Upload
amaya-bradshaw
View
65
Download
12
Embed Size (px)
DESCRIPTION
Lesson 9.1-9.2 WS SOLUTIONS. Worksheet SOLUTIONS. a. 3. x. a. 4. 3. 3. C = (11, -1). 5.7. 3. x. 6.8. 4.2426. 7.8393. 3. Hypotenuse should be the longest side of a right triangle. 3. 4. R. 15. P. 20. Q. Worksheet SOLUTIONS. RIGHT β. ACUTE β. RIGHT β. RIGHT β. 7. 2.5. - PowerPoint PPT Presentation
Citation preview
Lesson 9.1-9.2 WSSOLUTIONS
Worksheet SOLUTIONS
5625β5184=π2
441=π2
β 441=π
21=π
752=722+π2196β64=π2
132=π2
β132=π
142=82+π2
a
π2=441+132
π=β57 3
π2=212+β1322
π2=57 3
3
676β576=π2
100=π2
β100=π
262=242+π2
100β36=π₯2
π₯=β64
102=62+π₯2
π₯2=64
a
π=10π₯=8
39=126 π₯
39=3 π₯13=π₯
x
h2=169+36
h=β205
h2=132+62
h2=205
hβ14.32 ππ
π΄=126ββ 40
π΄=3ββ 40
49β9=h2
40=h2
β 40=h
72=32+h2
3
π΄β18.97 ππ‘ 2
3
4
C = (11, -1)
π΄π΅=β25π΄π΅2=32+42
π΄π΅=5
6.8
13.4β7.7=5.7
5.7
6.82=5.72+π₯2
x
46.24=32.49+π₯2
13.75=π₯2
βππ .ππ=ππ΄=πβh
π΄=13.4ββ13.75π¨βππ .πππππ
3
3
π π 2=18π π=β18
π π 2=32+32
π π=ππ=β18
π π 2β32+(7.2426)2ππ +ππ=πΊπΌ=3+β18β7.2426
π π 2β61.4552πΉπΌ βπ .ππππ
4.2426 7.8393
π π 2β32+(15 .0819)2
π π 2β236 .4637πΉπ½ βππ .ππππ¦
π2=16π=4
4
Hypotenuse should be the longest side of a right triangle
3
PQ
R
15
20
π π2=152+202
π π2=225+400π π2=625π π=25
π΄=1215β20
π΄=150 ππ2
Worksheet SOLUTIONS
1202=982+762
14400=9604+577614400<15380
ACUTE β
2212=2042+852
48841=41616+722548841=48841
RIGHT β
52=4.82+1.4
25=23.04+1.96
25=25RIGHT β
822=802+182
6724=6400+3246724=6724
RIGHT β
7
3.5
72ΒΏ3.52+π₯2
π
49β12.25=π₯2
36.75=π₯2
β36.75=π₯π .ππππβ π₯
Aβ Β½ *7*
A β 21.2177
2.5
42.25=36+6.256.52=62+2.52
42.25=42.25
Pyth thm works
90Β°
452=72+π₯2
2025β49=π₯2
1976=π₯2
β1976=π₯
4 4.45βπ₯
3
4
6
6β2 32+42
36β 9+16 NOT a Rectangle
5β2 32+42
25=9+16 YES a Rectangle
Cannot be determined β No hypotenuse given