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8/3/2019 Lecture2-The Equations of Heat Conduction
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Chapter TwoTHE EQUATIONS OF HEATCONDUCTIONS 2.1 One-Dimensional Heat Conduction Equation
2.2 Boundary Conditions
2-3 Mathematical Formulation of Some Heat
Transfer Problems
Problems
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This chapter is concerned with derivation of
the basic equations and the appropriateboundary conditions that govern the
temperature distribution in solids.
We develop the one-dimensional unsteadyheat conduction equation in rectangular,
cylindrical, and spherical coordinate systems
along with their appropriate boundaryconditions.
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2.1 One-Dimensional Heat Conduction Equation
Consider a solid whose temperature T(x,t)
depends on time and varies in only one direction,
say, along the x coordinate. The x axis in therectangular system refers to the usual x axis, but
in the cylindrical or the spherical coordinate
system it refers to the radial coordinate r. The
heat flow by conduction in the x-direction is given
by the Fourier law
For generality in the analysis, an external
volumetric heat source g(x,t), in W/m3 , generated
within the medium is considered.
x
T
kAQ
(2-1)
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To derive the conduction equation, we consider a
volume element of thickness x and area A normal to
the x axis as illustrated in Fig. 2.1. Applying the
general energy balance equation on this solid element
of constant volume, one obtains:
0
x
Heat flowIn, Qx
x x+x
Heat flow out,Qx+xQx+xEnergy source, (Ax)g
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( ) )12(... =+dt
dEEEE stgoutin
=
+
energyernal
ofincreaseofRate
generation
energyofRate
conductionbygain
heatofrateNet
int
t
TxAC
t
UxgAQQ xxx
= )()(
The above energy equation can now be arranged in the form
t
TACAg
x
QQp
xxx
=
)(
0
xAs
x
Q
x
QQ xxx
+ )(
t
TCgx
Q
Ap
=+
1
(2-2)
(2-3)
(2-4)
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tTCg
xTAk
xAp =+
1
Introducing Q given by Eq.(2.1) into the above equation,
we obtain the one- dimensional conduction equation in
the general form
2-1.1 Rectangular Coordinate
The area A =const., then conduction equation becomes
t
TCxg
x
Tk
xp
=+
)()(
2-1.2 Cylindrical Coordinate
The variable x is replaced by the radial variable r, and A=2rl r.Then the general one-dimensional conduction equation in the
cylindrical coordinate takes the form
t
TCrg
r
Tkr
rrp
=+
)()(
1
(2-5)
(2-6)
(2-7)
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2-1.3 Spherical Coordinate
The variable x is replaced by the radial variable r, and the area
A=4 r2, the one-dimensional conduction equation for the spherical
coordinate becomes
A General Compact One-Dimensional Conduction Equation
t
TCrg
r
Tkr
rrp
=+
)()(
1 22
t
TCrg
r
Tkr
rrp
n
n
=+
)()(
1
=
=
=
coordinatesphericalforn
coordinatelcylindricaforn
xbyreplacedisrandcoordinategularrecforn
2
1
,tan0
(2-8)
(2-9)
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2-1.5 Special Cases
For constant k and Cp ,Eq.(2-9) can be simplified to
= thermal diffusivity of material, m2/s.
Thermal Diffusivity
The physical meaning of thermal diffusivity isassociated with the propagation of heat into themedium during changes of temperature with time.The higher the thermal diffusivity, the faster thepropagation of heat will be through the mediumand consequently the shorter the time is to reachthe steady state condition.
tT
krg
rTr
rr
n
n =
1)()(1
PC
k
(2-10)
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2.2 Boundary Conditions
To solve the one-dimensional, time-dependent heat
conduction equation, two boundary conditions areneeded in addition to the initial condition.
Types of Thermal Boundary Conditions:
a- Prescribed Temperature boundary condition:The mathematical formulation of this type of boundary
condition can be written as:T(x,t) = T1 at x=0, t > 0 (2.14a)
T(x,t) = T2 at x=L, t > 0 (2.14b)
0 L x
T = T1 T = T2
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b- Prescribed Heat Flux Boundary Condition
0L x
0a b
r
Heat Supply
ConductionFlux
ConductionFlux
Heat
Supply
Conduction
Flux
ConductionFlux
HeatSupply
qo= -k
rrrTkq
== )( 11
r
rrTkq
==
)( 22
Lqx
LxTk =
= )(
x
xT
= )0(
0qx
Tk =
Lqx
Tk =
at x=0, t>0
at x=L, t>0
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c- Convection Boundary Conditions
The general thermal boundary condition can be stated as:
0L
x
0r
1
r2 r
Fluid atT1 ,h1
Fluid atT2 ,h2
Qconv. = Qcond.
Qcond. = Qconv.
Qconv. = Qcond.
Qcond. = Qconv.
Fluid atT2 ,h2
Fluid atT1 ,h1
a- Plate b- Hollow cylinder ors here
==
= platetheoxat
surfacethefromConduction
xatsurfacethetoT
atfluidfromConvection
int001
x
TkTTh= )( 11
x
TkTTh
= )( 22
at x=0
at x=L
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Thermal and geometric symmetry
If the solid body has a thermal and geometric symmetry
about a common symmetric axis
Thermal boundary conditions of symmetric slab
Consider a plane wall of thickness 2L initially at a temperature Ti and
for times t>0 is subjected to convection at the boundaries x=0 and x=2L asshown in Fig. (2.6). The environment has a temperature T and a
convection coefficient h at both boundary surfaces. The thermal boundary
conditions at boundary surfaces become
0=
rT at the symmetry axis.
0=
x
T
0)( =+
TThx
Tk
L L
x-x
0
Thermal
&GeometricSymmetry plane
FluidT ,h
FluidT ,h
at x=0
at x=L