1+-1) = 0,k = -1,
Another Plane in HCP
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MSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006-10
(1 1 1) plane of FCC
z
x
y
z
a1
a2
a3
(0 0 0 1) plane of HCPSAME THING!*
SUMMARY
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SUMMARY
• Crystal Structure can be defined by space lattice and basis atoms (lattice decorations or motifs).
• Only 14 Bravais Lattices are possible. We focus only on FCC, HCP,
and BCC, i.e., the majority in the periodic table.
• We now can identify and determined: atomic positions, atomic planes
(Miller Indices), packing along directions (LD) and in planes (PD).
• We now know how to determine structure mathematically.
So how to we do it experimentally? DIFFRACTION .