Lecture2-The Equations of Heat Conduction

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    Chapter TwoTHE EQUATIONS OF HEATCONDUCTIONS 2.1 One-Dimensional Heat Conduction Equation

    2.2 Boundary Conditions

    2-3 Mathematical Formulation of Some Heat

    Transfer Problems

    Problems

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    This chapter is concerned with derivation of

    the basic equations and the appropriateboundary conditions that govern the

    temperature distribution in solids.

    We develop the one-dimensional unsteadyheat conduction equation in rectangular,

    cylindrical, and spherical coordinate systems

    along with their appropriate boundaryconditions.

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    2.1 One-Dimensional Heat Conduction Equation

    Consider a solid whose temperature T(x,t)

    depends on time and varies in only one direction,

    say, along the x coordinate. The x axis in therectangular system refers to the usual x axis, but

    in the cylindrical or the spherical coordinate

    system it refers to the radial coordinate r. The

    heat flow by conduction in the x-direction is given

    by the Fourier law

    For generality in the analysis, an external

    volumetric heat source g(x,t), in W/m3 , generated

    within the medium is considered.

    x

    T

    kAQ

    (2-1)

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    To derive the conduction equation, we consider a

    volume element of thickness x and area A normal to

    the x axis as illustrated in Fig. 2.1. Applying the

    general energy balance equation on this solid element

    of constant volume, one obtains:

    0

    x

    Heat flowIn, Qx

    x x+x

    Heat flow out,Qx+xQx+xEnergy source, (Ax)g

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    ( ) )12(... =+dt

    dEEEE stgoutin

    =

    +

    energyernal

    ofincreaseofRate

    generation

    energyofRate

    conductionbygain

    heatofrateNet

    int

    t

    TxAC

    t

    UxgAQQ xxx

    = )()(

    The above energy equation can now be arranged in the form

    t

    TACAg

    x

    QQp

    xxx

    =

    )(

    0

    xAs

    x

    Q

    x

    QQ xxx

    + )(

    t

    TCgx

    Q

    Ap

    =+

    1

    (2-2)

    (2-3)

    (2-4)

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    tTCg

    xTAk

    xAp =+

    1

    Introducing Q given by Eq.(2.1) into the above equation,

    we obtain the one- dimensional conduction equation in

    the general form

    2-1.1 Rectangular Coordinate

    The area A =const., then conduction equation becomes

    t

    TCxg

    x

    Tk

    xp

    =+

    )()(

    2-1.2 Cylindrical Coordinate

    The variable x is replaced by the radial variable r, and A=2rl r.Then the general one-dimensional conduction equation in the

    cylindrical coordinate takes the form

    t

    TCrg

    r

    Tkr

    rrp

    =+

    )()(

    1

    (2-5)

    (2-6)

    (2-7)

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    2-1.3 Spherical Coordinate

    The variable x is replaced by the radial variable r, and the area

    A=4 r2, the one-dimensional conduction equation for the spherical

    coordinate becomes

    A General Compact One-Dimensional Conduction Equation

    t

    TCrg

    r

    Tkr

    rrp

    =+

    )()(

    1 22

    t

    TCrg

    r

    Tkr

    rrp

    n

    n

    =+

    )()(

    1

    =

    =

    =

    coordinatesphericalforn

    coordinatelcylindricaforn

    xbyreplacedisrandcoordinategularrecforn

    2

    1

    ,tan0

    (2-8)

    (2-9)

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    2-1.5 Special Cases

    For constant k and Cp ,Eq.(2-9) can be simplified to

    = thermal diffusivity of material, m2/s.

    Thermal Diffusivity

    The physical meaning of thermal diffusivity isassociated with the propagation of heat into themedium during changes of temperature with time.The higher the thermal diffusivity, the faster thepropagation of heat will be through the mediumand consequently the shorter the time is to reachthe steady state condition.

    tT

    krg

    rTr

    rr

    n

    n =

    1)()(1

    PC

    k

    (2-10)

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    2.2 Boundary Conditions

    To solve the one-dimensional, time-dependent heat

    conduction equation, two boundary conditions areneeded in addition to the initial condition.

    Types of Thermal Boundary Conditions:

    a- Prescribed Temperature boundary condition:The mathematical formulation of this type of boundary

    condition can be written as:T(x,t) = T1 at x=0, t > 0 (2.14a)

    T(x,t) = T2 at x=L, t > 0 (2.14b)

    0 L x

    T = T1 T = T2

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    b- Prescribed Heat Flux Boundary Condition

    0L x

    0a b

    r

    Heat Supply

    ConductionFlux

    ConductionFlux

    Heat

    Supply

    Conduction

    Flux

    ConductionFlux

    HeatSupply

    qo= -k

    rrrTkq

    == )( 11

    r

    rrTkq

    ==

    )( 22

    Lqx

    LxTk =

    = )(

    x

    xT

    = )0(

    0qx

    Tk =

    Lqx

    Tk =

    at x=0, t>0

    at x=L, t>0

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    c- Convection Boundary Conditions

    The general thermal boundary condition can be stated as:

    0L

    x

    0r

    1

    r2 r

    Fluid atT1 ,h1

    Fluid atT2 ,h2

    Qconv. = Qcond.

    Qcond. = Qconv.

    Qconv. = Qcond.

    Qcond. = Qconv.

    Fluid atT2 ,h2

    Fluid atT1 ,h1

    a- Plate b- Hollow cylinder ors here

    ==

    = platetheoxat

    surfacethefromConduction

    xatsurfacethetoT

    atfluidfromConvection

    int001

    x

    TkTTh= )( 11

    x

    TkTTh

    = )( 22

    at x=0

    at x=L

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    Thermal and geometric symmetry

    If the solid body has a thermal and geometric symmetry

    about a common symmetric axis

    Thermal boundary conditions of symmetric slab

    Consider a plane wall of thickness 2L initially at a temperature Ti and

    for times t>0 is subjected to convection at the boundaries x=0 and x=2L asshown in Fig. (2.6). The environment has a temperature T and a

    convection coefficient h at both boundary surfaces. The thermal boundary

    conditions at boundary surfaces become

    0=

    rT at the symmetry axis.

    0=

    x

    T

    0)( =+

    TThx

    Tk

    L L

    x-x

    0

    Thermal

    &GeometricSymmetry plane

    FluidT ,h

    FluidT ,h

    at x=0

    at x=L