Lecture 5. Chemical Reaction (Part 3. Redox)

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  • CHEMICAL REACTIONS:

    Reduction-Oxidation Reaction

    GENERAL CHEMISTRY

    LECTURE 5

    cont.

  • 5.1 Redox Reaction

    5.2 Oxidation Number of Atoms

    5.3 Reducing and Oxidizing agent in a Redox Reaction

    Scope of the Study

    5.4 Activity series of metals

  • Figure 5.1 The redox process in compound formation.

    *key chemical event is the net movement of electrons from one reactant to another

  • Oxidation

    Redox Terminology

    Reduction

    Oxidation (electron loss of Mg): Mg Mg2+ + 2e-

    Reduction (electron gain by O2): O2 + 2e- O2-

    Consider: Mg + O2 MgO

    O2 oxidizes Mg, O2 is the Oxidizing agent

    Mg reduces O2, Mg is the Reducing agent

    LEORA

    GEROA

    is the loss of electrons (increased in the oxidation state)

    is the gain of electrons (decreased in the oxidation state)

  • Reaction of Sodium and Chlorine

  • Oxidation number (O.N) or oxidation state is the charge of an atom in a molecule when electrons are transferred completely.

  • 1. Oxidation state of an atom in an element = 0

    2. Oxidation state of monatomic ion = charge of the ion

    3. Oxygen = 2 in covalent compounds (except in peroxides where it = 1)

    4. Hydrogen = +1 in covalent compounds

    5. Fluorine = 1 in compounds

    6. Sum of oxidation states = 0 in compounds

    7. Sum of oxidation states = charge of the ion in ions

    General Rules for Assigning Oxidation States

  • Exercise No. 1 Determining the Oxidation Number of an Element

    1. Determine the oxidation number (O.N.) of each element in these compounds:

    (a) Zinc chloride (b) Sulfur trioxide

    (c) Nitrate ion

    SOLUTION:

    (a) ZnCl2

    (b) SO3

    (c) NO3-

    The O.N. for zinc is +2 and that for chloride is -1.

    Oxygen has an O.N. of -2

    S + 3(-2) = 0; Therefore, S = +6

    Oxygen has an O.N of -2

    N + 3(-2) = -1; Therefore, N =+5

    (d) Hydrogen phosphate ion

    (d) HPO42- Oxygen has an O.N of -2.

    Hydrogen has an O.N of +1

    1 + P + 4(-2) = -2; Therefore, P =+5

  • 2. Find the oxidation states for each of the elements in each of the following compounds:

    K2Cr2O7 CO3

    2-

    MnO2 PCl5 SF4

    K = +1; Cr = +6; O = 2

    C = +4; O = 2

    Mn = +4; O = 2

    P = +5; Cl = 1

    S = +4; F = 1

    Exercise No. 2 Determining the Oxidation Number of an Element

  • Figure 5.2 A summary of terminology for oxidation-reduction (redox) reactions.

    LEORA

    GEROA

  • 3. Which of the following are oxidation-reduction reactions? Identify the oxidizing agent and the reducing agent.

    Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g)

    Cr2O72-(aq) + 2OH-(aq) 2CrO4

    2-(aq) + H2O(l)

    2CuCl(aq) CuCl2(aq) + Cu(s)

    Recognizing Oxidizing and Reducing Agents Exercise No. 3

  • Zn(s) + 2H+ (aq) + 2Cl-(aq) Zn2+(aq) + 2Cl(aq) + H2(g)

    0 +1 1 +2 1 0

    1. Identify the oxidation states of each atom in the equation.

    Determining Oxidizing and Reducing Agent

    Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g)

  • H+ gained e Zn(s) + 2H+ (aq) + 2Cl-(aq) Zn2+(aq) + 2Cl(aq) + H2(g)

    0 +1 1 +2 1 0

    Zn lost e-

    The oxidation state of chlorine remains unchanged.

    Determining Oxidizing and Reducing Agent

    2. Which gained or lose electrons?

  • gained of e- : reduction Zn(s) + 2H+ (aq) + 2Cl-(aq) Zn2+(aq) + 2Cl(aq) + H2(g)

    0 +1 1 +2 1 0

    lost of e- : oxidation

    Determining Oxidizing and Reducing Agent

    2. Which gained or lose electrons?

  • gained of e- : reduction Zn(s) + 2H+ (aq) + 2Cl-(aq) Zn2+(aq) + 2Cl(aq) + H2(g)

    0 +1 1 +2 1 0

    lost of e- : oxidation

    Zn is the reducing agent HCl is the oxdizing agent

    Determining Oxidizing and Reducing Agent

    3. Identify OA and RA

    LEORA

    GEROA

  • 3. Which of the following are oxidation-reduction reactions? Identify the oxidizing agent and the reducing agent.

    Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g)

    Cr2O72-(aq) + 2OH-(aq) 2CrO4

    2-(aq) + H2O(l)

    2CuCl(aq) CuCl2(aq) + Cu(s)

    Recognizing Oxidizing and Reducing Agents Exercise No. 3

  • Disproportionation reaction

    The same substance is both oxidized and reduced.

    Examples:

    2CuCl(aq) CuCl2(aq) + Cu(s)

    2H2O2(l) 2H2O(l) + O2(g)

  • Recognizing Oxidizing and Reducing Agents

    4. Identify the oxidizing agent and reducing agent in each of the following:

    (a) 2Al(s) + 3H2SO4(aq) Al2(SO4)3(aq) + 3H2(g)

    (b) PbO(s) + CO(g) Pb(s) + CO2(g)

    (c) 2H2(g) + O2(g) 2H2O(g)

    Assign an O.N. for each atom and see which atom gained and which atom lost electrons in going from reactants to products.

    An increase in O.N. means the species was oxidized (and is the reducing agent) and a decrease in O.N. means the species was reduced (is the oxidizing agent).

    (a) 2Al(s) + 3H2SO4(aq) Al2(SO4)3(aq) + 3H2(g)

    0 0 +6 +1 -2 +3 +6 -2 SOLUTION:

    The O.N. of Al increases; Al is oxidized; it is the reducing agent.

    The O.N. of H decreases; H is reduced; H2SO4 is the oxidizing agent.

    Exercise No. 4

  • Recognizing Oxidizing and Reducing Agents

    continued

    (c) 2H2(g) + O2(g) 2H2O(g)

    (b) PbO(s) + CO(g) Pb(s) + CO2(g)

    +2 -2 +2 -2 0 +4 -2

    0 0 +1 -2

    The O.N. of C increases; C is oxidized; CO is the reducing agent.

    The O.N. of Pb decreases; Pb is reduced; PbO is the oxidizing agent.

    The O.N. of H increases; it is oxidized; H2 is the reducing agent.

    The O.N. of O decreases; it is reduced; O2 is the oxidizing agent.

    Exercise No. 4

  • Displacing One Element by Another:

    Activity Series

    The activity series of metals

    -elements are rank in order of their ability to displace one another.

  • Figure 5.4 An active metal displacing hydrogen from water.

  • The activity series of the metals.

    (a) 2Al(s) + 6H2O(g) 2Al(OH)3(s) + 3H2(g)

    (b) Ni(s) + 2H+ (g) Ni+ (g) + H2(g)

  • Figure 5.5 Displacing one metal by another.

  • The TOP METAL will reduce the CATION of the METAL BELOW!

    Ba(s) + Ca2+

    (aq) Ca(s) + Ba2+

    (aq)

    Mg(s) + Zn2+

    (aq) Zn(s) + Mg2+

    (aq)

    How about: Al(s) + Na

    +(aq) ?

    Sr(s) + Al3+

    (aq) ? No reaction

    Al(s) + Sr2+

    (aq)

  • Additional Exercises Identifying the Type of Redox Reaction

    PROBLEM: Classify each of the following redox reactions as a combination, decomposition, or displacement reaction, write a balanced molecular equation for each, as well as total and net ionic equations for part (c), and identify the oxidizing and reducing agents:

    (a) Magnesium(s) + nitrogen(g) magnesium nitride (aq)

    (b) Hydrogen peroxide(l) water(l) + oxygen gas

    (c) Aluminum(s) + lead(II) nitrate(aq) aluminum nitrate(aq) + lead(s)

  • (a) Magnesium(s) + nitrogen(g) magnesium nitride (aq)

    (a) Combination

    Mg is the reducing agent; N2 is the oxidizing agent.

    3

    0 0 +2 -3

    Mg(s) + N2(g) Mg3N2(aq)

    (b) Decomposition

    H2O2 is the oxidizing and reducing agent.

    H2O2(l) H2O(l) + O2(g)

    +1 -1 +1 -2 0

    or

    2H2O2(l) 2H2O(l) + O2(g)

    1 2

    (b) Hydrogen peroxide(l) water(l) + oxygen gas

    Additional Exercises Identifying the Type of Redox Reaction

  • (c) Displacement

    Al(s) + Pb(NO3)2(aq) Al(NO3)3(aq) + Pb(s)

    0 +2 +5 -2 +3 +5 -2 0

    2Al(s) + 3Pb(NO3)2(aq) 2Al(NO3)3(aq) + 3Pb(s)

    Pb(NO3)2 is the oxidizing agent; Al is the reducing agent.

    (c) Aluminum(s) + lead(II) nitrate(aq) aluminum nitrate(aq) + lead(s)

    Additional Exercises Identifying the Type of Redox Reaction