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Lesson 9.5-The Distance Formula HW:9.5/ 1-14

Lesson 9.5-The Distance Formula

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Lesson 9.5-The Distance Formula. HW:9.5/ 1-14. Isosceles Right ∆Theorem. 45 ° – 45 ° – 90 ° Triangle In a 45 ° – 45 ° – 90 ° triangle the hypotenuse is the square root of two * as long as each leg. Theorem. 30 ° – 60 ° – 90 ° Triangle - PowerPoint PPT Presentation

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Page 1: Lesson 9.5-The  Distance Formula

Lesson 9.5-The Distance Formula

HW:9.5/ 1-14

Page 2: Lesson 9.5-The  Distance Formula

Isosceles Right ∆Theorem

2x

• 45° – 45° – 90° TriangleIn a 45° – 45° – 90° triangle the hypotenuse is the square root of two * as long as each leg

Page 3: Lesson 9.5-The  Distance Formula

Theorem

2

• 30° – 60° – 90° TriangleIn a 30° – 60° – 90° triangle, the hypotenuse is twice as long as the shorter leg, and the longer leg is the square root of three times as long as the shorter leg

𝑥√3

Page 4: Lesson 9.5-The  Distance Formula

Problem Solving Strategy

Know the basic triangle rules

Solve for the other sides

Set known information equal to the corresponding part of the basic triangle

Page 5: Lesson 9.5-The  Distance Formula

New MaterialTHE DISTANCE FORMULA

Page 6: Lesson 9.5-The  Distance Formula

Coordinate Geometry

Page 7: Lesson 9.5-The  Distance Formula

Coordinate Geometry - InvestigationUse the Pythagorean Theorem to find the length of the segment

2

4

22 42 c

c 5220 c

47.4c 6

2

22 26 c

10240 c

32.6c

Page 8: Lesson 9.5-The  Distance Formula

Coordinate Geometry

(AB)2 = (x2 - x1)2 + (y2 - y1)2

The Distance Formula is based on the Pythagorean Theorem

The distance between points A(x1,y1) and B(x2,y2) is given by

Page 9: Lesson 9.5-The  Distance Formula

Coordinate Geometry - Example

Page 10: Lesson 9.5-The  Distance Formula

Exploration

• Get your supplies- Graph Paper- ruler- pencil

• Create a large XY coordinate grid

Page 11: Lesson 9.5-The  Distance Formula

Copy and label these points onto your graph paper, include the coordinates of each point

Exploration

Page 12: Lesson 9.5-The  Distance Formula

Exploration• Find the distance between the listed attractions• Use the Pythagorean theorem. • Draw right triangle if necessary.

Page 13: Lesson 9.5-The  Distance Formula

a. Bumper cars to sledge hammera. (-4, -3) to (2, -3)

x

y

Distance = 6

Page 14: Lesson 9.5-The  Distance Formula

b. Ferris Wheel and Hall of Mirrors(0, 0) and (3, 1)

x

y

3

1

Use the Pythagorean Theorem

=

=10

c

𝑐=√10𝑐 ≈3.16

Page 15: Lesson 9.5-The  Distance Formula

b. Ferris Wheel and Hall of Mirrors (0, 0) and (3, 1)

22 )10(30 22 )1()3(

16.310

𝑐=√𝑥2+𝑦 2

Using the points and Pythagorean theorem = DISTANCE FORMULA

Page 16: Lesson 9.5-The  Distance Formula

y Use the Pythagorean theorem

=

= 25

𝑐=√25𝑐=5

c. Refreshment Stand to Ball Toss(-5, 2) to (-2, -2)

x

3

4 c

Page 17: Lesson 9.5-The  Distance Formula

c. Refreshment Stand to Ball Toss (-5, 2) to (-2, -2)

22 )22(25 22 )4()3(

525

𝑐=√𝑥2+𝑦 2

Using the points and Pythagorean theorem = DISTANCE FORMULA

Page 18: Lesson 9.5-The  Distance Formula

y Use the Pythagorean theorem

=

=85

𝒄=√𝟖𝟓𝒄≈𝟗 .𝟐𝟐

d. Bumper Cars to Mime Tent(-4, -3) to (3, 3)

x

7

6c

Page 19: Lesson 9.5-The  Distance Formula

d. Bumper Cars to Mime Tente. (-4, -3) to (3, 3)

22 )33(34

22 )6()7(

22.985

Page 20: Lesson 9.5-The  Distance Formula

ExplorationIf your car is parked at the coordinates (17, -9),

and each grid unit represents 0.1 mile, how far is from your car to the refreshment stand?

22 29)5(17 d

22 )11(22 d

60.24605 d ≈2.46 Milesunits *0.1 miles

Try to complete this without plotting the location of your car.

Car to Refreshment stand(17, -9) to (-5, 2)

Page 21: Lesson 9.5-The  Distance Formula

22 02)3(1 d

22 24 d

20d

Find the distance between the points at (1, 2) and (–3, 0).

222

222 yyxxd

47.452

Page 22: Lesson 9.5-The  Distance Formula

22 63)4(2 d

22 )3(6 d

45d

Find the distance between the points at (2, 3) and (–4, 6).

71.653

Page 23: Lesson 9.5-The  Distance Formula

Find the distance between the points at (5, 4) and (0, –2).

√ ( 4+2 )2+ (5−0 )2

√ (6 )2+ (5 )2

√36+25

√61≈7.81

Page 24: Lesson 9.5-The  Distance Formula

Horseshoes Marcy is pitching a horseshoe in her local park. Her first pitch is 9 inches to the left and 3 inches below the pin. What is the distance between the horseshoe and the pin?

&

√¿¿¿√¿¿¿

√90

3√10≈9.49 𝑖𝑛

Page 25: Lesson 9.5-The  Distance Formula

Homework

Lesson 9.5 - Distance Formula9.5/1-14