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Lesson 3-9 Weighted Averages

Lesson 3-9

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Lesson 3-9. Weighted Averages. Objectives. Solve mixture problems Solve uniform motion problems. Vocabulary. Weighted average – sum of the product of the number of units and the value per unit divided by the sum of the number of units - PowerPoint PPT Presentation

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Page 1: Lesson 3-9

Lesson 3-9

Weighted Averages

Page 2: Lesson 3-9
Page 3: Lesson 3-9
Page 4: Lesson 3-9

Objectives

• Solve mixture problems

• Solve uniform motion problems

Page 5: Lesson 3-9

Vocabulary

• Weighted average – sum of the product of the number of units and the value per unit divided by the sum of the number of units

• Mixture problems – problems in which two or more parts are combined into a whole

• Uniform motion problems – problems where an object moves at certain speed or rate

Page 6: Lesson 3-9

Mixture Problems

• Step 1:

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Example 1

Pets Jeri likes to feed her cat gourmet cat food that costs $1.75 per pound. However, food at that price is too expensive so she combines it with cheaper cat food that costs $0.50 per pound. How many pounds of cheaper food should Jeri buy to go with 5 pounds of gourmet food, if she wants the price to be $1.00 per pound?

Units (lb) Price per Unit Price

Gourmet cat food

Gourmet cat food

Mixed cat food

Let w = the number of pounds of cheaper cat food. Make a table.

5 $1.75 $8.75w $0.50 0.5w

5 + w $1.00 1.00(5 + w)

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Example 1 cont

Original equation

Distributive Property

Subtract 0.5w from each side.

Simplify.

Simplify.

Subtract 5.0 from each side.

Simplify.

Divide each side by 0.5.

Answer: Jerry should buy 7.5 pounds of cheaper cat food to be mixed with the 4 pounds of gourmet cat food to equal out to $1.00 per pound of cat food.

Page 9: Lesson 3-9

Example 2

Auto Maintenance To provide protection against freezing, a car’s radiator should contain a solution of 50% antifreeze. Darryl has 2 gallons of a 35% antifreeze solution. How many gallons of 100% antifreeze should Darryl add to his solution to produce a solution of 50% antifreeze?

35% Solution

100% Solution

50% Solution

Amount of Solution (gallons)

Price

Let g = the number of gallons of 100% antifreeze to be added. Make a table.

2 0.35(2)

g 1.0(g)

2 + g 0.50(2 + g)

Page 10: Lesson 3-9

Example 2 cont

Original equation

Distributive Property

Amount of antifreeze in 35% solution plus

amount of antifreeze in

100% solution equals

amount of antifreeze in

50% solution.

Simplify.

Subtract 0.50g from each side.

0.35(2) 1.0(g) 0.50(2 + g)

Subtract 0.70 from each side.

Simplify.

Page 11: Lesson 3-9

Example 3

To find the average speed for each leg of the trip, rewrite .

Air Travel Mirasol took a non-stop flight from Newark to Austin to visit her grandmother. The 1500-mile trip took three hours and 45 minutes. Because of bad weather, the return trip took four hours and 45 minutes. What was her average speed for the round trip?

Going

Returning

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Example 3 cont

Simplify.

Answer: The average speed for the round trip was about 343.9 miles per hour.

Definition of weighted average

Round Trip

Page 13: Lesson 3-9

Example 4

Rescue A railroad switching operator has discovered that two trains are heading toward each other on the same track. Currently, the trains are 53 miles apart. One train is traveling at 75 miles per hour and the other train is traveling at 40 miles per hour. The faster train will require 5 miles to stop safely, and the slower train will require 3 miles to stop safely. About how many minutes does the operator have to warn the train engineers to stop their trains?

Draw a diagram.

53 miles apart

Takes 5 miles to stop Takes 3 miles to stop

Page 14: Lesson 3-9

Example 4 cont

Fast train

Other train

r d = rtt

Let m = the number of minutes that the operator has to warn the train engineers to stop their trains safely. Make a table.

75 m

40 m

75m

40m

Original equation

Simplify.

Divide each side by 115.

Answer: The operator has about 23 minutes to warn the engineers.

Round to the nearest hundredth.

Convert to minutes by multiplying by 60.

Page 15: Lesson 3-9

Summary & Homework

• Summary:– The weighted average of a set of data is the sum of

the product of each number in the set and its weight divided by the sum of all the weights

– The formula d = rt (distance = rate of change (velocity) time) is used to solve uniform motion problems

• Homework: – none