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1 Lesson 1.2.6 Applications of Equations

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Applications of Equations. Lesson 1.2.6. Lesson 1.2.6. Applications of Equations. California Standards: Algebra and Functions 4.1 - PowerPoint PPT Presentation

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Page 1: Lesson 1.2.6

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Lesson 1.2.6Lesson 1.2.6

Applications ofEquations

Applications ofEquations

Page 2: Lesson 1.2.6

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Lesson

1.2.6Applications of EquationsApplications of Equations

California Standards:Algebra and Functions 4.1Solve two-step linear equations and inequalities in one variable over the rational numbers, interpret the solution or solutions in the context from which they arose, and verify the reasonableness of the results.

Mathematical Reasoning 2.1Use estimation to verify the reasonableness of calculated results.

What it means for you:You’ll see how to use equations to help solve real-life math problems, and how to check if your answer is sensible.

Key Words:• model

• check

• reasonable

• sensible

Page 3: Lesson 1.2.6

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Lesson

1.2.6Applications of EquationsApplications of Equations

Equations can be really useful in helping you to understand real-life situations.

Writing an equation can help you sort out the information contained in a word problem and turn it into a number problem.

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Equations Can Describe Real-Life Situations

Lesson

1.2.6Applications of EquationsApplications of Equations

An equation can help you to model a real-life situation — to describe it in math terms.

You can use an equation to help you describe almost any situation that involves numbers and unknown numbers.

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Lesson

1.2.6Applications of EquationsApplications of Equations

For example:• You’ve just had your car repaired. The bill was $280.• You know the parts cost $120.• You know the mechanic charges labor at $40 per hour. • You want to know how long the mechanic worked on

your car — you need an equation.

Let h = number of hours worked by mechanic.

40h + 120 = 280

40h = 160

h = 4

1. Choose a variable.

2. Write an equation.

3. Solve the equation. The amount billed

Cost of parts

Cost of labor Subtract 120 from both sidesDivide both sides by 40

So the mechanic must have worked on your car for 4 hours.

Page 6: Lesson 1.2.6

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Example 1

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

At the school supply store, Mr. Ellis bought a notebook costing $3, and six pens. He spent $15 in total. Find the price of one pen, p.

Solution

First write out the information you have:• Total spent = $15• Cost of notebook = $3• Cost of six pens = 6p

You know that six pens and the notebook cost a total of $15. So you can write an equation with the cost of each of the items bought on one side, and the total spent on the other.

Solution continues…

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Example 1

Lesson

1.2.6Applications of EquationsApplications of Equations

At the school supply store, Mr. Ellis bought a notebook costing $3 and six pens. He spent $15 in total. Find the price of one pen, p.

Solution (continued)6p + 3 = 15

Now you have a two-step equation. You can find the cost of one pen by solving it.

The total cost

Cost of notebook

Cost of pens

Solution continues…

Page 8: Lesson 1.2.6

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Example 1

Lesson

1.2.6Applications of EquationsApplications of Equations

At the school supply store, Mr. Ellis bought a notebook costing $3 and six pens. He spent $15 in total. Find the price of one pen, p.

Solution (continued)

6p + 3 = 15

One pen costs $2.

6p = 12

p = 2

Write out the equation

Subtract 3 from both sides

Divide both sides by 6

Page 9: Lesson 1.2.6

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Guided Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

Write an equation to describe each of the situations in Exercises 1–3. Then solve it to find the value of the variable.

1. Emily is seven years older than Ariela. The sum of their ages is 45. How old is Ariela?

2. A sale rack at a store has shirts for $9 each. Raul has $50 and a coupon for $4 off any purchase. How many shirts can he buy?

3. The price for renting bikes is $15 for half a day, then $3 for each additional hour. How many hours longer than half a day can you keep a bike if you have $24?

A + A + 7 = 45, A = 19

9S – 4 = 50, S = 6

15 + 3h = 24, h = 3

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You Need to Check That Your Answer is Reasonable

Lesson

1.2.6Applications of EquationsApplications of Equations

When you’ve solved an equation that describes a real-life problem, you need to look at your answer carefully and see if it is reasonable.

Here are two important things to think about:

1. Does your answer make sense?

2. Is your answer about the right size?

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1) Does Your Answer Make Sense?

Lesson

1.2.6Applications of EquationsApplications of Equations

You must always check that the answer makes sense in the context of the question. For example:

An orchard charges $1.10 for a pound of apples. You have $8.25. How many pounds of apples can you buy?

Set up an equation to describe the problem:

Number of pounds = 8.25 ÷ 1.10 = 7.5

This is a reasonable answer as the orchard will happily sell you half a pound of apples.

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A store charges $1.10 for a bag of apples. You have $8.25. How many bags of apples can you buy?

Set up an equation to describe the problem:

Number of bags = 8.25 ÷ 1.10 = 7.5

This is not a reasonable answer — the store wouldn’t sell you half a bag of apples. You could only buy 7 bags.

Lesson

1.2.6Applications of EquationsApplications of Equations

But look what happens if you change the problem slightly.

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2) Is Your Answer About the Right Size?

Lesson

1.2.6Applications of EquationsApplications of Equations

The size of your answer has to make sense in relation to the question that is being asked. For example:

1. If you’re finding the height of a mountain, and your answer is 5 feet, it’s not reasonable.

2. If you’re finding the height of a person, and your answer is 5000 feet, that’s not reasonable either.

If the size of your answer doesn’t seem reasonable then it’s really important to go back and check your work to see if you’ve made an error somewhere.

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Example 2

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

Kea is going to walk 1.5 miles at a steady speed of 3 miles per hour. She works out how long it will take using the work shown. Is her answer reasonable?

Solution

Given that Kea’s walk is only 1.5 miles long and she walks at 3 mi/h, 4.5 hours is not a reasonable answer — it is much too long.

(Kea multiplied the distance of the walk by her speed. She should divide the distance by the speed instead: Time = 1.5 ÷ 3 = 0.5 hours.)

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Guided Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

4. Pete is buying trading cards. One card costs 20¢. He says 10 cards will cost $20. Is this a sensible answer? Explain why or why not.

5. Six friends earn $87 washing cars. How much will each one get if they split it evenly? Is your answer reasonable in the context of the question?

This is not reasonable — his answer is much too big. 10 cards will cost $2.

Each will get $14.50. This is reasonable, as they can get fractions of dollars each (and it seems about the right size).

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Guided Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

6. A yard has a 150-foot perimeter. Fencing is sold in 40-foot rolls. Write an equation to describe the number of rolls, n, you need to buy to fence the yard. Solve the equation. Is your answer reasonable in the context of the question?

7. Ana is as tall as T.J., who is 174 cm tall.

Write an equation to describe Ana’s height, A. Solve it. Is the size of your answer reasonable?

40n = 150, n = 3.75. This isn’t reasonable: you couldn’t buy part of a roll. You would have to buy 4.

A = • 174 = 145 cm. This is a reasonable height. 5

6

5

6

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Independent Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

Write an equation to describe each situation in Exercises 1–2, and solve the equation to answer the question.

1. Don has spent $474 ordering sticks for his hockey team. A stick costs $50. Shipping costs $24. How many did he buy?

2. Tiana is saving up to buy a fishing rod. The rod costs $99 with tax. She already has $27, and can afford to save another $12 each week. How long will it take her to save enough for the rod?

50x + 24 = 474, 9 sticks.

27 + 12x = 99, 6 weeks.

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Independent Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

3. Joy went to the fabric store to buy ribbon. She got f feet, and spent $5. The ribbon cost 80¢ a foot. Write an equation to describe how much she got. Solve it. Is your answer reasonable in the context of the question?

4. Mike is asked to multiply 5 by . He says the answer is 10.

Is this reasonable in the context of the question? Explain why or why not.

1

2

0.8f = $5, f = 6.25 feet. This is reasonable: the store is likely to be happy to sell her part of a foot of ribbon.

This isn’t reasonable: when you multiply a number by a fraction less than 1, the answer should be smaller than the original number.

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Independent Practice

Solution follows…

Lesson

1.2.6Applications of EquationsApplications of Equations

5. Two friends run a dog walking service, each walking the same number of dogs. Write and solve an equation to show how many dogs, d, each friend walks if they walk nine dogs between them. Is your answer reasonable?

2d = 9, d = 4.5. This isn’t reasonable. You couldn’t walk part of a dog.

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Round UpRound Up

Lesson

1.2.6Applications of EquationsApplications of Equations

Equations can help you to understand situations.

They can also help you to describe a real-life math problem involving an unknown number and come up with a solution.

But don’t forget to always think carefully about whether the answer is a reasonable one in relation to the question.