Lecture 9 Kirchoffs Laws

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    MMPE 402 Mine Ventilation

    Lecture 9 Kirchoffs Laws and

    Network Analysis

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    Kirchoffs Laws

    0

    j M!

    Kirchoffs first law states that the sum of the flows entering and

    leaving junction j must sum to zero

    Thus

    Q is m3/s and is in kg/m3

    But

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    Kirchoffs Laws

    Kirchoffs second law states that the sum of the pressure losses

    and gains around around a closed loop (mesh) must sum to zero.

    Since around a loop delta Z equals zero and the change in kinetic

    energy is negligible then summing around m meshes gives

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    Kirchoffs Laws

    This may be converted to pressure by

    Note this equation is only valid for incompressible flow, if the flow

    is compressible the analysis must be done on mass flow

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    Kirchoffs LawsWhere

    P is the frictional pressure drop

    Pfis the pressure added to the system by the fan

    NVP is the ventilation pressure associated with natural

    ventilation

    To use Kirchoffs second on in network analysis we need to

    recall that

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    Kirchoffs Laws

    Since

    Thus Kirchoffs second law for compressible flow gives

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    Kirchoffs Laws

    Since signs are important a better way towrite it is

    For incompressible flow Kirchoffs laws gives

    Where R is Atkinsons resistance value

    and all pressures are referred to the

    same density usually 1.2

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    Deviation from the Square Law

    It has been found

    that

    Experiments where ln P vs ln Q gives values of n from

    1.8 to 2.05

    n changes due to the flow not always being turbulent,it can be in the transition phase or even laminar in

    which case n=1 and

    Is better expressed as

    Is not always true

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    Methods of solving ventilation

    NetworksWe will use n in our derivations for methods of solving

    ventilation networks.

    In general

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    Methods of solving ventilation

    Networks

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    Methods of solving ventilation

    Networks

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    Methods of solving ventilation

    Networks Example 1

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    Methods of solving ventilation

    Networks Example 1

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    Methods of solving ventilation

    Networks Example 1

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    Methods of solving ventilation

    Networks Example 1

    Given the diagram below for nine airways determine the

    equivalent resistance for the system

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    Methods of solving ventilation

    Networks Example 1

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    Methods of solving ventilation

    Networks Example 1

    0.548

    0.298

    0.298

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    Controlled Splitting

    There will be cases when the amount of airflow required in a drift

    will not occur by natural means in a parallel circuit. To manage

    the airflows regulators are used to induce pressure drops for

    drifts in parallel so that the required airflows are obtained. The

    drift without an artificial resistance is called the free split.

    Obviously this method will increase energy costs due to the

    increase in pressure loss caused by the regulators.

    Correspondingly it makes sense that the free split be the drift or

    airway that has the highest pressure drop.

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    Mesh Analysis

    The minimum number of meshes necessary to solve a

    network is 1m b j!

    Where

    m is the number of meshes

    b is the number of branches

    j is the number of junctions

    All branches must be included in a mesh

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    Mesh Analysis Example