4
Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page 1 of 4 Radical Equations Activity Solve. 1. 20 2 7 x x = ( ) ( ) ( ) ( )( ) 2 2 2 2 20 2 7 20 2 7 400 2 7 400 2 7 2 7 2 7 2 7 400 2 7 400 0 2 25 16 0 x x x x x x x x x x x x x x x x = = = = = = + = 2 25 0 or 16 0 25 or 16 2 x x x x + = = =− = 25 2 x ≠− since x cannot be negative Check: 16 x = ( ) ? ? ? ? 20 16 2 16 7 20 4 25 20 4 5 4 4 = = = = Answer: 16 x =

Lesson 9: Rational Exponents and Radicals · Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page

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Page 1: Lesson 9: Rational Exponents and Radicals · Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page

Lesson 9: Rational Exponents and Radicals Digging Deeper solutions

Algebra 1

© 2009 Duke University Talent Identification Program

Page 1 of 4

Radical Equations Activity

Solve.

1. 20

2 7x

x=

( )

( ) ( )

( ) ( )

22

2

2

20

2 7

20

2 7

400

2 7

4002 7 2 7

2 7

2 7 400

2 7 400 0

2 25 16 0

xx

xx

xx

x x xx

x x

x x

x x

=−

=

=−

− ⋅ = − −

− =

− − =

+ − =

2 25 0 or 16 0

25 or 16

2

x x

x x

+ = − =

= − =

25

2x ≠ − since x cannot be negative

Check: 16x =

( )

?

?

?

?

2016

2 16 7

204

25

204

5

4 4

=−

=

=

= �

Answer: 16x =

Page 2: Lesson 9: Rational Exponents and Radicals · Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page

Lesson 9: Rational Exponents and Radicals Digging Deeper solutions

Algebra 1

© 2009 Duke University Talent Identification Program

Page 2 of 4

2. 2 5 2 1 0z z+ + + − =

To solve this, we’ll isolate one of the radicals and square both sides.

Then we’ll isolate the other radical and square both sides again.

( ) ( )( )

( ) ( )( )

( ) ( )

2 2

22

2

2

2

2 5 2 1 0

2 5 1 2

2 5 1 2

2 5 1 2 2 2

2 2 2

2 2 2

4 4 4 2

4 4 4 8

4 0

2 2 0

z z

z z

z z

z z z

z z

z z

z z z

z z z

z

z z

+ + + − =

+ = − +

+ = − +

+ = − + + +

+ = − +

+ = − +

+ + = +

+ + = +

− =

+ − =

2 0 or 2 0

2 or 2

z z

z z

+ = − =

= − =

Check: 2z = − 2z =

( ) ( )

?

?

?

?

?

2 5 2 1 0

2 2 5 2 2 1 0

1 0 1 0

1 0 1 0

0 0

z z+ + + − =

− + + − + − =

+ − =

+ − =

= �

( ) ( )

?

?

?

?

?

2 5 2 1 0

2 2 5 2 2 1 0

9 4 1 0

3 2 1 0

4 0

z z+ + + − =

+ + + − =

+ − =

+ − =

= �

Answer: 2z = −

Page 3: Lesson 9: Rational Exponents and Radicals · Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page

Lesson 9: Rational Exponents and Radicals Digging Deeper solutions

Algebra 1

© 2009 Duke University Talent Identification Program

Page 3 of 4

3. ( )3

419 27 0m − − =

( )

( )

( )

( )( )

3

4

3

4

443 334

43

4

19 27 0

19 27

19 27

19 27

19 3

19 81

100

m

m

m

m

m

m

m

− − =

− =

− =

− =

− =

− =

=

Check: 100m =

( )

( )

( )

( )( )

3 ?

4

3 ?

4

3 ?

4

?34

?3

?

?

19 27 0

100 19 27 0

81 27 0

81 27 0

3 27 0

27 27 0

0 0

m − − =

− − =

− =

− =

− =

− =

= �

Answer: 100m =

Page 4: Lesson 9: Rational Exponents and Radicals · Lesson 9: Rational Exponents and Radicals Digging Deeper solutions Algebra 1 © 2009 Duke University Talent Identification Program Page

Lesson 9: Rational Exponents and Radicals Digging Deeper solutions

Algebra 1

© 2009 Duke University Talent Identification Program

Page 4 of 4

4. Find the distance between the points (4, 8) and (-2, 5).

( )( ) ( )

( ) ( )

2 2

2 2

4 2 8 5

6 3

36 9

45

9 5

3 5

d = − − + −

= +

= +

=

= ⋅

=

Distance is 3 5