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Introduction
•WiMAX (Worldwide Interoperability for Microwave
Access) is a technology standard for long-range wireless
networking for both mobile and fixed connections.
•WiMAX would operate similar to Wi-Fi but at a higher
speeds, over greater distances, and for a greater number of
users.
WiMAX advantages• WiMAX technology offers:
1- High speed of broadband service of 70 Mbps
2 – Broad coverage - like cell phones with
coverage radius of 50 Km
WiMAX Parts
• WiMAX system consists of two parts:
1) WiMAX Tower; it is similar to cell phone tower with large coverage area (~8.000 square km).
2) WiMAX Receiver ; it could be a small box or PCMCIA card.
WiMAX Modes
• WiMAX has two modes:
1) Non line-of-sight; where a small antenna on a
computer connects to the WiMAX tower. It uses a
lower frequency rang 2 GHz – 11GHz. (802.16a)
2) Line-of-sight; where a fixed dish antenna
points straight at the WiMAX tower. It uses higher
frequency 10 GHz up to 66 GHz.
802.16 Standard Specifications
• Range - 50-km radius from base station
• Speed - 70 Mbps
• Line-of-sight is not needed between user and base station
• Frequency bands - 2 to 11 GHz and 10 to 66 GHz (licensed
and unlicensed bands)
• Are metropolitan in scale
• Use point-to-multipoint architecture with stationary rooftop or
tower-mounted antennas
WiMax Applications
• Digital audio/video multicast
• Digital telephony
• ATM
• Internet protocol
• Bridged LAN
• Back-haul
• Frame relay
• City Wide Camera Network
WiMAX Application Example:
Citywide Wireless Video
Surveillance
• Designing a Citywide Wireless Surveillance System – “the
right way” – is a highly complex task, underestimated by
many.
• When high motion is encountered, at 30 Frames Per Second
(FPS) and 4CIF resolution, a single video stream requires as
much as 4 Mbps (using MPEG-4 encoding).
Cont.
• In most citywide surveillance systems, wireless technology
enables a municipality to build out the system at an affordable
cost point. However, if the wireless part of the network is not
properly designed, the customer will be disappointed with the
performance of the network.
Example 1
• Assume in the Network below we have the following number
of cameras in each site.
• If the Camera bandwidth requirement is 4 Mbps, then calculate
the bandwidth required for Link 1 and Link 2 and then pickup
the right solution for each link.
• TX power of 30 dBm and Antenna Gain of 18 dBi
• Link 1 is 10 Km
• Link 2 is 12 Km
• Please calculate Link budget for both Links
• Frequency is 5 GHz
Solution
• First we need to calculate the data rate required in each link
• Link 1 = S1 + S2 +S4 = 4 Cameras
• So Link 1 data rate = 4 Mbps x 4 = 16 Mbps
• Link 2 = S3 + S5 = 3 Cameras
• So Link 2 data rate = 4 Mbps x 3 =12 Mbps
• From the table pick the right receive sensitivity and then
calculate the link budget.
• Receive Sensitivity for Link 1 is -91.67 dBm
• Link 1 FSL = 32.44 + 20 * log(d) + 20 log(f)
• = 32.44 + 20 * log (10) + 20 * log (5000) = 126.42 dB
• Receive Sensitivity for Link 1 is -94.43 dBm
• Link 2 FSL = 32.44 + 20 * log(d) + 20 log(f)
• = 32.44 20 * log (12) + 20 * log (5000) = dB 128
•18
Link 1: Link budget Calculation
30 dBm (TX Power AP)
0 dB (Cable Losses AP) + 18 dBi (Antenna Gain AP)
-126.42 dB (free space loss @5 km)
+ 18 dBi (Antenna Gain Client) 0 dB (Cable Losses Client)
-60.42 dBm (expected received signal level)
- -91.68 dBm (sensitivity of Client)
31.26 dB (link margin)