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Lecture 3. Demand for junctions. Domestic Demand:. Domestic Demand:. For the 1 st junction : P domestic = Area*Population Density = 3256.82* 0.05= 163 Q domestic = P domestic *150 *1.35 /1000 = 32.98 m³/d - PowerPoint PPT Presentation
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Domestic Demand:
#JElevation ( m )
Domestic
AreaDensityPopulation
Q
(m²( (m3/d(
J134.033256.820.05162.8432.98
J229.066493.580.05324.6865.75
J325.305778.820.05288.9458.51
J425.206637.210.05331.8667.20
J526.704675.620.05233.7847.34
For the 1st junction :P domestic = Area*Population Density
= 3256.82* 0.05= 163 Q domestic = P domestic*150 *1.35 /1000 = 32.98 m³/d Average Demand for capita / day =150 L/c/dThe value 1.35 = 25% loses in the network
and the equivalent commercial demand which was taken 10% domestic demand.
Domestic Demand:
For public demand:
Average Demand for capita / day = 40 L/c/d
Q public = # employee * 40 * 1.25 (25%
UFW)
Public Demand:
Public Demand:
#J
Public
Area #Employees
Q
(m²( (m3/d(
J10 00
J20 00
J30 00
J4548.38109.685.5
J51922.40384.4819
For junction 4 which has a public demand,
Area = 548.38 m² ,
Let # of employee = 0.2*Area =109.68 =110
person
Q public =110*40*1.25/1000 = 5.5 m³ /day
Public Demand:
Commercial Demand:
For junction which has a commercial demand,
Let # of = 1200 person/day
Average Demand for capita / day = 30 L/c/d
Q Commercial = 1200*30*1.25/1000 = 45 m³ /day
(25% UFW)
Industrial Demand:
For junction which has an industrial demand,
Let # of workers = 850 person
Average Demand for capita / day = 30 L/c/d
Add 30% for cleaning works.. etc
Q Industrial = 850*30*1.55/1000 = 40 m³ /day
(25% UFW, 30% Others)
School Demand:
For junction which has a school demand,
# of pupils/school = 1200 pupil
Average Demand for capita / day = 10 L/c/d
Q school = 1200*10*1.25/1000 = 15 m³ /day
(25% UFW)
Hospital Demand:
For junction which has a hospital demand,
Let # of beds = 160
Average Demand for capita / day = 300 L/c/d
Q Hospital = 160*300*1.25/1000 = 60 m³ /day
(25% UFW)
Mosque Demand:
For junction which has a mosque demand,
# of prayers/day =500 person
Average Demand for capita / day = 25 L/c/d
Q Mosque = 500*25*1.25/1000 = 15.7 m³ /day
(25% UFW)
Agricultural Demand:
For junction which has a agricultural demand,
Agricultural demand varies according to the
type of trees.
Demand for Green areas = 5
m3/Donum/Week
Average Demand / day = ??? m3/d
Don’t Forget (25% UFW)
Tourist Demand:
For junction which has a tourist demand,
Demand for Hotels = 180 L/C/d
Average Demand / day = ??? m3/d
Don’t Forget (25% UFW)
Total Demand:
Qtotal of network = ∑ Qnodes m3/day
Average Demand:
For each type of demand
Qavg_i = ∑ Qnodes / 24 m3/hr
Where (i) is the type of demand