Marking Scheme — Computer Sciencecbseocean.weebly.com/uploads/2/8/1/5/28152469/2015csms.pdfMarking Scheme — Computer Science General Instructions : z The answers given in the marking

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Marking Scheme — Computer Science

General Instructions :

The answers given in the marking scheme are SUGGESTIVE, Examiners are requested to

award marks for all alternative correct Solutions/Answers conveying similar meaning.

All programming questions have to be answered with respect to C++ Language for Section

A and Python for Section B (All presently supported versions of compilers/interpreters

should the considered).

In C++/Python, ignore case sensitivity for identifiers (Variable / Functions / Structures /

Class Names) unless explicitly specified in question.

In SQL related questions:

– Both ways of text/character entries should be acceptable. For example: "AMAR"

and 'amar' both are acceptable.

– All date entries should be acceptable for example: 'YYVY-MM-DD', 'YY-MM-

DD', 'DD-Mon-YY', UDD/MM/YY" , 'DD/MMIYY', 'MM/DD/YY", 'MM/DD/

YY' and {MM/DD/YY} are correct.

– Semicolon should be ignored for terminating the SQL statements.

– Ignore case sensitivity for commands.

– Ignore headers in output questions.

QUESTION PAPER CODE 91/1EXPECTED ANSWERS

Section-A(Only for C++ Candidates)

1. (a) Find the correct identifiers out of the following, which can be used for naming

variable, constants or functions in a C++ program: 2

While, for, Float, new, 2ndName, A%B, Amount2, _Counter

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Ans While, Float, Amount2,_Counter

(½ Mark for each correct identifier)

Note:

Deduct ½ Mark for writing additional incorrect identifier(s)

No marks to be awarded if all the identifiers are mentioned

(b) Observe the following program very carefully and write the names of

those header file(s), which are essentially needed to compile and execute the

following program successfully: 1

typedef char TEXT [80];

void main ()

{

TEXT Str[] = "Peace is supreme";

int Index=0;

while (Str[Index] !='\0')

if (isupper(Str[Index]"

Str[Index++]='#';

else

Str[Index++]='*';

puts (Str);

}

Ans ctype, stdio

(½ Mark for each correct header file)

Note:

Ignore any additional header file(s)

422

(c) Observe the following C++ code very carefully and rewrite it after removing

any/all syntactical errors with each correction underlined. 2

Note: Assume all required header files are" already being included in the

program.

#Define float Max=70.0;

Void maine)

{

int Speed

char Stop='N';

cin>>Speed;

if Speed>Max

Stop='Y';

cout<<Stop<<end;

}

Ans #define Max 70.0 //Error 1,2,3

void main () //Error 4

{

int Speed ; //Error 5

char Stop=' N' ;

cin>>Speed;

if (Speed>Max) //Error 6

Stop=' Y' ;

cout<<Stop<<endl; //Error 7

}

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(½ Mark for each correction upto a maximum of 4 corrections)

OR

(1 Mark for only identifying any 4 errors, without suggesting

corrections)

(d) Write the output of the following C++ program code: 2

Note : Assume all required header files are already being included in the

program.

void Position(int &Cl, int C2=3)

{

C1+=2;

C2+=Y;

}

void main()

{

int Pl=20, P2=4;

Position(Pl);

cout<<P1<<","<<P2<<endl;

Position(P2,Pl);

cout<<Pl<<","<<P2<<endl;

}

Ans 22, 4

22, 6

(½ Mark for each correct value of output)

424

Note:

Deduct V2 Mark for not considering any or all end/(s) at properp/ace(s)

Deduct 'l'2 Mark for not considering any or all ',' at properplace(s)

OR

(Full 2 marks to be awarded for mentioning Syntax Error ORundeclared variable Y)

(e) Write the output of the following C++ program code: 3

Note: Assume all required header files are already being included in the

program.

class Calc

{

char Grade;

int Bonus;

public:

Calc() {Grade='E';Bonus=0;}

void Down(int G)

{

Grade-=G;

}

Void Up (int G)

{

Grade+=G;

Bonus++;

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}

void Show()

{

cout<<Grade<<"#"<<Bonus<<end1;

}

};

void main()

{

Calc c;

C.Down(2);

C. Show();

C.Up(7);

C.Show();

C.Down(2);

C. Show();

}

Ans C#0

J#l

H#l

(1 Mark for each correct line of output)

Note:

Deduct ½ Mark for not considering any or all end/(s) at properplace(s)

Deduct ½ Mark for not writing any or all # symbol(s)

OR

426

(Full 3 marks to be awarded if undeclared object C OR ERROR isidentified)

(f) Study the following program and select the possible output(s) from the options(i) to (iv) following it. Also, write the maximum and the minimum values thatcan be assigned to the variable NVM. 2

Note:

– Assume all required header files are already being included in theprogram.

– random(n) function generates an integer between 0 and n - 1.

void main()

{

randomize();

int NOM;

NOM=random(3)+2;

char TEXT[]="ABCDEFGHIJK";

for (int I=1;I<=NOM; I++)

{

for(int J=NUM; J<=7iJ++)

cout<<TEXT[J];

cout<<end1;

}

}

(i) FGHI (ii) BCDEFGH (iii) EFGH (iv) CDEFGH

FGHI BCDEFGH EFGH CDEFGH

FGHI EFGH

FGHI EFGH

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Ans (iii) and (iv) Minimum value of NUM = 2

Maximum value of NUM = 4

(½ Mark for writing option (iii) )

(½ Mark for writing option (iv) )

Note: Deduct V2 mark for writing each additional option along with

both correct options

(½ Mark for writing correct Minimum value of NUM)

(½ Mark for writing correct Maximum value of NUM)

2. (a) What is a copy constructor? Give a suitable example in C++ to illustrate with

its definition within a class and a declaration of an object with the help of it. 2

Ans A copy constructor is an overloaded constructor in which an object of the

same class is passed as reference parameter.

class Point

{

int x;

public:

Point () {x=0;}

Point (Point &p) // Copy constructor

{x = p.x;}

:

} ;

void main ()

{

Point p1;

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Point p2(p1);//Copy constructor is called here

//OR

Point p3=pl;//Copy constructor is called here

}

(1½ Mark to be awarded if the copy constructor is explained with an

appropriate example)

OR

(1 Mark for correct explanation of copy constructor only without an

example)

(½ Mark for correct declaration of an object)

(b) Observe the following C++ code and answer the questions (i) and (ii) : 2

class Traveller

{

long PNR;

char TName[20];

public :

Traveller() //Function 1

{cout<<"Ready"<<endl;}

void Book(long P,char N[]) //Function 2

{PNR = P, strcpy(TName, N);}

void Print() //Function 3

{cout<<PNR << TName <<end1;}

~Traveller() //Function 4

cout<<"Booking cancelled"<<endl;

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};

(i) Fill in the blank: statements in Line 1 and Line 2 to execute Function 2

and Function 3 respectively in the following code: 1

void main()

{

Traveller T;

___________ //Line 1

___________ //Line 2

}//Stops here

Ans T.Book(1234567,"Ravi"); //Line 1

T.Print(); //Line 2

(½ Mark for writing each correct Function)

(ii) Which function will be executed at l//Stops here? What is this function

referred as ? 1

Ans Function 4

OR

~Traveller()

It is a Destructor function.

(½ Mark for writing Function 4 or - Traveller())

(½ Mark for referring Destructor)

(c) Write the definition of a class PIC in C++ with following description: 4

Private Members

- Pno //Data member for Picture Number (an integer)

- Category//Data member for Picture Category (a string)

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- Location//Data member for Exhibition Location (a string)

- FixLocation //A member function to assign

//Exhibition Location as per category

//as shown in the following table

Category Location

Classic Amina

Modern Jim P1aq

Antique Ustad Khan

Public Members

- Enter() //A function to allow user to enter values

//Pno, category and call FixLocation() function

- SeeAll() //A function to display all the data members

Ans class PIC

{

int Pno;

char Category[20];

char Location[20];

void FixLocation();

public:

void Enter();

void SeeA11();

} ;

void PIC::FixLocation()

{

431

if (strcmpi (Category,"Classic")==0)

strcpy(Location,"Amina") ;

else if(strcmpi(Category,"Mbdern")==O)

strcpy(Location,"Jim Plaq");

else if strcmpi (Category, "Antique") ==0)

strcpy(Location,"Ustad Khan");

}

void PIC::Enter()

{

cin>>Pno;gets(Category) ;

FixLocation() ;

}

void PIC:: SeeA11()

{

cout<<Pno<<Category<<Location<<endl;

}

(½ Mark for correct syntax for class header)

(½ Mark for correct declaration of data members)

(1 Mark for correct definition of FixLocation())

(1 Mark for correct definition of Enter() with proper invocation ofFixLocation() function)

(1 Mark for correct definition of SeeAll())

NOTE:

Deduct ½ Mark if FixLocation() is not invoked properly insideEnter() function

432

No marks to be deducted for defining Member Functions insidethe class

strcmp()/strcmpi() acceptable

(d) Answer the questions (i) to (iv) based on the following: 4

class Exterior

{

int OrderId;

char Address[20];

protected:

float Advance;

public:

Exterior();

void Book(); void View();

};

class Paint:public Exterior

{

int WallArea,ColorCode;

protected:

char Type;

public:

Paint ();

void PBook();

void PView();

};

433

class Bill : public Paint

{

float Charges;

void Calculate();

public :

Bill ();

void Bil11ng ();

void Print ();

};

(i) Which type of Inheritance out of the following is illustrated in the aboveexample?

– Single Level Inheritance

– Multi Level Inheritance

– Multiple Inheritance

Ans Multi Level Inheritance

(1 Mark for mentioning correct option)

(ii) Write the names of all the data members, which are directly accessiblefrom the member functions of class Paint.

Ans WallArea, ColorCode,Type, Advance

(1 Mark for correct answer)

Note: No marks to be awarded for any partial/additional answer(s)

(iii) Write the names of all the member functions, which are directly accessiblefrom an object of class Bill.

Ans Billing(), Print(), PBook(), PView(), Book(), View()


434

Note:

No marks to be awarded for any partial/additional answer(s)

Constructors can be ignored

(iv) What will be the order ·of execution of the constructors, when an object

of class Bill is declared ?

Ans Exterior(), Paint(), Bill()


Note: No marks to be awarded for any other order

3. (a) Write the definition of a function Alter(int A[], int N) in C++, which should

change all the multiples of 5 in the array to 5 and rest of the elements as O.

For example, if an array of 10 integers is as follows: 2

A[0] A[1] A[2] A[3] A[4] A[5] A[6] A[7] A[8] A[9]

55 43 20 16 39 90 83 40 48 25

After executing the function, the array content should be changed as follows:

A[O] A[l] A[2] A[3] A[4] A[5] A[6] A[7] A[8] A[9]

5 0 5 0 0 5 0 5 0 5

Ans void Alter (int A[ ] lint N)

{

for (int i=0;i<N;i++)

if (A[i] %5==0)

A[i]=5;

else

A[i]=0;

}

435

OR

Any other correct equivalent function definition

(½ Mark for correct loop)

(½ Mark for correct checking of divisibility of array elements by 5)

(½ Mark for correct use of else OR correct checking of non divisibility

of array elements by 5 )

(½ Mark for correct assignment of 5 and 0 for multiples and nonmultiples of 5 respectively)

(b) A two dimensional array P[20] [50] is stored in the memory along the rowwith each of its element occupying 4 bytes, find the address of the elementP[10] [30], if the element P[5] [5] is stored at the memory location 15000. 3

Ans Loc(P[I] [J]) along the row

=BaseAddress+W [(I-LBR)*C+(J-LBC)]

(where C is the number of columns, LBR=LBC=O)

LOC (P [5] [5] )

= BaseAddress + W*[I*C + J]

15000 = BaseAddress + 4*[5*50 + 5]

= BaseAddress + 4*[250 + 5]

= BaseAddress + 4*255

= BaseAddress + 1020

BaseAddress = 15000-1020 = 13980

LOC (P [10] [30]) = 13980 + 4* [10*50+30]

= 13980 + 4*530

= 13980 + 2120

= 16100

436

OR

LOC (P [ 10] [30] )

= Loc(P[5] [5])+ W[(I-LBR)*C+(J-LBC)]

= 15000 + 4[(10-5)*50 + (30-5)]

= 15000 + 4[ 5*50 + 25]

= 15000 + 4 *275

= 15000 + 1100

= 16100

OR

(Where C is the number of columns and LBR=LBC=l)

LOC (P [5] [5])

15000 = BaseAddress + W [( I-1)*C + (J-1)]

= BaseAddress + 4[4*50 + 4]

= BaseAddress + 4[200 + 4]

= BaseAddress + 4 * 204

= BaseAddress + 816

BaseAddress = 15000 - 816 = 14184

LOC (P [10] [30])

= 14184 + 4[(10-1)*50 + (30-1)]

= 14184 + 4[9*50 + 29]

= 14184 + 4[450 + 29]

= 14184 + 4*479

= 14184 + 1916

= 16100

437

(1 Mark for writing correct formula (for row major) ORsubstituting formula with correct values)

( 1 Mark for at least one step of intermediate calculation)

( 1 Mark for final correct address)

(c) Write the definition of a member function Pop( ) in C++, to delete a bookfrom a dynamic stack of TEXTBOOKS considering the following code isalready included in the program. 4

struct TEXTBOOKS

{

char ISBN[20]; char TITLE[80];

TEXTBOOKS *Link;

};

class STACK

{

TEXTBOOKS *Top;

public:

STACK() {Top=NULL;}

void Push();

void pope);

~STACK();

};

Ans void STACK::POP ()

{

if (Top!=NULL)

438

{

TEXTBOOKS *Temp;

Temp=Top;

cout<<Top->ISBN<<Top->TITLE<<"deleted"<<endl;

Top=Top->Link;

delete Temp;

}

else

cout<<"Stack EmptY"<<endl;

}

OR


(1 Mark for checking Empty/Non-empty STACK)

( 1 Mark for assigning Top to Temp)

(1 Mark for linking the Top to next node)

(1 Mark for deleting Temp node)

(d) Write a function REVCOL (int P[] [5], int N, int M) in C++ to display

the content of a two dimensional array, with each column content in reverse

order. 3

Note: Array may contain any number of rows.

For example, if the content of array is as follows:

15 12 56 45 51

13 91 92 87 63

11 23 61 46 81

439

The function should display output as :

11 23 61 46 81

13 91 92 87 63

15 12 56 45 51

Ans void REVCOL(int P[] [5],int N,int M)

{

for(int I=N-1;I>=0; I--)

{

for(int J=0; J<M; J++)

cout<<P[1] [J];

cout<<endl;

}

}

OR

void REVCOL(int P[] [5],int N,int M)

{

for(int I=0;1<N/2;1++)

{

for(int J=0;J<M;J++)

{

int T = P[1] [J];

P[1] [J] = P[N-1-l] [J];

P[N-I-l] [J] = T;

}

440

}

for (I=0; I<N; 1++)

{

for(int J=0; J<M; J++)

cout<<P[1] [J];

cout<<endl;

}

}

(1 Mark for correct nestjng of loop(s)

(1½ Mark for correct logic for reversing the content of each column)

(½ Mark for correctly displaying the content)

Note:

N and M can be written interchangeably for number of rows

and columns

(e) Convert the following infix expression to its equivalent Postfix expression,

showing the stack contents for each step of conversion. 2

X / Y + U* (V-W)

Ans X / Y + U*(V-W) = ((X / Y) + (U*(V-W)))

Element Stack Postfix

(

(

X X

/ / X

Y / XY

441

) XY/

+ + XY/

( + XY/

U + XY/U

* + * XY/U

( + * XY/U

V + * XY/UV

- + * - XY/UV

W + * - XY/UVW

) + * XY/UVW-

) + XY/UVW-*

) XY/UVW-*+

OR


X X

/ / X

Y / XY

+ + XY

U + XY/U

* +* XY/U

( +*( XY/U

V +*( XY/UV

- +*(- XY/UV

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W +*(- XY/UVW-

) +* XY/UVW-*

XY/UVW-*+

OR

Any other method for converting the given Infix expression to its

equivalent Postfix expression showing stack contents

(½ Mark for converting expression up to each operator)

OR

(1 Mark to be given for writing correct answer without showing the

Stack Content on each step)

4. (a) Write function definition for SUCCESS( ) in C++ to read the content of a text

file STORY.TXT, count the presence of word STORY and display the number

of occurrence of this word. 2

Note:

– The word STORY should be an independent word

– Ignore type cases (i.e. lower/upper case)

Example:

If the content of the file STORY.TXT is as follows:

Success shows others that we can do it. It is

possible to achieve success with hard work. Lot

of money does not mean SUCCESS.

The function SUCCESS( ) should display the following:

3

Ans voidSUCCESS ()

{

443

int count=0;

ifstream f("STORY.TXT") ;

char s[20] ;

while (!f.eof () )

{

f>>s;

if (strcmpi (s,"STORY")==0)

//OR if(strcmpi(s,"SUCCESS")==0)

count++;

}

cout<<count;

f.close () ;

}

OR

Any other correct function definition

(½ Mark for opening STORY. TXT correctly)

(½ Mark for reading each word (using any method) from the file)

(½ Mark for comparing the word with STORY OR SUCCESS)

(½ Mark for displaying correct count of STORY OR SUCCESS)

NOTE:

(½ Mark to be deducted if STORY or SUCCESS is compared withoutignoring the case)

(b) Write a definition for function Economic ( ) in C++ to read each record of a

binary file ITEMS.DAT, find and display those items, which costs less than

444

2500. Assume that the file ITEMS.DAT is created with the help of objects of

class ITEMS, which is defined below: 3

class ITEMS

{

int ID;char GIFT[20]; float Cost;

public :

void Get ()

{

cin>>CODE;gets(GIFT);cin>>Cost;

}

void See ()

{

cout<<ID<<":"<<GIFT<<":"<<Cost<<end1;

}

float GetCost() {return Cost;}.

};

Ans void Economic()

{

ITEMS I;

ifstream fin ("ITEMS.DAT", ios::binary);

while (fin.read((char *)&I,sizeof(I)))

{

if(I.GetCost()<2500)

I. See () ;

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}

fin. close () ;

}

OR


(½ Mark for opening ITEMS.DAT correctly)

(1 Mark for reading all records from the file)

(1 Mark for checking value of Cost < 2500 )

(½ Mark for displaying the desired items)

(c) Find the output of the following C++ code considering that the binary file

CLIENTS.DAT exists on the hard disk with records of 100 members. 1

class CLIENTS

{

int Cno;char Name[20];

public :

void In(); void Out();

};

void main()

{

fstream CF;

CF.open("CLIENTS.DAT",ios::binary|ios::in);

CLIENTS C;

CF.read((char*) &C, sizeof(C));


446


int POS=CF.tellg()/sizeof(C);

cout<<"PRESENT RECORD:"<<POS<<end1;

CF.close () ;

}

Ans PRESENT RECORD: 3

(1 Mark for writing PRESENT RECORD: 3)

OR

(1 Mark for writing only 3)

OR

(½ Mark for writing only PRESENT RECORD:)

Section-B

(Only for Python Candidates)

1. (a) How is_init( ) _different from _del ( ) _ ? 2

Ans _init_() is the class constructor or initialization method which is automaticallyinvoked when we create a new instance of a class

_del_() is a destructor which is automatically invoked when an object(instance) goes out of scope.

For Example:

class Sample:

def _init__(se1f) :

se1f.data = 79

print ('Data:',self.data, 'created')

def _de1 __ (self) :

print('Data: ',self.data,'deleted')

447

s = Sample ()

del s

(2 Marks for correct differentiation)

OR

(2 Marks for differentiation through example)

OR

(1 Mark for each correct definition)

(b) Name the function/method required to 1

(i) check if a string contains only uppercase letters

(ii) gives the total length of the list.

Ans (i) isupper()

(ii) len()

(½ Mark for each correct function/ method name)

(c) Rewrite the following code in python after removing all syntax error(s).

Underline each correction done in the code. 2

def Tot(Number) #Method to find Total

Sum=0

for C in Range (1, Number+1):

Sum+=C

RETURN Sum

print Tot[3] #Function Calls

print Tot[6]

Ans def Tot (Number) : #Method to find Total #Error 1

Sum=0

448

for C in range (1, Number+1) : #Error 2

Sum+=C

return Sum #Error 3

print Tot (3) #Function Call #Error 4

print Tot (6) #Error 4

(½ Mark for each correction)

OR

(1 mark for identifying all the errors, without suggesting corrections)

(d) Find and write the output of the following python code : 2

for Name in ['Jayes', 'Ramya', 'Taruna', 'Suraj']:

print Name

if Name[0]== 'T':

break

else :

print 'Finished1'

print 'Got it!'

Ans Jayes

Ramya

Taruna

Got it!

(½ Mark for each correct line)

Note:

Deduct ½ Mark for not considering any or all line breaks at properplace(s)

449

(e) Find and write the output of the following python code : 3

class Worker :

def_init_(self,id,name) : #constructor

self.ID=id

self.NAME=name

def Change(self):

self.ID=self.ID+10

self.NAME='Harish'

def Display (self,ROW) :

print self.ID,self.NAME,ROW

w=Worker(55,'Fardeen')

w.Display(l)

w.Change ()

w.Display(2)

print w.ID+len(w.NAME)

Ans 55 Fardeen 1

65 Harish 2

71

(1 Mark for each correct line)

Note:

Deduct ½ Mark for not considering any or all line break(s) at properplace(s).

(f) What are the possible outcome(s) executed from the following code? Alsospecify the maximum and minimum values that can be assigned to variable

NUMBER. 2

450

STRING="CBSEONLINE"

NUMBER=random.randint(0,3)

N=9

while STRING[N] !='L':

print STRING[N]+STRING[NUMBER]+'#',

NUMBER=NUMBER+l

N=N-l

(i) ES#NE#IO# (ii) LE#NO#ON# (iii) NS#IE#LO#

(iv) EC#NB#IS#

Ans (i) ES#NE#IO#

(iv) EC#NB#IS#

Minimum value of NUMBER = 0

Maximum value of NUMBER = 3

(½ Mark for writing option (i))

(½ Mark for writing option (iv) )

Note:

Deduct ½ mark for writing each additional option along withboth correct options

(½ Mark for writing correct Minimum value of NUMBER)

(½ Mark for writing correct Maximum value of NUMBER)

2. (a) Illustrate the concept inheritance with the help of a python code. 2

Ans class Base :

def __init__ (self):

print "Base Constructor at work ... "

451

def show (self) :

print "Hello Base"

class Der(Base) :

def __init__ (self):

print "Derived Constructor at work ... "

def display (self) :

print "Hello from Derived"

(1 Mark for base class)

(1 Mark for derived class)

(b) What will be the output of the following python code ? Explain the try and

except used in the code. 2

U=0

V=6

print 'First'

try:

print 'Second'

M=V/U

print 'Third',M

except ZeroDivisionError

print V*3

print 'Fourth'

except:

print V*4

print 'Fifth'

452

Ans First

Second

18

Fourth

The code written within try triggers the exception written after exceptZero Division Error: in case there is a division by zero error otherwisethe default exception is executed

OR

Any other correct explanation for usage of try and except

(½ Mark for first two lines of correct output)

(½ Mark for next two lines of correct output)

(½ Mark each for correct explanation of try and except)

(c) Write a class PICTURE in Python with following specifications: 4

Instance Attributes

- Pno # Numeric value

- Category # String value

- Location # Exhibition Location with String value

Methods:

- FixLocation() # A method to assign

# Exhibition Location as per Category

# as shown in the following table

Category Location

Classic Amina

Modern Jim Plaq

Antique Ustad Khan

453

- Enter() # A function to allow user to enter values

# Pno, Category and call FixLocation()method

- SeeAll()# A function to display all the data members

Ans class PICTURE:

Pno=0

Category=" "

Location=" "

def FixLocation() :

if self.Category=="Classic":

self. Location="Amina"

elif self.Category "Modern":

self.Location="Jim Plaq"

elif self.Category=="Antique":

self.Location="Ustad Khan"

def Enter() :

self.Pno=int(input("Enter Pno:"))

self.Category=input("Enter Name:")

self.FixLocation()

def SeeA11 ()

print self.Pno,self.Category,self.Location


(½ Mark for correct declaration of instance attributes)

(1 Mark for correct definition of FixLocation())

(1 Mark for correct definition of Enter() with proper invocation ofFixLocation() method)

454

(1 Mark for correct definition of SeeAll())

NOTE:

Deduct ½ Mark if FixLocation() is not invoked properly inside Enter()

method

(d) What is operator overloading with methods ? Illustrate with the help of anexample using a python code. 2

Ans Operator overloading is an ability to use an operator in more than one form.

Examples:

In the following example operator + is used for finding the sum of

two integers:

a = 7

b = 5

print (a+b) # gives the output: 12

Whereas in the next example, shown below the same + operator is used to

add two strings:

a = 'Indian'

b = 'Government'

print (a+b) #gives the output: Indian Government

(1 Mark for correct definition of Operator overloading)

(1 Mark for correct example of Python code to illustrate Operator

overloading)

(e) Write a method in python to display the elements of list thrice if it is a numberand display the element terminated with '#' if it is not a number. 2

For example, if the content of list is as follows :

ThisList=['41', 'DROND', 'GIRIRAJ', '13', 'ZARA']

455

The output should be

414141

DROND#

GIRIRAJ#

131313

ZARA#

Ans def fun (L) :

for I in L:

if I.isnumeric() :

print(3*I) # equivalently: print(I+I+I)

else:

print(I+'#')


(½ Mark for checking numeric/non numeric)

(½ Mark for displaying numeric content)


3. (a) What will be the status of the following list after fourth pass of bubble sort

and fourth pass of selection sort used for arranging the following elements in

descending order ? 3

14, 10, -12, 9, 15, 35

Ans Bubble Sort

14,10,-12,9,15,35 (Original Content)

i. 14,10,9,15,35,-12

ii. 14,10,15,35,9,-12

456

iii. 14,15,35,10,9,-12

iv. 15,35,14,10,9,-12 (Unsorted status

after 4th pass)

Selection Sort

14,10,-12,9,15,35 (Original Content)

i. 35,10,-12,9,15,14

ii. 35,15,-12,9,10,14

iii. 35,15,14,9,10,-12

iv. 35,15,14,10,9,-12

For Bubble Sort

(1½ Mark if (iv) pass is correct)

OR

(½ Mark for (i) pass)

(½ Mark for (jj) pass)

(½ Mark for (iii) pass)

For Selection Sort


OR

(½ Mark for {i) pass)

(½ Mark for (ii) pass)


(b) Write a method in python to search for a value in a given list (assuming that the

elements in list are in ascending order) with the help of Binary Search method.

The method should return -1 if the value not present else it should return

position of the value present in the list. 2

457

Ans def bSearch(L, key):

low = 0

high = len(L)-l

found = False

while (low <= high) and (not found) :

mid = (low+high)//2

if L[mid]== key:

found = True

elif L[mid] < key:

low = mid + 1

else:

high = mid - 1

if found:

return mid+1 # may even be 'return mid'

else:

return -1

(½ Mark for correct Initialization of lower and upper bounds)


(½ Mark for reassigning Mid, Low, Up bound)

(½ Mark for returning correct value)

(c) Write PUSH (Books) and POP (Books) methods in python to add Books

and remove Books considering them to act as Push and Pop operations of

Stack. 4

Ans def push (Books):

458

Stack.append (Books)

print 'Element:',Book,'inserted successfully'

def pop() :

if Stack == []:

print (' Stack is empty! ')

e1se:

print('De1eted element is', Stack.pop())

(2 Marks for correctly pushing an element into the stack)

(1 Mark for checking empty stack in POP()

(1 Mark for popping element from stack)

(d) Write a method in python to find and display the prime numbers between 2 to

N. Pass N as argument to the method. 3

Ans def prime_numbers(N):

for I in range(2, N+1):

M = I // 2

IsPrime=l

for J in range(2, M+1) :

if I % J == 0:

IsPrime=0

break

if IsPrime==l:

print (I)

OR

Any other correct equivalent method definition

459

(1 Mark for correct loops)

(1 Mark for checking prime numbers between 2 to N)

(1 Mark for displaying the numbers)

(e) Evaluate the following postfix notation of expression. Show status of stack

after every operation. 2

84, 62, -, 14, 3, ", +

Ans E1ement Stack

84 84

62 84, 62

- 22

14 22, 14

3 22, 14, 3

* 22, 42

+ 64

(1 mark for evaluating till 22)

(½ mark for evaluating till 22,42)

(½ mark for evaluating till final 64)

Note:

Only 1 mark to be awarded for evaluating final answer as 64 without

showing stack contents

4. (a) Differentiate between the following : 1

(i) f = open ('diary. txt', 'r' )

(ii) f = open ('diary. txt', 'w')

460

Ans (i) diary.txt is opened for reading data

(ii) diary. txt is opened for writing data

(1 mark for writing correct difference)

OR

(½ Mark for each correct explanation of (i) and (11))

(b) Write a method in python to read the content from a text file diary.txt line by

line and display the same on screen. 2

Ans def read_file () :

inFile = open('diary.txt','r')

for line in inFile:

print line

(½ Mark for opening the file)

(1 Mark for reading all lines)

(½ Mark for displaying all lines)

(c) Consider the following definition of class Member, write a method in python

to write the content in a pickled file member.dat. 3

class Member:

def_init_(se1f,Mno,N):

se1f.Memno=Mno

se1f.Name=N

def Show(self):

Display(self.Memno,"#",self.Name)

Ans import pickle

class Member:

461

def_init_(self, Mno, N) :

self.Memno=Mno

self.Name=N

def Show (self) :

Display (self.Memno, "#", self . Name)

def store_data (self) :

piFile = open ('member. dat', 'wb')

pickle.dump (self, piFile)

piFile.close()

(1 Mark for method header)

(1 Mark for opening the file member dat in correct mode)

(1 Mark each for writing member details into the file)

Section-C

(For all Candidates)

5. (a) Observe the following table carefully and write the names of the most

appropriate columns, which can be considered as (i) candidate keys and

(ii) primary key. 2

Id Product Qty Price Transaction Date

101 Plastic Folder 12" 100 3400 2014-12-14

104 Pen Stand Standard 200 4500 2015-01-31

105 Stapler Medium 250 1200 2015-02-28

109 Punching Machine Big 200 1400 2015-03-12

103 Stapler Mini 100 1500 2015-02-02

462

Ans Candidate keys : ld, Product

Primary keys : ld

(1 Mark for writing correct Candidate keys)

(1 Mark for writing correct Primary key)

Note:

No marks to be deducted for mentioning Price andlor TransactionDate as additional candidate keys.

(b) Consider the following DEPT and WORKER tables. Write SQL queries for(i) to (iv) and find outputs for SQL queries (v) to (viii) : 6

Table: DEPT

DCODE DEPARTMENT CITY

D01 MEDIA DELHI

D02 MARKETING DELHI

D03 INFRASTRUCTURE MUMBAI

DO5 FINANCE KOLKATA

D04 HUMAN RESOURCE MUMBAI

Table: WORKER

WNO NAME DOJ DOB GENDER DCODE

1001 George K 2013-09-02 1991-09-01 MALE DO1

1002 Ryma Sen 2012-12-11 1990-12-15 FEMALE D03

1003 Mohitesh 2013-02-03 1987-09-04 MALE DOS

1007 Ani1 Jha 2014-01-17 1984-10-19 MALE D04

1004 Manila Sahai 2012-12-09 1986-11-14 FEMALE DO1

1005 R SAHAY 2013-11-18 1987-03-31 MALE D02

1006 Jaya Priya 2014-06-09 1985-06-23 FEMALE DOS

463

Note: DOJ refers to date of joining and DOB refers to date of Birth ofworkers.

(i) To display Wno, Name, Gender from the table WORKER in descendingorder of Wno.

Ans SELECT Wno,Narne,GenderFROM Worker

ORDER BY Wno DESC;

(½ Mark for SELECT Wno, Name, Gender FROM Worker)

(½ Mark for ORDER BY Wno DESC)

(ii) To display the Name of all the FEMALE workers from the tableWORKER.

Ans SELECT Name FROM Worker

WHERE Gender='FEMALE' ;

(½ Mark for SELECT Name FROM Worker)

(½ Mark for WHERE Gender =' FEMALE' )

(iii) To display the Wno and Name of those workers from the tableWORKER who are born between '1987-01-01' and '1991-12-01'.

Ans SELECT Wno, Name FROM Worker

WHERE DOB BETWEEN '1987-01-01' AND '1991-12-01';

OR

SELECT Wno, Name FROM Worker

WHERE DOB >='1987-01-01' AND DOB <='1991-12-01'

(½ Mark for SELECT Wno, Name FROM Worker)

(½ Mark for

WHERE DOB BETWEEN '1987-01-01' AND '1991-12-01'

OR

WHERE DOB >='1987-01-01' AND DOB <='1991-12-01')

464

(iv) To count and display MALE workers who have joined after'

1986-01-01' .

Ans SELECT COUNT(*) FROM Worker

WHERE GENDER='MALE' AND DOJ > '1986-01-01';

OR

SELECT * FROM Worker

WHERE GENDER='MALE' AND DOJ > '1986-01-01';

(Any valid query for counting and/or displaying for male workers will

be awarded 1 mark)

(v) SELECT COUNT(*), DCODE FROM WORKER

GROUP BY DCODE HAVING COUNT(*)>1;

Ans COUNT(*) DCODE

2 D01

2 D05

(½ Mark for correct output)

(vi) SELECT DISTINCT DEPARTMENT FROM DEPT;

Ans Department

MEDIA

MARKETING

INFRASTRUCTURE

FINANCE

HUMAN RESOURCE


465

(vii) SELECT NAME, DEPARTMENT, CITY FRQM WORKER W,DEPT

D WHERE W. DCODE=D.DCODE AND WNO<100"3 ;

Ans NAME DEPARTMENT CITY

George K MEDIA DELHI

Ryma Sen INFRASTRUCTURE MUMBAI


(viii) SELECT MAX(DOJ), MIN(DOB) FROM WORKER;

Ans MAX (DOJ) MIN (DOB)

2014-06-09 1984-10-19


Note: In the output queries, please ignore the order of rows

6. (a) Verify the following using Boolean Laws. 2

x + Y' = X.Y+X.Y'+X'.Y'

Ans L.H.S

=X + Y'

=X. (Y+Y') + (X + X') . Y'

=X.Y + X.Y' + X.Y' + X' . Y'

=X.Y + X.Y' + X' . Y'

=R.H.S

OR

R.H.S

=X. Y + X. Y' + X'. Y'

=X. (Y + Y') + X'. Y'

466

=X.1+ X'. Y'

=X + X'. Y'

=X + Y'

=L.H.S

(2 Marks for any valid verification using Boolean Laws)

OR

(1 Mark for partial correct verification using Boolean Laws)

(b) Draw the Logic Circuit for the following Boolean Expression : 2

(U + V').W' + Z

Ans

(½ Mark for v' and W')

(½ Mark for (U+ V'))

(½ Mark for (U+V'). W')

(½ Mark for (U+V'). W'+Z)

(c) Derive a Canonical SOP expression for a Boolean function F, represented by

the following truth table : 1

A B C F(A,B,C)

0 0 0 1

0 0 1 0

0 1 0 0

0 1 1 1

467

1 0 0 1

1 0 1 0

1 1 0 0

1 1 1 1

Ans F(A,B,C) = A'B'C' + A'BC + AB'C' + ABC

OR

F(A,B,C) = ∑ (0,3,4,7)

(1 Mark for the correct SOP form)

OR

(Vl Mark for writing any two term correctly)

Note: Deduct ½ mark if wrong variable names are used

(d) Reduce. the following Boolean Expression to its simplest form using K-Map : 3

F(X,Y,Z,W) = ∑(O,1,6,8,9,10,11,12,15)

Ans

468

Simplified Expression: XV' + Y'Z' + XZ'W' + XZW + X'YZW'

(½ Mark for each of grouping - 5 groups x ½ = 2½ Marks)

(½ Mark for writing final expression in reduced/minimal/nonredundant form as XV' + Y'Z' + XZ'W' + XZW + X'YZW' )


7. (a) Illustrate the layout for connecting 5 computers in a Bus and a Star topologyof Networks. 1

Ans

OR any valid illustration of Bus and Star Topology.

(½ Mark for drawing each correct layout)

(b) What is a spam mail ? 1

Ans Spam is the abuse of electronic messaging systems (including most broadcastmedia, digital delivery systems) to send unsolicited bulk messagesindiscriminately.

(1 Mark for correct explanation)

(c) Differentiate between ftp and http. 1

Ans FTP is a protocol to transfer files over the Internet

HTTP is a protocol which allows the use of HTML to browse web pages inthe World Wide Web.

(1 Mark for any valid differentiation)

469

(d) Out of the following, which is the fastest (i) wired and (ii) wireless medium of

communication?

Infrared, Coaxial Cable, Ethernet Cable, Microwave, Optical Fiber 1

Ans (i) Wired - Optical Fiber

(ii) Wireless - Infrared OR Microwave

(½ Mark each for Wired and Wireless medium of communication)

(e) What is Worm? How is it removed? 1

Ans A worm is a self-replicating computer program. It uses a network to send

copies of itself to other computers on the network and it may do so without

any user intervention.

Most of the common anti-virus(anti-worm) remove worm.

(½ Mark for writing correct meaning of Worm)

(½ Mark for correct definition of removing Worm)

(f) Out of the following, which all comes under cyber crime?

(i) Stealing away a brand new computer from a showroom.

(ii) Getting in someone's social networking account without his consentand posting pictures on his behalf to harass him.

(iii) Secretly copying files from server of a call center and selling it to theother organization.

(iv) Viewing sites on a internet browser.

Ans (ii) & (iii)

(½ Mark for choosing each of the correct options)

Note:

No marks to be given, if all options are there in the answer

½ Mark to be deducted, if one extra option is given along with

the correct options

470

(g) Perfect Edu Services Ltd. is an educational organization. It is planning tosetup its India campus at Chennai with its head office at Delhi. The Chennaicampus has 4 main buildings - ADMIN, ENGINEERING, BUSINESS andMEDIA.

You as a network expert have to suggest the best network related solutionsfor their problems raised in (i) to (iv), keeping in mind the distances betweenthe buildings and other given parameters.

DELHI CHENNAI

Head Office Campus ENGINEERING

ADMIN BUSINESS

MEDIA

Shortest distances between various buildings :

ADMIN to ENGINEERING 55m

ADMIN to BUSINESS 90m

ADMIN to MEDIA 50m

ENGINEERING to BUSINESS 55m

ENGINEERING to MEDIA 50m

BUSINESS to MEDIA 45m

DELHI Head Office to CHENNAI Campus 2175 km

Number of Computers installed at various buildings are as follows :

ADMIN 110

ENGINEERING 75

BUSINESS 40

MEDIA 12

DELHI Head Office 20

471

(i) Suggest the most appropriate location of the server inside the

CHENNAI campus (out of the 4 buildings), to get the best connectivity

for maximum no. of computers. Justify your answer. 1

Ans ADMIN (due to maximum number of computers)

OR

MEDIA (due to shorter distance from the other buildings)

(1 Mark for mentioning Correct building name with reason)

OR

(½ Mark to be deducted for not giving reason)

(ii) Suggest and draw the cable layout to efficiently connect various build-

ings within the CHENNAI campus for connecting the computers. 1

Ans Anyone of the following

(1 Mark for drawing correct layout)

(iii) Which hardware device will you suggest to be procured by the

company to be installed to protect and control the internet uses within

the campus ? 1

Ans Firewall OR Router

(1 Mark for correct Answer)

(iv) Which of the following will you suggest to establish the online face-

to-face communication between the people in the Admin Office of

CHENNAI campus and DELHI Head Office? 1

(a) Cable TV

472

(b) Email

(c) Video Conferencing

(d) Text Chat

Ans Video Conferencing

(1 Mark for correct Option / Answer)

QUESTION PAPER CODE 91EXPECTED ANSWERS

Section-A

(Only for C++ Candidates)

1. (a) Find the correct identifiers out of the following, which can be used for namingVariable, Constants or Functions in a C++ program : 2

For, while, INT, NeW, delete, 1stName, Add+Subtract, name1

Ans For, INT, NeW, namel

(½ Mark for each correct identifier)

Note:

Deduct ½ Mark for writing additional incorrect identifier(s)

No marks to be awarded if all the identifiers are mentioned

(b) Observe the following program very carefully and write the names of thoseheader filets), which are essentially needed to compile and execute thefollowingprogram successfully : 1

typedef char STRING[80];

void main()

{

STRING Txt [] = "We love Peace";

473

int Count=O;

while (Txt[Count] !='\O')

if (isa1pha(Txt[Count]"

Txt[Count++]='@';

else

Txt[Count++]='#';

puts(Txt);

}

Ans ctype, stdio

(½ mark for each header file)

Note: Ignore any additional header file(s)

(c) Observe the following C++ code very carefully and rewrite it after removingany/all syntactical errors with each correction underlined. 2

Note : Assume all required header files are already being included in theprogram.

#Define float MaxSpeed=60.5;

void main()

{

int MySpeed

char Alert='N' ;

cin>>MySpeed;

if MySpeed>MaxSpeed

Alert=' Y' ;

cout<<Alert<<endline;

}

474

Ans #define float MaxSpeed_60.5 ; //Error 1,2,3

void main ()

{

int MySpeed ; //Error 4

char Alert='N' ;

cin>>MySpeed;

if (MySpeed>MaxSpeed) //Error 5

Alert=' Y' ;

cout<<Alert<<endl ; //Error 6

}

(½ Mark for each correction upto a maximum of 4 corrections)

OR

(1 mark for only identifying any 4 errors, without suggesting

corrections).

(d) Write the output of the following C++ program code: 2

Note : Assume all required header files are already being included in the

program.

void Location(int &X,int Y=4)

{

Y+=2;

X+=Y;

}

void main ()

{

475

int PX=10,PY=2;

Location (PY) ;

cout<<PX<<","<<PY<<end1 ;

Location(PX,PY);

cout<<PX<<","<<PY<<end1 ;

}

Ans 10,8

20,8

(½ Mark for each correct value)

Note:

Deduct ½ Mark for not considering any or all end/(s) at properplace(s)

Deduct ½ Mark for not considering any or all ',' at proper place(s)

(e) Write the output of the following C++ program code: 3

Note: Assume all required header files are already being included in theprogram.

class Eva1

{

char Level;

int Point;

public:

Eva1() {Level='E'; Point=O;}

void Sink(int L)

{

Level-=L;

476

}

void Float(int L)

{

Level+=L;

Point++;

}

void Show()

{

cout<<Leve1<<"#"<<Point<<end1;

}

} ;

void main ()

{

Eval E;

E.Sink(3);

E.Show ();

E.Float(7);

E.Show ();

E.Sink(2);

E.Show ();

}

Ans B#0

1#1

G#l

477

(1 Mark for each correct line of output)

Note:

Deduct ½ Mark for not considering any or all end/(s) at proper

place(s)

Deduct ½ Mark for not writing any or all # symbol(s)

(f) Study the following program and select the possible output(s) from the options(i) to (iv) following it. Also, write the maximum and the minimum values thatcan be assigned to the variable VAL. 2

Note:

– Assume all required header files are already being included in theprogram.

– random(n) function generates an integer between 0 and n-l.

void main ()

{

randomize();

int VAL;

VAL=random(3) +2;

char GUESS[]="ABCDEFGHIJK";

for (int I=l;I<=VAL; I++)

{

for(int J=VAL; J<=7;J++)

cout<<GUESS [J] ;

cout<<endl;

}

}

478

(i) (ii) (iii) (iv)

BCDEFGH CDEFGH EFGH FGHI

BCDEFGH CDEFGH EFGH FGHI

EFGH FGHI

EFGH FGHI

Ans (ii) and (iii)

Min Value of VAL = 2

Max Value of VAL = 4

(½ Mark for writing option (ii) )


Note:

Deduct ½ mark for writing each additional option along with

both correct options

(½ Mark for writing correct Minimum value of VAL)

(½ Mark for writing correct Maximum value of VAL)

2. (a) What is a copy constructor ? Give a suitable example in C++ to illustrate

with its definition within a class and a declaration of an object with the help of

it. 2

Ans A copy constructor is an overloaded constructor in which an object of the

same class is passed as reference parameter.

class Point

{

int x;

public:

479

Point () {x=O; }

Point(Point &p) // Copy constructor

{x=p.x;}

} ;

void main ()

{

Point pl;

Point p2(pl) ;//Copy constructor is called here

//OR

Point p3=pl;//Copy constructor is called here

}

(1½ Mark to be awarded if the copy constructor is explained with anappropriate example)

OR

(1 Mark for correct explanation of copy constructor only without anexample)

(½ Mark for correct declaration of an object)

(b) Observe the following C++ code and answer the questions (i) and (ii) :

class Passenger

{

long PNR;

char Name [201 ;

public:

Passenger () //Function 1

{ cout<<"Ready"<<endl; }

480

void Book(long P,char N[]) //Function 2

{ PNR = P; strcpy (Name, N)·; }

void Print () //Function 3

{ cout<<PNR << Name <<endl; }

~Passenger () //Function 4

{ cout<<"Booking cancelled! "<<endl; }

} ;

(i) Fill in the blank statements in Line 1 and Line 2 to execute Function 2

and Function 3 respectively in the following code : 1

void main()

{

Passenger P;

_____________ //Line 1

_____________ //Line 2

}//Ends here

Ans P. Book (1234567,"Ravi"); //Line 1

P.Print() ; //Line 2

(½ Mark for writing each correct Function)

(ii) Which function will be executed at } / / Ends here ? What is this func-

tion referred as ? 1

Ans Function 4

OR

~Passenger ()

It is a Destructor function.

481

(½ Mark for writing Function 4 OR ~Passenger())

(½ Mark for referring Destructor)

(c) Write the definition of a class Photo ill C++ with following description: 4

Private Members

- Pno //Data member for Picture Number (an integer)

- Category//Data member for Picture Category (a string)

- Location//Data member for Exhibition Location (a string)

- FixLocation //A member function to assign

//Exhibition Location as per category

//as shown in the following table

Category Exhibit

Antique Zaveri

Modern Johnsen

Classic Terenida

Public Members

- Enter() //A function to allow user to enter values

//Pno, category and call FixLocation() function

- SeeAll() //A function to display all the data members

Ans class Photo

{

int Pno;

char Category[20];

char Exhibit[20];

void FixExhibit() ;

482

public:

void Register 0 ;

void ViewA11();

} ;

void Photo::FixExhibit()

{

if (strcmpi (Category, "Antique") ==0)

strcpy(Exhibit,"Zaveri");

else if(strcmpi(Category,"Modern")==0)

strcpy(Exhibit,"Johnsen") ;

else if strcmpi(Category,"Classic")==0)

strcpy(Exhibit,"Terenida") ;

}

void Photo::Register()

{

cin"Pno;

gets (Category) ;

FixExhibit();

}

void Photo:: ViewAll()

{

cout<<Pno<<Category<<Exhibit<<endl;

}

483


(½ Mark for correct declaration of data members)

(1 Mark for correct definition of FixExhibit))

(1 Mark for correct definition of Register()) with proper invocation of

FixExhibit() function)

(1 Mark for correct definition of ViewAIl())

NOTE:

Deduct ½ Mark if FixExhibit() is not invoked properly inside

Register() function

No marks to be deducted for defining Member Functions inside

the class

Strcmp()/strcmpi() acceptable

(d) Answer the questions (i) to (iv) based on the following: 4

class Interior

{

int OrderId;

char Address[20];

protected:

float Advance;

public:

Interior();

void Book(); void View();

} ;

class Painting:public Interior

484

{

int Wa11Area,ColorCode;

protected:

char Type;

public:

Painting () ;

void PBook();

void PView();

} ;

class Billing : public Painting

{

float Charges;

void Calculate();

public:

Billing();

void Bill();

void Bi11Print();

} ;

(i) Which type of Inheritance out of the following is illustrated in the above

example?

– Single Level Inheritance

– Multi Level Inheritance

– Multiple Inheritance

485

Ans Multi Level Inheritance

(1 Mark for mentioning correct option)

(ii) Write the names of all the data members, which are directly accessible

from the member functions of class Painting.

Ans WallArea, ColorCode,Type, Advance


Note:

No marks to be awarded for any partial or additional answer(s)

(iii) Write the names of all the member functions, which are directly accessible

from an object of class Billing.

Ans Bill(), BillPrint(), PBook(), PView(), Book(), View()


Note: No marks to be awardedfor any partial/additional answer(s)

Constructors can be ignored

(iv) What will be the order of execution of the constructors, when an object

of class Billing is declared ?

Ans Interior, Painting, Billing


Note: No marks to be awarded for any other order

3. (a) Write the definition of a function Change (int P[], int N) in C++, which should

change all the multiples of 10 in the array to 10 and rest of the elements as 1.

For example, if an array of 10 integers is as follows: 2

P[0] P[l] P[2] P[3] P[4] P[5] P[6] P[7] P[8] P[9]

100 43 20 56 32 91 80 40 45 21

After executing the function, the array content should be changed as follows:

486

P[0] P[l] P[2] P[3] P[4] P[5] P[6] P[7] P[8] P[9]

10 1 10 1 1 1 10 10 1 1

Ans void Change (int P[ ],int N)

{

for (int i=0;i<N;i++)

if(P[i]%10==0)

P[i]=10;

else

P[i]=l;

}

OR



(½ Mark for correct checking of divisibility of array elements by 10)

(½ Mark for correct use of else OR correct checking of non divisibility

of array elements by 10 )

(½ Mark for correct assignment of 10 and 1 for multiples and non

multiples of 10 respectively)

(b) A two dimensional array ARR[50][20] is stored in the memory along the rowwith each of its elements occupying 4 bytes. Find the address of the elementARR[30] [10], if the element ARR[10] [5] is stored at the memory location15000. 3

Ans Loc (ARR[I] [J]) along the row

=BaseAddress + W [( I - LBR)*C + (J - LBC)]

(where C is the number of columns, LBR = LBC = 0

487

LOC (ARR[10] [5])

= BaseAddress + W [I*C + J]

15000 = BaseAddress + 4[10*20 + 5]


= BaseAddress + 4 x 205

= BaseAddress + 820

BaseAddress = 15000-820

= 14180

LOC (ARR[30] [10]) = 14180 + 4 [30 * 20 + 10]

= 14180 + 4 * 610

= 14180 + 2440

= 16620

OR

LOC(ARR[30] [10])

= LOC(ARR[10] [5])+ W[( I-LBR)*C + (J-LBC)]

= 15000 + 4 [ (30-10) *20 + (10-5)]

= 15000 + 4[ 20*20 + 5]

= 15000 + 4 *405

= 15000 + 1620

= 16620

OR

Where C is the number of columns and LBR=LBC=l

LOC (ARR[10] [5])

15000 = BaseAddress + W [( I-I) *C + (J-l)]

488

= BaseAddress + 4[9*20 + 4]


= BaseAddress + 4 * 184

= BaseAddress + 736

BaseAddress = 15000 - 736

= 14264

LOC(ARR[30] [10])

= 14264 + 4[(30-1)*20 + (10-1)]

= 14264 + 4[29*20 + 9]

= 14264 + 4[580 + 9]

= 14264 + 4*589

= 14264 + 2356

= 16620

(1 Mark for writing correct formula (for row major) OR substitutingformula with correct values)

( 1 Mark for at least one step of intermediate calculation)

( 1 Mark for final correct address)

(c) Write the definition of a member function PUSH( ) in C++, to add a newbook in a dynamic stack of BOOKS considering the following code is alreadyincluded in the program : 4

struct BOOKS

{

char ISBN[20], TITLE[80];

BOOKS *Link;

} ;

489

class STACK

{

BOOKS *Top;

public:

STACK() {Top=NULL;}

void PUSH();

void POP() ;

~STACK() ;

} ;

Ans void STACK: :PUSH()

{

BOOKS *Temp;

Temp=new BOOKS;

gets (Temp->1SBN) ;

gets (Temp->T1TLE) ;

Temp->Link=Top;

Top=Temp;

}

OR


(1 Mark for creating a new node of BOOKS dynamically)

(½ Mark for entering value of ISBN)

(½ Mark for entering value of TITLE)

(1 Mark for linking the new node of BOOKS to the Top)

(1 Mark for making the new node of BOOKS as Top)

490

(d) Write a function REVROW(int P[ ][5],int N,int M) in C++ to displaythe content of a two dimensional array, with each row content in reverse

order. 3

For example, if the content of array is as follows :

15 12 56 45 51

13 91 92 87 63

11 23 61 46 81

The function should display output as

51 45 56 12 15

63 87 92 91 13

81 46 61 23 81

Ans void REVROW(int P[] [5],int N,int M)

{

for(int 1=0; 1<Ni 1++)

{ for(int J<M-l; J>=O; J--)

cout<<P[1] [J] ;

cout<<end1;

}

}

OR

void REVROW(int P[ ] [5],int N,int M)

{

for(int I=0; 1<N; 1++)

{

491

for(int J=0; J<M/2; J++)

{

int T = P[1] [J];

P [I] [J] = P[1] [M-J-l];

P [I] [M-J-l] = T;

}

}

for (I=0 i 1<N; 1++)

{

for (int J=0; J<M; J++)

cout<<P [I] [J] ;

cout<<endl;

}

}

(1 Mark for correct nesting of loop(s))

(1½ Mark for correct logic for reversing the content of each row)

(½ Mark for correctly displaying the content)

Note: N and M can be written interchangeably for number of rows

and columns

(e) Convert the following Infix expression to its equivalent Postfix expression,

showing the stack contents for each step of conversion : 2

U * V + R/(S-T)

Ans U * V + R/(S-T)

= ((U * V)+(R/(S-T)))

492


(

(

U U

* *

V UV

) UV*

+ +

(

R UV*R

/ +/

(

S UV*RS

- +/-

T UV*RST

) UV*RST-

) UV*RST-/

) UV*RST-/+

OR


U U

* * U

V * UV

493

+ + UV*

R + UV*R

/ +/ UV*R

( +/ ( UV*R

S +/ ( UV*RS

- +/(- UV*RS

T +/(- UV*RST

) +/ UV*RST-

+ UV*RST-/

UV*RST-/+

OR

Any other method for converting the given Infix expression to its

equivalent Postfix expression showing stack contents

(½ mark for converting expression up to each operator)

OR

(1 mark to be given for writing correct answer without showing the

stack content)

4. (a) Write function definition for TOWER( ) in C++ to read the content of a text

file WRITEUP.TXT, count the presence of word TOWER and display the

number of occurrences of this word. 2

Note:

– The word TOWER should be an independent word

– Ignore type cases (i.e. lower/upper case)

Example:

494

If the content of the file WRITEUP.TXT is as follws :

Tower of hanoi is an interesting problem. Mobile

phone tower is away from here. Views from EIFFEL

TOWER are amazing.

The function TOWER( ) should display the following:

3

Ans voidTOWER()

{

int count=0;

ifstream f("WRITEUP.TXT") ;

char s[20];

while (! f .eof () )

{

f>>s;

if (strcmpi (s, "TOWER") ==0)

count++;

}

cout<<count;

f. close () ;

}

OR

Any other correct function definition

(½ Mark for opening WRITEUP. TXT correctly)

(½ Mark for reading each word (using any method) from the file)

495

(½ Mark for comparing the word with TOWER)

(½ Mark for displaying correct count of TOWER)

NOTE:

(½ Mark to be deducted if TOWER is compared without ignoring the

case)

(b) Write a definition for function COSTLY() in C++ to read each record of a

binary file GIFTS.DAT, find and display those items, which are priced more

than 2000. Assume that the file GIFTS.DAT is created with the help of objects

of class GIFTS, which is defined below: 3

class GIFTS

{

int CODE;char ITEM[20]; float PRICE;

public:

void Procure ()

{

cin>>CODE; gets (ITEM);cin>>PRICE;

}

void View()

{

cout<<CODE<<": "<<ITEM<<": "<<PRICE<<endl;

}

float GetPrice() {return PRICE;}.

} ;

496

Ans void COSTLY()

{

GIFTS G;

ifstream fin("GIFTS.DAT",ios::binary);

while (fin.read"char *)&G,sizeof(G)))

{

if (G.GetPrice ()>2000)

G.View();

}

fin. close ();

}

OR


(½ Mark for opening GIFTS.DAT correctly)

(1 Mark for reading all records from the file)

(1 Mark for checking value of PRICE > 2000 )

(½ Mark for displaying the desired items)

(c) Find the output of the following C++ code considering that the binary file

MEMBER.DAT exists on the hard disk with records of 100 members: 1

class MEMBER

{

int Mno; char Name[20];

public:

void In();void Cut();

497

} ;

void main()

{

fstream MF;

MF.open ("MEMBER. DAT",ios:: binary|ios::in);

MEMBER M;

MF.read((char*)&M, sizeof(M));



int POSITION= MF.tellg()/sizeof(M);

cout<<"PRESENT RECORD:"<<POSITION<<end1;

MF.close();

}

Ans PRESENT RECORD: 3

(1 Mark for writing PRESENT RECORD: 3)

OR

(1 Mark for writing only 3)

OR

(½ Mark for writing only PRESENT RECORD:)

Section - B

(Only for Python candidates)

1. (a) How is___init()___different from___del ()___? 2

Ans _init_() is the class constructor or initialization method which is automatically

invoked when we create a new instance of a class.

498

_del_() is a destructor which is automatically invoked when an object(instance) goes out of scope.

For Example:

class Sample:

def __ init __ (self) :

self.data = 79

print('Data:' ,self.data,'created')

def __ del __ (self) :

print (' Data: ' , self. data, 'deleted')

s = Sample ()

del s

(2 Marks for correct differentiation)

OR

(2 Marks for differentiation through example)

OR

(1 Mark for each correct definition)

(b) Name the function/method required to 1

(i) check if a string contains only alphabets

(ii) give the total length of the list

Ans isalpha ()

len()

(½ Mark for each correct function/ method name)

(c) Rewrite the following code in python after removing all syntax error(s).Underline each correction done in the code. 2

def Sum(Count) #Method to ·find sum

499

S=O

for I in Range (1,Count+l) :

S+=I

RETURN S

print Sum[2] #Function Call

print Sum[5]

Ans def Sum(Count) : #Method to find sum #Error 1

S=O

for I in range (1,Count+l): #Error 2

S+=I

return S #Error 3

print Sum (2) #Function Call #Error 4

print Sum (5) #Error 4

(½ Mark for each correction)

OR

(1 mark for identifying all the errors, without suggesting corrections)

(d) Find and write the output of the following python code: 2

for Name in ['John', 'Garima','Seema','Karan']:

print Name

if Name[O]='S':

break

else:

print 'Completed!'

print 'We1done!'

500

Ans John

Garima

Seema

Weldone!

(½ Mark for each correct line)

Note:

Deduct ½ Mark for not considering any or all line breaks at properplace(s)

(e) Find and write the output of the following python code: 3

class Emp:

def_init_(se1f,code,nm): #constructor

se1f.Code=code

se1f.Name=nm

def Manip(self) :

se1f.Code=self.Code+10

se1f.Name='Karan'

def Show (se1f,line) :

print se1f.Code,self.Name,line

s=Emp (25, 'Mamta')

s.Show(l)

s.Manip()

s.Show(2)

print s.Code+1en(s.Name)

501

Ans 25 Mamta 1

35 Karan 2

40

(1 Mark for each correct line)

Note:

Deduct ½ Mark for not considering any or all line break(s) at proper

place(s).

(f) What are the possible outcome(s) executed from the following code?

Also specify the maximum and minimum values that can be assigned to variable

COUNT. 2

TEXT="CBSEONLINE"

COUNT=random.randint(0,3)

C=9

while TEXT[C]!='L' :

print TEXT[C]+TEXT[COUNT]+'*',

COUNT=COUNT+1

C=C-l

(i) (ii) (iii) (iv)

EC*NB*IS* NS*IE*LO* ES*NE*IO* LE*NO*ON*

Ans (i) EC*NB*IS*

(iii) ES*NE*IO*

Minimum COUNT = 0 Maximum COUNT = 3

(½ Mark for writing option (i) )


502

Note:

Deduct V2 mark for writing each additional option along withboth correct options

(½ Mark for writing correct Minimum value of COUNT)

(½ Mark for writing correct Maximum value of COUNT)

2. (a) Illustrate the concept inheritance with the help of a python code. 2

Ans class Base:

def __ init (self) :

print "Base Constructor at work ... "

def show (self) :

print "Hello Base"

class Der(Base) :

def __ init __ (self) :

print "Derived Constructor at work ... "

def display (self) :

print "Hello from Derived"

(1 Mark for base class)

(1 Mark for derived class)

(b) What will be the output of the following python code ? Explain the try and

except used in the code. 2

A=0

B=6

print 'One'

try:

503

print 'Two'

X=B/A

Print 'Three'

except ZeroDivisionError:

print B*2

print 'Four'

except:

print B*3

print 'Five'

Ans One

Two

12

Four

The code written within try triggers the exception written after except

ZeroDivisionError: in case there is a division by zero error otherwise the default

exception is executed

OR

Any other correct explanation for usage of try and except

(½ Mark for first two lines of correct output)

(½ Mark for next two lines of correct output)

(½ Mark each for correct explanation of try and except)

(c) Write a class PHOTO in Python with following specifications: 4

Instance Attributes

- Pno # Numeric value

- Category # String Value

504

- Exhibit # Exhibition Gallery with String value

Methods:

- FixExhibit() #A method to assign

#Exhibition Gallery as per Category

#as shown in the following table

Category Exhibit

Antique Zaveri

Modern Johnsen

Classic Terenida

- Register() #A function to allow user

#to enter values of Pno, Category

#and call FixExhibit() method

- ViewA11() #A function to display all the data

#members

Ans class PHOTO:

Pno=0

Category=" "

Exhibit=" "

def FixExhibit() :

if self.Category=="Antique":

self. Exhibit="Zaveri"

elif self .Category="Modern": -

self. Exhihit="Johnsen"

elif self.Category=="Classic":

self. Exhihit="Terenida"

505

def Register () :

self.Pno=int(input("Enter Pno:")

self. Category=input ("Enter Name: ")

self. FixExhibit ()

def ViewAll ()

print self.pno,self.Category,self.Exhibit


(½ Mark for correct declaration of instance attributes)

(1 Mark for correct definition of FixExhibit())

(1 Mark for correct definition of Register() with proper invocation of

FixExhibit() method)

(1 Mark for correct definition of ViewAll())

NOTE:

Deduct ½ Mark if FixExhibit() is not invoked properly inside Register()

method

(d) What is operator overloading with methods? Illustrate with the help of an

example using a python code. 2

Ans Operator overloading is an ability to use an operator in more than one form.

Examples:

In the following example operator + is used for finding the sum of two integers:

a = 7

b = 5

print (a+b) # gives the output: 12

Whereas in the next example, shown below the same + operator is used to

add two strings:

506

a = 'Indian'

b = 'Government'

print (a+b) # # gives the output: Indian

Government

(1 Mark for correct definition of Operator overloading)

(1 Mark for correct example of Python code to illustrate Operatoroverloading)

(e) Write a method in python to display the elements of list twice, if it is a numberand display the element terminated with '*' if it is not a number. 2

For example, if the content of list is as follows :

MyList=['RAMAN','21','YOGRAJ','3','TARA']

The output should be

RAMAN *

2121

YOGRAJ*

33

TARA*

Ans def fun(L) :

for I in L:

if I.isnumeric():

print(2*I) # equivalently: print (I+I)

else:

print(I+'*')


(½ Mark for checking numeric/non numeric)



507

3. (a) What will be the status of the following list after fourth pass of bubble sortand fourth pass of selection sort used for arranging the following elements indescending order? 3

34,-6,12,-3,45,25

Ans Bubble Sort

34,-6,12,-3,45,25 (Original Content)

i. 34,12,-3,45,25,-6

ii. 34,12,45,25,-3,-6

iii.34,45,25,12,-3,-6

iv. 45,34,25,12,-3,-6

Selection Sort

34,-6,12,-3,45,25 (Original Content)

i. 45,-6,12,-3,34,25

ii. 45,34,12,-3,-6,25

iii.45,34,25,-3,-6,12

iv. 45,34,25,12,-6,-3 (Unsorted status

after 4th pass)

For Bubble Sort


OR




For Selection Sort


508

OR




(b) Write a method in python to search for a value in a given list (assuming thatthe. elements in list are in ascending order) with the help of Binary Searchmethod. The method should return -1, if the value not present else it shouldreturn position of the value present in the list. 2

Ans def bSearch(L, key):

low = 0

high = len(L)-1

found = False

while (low <= high) and (not found) :

mid = (low<=high)//2

if L[mid] == key:

found = True

elif L[mid] < key:

low = mid + 1

else:

high = mid - 1

if found:

return mid+l # may even be 'return mid'

else:

return -1

(½ Mark for correct Initialization of lower and upper bounds)

509


(½ Mark for reassigning Mid,Low,Up bound)

(½ Mark for returning correct value)

(c) Write PUSH(Names) and POP(Names) methods in python to add Namesand Remove names considering them to act as Push and Pop operations ofStack. 4

Ans def push (Name) :

Stack. append (Name)

print'Element:' ,Name, 'inserted successfully'

def pop () :

if Stack == [] :

print (' Stack is empty! ')

else:

print('Deleted element is',Stack.pop())

(2 Marks for correctly pushing an element into the stack)

(1 Mark for checking empty stack in POP())

(1 Mark for popping element from stack)

(d) Write a method in python to find and display the composite numbers between2 to N. Pass N as argument to the method. 3

Ans def composite_numbers (N):

for I in range (2, N+1) :

M = I // 2

for J in range(2, M+l) :

if I % J == 0:

print (I)

break

510

OR

Any other correct equivalent method definition

(1 Mark for correct loops)

(1 Mark for checking composite numbers between 2 to N)

(1 Mark for displaying the numbers)

(e) Evaluate the following postfix notation of expression. Show status of stack

after every operation. 2

34,23,+,4,5,*,-

Ans Element Stack

34 34

23 34, 23

+ 57

4 57, 4

5 57, 4, 5

* 57, 20

- 37

(1 mark for evaluating till 57)

(½ mark for evaluating till 57, 20)

(½ mark for evaluating till final 37)

Note:

Only 1 mark to be awarded for evaluating final answer as 37 without

showing stack contents

511

4. (a) Differentiate between the following : 1

(i) f = open ('diary.txt', 'a')

(ii) f = open ('diary.txt', 'w')

Ans (i) diary.txt is opened for writing data at the end of file

(ii) diary.txt is opened for writing data from the beginning of file in createmode

(1 mark for writing correct difference)

OR

(½ Mark for each correct explanation of (i) and (ii))

(b) Write a method in python to read the content from a text file story.txt line byline and display the same on screen. 2

Ans def read_file () :

inFile = open('story.txt', 'r' )

for line in inFile:

print line

(½ Mark for opening the file)

(1 Mark for reading all lines)

(½ Mark for displaying all lines)

(c) Consider the following definition of class Student. Write a method in pythonto write the content in a pickled file student.dat. 3

class Student:

def__init__(se1f,A,N) :

se1f.Admno=A

se1f.Name=N

def Show (se1f) :

print (se1f.Admno, "#", self . Name)

512

Ans import pickle

class Student:

def _init_ (self, A, N):

self.Admno = A

self.Name = N

def show (self) :

print (self.Admno, "#" ,self. Name)

def store_data (self) :

piFile = open('student.dat','wb')

pickle.dump(self, piFile)

piFile.close ()

(1 Mark for method header)

(1 Mark for opening the file student.dat in correct mode)

(1 Mark each for writing student details into the file)

SECTION C

[For all candidates]

5. (a) Observe the following table carefully and write the names of the mostappropriate columns, which can be considered as (i) candidate keys and(ii) primary key: 2

Code Item Qty Price Transaction Date

1001 Plastic Folder 14" 100 3400 2014-12-14

1004 Pen Stand Standard 200 4500 2015-01-31

1005 Stapler Mini 250 1200 2015-02-28

1009 Punching Machine Small 200 1400 2015-03-12

1003 Stapler Big 100 1500 2015-02-02

513

Ans Candidate keys : Code, Item

Primary keys : Code

(1 Mark for writing correct Candidate keys)

(1 Mark for writing correct Primary key)

Note:

No marks to be deducted for mentioning Price and/orTransaction Date as additional candidate keys.

(b) Consider the following DEPT and EMPLOYEE tables. Write SQL queriesfor (i) to (iv) and find outputs for SQL queries (v) to (viii). 6

Table : DEPT

DCODE DEPARTMENT LOCATION

DO1 INFRASTRUCTURE DELHI

D02 MARKETING DELHI

D03 MEDIA MUMBAI

DOS FINANCE KOLKATA

D04 HUMAN RESOURCE MUMBAI

Table : EMPLOYEE

ENO NAME DOJ DOB GENDER DCODE

1001 George K 2013-09-02 1991-09-01 MALE DOl

1002 Ryma Sen 2012-12-11 1990-12-15 FEMALE D03

1003 Mohitesh 2013-02-03 1987-09-04 MALE D05

1007 Anil Jha 2014-01-17 1984-10-19 MALE D04

1004 Manila Sahai 2012-12-09 1986-11-14 FEMALE DOl

1005 R SAHAY 2013-11-18 1987-03-31 MALE D02

1006 Jaya Priya 2014-06-09 1985-06-23 FEMALE DOS

514

Note: DOJ refers to date of joining and DOB refers to date of Birth ofemployees.

(i) To display Eno, Name, Gender from the table EMPLOYEE in ascendingorder of Eno.

Ans SELECT Eno, Name, Gender FROM Employee

ORDER BY Eno;

(½ Mark for SELECT Eno, Name, Gender FROM Employee)

(½ Mark for ORDER BY Eno)

(ii) To display the Name of all the MALE employees from the tableEMPLOYEE.

Ans SELECT Name FROM Employee WHERE Gender='MALE' ;

(½ Mark for SELECT Name FROM Employee)

(½ Mark for WHERE Gender=' MALE' )

(iii) To display the Eno and Name of those employees from the tableEMPLOYEE who are born between '1987-01-01' and '1991-12-01'.

Ans SELECT Eno,Name FROM Employee


OR

SELECT Eno,Name FROM Employee

WHERE DOB >='1987-01-01' AND DOB <='1991-12-01';

OR

SELECT Eno,Name FROM Employee

WHERE DOB >'1987-01-01' AND DOB <'1991-12-01';

(½ Mark for SELECT Eno,Name FROM Employee)

(½ Mark for


515

OR WHERE DOB >='1987-01-01' AND DOB <='1991-12-01'

OR WHERE DOB >'1987-01-01' AND DOB <'1991-12-01')

(iv) To count and display FEMALE employees who have joined after'1986-01-01'.

Ans SELECT count(*) FROM Employee

WHERE GENDER='FEMALE' AND DOJ > '1986-01-01' ;

OR

SELECT * FROM Employee

WHERE GENDER='FEMALE' AND DOJ > '1986-01-01' ;

(Any valid query for counting and/ordisplaying for female employeeswill be awarded 1 mark)

(v) SELECT COUNT (*), DCODE FROM EMPLOYEE

GROUP BY DCODE HAVING COUNT(*)>l;

Ans COUNT DCODE

2 D01

2 D05


(vi) SELECT DISTINCT DEPARTMENT FROM DEPT;

Ans Department

INFRASTRUCTURE

MARKETING

MEDIA

FINANCE

HUMAN RESOURCE


516

(vii) SELECT NAME, DEPARTMENT FROM EMPLOYEE E, DEPT D

WHERE E.DCODE=D.DCODE AND ENO<1003;

Ans NAME DEPARTMENT

George K INFRASTRUCTURE

Ryma Sen MEDIA


(viii) SELECT MAX (DOJ), MIN (DOB) FROM EMPLOYEE;

Ans MAX (DOJ) MIN(DOB)

2014-06-09 1984-10-19


Note: In the output queries, please ignore the order of rows.

6. (a) Verify the following using Boolean Laws : 2

U'+V = U'V'+ U' .V + U.V

Ans L.H.S

=U'+ V

=U'.(V+V') + V. (U' + U)

=U'. V + U' . V' + U' . V + U. V

=U'.V+U'.V'+U.V

=R.H.S

OR

R.H.S

=U' V'+U'. V + U, V

=U'.(V' + V) + U. V

=U'.1 + U. V

=U'+ U.V

517

=U'+ V

=L.H.S

(2 Marks for any valid verification using Boolean Laws)

OR

(1 Mark for partial correct verification using Boolean Laws)

(b) Draw the Logic Circuit for the following Boolean Expression : 2

(X'+Y).Z + W'

Ans

(½ Mark for X' and W')

(½ Mark for (X'+ Y')

(½ Mark for (X'+Y).Z)

(½ Mark for (X'+Y).Z+W')

(c) Derive a Canonical POS expression for a Boolean function F, representedby the following truth table : 1

p Q R F(P,Q,R)

0 0 0 1

0 0 1 0

0 1 0 0

0 1 1 1

1 0 0 1

1 0 1 0

1 1 0 0

1 1 1 1

518

Ans F(P,Q,R)= (P+Q+R')(P+Q'+R)(P'+Q+R')(P'+Q'+R)

OR

F(P,Q,R)= II(1,2,5,6)

(1 Mark for the correct POS form)

OR

(½ Mark for writing any two term correctly)


(d) Reduce the following Boolean Expression to its simplest form using K-Map: 3

F(X,Y,Z,W)= ∑(0,1,4,5,6,7,8,9,11,15)

Ans

Simplified Expression: Y'Z' + X'Y + XZW

(½ Mark for drawing K-Map with correct variable names)

(½ Mark for placing all 1s at correct positions in K-Map)

519

(½ Mark for each of three grouping Y'Z' , X'Y , XZW)

(½ Mark for writing final expression in reduced/minimal/nonredundant form as Y'Z' + X'Y + XZW )


7. (a) Illustrate the layout for connecting 5 computers in a Bus and a Star topologyof Networks. 1

Ans

OR any valid illustration of Bus and Star Topology.

(½ Mark for drawing each correct layout)

(b) What kind of data gets stored in cookies and how is it useful? 1

Ans When a Website with cookie capabilities is visited , its server sends certain

information about the browser, which is stored in the hard drive as a text file.

It's a way for the server to remember things about the visited sites.

(1 Mark for correct kind of data stored)

(c) Differentiate between packet switching over message switching? 1

Ans Packet Switching-follows store and forward principle for fixed packets.

Fixes an upper limit for packet size.

Message Switching-follows store and forward principle for complete

message. No limit on block size.

520

(1 Mark for any valid differentiation)

OR

(1 Mark for correct definition of Packet Switching only)

(d) Out of the following, which is the fastest (i) wired and (ii) wireless medium ofcommunication? 1

Infrared, Coaxial Cable, Ethernet Cable, Microwave, Optical Fiber

Ans (i) Wired - Optical Fiber

(ii) Wireless - Infrared OR Microwave

(½ Mark each for Wired and Wireless medium of communication)

(e) What is Trojan Horse? 1

Ans A Trojan Horse is a code hidden in a program, that looks safe but has hidden

side effects typically causing loss or theft of data, and possible system harm.

(1 Mark for writing correct meaning of Trojan)

(f) Out of the following, which all comes under cyber crime? 1

(i) Stealing away a brand new hard disk from a showroom.

(ii) Getting in someone's social networking account without his consentand posting on his behalf.

(iii) Secretly copying data from server of an organization and selling it tothe other organization.

(iv) Looking at online activities of a friends blog.

Ans (ii) & (iii)

(½ Mark for choosing each of the correct options)

Note:

No marks to be given, if all options are there in the answer

½ Mark to be deducted, if one extra option is given along with

the correct options

521

(g) Xcelencia Edu Services Ltd. is an educational organization. It is planning toset up its India campus at Hyderabad with its head office at Delhi. TheHyderabad campus has 4 main. buildings - ADMIN, SCIENCE, BUSINESSand ARTS. You as a network expert have to suggest the best network relatedsolutions for their problems raised in (i) to (iv), keeping in mind the distancesbetween the buildings and other given parameters.

DELHI HYDERABAD

Head Office Campus SCIENCE

ADMIN BUSINESS

ARTS

Shortest distances between various buildings :

ADMIN to SCIENCE 65m

ADMIN to BUSINESS 100m

ADMIN to ARTS 60m

SCIENCE to BUSINESS 75m

SCIENCE to ARTS 60m

BUSINESS to ARTS 50m

DELHI Head Office to HYDERABAD Campus 1600Km

Number of computers installed at various buildings are as follows:

ADMIN 100

SCIENCE 85

BUSINESS 40

ARTS 12

DELHI Head Office 20

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(i) Suggest the most appropriate location of the server inside the

HYDERABAD campus (out of the 4 buildings), to get the best

connectivity for maximum number of computers. Justify your answer. 1

Ans ADMIN (due to maximum number of computers)

OR

ARTS (due to shorter distance from the other buildings)

(1 Mark for mentioning Correct building name with reason)

OR

(½ Mark to be deducted for not giving reason)

(ii) Suggest and draw the cable layout to efficiently connect various

buildings within the HYDERABAD campus for connecting the com-

puters. 1

Ans Anyone of the following

(1 Mark for drawing correct layout)

(iii) Which hardware device will you suggest to be procured by the

company to be installed to protect and control the internet uses within

the campus? 1

Ans Firewall OR Router

(1 Mark for correct Answer)

(iv) Which of the following will you suggest to establish the online face-

to-face communication between the people in the Admin Office of

HYDERABAD campus and DELHI Head Office? 1

523

(i) E-mail

(ii) Text Chat

(iii) Video Conferencing

(iv) Cable TV

Ans Video Conferencing

(1 Mark for correct Option / Answer)

Documents

Marking Scheme — Computer Sciencecbseocean.weebly.com/uploads/2/8/1/5/28152469/2015csms.pdfMarking Scheme — Computer Science General Instructions : z The answers given in the marking