Linear Integrated Circuits Unit2 Raghudathesh VTU

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    LINEAR INTEGRATED CIRCUITS (VTU) - 10EC46

    UNIT - 2

    Op-Amps as AC Amplifiers: Capacitor coupled Voltage Follower, High input impedance

    Capacitor coupled Voltage Follower, Capacitor coupled Non-inverting Amplifiers, High input

    impedance - Capacitor coupled Non-inverting Amplifiers, Capacitor coupled Inverting

    amplifiers, setting the upper cut-off frequency, Capacitor coupled Difference amplifier, Use of a

    single polarity power supply. 7 Hours 

    TEXT BOOKS:

    1. “Operational Amplifiers and Linear IC’s”, David A. Bell, 2nd

     edition, PHI/Pearson, 2004.

    2. “Linear Integrated Circuits”, D. Roy Choudhury and Shail B. Jain, 2nd

     edition, Reprint 2006,

     New Age International.

    Special Thanks To:

    Faculty (Chronological):

    Students:

    BY:

    RAGHUDATHESH G P

    Asst Prof

    ECE Dept, GMIT

    Davangere 577004

    Cell: +917411459249

    Mail: [email protected] 

    Website: raghudathesh.weebly.com  

    Quotes:

    A warm smile is the universal language of kindness.

    It always seems impossible unitll its done.Everyone thinks of changing the nation; but no one thinks of changing himself The first step towards change is awareness. The second step is acceptance.Trust, but verify.

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    mailto:[email protected]:[email protected]:[email protected]:[email protected]

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    Introduction: 

    Op-Amp can be used as both AC and DC Amplifiers.

    The Op-Amp circuit which is used to amplifying AC signals are called as AC amplifiers.

    Operational amplifier circuits can readily be capacitor coupled at the input and output so

    that they operate only as ac amplifiers.

    Capacitors must not be allowed to interrupt the bias current paths  to the op-amp

    input terminals.

    While designing such AC amplifiers, the low and high frequency limits must be taken

    care of.

    Since capacitors have their highest impedances at the lowest signal frequency, all

    coupling capacitor values must be calculated at the desired lower cutoff frequency

    (f 1).

    The impedance of coupling capacitors at (f 1) is usually determined as one-tenth of the

    resistance in series with them.

    The largest capacitor in the circuit is normally selected to determine (f 1) and in this case

    the capacitive impedance is made equal to the series-connected resistance.

    Ex. Application: Audio input which has well defined range of frequencies and any signal

    outside this range must be rejected.

    Impedance equalization at the two inputs, is not essential  as it will only result in DC

    shift at the output.

    All AC and DC amplifiers have a RC lowpass or high pass circuits at the input and

    output.

    Figure 2.1: Response of Highpass and Lowpass Filter

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    Capacitor Coupled Voltage Follower:

      The voltage follower is a unity gain buffer amplifier.

      An AC Coupled voltage follower is as shown in the figure 2.2 below. The amplifier

    couples both input and output through high pass filter.

    Figure 2.2: Capacitor Coupled Voltage Follower 

      For AC amplifiers it is necessary that the input DC bias currents should not interrupted

     by the coupling capacitors at the inputs hence, resistance R 1  is connected between non-

    inverting terminal and the ground which carries the input bias current IB.

      A resistor equal to R 1 might he included in series with the inverting terminal to equalize

    the IBR B voltage drop and thus minimize the out-put offset voltage. However, in the case

    of a circuit with its output capacitor-coupled, small DC offset output voltages are

    unimportant because they are blocked by the capacitor. 

      Design:

      Involves calculations of R 1, C1 and C2.

      To ensure minimum power dissipation and minimum current drawn from the

     power supply, larger value resistors are used and is given by,

      ------- (1)  The input impedance of non-inverting voltage follower is very very large which is

    in parallel with the resistance R 1, hence circuit input impedance Zin is given as,

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          ------- (2)  Here    Since   is very very large which is in parallel with the resistance R 1.Thus, parallel combination is smaller than the smallest than R 1 and is almost equal to

    R 1.

    ------- (3)

      Load resistor R L normally has a lower resistance than R 1.

      Capacitor value is inversely proportional to the resistance in series with it, and C2 

    is selected usually larger than C1.

      At the circuit low 3 dB frequency (f l), the impedance of C1  should be muchsmaller than Zin  as the signal voltage gets divide across XC1  and Zin  as shown

     below.

    Figure 2.3: signal voltage gets divide across XC1 and Zin 

      C1 is calculated as,

        ------ (4)

      From equation (3) and expanding XC1 

       

     

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    --------- (5)

      As shown in figure 2.4 below, the circuit output voltage Vo is divided across XC2

    and R L to give the load voltage VL.

    Figure 2.3: output voltage gets divide across XC2 and R L 

      The equation for VL is

     

         When XC2 = R L, then

       

        Apply log on both sides we get,

     

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           ------- (6)

      The circuit low 3 dB frequency (f 1) occurs when XC2  = R L. Therefore, C2  is

    calculated from

           

    ----------- (7)

      The above design approach gives the smallest possible capacitor values. When

    selecting standard value components, the next larger standard size should be

    chosen to give capacitive impedances slightly smaller than calculated.

     

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    High Zin Capacitor-Coupled Voltage Follower:

      The input impedance of the capacitor-coupled voltage follower is set by the value of

    resistor R 1  is not very large and has much smaller input impedance than the direct-

    coupled voltage follower.

      To use voltage follower as buffer it is necessary that the input impedance should be verylarge.

      Figure 2.4 shows a method by which the input impedance of the capacitor-coupled

    voltage follower can be substantially increased.

    Figure 2.4: High input impedance capacitor-coupled voltage follower

      Capacitor C2 is connected between inverting input terminal and junction point of R 1 and

    R 2.

      For AC purpose, C2 acts as an AC short circuit so that Vo is developed across R 2.

      Voltage developed across R 1 is given as,

       

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        ------- (1)  Current i1 is given as,

       From equation (1) we get

       Input impedance is given by,

     ------- (2)

      Since M (open loop gain) is very large, this modified circuit has very very high input

    impedance.

      This method is called as bootstrapping of biasing resistance.

      Design Steps:  The resistors R 1 and R 2 are treated to be single resistors and its value is obtained

    as

       

      With R 1 = R 2 

       Selection of C1  ideally can be done same as the basic capacitor coupled voltage

    follower. Due to effect of stray capacitance, XC1 is selected as

     

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      To keep feedback voltage same as output voltage Vo  which is equal to inputvoltage vi at the lowest operating frequency

           The capacitor C3 is given as,

           

       As R 1 = R 2 = R (max)/2 thus,

     

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    Capacitor-Coupled Non-inverting Amplifier: 

      Figure 2.5 below shows the circuit for capacitor-coupled non-inverting amplifier

    Figure 2.5: Capacitor-Coupled Non-inverting Amplifier

      In the above figure the input is connected to the non-inverting terminal by coupling it to a

    input capacitor. Thus, to provide a path for DC input bias current, the non-inverting

    terminal is grounded through resistance R 1.

      The output is capacitor coupled through capacitor C2. As amplifier is used for AC

    Quantity, the DC offset voltage present at the output if any is not significant.

      To ensure minimum power dissipation and minimum current drawn from the power

    supply, larger value resistors are used and is given by,

      The input impedance of non-inverting amplifier is very very large which is in parallel

    with the resistance R 1, hence circuit input impedance Zin is given as,

       

      Here    Since   is very very large which is in parallel with the resistance R 1.Thus, parallel

    combination is smaller than the smallest than R 1 and is almost equal to R 1.

     

     

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      From Potential divider logic the resistor values R 2 and R 3 are determined using Vi, Vo, I2.

    By convention we select I2 much larger than IB(max) by about 100 times.

       From the concept of virtual ground, Vin = VA = VB thus

      Using the concept of closed loop voltage gain Av output voltage is given as

       

         As Vo appears across (R 2 + R 3) hence,

     

      At the circuit low 3 dB frequency (f l), the impedance of C1 should be much smaller than

    Zin as the signal voltage gets divide across XC1 and Zin as shown below.

    Figure 2.6: signal voltage gets divide across XC1 and Zin 

     

     

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      C1 is calculated as,

         As Zin = R 1 and expanding XC1 

       

      The circuit low 3 dB frequency (f 1) occurs when XC2 = R L. Therefore, C2  is calculated

    from

         

     

     

     

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    High Zin, Capacitor-Coupled Non-inverting Amplifier: 

      The input impedance of the capacitor-coupled non-inverting amplifier is set by the value

    of resistor R 1 is not very large and needed to be increased in much application.

      Improvement in input impedance Zin is done by modifying the circuit as below

    Figure 2.7: High Zin Capacitor-Coupled Non-inverting Amplifier

      Input impedance Zin for the above circuit is given as,

      ------ (1)

      Within the operating bandwidth, the capacitor C2  act as short circuit. Using potential

    divider rule the voltage across resistor R 3 is given as

      ------- (2)  Thus, from above equation we see that the feedback voltage is attenuated by a factor of,

      ------ (3)  Thus substituting equation (3) in (2) we get,

      ------- (4)

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      As open loop gain (M) is very large the modified circuit has large input impedance.

      This method is called as bootstrapping of biasing resistance.

      Design Steps:

      The resistors R 1 and R 2 are treated to be single resistors and its value is obtained

    as

         

      In the pass-band the gain of non-inverting amplifier is

       

         The value of resistor R 2 and R 3 for high Zin circuit are determined exactly as for a

    direct-coupled non-inverting amplifier. For equal IBR B,

     Usually,  

      With R 1 = R 3 

     

      Above is applicable for bipolar op-amps only. For BiFET op-amps must be equal

    to  and R 2 = 1MΩ.   Capacitor value C1 is chosen as 1000pF to be much larger than stray capacitances.

      At lower 3dB frequency f L the gain of the amplifier is given wrt pass band as

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            --------- (11)  At frequency f L the gain of the amplifier considering impedance is given as,

       Since Av >> 1 the above equation is written as,

       Considering only real terms we get,

      ------- (12)  In pass-band the gain is dependant only on resistive terms hence,

       Since Av >> 1 the above equation is written as,

      ------- (13)  Substitute equations (12) and (13) in (11) we get,

     

     

        

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      As XC3 is equal to R 3/10 hence, Capacitor C3 is given as,

     Capacitor-Coupled Inverting Amplifier:

      Figure 2.7 below shows the circuit for capacitor-coupled inverting amplifier

    Figure 2.7: Capacitor-Coupled Inverting Amplifier

      In the above circuit the bias current to the op-amp inverting input terminal flows via

    resistor R 2, so coupling capacitor C1 does not interrupt the input bias current. 

       No resistor is included in series with the non-inverting input terminal, because a small

    DC offset is not important with a capacitor-coupled output.

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      If it is desired to equalize the IBR B voltage drops, the resistance in series with the non-

    inverting input should equal R 2  because R 1  is not part of the bias current path at the

    inverting input terminal.

      Design:

      From the concept of virtual ground,

       As Vo appears across (R 2) hence,

     

      C1 is calculated as,

         As Zin = R 1 and expanding XC1 

     

     

      The circuit low 3 dB frequency (f 1) occurs when XC2  = R L. Therefore, C2  is

    calculated from

           

     

     

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    Setting the Upper Cutoff Frequency: 

      The highest signal frequency that can be processed by an op-amp circuit depends on the

    op-amp selected like 741, LF353 etc.

      Consider an application where very low frequency signals are to be amplified and

    unwanted higher frequency noise voltages are to be excluded.  In the above application, the circuit voltage gain should be made to fall off just above the

    highest desired signal frequency.

      This can be achieved by connecting a feedback capacitor Cf  from the op-amp output to its

    inverting input terminal as shown in figure 2.8 (a) and (b) below 

    Figure 2.8 (a): Inverting Amplifier 

    Figure 2.8 (b): Non-Inverting Amplifier 

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      Voltage gain for inverting amplifier is given as,

       

       

       

     

     

     

         

      Magnitude of AV is given as,

           

      Say if XCf  = R 2 then,

         

         

        

         

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      The above equation indicates that the gain is 3 dB below the normal voltage gain (R 2/R 1).

    Hence, upper cut-off frequency f 2  can be set at a desired value by selecting Cf   which

    makes XCf   = R 2 at the required frequency.

         

      For the case of non-inverting amplifier the result derived from inverting amplifier is

    equally applicable provided that to implement such circuit upper cut-off frequency of op-

    amp must be much higher than the desired maximum frequency for the circuit.

    Capacitor Coupled Difference Amplifier or Subtractor:

      Capacitor Coupled Difference Amplifier is as shown in figure 2.9 as shown below

    Figure 2.9: Capacitor Coupled Difference Amplifier

      We employ superposition theorem to solve the circuit

      Case1: let V1 be operational and V2 be grounded. Output be represented as Vo1 as shown

    in figure 2.10 below

     

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    Figure 2.10: op-amp configured as a difference amplifier with V1 Operational

      Looking in to the above figure we see that it is a inverting amplifier configuration, hence

    gain is given as

     

      ------ (1)

      The output voltage is given as

            --------- (2)

      Case2: let V2 be operational and V1 be grounded. Output be represented as Vo2 as shown

    in figure 1.34 below

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    Figure 2.11: op-amp configured as a difference amplifier with V2 Operational

      Looking in to the above figure we see that it is a non-inverting amplifier configuration,

    hence gain is given as

     

      ------ (3)

      The output voltage is given as

         

      The voltage VA is given by Ohms law as,

         

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      Substituting VA in Vo2 we get,   ------- (4)  Adding both the outputs we get,

      ------- (5)   Now Say we select the resistances R 1 = R 3 and R 2 = R 4  in such case above equation is

    reduced to,

       

       

    -------- (6)

       Now say if R 2 = R 1 in this case the output is the difference value of 2 input voltages.

      From the concept of virtual ground,

       Resistance R 2 is given as

       Resistance R 3 is given as

       Resistance R 4 is given as    C1 is calculated as,

     

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           As Zin = R 1 and expanding XC1 

       

      C2 is calculated as,

         

       The circuit low 3 dB frequency (f 1) occurs when XC3 = R L. Therefore, C3  is calculated

    from

         

     

       If upper cut-off frequency is to be set, then the capacitors must be connected across

    resistors R 2 and R 4 as shown in figure 2.12 below

     

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    Figure 2.12: Setting Upper cut-off Frequency for Difference Amplifier

      For the case of upper cut-off frequency capacitor Cf1 is determined as,

       

     

       For the case of upper cut-off frequency capacitor Cf2 is determined as,

       

       

      Here,

      f 2 = desired upper cut-off frequency

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    Use of Single Polarity Supply:  Most of the operational amplifiers are designed to be used with dual supply such that the

    magnitudes of both positive and negative supply voltages with respect to ground are

    equal.

      If we neglect the offset voltage, output voltage is zero when input signal is zero. The DCreference value of the resulting output is also zero and the maximum output voltage

     possible is slightly less than the positive and negative supply voltage.

      Instead of using bipolar power supply, the operational amplifiers can be externally biased

    using a single supply voltage also.

      The above case is possible if an additional coupling capacitor is used to remove unwanted

    DC levels. As such a capacitor blocks DC, the offset voltage and DC level in the output

    has hardly any effect on the operation of the amplifier.

      Hence single supply biasing is possible only in case of AC amplifiers.

      The operational amplifier using a single supply biasing, must be able to produce both

    negative going and positive going signals.

      For the above purpose an AC level is purposely inserted, in such a single supply biasing.

      The operational amplifier's quiescent DC output voltage is set to one half of the single

     positive supply i.e. 1/2 Vcc, in single supply biasing. This ensures that the positive output

    swing equals the negative.

      The DC level of 1/2 Vcc is inserted by using a voltage divider network at the non-

    inverting input terminal. The resistance values of a divider are made equal so that the

    output across one resistance is half the supply voltage, +Vcc.

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    Voltage Divider Using Single Polarity Supply:

      Capacitor coupled op-amp circuits can be easily adapted to use a single polarity supply

    voltage because the capacitors block the DC bias voltages at input and output.

      A capacitor coupled voltage follower circuit using a single-polarity supply is illustrated in

    figure 2.13 below

    Figure 2.13: capacitor coupled voltage follower using single polarity supply

      If the op-amp data sheet lists the minimum supply voltage as ±9 V, then a minimum of 18

    V should be used in a single-polarity supply situation. Also, the specified maximum

    supply voltage should not be exceeded.

      The potential divider (R 1 and R 2) sets the bias voltage at the non-inverting input terminal

    as approximately Vcc/2. This means that the DC levels of the output terminal and the

    inverting input are also at Vcc/2.

      Thus, with an 18 V supply, the positive supply terminal is +9 V with respect to the bias

    level at the input and output terminals, and the negative supply terminal is -9 V with

    respect to those terminals.

      The voltage drop across each resistor is usually selected as Vcc/2; although it could be

    above or below this point within the specified input voltage range for the op-amp.

      Design Steps:

      Current I2 is selected larger than IB thus,

       As voltage drop across each resistor is usually selected as Vcc/2 hence each

    resistor value is given as,

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      Thus the input impedance becomes,

       The input capacitor C1 at input side is given as,

         Expanding XC1 

     

     

      The circuit low 3 dB frequency (f 1) occurs when XC3  = R L. Therefore, C2  is

    calculated from

         

     

     

     

     

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    High Input Impedance Voltage Follower Using a Single-Polarity Supply:

      Figure 2.14 shows a high input impedance voltage follower using a single-polarity supply

    Figure 2.14: High Input Impedance Voltage Follower Using a Single-Polarity Supply

      In the above circuit the resistors R 1 and R 2 provides a potential of Vcc/2 which is applied

    to non-inverting input via resistor R 3, which is used to provide a bias current path.

      The capacitor bootstraps R 3 making input impedance very large and is given as

       Current I2 is selected larger than IB thus,

       As voltage drop across each resistor is usually selected as V cc/2 hence each resistor value

    is given as,

      As input impedance Zin is very large and resistors (R 1||R 2) are in series with with C2 it is

    given as,

     

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    Capacitor Coupled Non-Inverting Amplifier Using a Single-Polarity Supply: 

      Figure 2.15 shows the circuit of a capacitor coupled non-inverting amplifier using a

    single-polarity supply.

    Figure 2.15: capacitor coupled non-inverting amplifier using a s ingle-polarity supply

      In the above circuit Potential divider R 1  and R 2  used to set the bias voltage at

    approximately Vcc/2.

      The bottom of resistor R 4  is capacitor-coupled to ground via capacitor C3. If this point

    was directly grounded, the DC voltage at the op-amp output terminal would tend toward

    AV∙(bias level at the non-inverting input), or AV∙Vcc/2. This would saturate the output at

    approximately Vcc - 1 V.

     

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      With C3  in the circuit as shown in figure 2.15, and R 3  connecting the inverting input

    terminal to the output, the op-amp behaves as a DC voltage follower.

      The DC voltage level at the op-amp output terminal is then the same as that at the non-

    inverting input terminal (Vcc/2).

      For ac voltages, C3 behaves as a short circuit, so that the AC voltage gain AV is given as

         Design Steps:

      Current I2 & I4 is selected larger than IB thus,

     

       As voltage drop across each resistor is usually selected as Vcc/2 hence each

    resistor value is given as,

      AC voltage Gain is given as

         From the concept of virtual ground, Vin = VA = VB thus

     

      As Vo appears across (R 3 + R 4) hence,

     

     

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      Thus the input impedance becomes,

       The input capacitor C1 at input side is given as,

         Expanding XC1 

     

     

      The circuit low 3 dB frequency (f 1) occurs when XC2  = R L. Therefore, C2  is

    calculated from

           

      Capacitor C3 should be selected to have impedance very much smaller than R 4 at

    the low 3 dB frequency of the circuit for a fixed load.

         

     

     

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    For variable load:

         

     

    High Input Impedance Capacitor-Coupled Non-Inverting Amplifier Using a

    Single-Polarity Supply:

      Figure 2.16 shows a high input impedance Capacitor-Coupled Non-Inverting Amplifier

    using a single-polarity supply

    Figure 2.16: High Input Impedance Capacitor-Coupled Non-Inverting Amplifier Using a Single-Polarity Supply

     

     

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      The above circuit is very similar to the high input impedance voltage follower circuit as

    discussed above but the only difference is that resistor R 4 is included in the non-inverting

    amplifier circuit to give a voltage gain greater than 1 and is given as

         The resistor R 3  is included to increase the input impedance by providing feedback

    through the capacitor C2.

      Current I2 is selected larger than IB thus,

     

      As voltage drop across each resistor is usually selected as V cc/2 hence each resistor valueis given as,

      Resistor R 4 is calculated using the voltage gain equation as above

      C1 is calculated as,

         As Zin = R 1 and expanding XC1 

     

     

     

     

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      The circuit low 3 dB frequency (f 1) occurs when XC3 = R L. Therefore, C3  is calculated

    from

           

      As C2 is in series with the resistor combination R 1||R 2 it is calculated as,

         

     

     

     

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    Capacitor Coupled Inverting Amplifier Using a Single-Polarity Supply:

      The circuit of an inverting amplifier using a single-polarity supply is shown in figure.

    2.17 below

    Figure 2.17: capacitor coupled non-inverting amplifier using a s ingle-polarity supply 

      In the above circuit Potential divider R 3  and R 4  used to set the bias voltage at

    approximately Vcc/2.

      The DC voltage level of the output and the inverting input terminal will then also be

    Vcc/2.

      Design Steps:

      The potential divider is designed by first selecting a current (I 4) which is much

    greater than the current flowing out of the potential divider (IB)

       As voltage drop across each resistor is usually selected as Vcc/2 hence each

    resistor value is given as,

      From the concept of virtual ground,

     

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    VTU Questions:

    1.  Draw a neat circuit diagram of a capacitor coupled voltage follower and explain its

    operation with necessary design steps. December 2015 (08 Marks), December 2014 (07

    Marks), June 2013 (06 Marks), December 2012 (10 Marks) 2.  Design a high impedance capacitor coupled non-inverting amplifier to have a low cutoff

    frequency of 200Hz. The input and output voltages are to be 16mV and 4V respectively

    and minimum load resistance is 10k Ω. select R 2  = 1 MΩ and C1  = 0.1µF. December

    2015 (06 Marks)

    3.  Explain how the upper cutoff frequency can be set for inverting amplifier with the help of

    neat circuit diagram and also explain design steps. December 2015 (06 Marks),

    December 2014 (06 Marks), June 2013 (06 Marks), June 2014 (07 Marks)

    4.  Design a capacitor coupled inverting amplifier using IC741. Op-amp to have a voltage

    gain of 75 output voltage amplitude of 3 V and a single frequency range of 20 Hz to 12kHz. The load resistance is 470 Ω. December 2014 (06 Marks)

    5.  Sketch a neat circuit diagram of a high Z in capacitor coupled voltage follower and explain

    its operation with necessary design steps. June 2014 (08 Marks)

    6.  A capacitor coupled non-inverting amplifier using IC741 op-amp has Av = 100 and Vo =

    5 V. The load resistance is 10 kΩ and the lower cut-off frequency is to be 100 Hz. Design

    a suitable circuit. June 2014 (08 Marks), June 2013(06 Marks)

    7.  Explain inverting AC amplifier with neat diagram and mention its design steps using only

    single-supply op-amp. June 2014 (06 Marks), December 2013 (08 Marks)

    8. 

    Sketch a neat circuit diagram of a high Zin  capacitor coupled non-inverting amplifier.

    Briefly explain its operation and show that the input impedance is very high compared to

    capacitor coupled non-inverting amplifier. December 2013 (08 Marks)

    9.  Design a high Zin capacitor coupled voltage follower using op-amp having lower cut-off

    frequency of 50 Hz and maximum input bias current of 500 nA. The load resistance is 3.9

    kΩ. If the open-loop gain is 2x105. Find the value of input impedance. Consider M(min) =

    50,000. December 2013 (06 Marks)

    10. Draw a neat circuit diagram and design steps for a Capacitor coupled inverting amplifier.

    June 2013 (08 Marks) 

    11. 

    With a neat circuit diagram, explain the design of high impedance capacitor coupled non-

    inverting amplifier. December 2012 (10 Marks)

    12. Design a capacitor coupled voltage follower using a 741 op-amp. The lower cut-off

    frequency for the circuit is to be 50 Hz and the load resistance is R L = 3.9 kΩ. June 2014

    (07 Marks) 

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    13. Explain the use of a single polarity supply for capacitor coupled non- inverting amplifier

    with circuit diagram using op-amp. June 2014 (06 Marks)

    14. Explain the realization of a CC voltage follower for AC amplifier applications, discussing

    cut-off frequency design concept. June 2015 (06 Marks)

    15. 

    Design a BIFET op-amp based high Zin CC non-inverting amplifier for a lower cut-offfrequency of 120 Hz. Given Vin = 20 mV, Vo = 5 V and R L-min = 10 kΩ. June 2015 (08

    Marks)

    16. Explain the concept and construction of a CC inverting amplifier using a single polarity

    supply (+ Vcc). June 2015 (08 Marks) 

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