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8/13/2019 m10180[Shannon's Noisy Channel Coding]
1/4
C= maxpX(x) {I(X; Y) |pX(x)} I(X; Y) X Y
R
C
> 0
n
R > C
C0.5
Yi= Xi+ i
Xi
i
2 Xi P
1
n
ni=1
Xi
2 P
8/13/2019 m10180[Shannon's Noisy Channel Coding]
2/4
nY= X +
n
1
n
ni=1
i
2
= 1
n
ni=1
(|yi xi|)2
2
n Y n
n2 X (|y x|)2 n2
Xi i Xi
1
n
ni=1
yi
2 P+ 2
|Y| n P+ 2
Y
n (P+ 2)
X Y
n2
n (P+ 2)
M =
n(2+P)
n
n2n
=
1 + P2
n2
n
C= 12 log2
1 + P
2
N02
P W P
2 =
WW
N02 df
= W N0
8/13/2019 m10180[Shannon's Noisy Channel Coding]
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12 log2
1 + P
N0W
2W
C=
2W
2 log2
1 +
P
N0W
bits/trans. x trans./sec
C= Wlog2
1 +
P
N0W
bits
sec
C= 3000log2(1 + 1000)30000bits
sec
8/13/2019 m10180[Shannon's Noisy Channel Coding]
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log2
1 +
P
2
n2