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CE - 363 Lecture 3: Track Resistances, Hauling Capacity Dr. Ankit Gupta, Assistant Professor Department of Civil Engineering National Institute of Technology Hamirpur

Lecture 3 Final

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Page 1: Lecture 3 Final

CE - 363

Lecture – 3: Track Resistances,

Hauling Capacity

Dr. Ankit Gupta, Assistant Professor

Department of Civil Engineering

National Institute of Technology Hamirpur

Page 2: Lecture 3 Final

Lecture Outline

Resistances to Traction

Hauling Capacity

Tractive effort of a locomotive

Classification of locomotives

Page 3: Lecture 3 Final

Traction

Definition:

The source through which the locomotive

drives power is called traction.

Sources:

Steam

Diesel fuel

Electric supply (AC/DC)

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Traction / Power has a bearing up on:

Load carrying capacity

Speed

Economy

Efficiency of service

Traction

Page 5: Lecture 3 Final

Traction - Comparison

Source of energy

Engine (Design/weight)

Overload capacity

Tractive effort available

Power utilization / fuel

consumption

Speeds

Rate of acceleration

Life of locomotive

Direction for use / need

of reversing

Driving skills

Shed requirements

Repairs and renewable

Personnel requirement

Flexibility (No of coaches

attached)

Track riding

Cost

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Working hours / day

Monthly kilometrage

Pollution and

hazards (smoke /

fire)

Availability for

service

Suitability (w.r.t. type

of traffic; availability

of fuel / water;

speeds; type of

operation)

Thermal efficiency

Slipping on /

adhesion with track

(of wheels)

Traction - Comparison

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Resistances to Traction

Resistances

Rolling

Stock

Track

Profile

Tractive

effort Wind

Speed

independent

Speed

dependent Atmospheric Gradient

Curves

Starting

Acceleration Journal

friction

Rolling

friction

Track

resistance

Internal

part friction

Track

irregularities

Vertical

movement

Flange

action

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Train Resistances (due to rolling stock)

Resistances due to track profile

Traction Loss (due to starting and

acceleration)

Wind resistances

Resistances to Traction

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Train Resistances

Train Resistances (RT1)

Resistances independent of speed

Resistances dependent on speed

Atmospheric resistances

Page 10: Lecture 3 Final

Resistances independent of speed are caused due to:

Friction imposed due to train components (locomotive, wagons / compartments), known as Journal friction Dependent up on type of bearing, lubricant

used and temperature of atmosphere

For roller bearing – 0.5 to 1.0 kg per tonne

For coupled boxes – 1.3 to 1.5 kg per tonne (Hard grease)

Train Resistances

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Resistances independent of speed (Rt1) are caused due to:

Friction between steel wheels and steel rails

Track resistance – wave action of rails

Resistance due to internal parts, e.g. cylinder and rim of driving wheels, etc.

Computation -

Rt1 = 0.0016 w,

where ‘w’ is weight of train in tonnes.

Train Resistances

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Resistances dependent of speed (Rt2):

caused due to -

Track irregularities

Vertical movement of wheels on rails

(improper joints and maintenance)

Flange action (oscillations, sways, etc.)

Rc α (1/length) of rigid base, or

Rc α (speed of the train)2

Train Resistances

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Resistances dependent of speed (Rt2):

caused due to -

Computed as -

Rt2 = 0.00008 w.v,

where ‘w’ is weight of train in tonnes and

‘v’ is speed of train in km ph.

Train Resistances

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Atmospheric Resistances (Rt3):

On sides and end of wagons /

locomotives

Wind is assumed as not blowing.

Computed as -

Rt3 = 0.0000006 w.v2,

where ‘w’ is weight of train in tonnes and

‘v’ is speed of train in km ph.

Train Resistances

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Train Resistances (RT1) = Rt1 + Rt2 + Rt3

RT1 = 0.0016w + 0.00008w.v + 0.0000006wv2

Train Resistances

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Resistances due to Track Profile (RT2):

Caused due to –

Gradients, and

Curves

Train Resistances

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Resistance due to gradient (Rg)

w = weight of train acting at CG

N = Normal pressure on rails

Computed as -

Rg = w tanΘ

N W

Θ Rg

G

Train Resistances

Page 18: Lecture 3 Final

Resistance due to curves (Rc)

Factors controlling are:

Rigidity of wheel base

Wear on inner side of outer rail due to flange of leading axle and inner side of inner rail due to flange of trailing axle, causing mount on rail

In other two cases it tends to derail

Train Resistances

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Resistance due to curves (Rc)

Factors controlling are:

Slippage of wheel (longitudinal and transverse)

Insufficient super-elevation: more pressure on inner rail

Extra super-elevation: more pressure on outer rail

Poor maintenance of track and components

Train Resistances

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Train Resistances

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Train Resistances

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Resistance due to curves (Rc)

Resistance increases with increase in

speed

G

R

D2

D1

D

Train Resistances

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Resistance due to curves (Rc)

Distance traveled by outer wheel = D1

Distance traveled by inner wheel = D2

Extra distance traveled = D1 – D2

If ‘F’ is the force of sliding friction,

then Work done is = (D1 – D2) F

Mean Resistance = {(D1 – D2) F} / D

= G.α.F / R. α

= F.G / R

Train Resistances

Page 24: Lecture 3 Final

Resistance due to curves (Rc)

Therefore, Resistance gets affected by

Force of sliding friction (F), Gauge of

track (G) and degree of curvature (R)

Recommended values of curve

resistances:

Broad gauge Rc = 0.0004w.D

Meter gauge Rc = 0.0003w.D

Narrow gauge Rc = 0.0002w.D

Train Resistances

Page 25: Lecture 3 Final

Tractive Resistances

Resistances due to Tractive Effort (RSA)

Get induced due to -

Starting operation

Acceleration given to a locomotive

Page 26: Lecture 3 Final

Resistance due to starting (RS)

Varies according to the type of an object

For locomotives RS = 0.15 w1

For vehicles RS = 0.005 w2

where w1 is weight of locomotive in

tonnes, and

w2 is weight of a vehicle in tonnes

Tractive Resistances

Page 27: Lecture 3 Final

Resistance due to acceleration (RA)

Caused due to change in speed with

respect to time

RA = 0.028 w (v2 – v1) / t

Where v1 = velocity at the beginning (km ph)

v2 = velocity at the end (km ph)

t = Time taken in seconds for achieving the

sped from v2 to v1

w = total weight of train in tonnes

Tractive Resistances

Page 28: Lecture 3 Final

Wind Resistances

Resistances due to Wind (RW)

Depends up on -

Direction of wind w.r.t. movement of train

Wind velocity

Sectional area exposed to wind

Direction of Train Movement

V CosΘ

V SinΘ Θ

Page 29: Lecture 3 Final

Resistances to Traction

Resistances due to Wind (RW)

RW = 0.000017 A V2

Where A = exposed area in sq. meters

V = velocity of wind in km ph

Total Resistance to Traction (RT)

RT = RT1 + RT2 + RSA + RW

Page 30: Lecture 3 Final

Hauling Capacity

Defined as the load that can be handled by the locomotive. It is an indicative of power available to a locomotive.

It can be computed as a product of coefficient of friction and weight on the driving wheels.

At the minimum level it should be equal to Traction Resistances.

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Hauling Capacity

The factors controlling the capacity are:

Weight coming on the driving wheels, and

Coefficient of friction

It largely depends up on:

Condition of rail surface, and

Speed of the locomotive

Page 32: Lecture 3 Final

Coefficient of friction - value

Condition of rail surface:

Very wet / very dry 0.25

Greasy 0.03

Average dampness 0.166

In tunnels / frosty condition 0.125

With respect to speed it varies between 0.1

at high speeds to 0.2 at low speeds

Hauling Capacity

HP
Highlight
Page 33: Lecture 3 Final

Hauling Capacity = µ.w.n = µ.W

Where µ = coefficient of friction

w = weight on driving axle

n = number of pairs of driving wheels

W = Total load on driving wheels

Maximum axle load in India

BG = 28.56 tonnes

MG = 17.34 tonnes

NG = 13.26 tonnes

Hauling Capacity

Page 34: Lecture 3 Final

Tractive Effort

It is usually equal to or little in excess of

hauling capacity.

Computed by equating work done by

tractive effort to the total power developed

by the locomotive.

Page 35: Lecture 3 Final

For steam locomotive:

It depends up on

Difference in pressure on two sides of

the cylinder (p)

Length of stroke (L)

Area of piston (a)

Diameter of piston (d)

Diameter of wheel (D)

Tractive Effort

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If Te is the mean tractive effort then,

Work done by a two cylinder engine

= 2.p.a.(2L) = π.p.L.d2

Work done in one revolution of driving

wheel = π. D. Te

Therefore, equating the work done

Te= p.d2.L / D

Hence, a small diameter wheel will

increase the tractive effort, but it will

reduce the speed of movement.

Tractive Effort

Page 37: Lecture 3 Final

For diesel locomotive

Te = 308 x HPr / V

Where HPr is rated horse power of the

engine,

V = Velocity in km ph

Tractive Effort

Page 38: Lecture 3 Final

Classification of Locomotives

Classified on the basis of:

Gauge for which manufactured

Type of traction available

Type of load to be carried

These are indicated using an alphabet

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Classification on the basis of Gauge for

which manufactured

Broad gauge X or W

Meter Gauge Y

Narrow gauge Z

Classification of Locomotives

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Classification on the basis of type of

traction available

Diesel D

AC Electric A

DC Electric C

Classification of Locomotives

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Classification on the basis of type of

load to be carried

Light passenger A or L

Standard passenger B or P

Heavy passenger C

Standard goods D or G

Heavy goods E

Mixed goods and passenger M

Shuttle or shunting U / T / W

Classification of Locomotives

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Salient features

Identifier Type Axle Load Length (m)

XA 4-6-2 13.2 T 19.2

XB 4-6-2 17.3 T 23.1

XC 4-6-2 20.1 T 23.2

XD 2-8-2 17.3 T 23.3

XE 2-8-2 22.9 T 24.0

YB 4-6-2 16.2 T 18.3

YC 4-6-2 12.2 T --

YD 2-8-2 10.2 T 18.2

ZB 2-6-2 6.1 T 12.8

ZE 2-8-2 8.1 T 14.6

Classification of Locomotives

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Common identifiers for different tractions Diesel

BG WDM1, WDM2, WDM4

MG YDM1, YDM2, YDM4

Latest WDG2, WDP1, WDP2

Electric BG WAM1, WAM2, WAM3, WAM4, WAP1

WAG1, WAG2, WAG3, WAG4, WAG5

WCM1, WCM2, WCM3, WCM4, WCG1

MG YAM1

Classification of Locomotives

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Classification of Locomotives

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Classification of Locomotives

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Classification of Locomotives

WAG9