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Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place. Lecture 17

Lecture 17

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Lecture 17. Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place. Web Lecture 17 Class Lecture 22–Thursday 4/4/2013. Introduction to Catalysts and Catalysis Interstage cooling - PowerPoint PPT Presentation

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Page 1: Lecture 17

Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of

chemical reactions and the design of the reactors in which they take place.

Lecture 17

Page 2: Lecture 17

Web Lecture 17Class Lecture 22–Thursday 4/4/2013Introduction to Catalysts and Catalysis Interstage coolingNoble Prize 2007Catalytic steps

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Page 3: Lecture 17

A Catalyst is a substance that affects the rate of chemical reaction but emerges from the process unchanged.

Catalysis is the occurrence, study, and use of catalysts and catalytic processes.

Approximately 1/3 of the GNP of materials produced in the U.S. involves a catalytic process.

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Catalysts and Catalysis

Page 4: Lecture 17

Different reaction paths

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Catalysts affect both selectivity and yield

Catalysts and Catalysis

Page 5: Lecture 17

Different shapes and sizes of catalyst.

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Catalysts and Catalysis

Page 6: Lecture 17

Catalytic packed-bed reactor, schematic.

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Catalysts and Catalysis

Page 7: Lecture 17

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Steps in a Catalytic Reaction

Page 8: Lecture 17

Reactions are not catalyzed over the entire surface but only at certain active sites or centers that result from unsaturated atoms in the surface.

An active site is a point on the surface that can form strong chemical bonds with an adsorbed atom or molecule.

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Active Sites

Page 9: Lecture 17

Active Sites – Ethylidyne on Platinum

Page 10: Lecture 17

Vacant and occupied sites

For the system shown, the total concentration of sites is

Ct = Cv + CA.S + CB.S

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The Adsorption Step

Page 11: Lecture 17

SASA

][atm /k

/ k- 1-

A

A-

AA

ASAVAASAvAAAD

kK

KCCPkCCPkr

VAAASAAD

VAAASAD

CPkCkrCPkCr

0/ 0 :mequilibriu @

) 1( AAVVAAVSAVt PKCCPKCCCC

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The Adsorption Step

𝐶𝑉=𝐶𝑡

1+𝐾 𝐴𝑃 𝐴

Page 12: Lecture 17

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Langmuir Adsorption Isotherm

Page 13: Lecture 17

Langmuir Adsorption Isotherm

AP

T

SA

CC

Increasing T

Slope=kA

13

AA

AA

t

SA

PKPK

CC

1

Langmuir Adsorption Isotherm

Page 14: Lecture 17

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The Surface Reaction Step

Page 15: Lecture 17

The Surface Reaction Step

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Page 16: Lecture 17

The Surface Reaction Step

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Page 17: Lecture 17

The Surface Reaction Step

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Page 18: Lecture 17

The Surface Reaction Step

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Page 19: Lecture 17

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Steps in a Catalytic Reaction

Page 20: Lecture 17

A B C

C S C S

rDC kD CCS PCCKDC

rDC rADC

KDC 1

KC

rDC kD CCS KCPCC

(10-20)

(10-21)

Desorption from the Surface for the Reaction

Page 21: Lecture 17

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Adsorption

Surface Reaction

Desorption

Which step is the Rate Limiting Step (RLS)?

SASA

A

kSA

vAAdAdACCPkrr

SBSA

SBSB

C

k

SBSASSACCkrr

BBBSBDDA CPkCkrr

Steps in a Single-Site Catalytic Reactor

Page 22: Lecture 17

Electrical analog to heterogeneous reactions

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The Rate Limiting Step:Which step has the largest resistance?

Page 23: Lecture 17

Collecting information for catalytic reactor design

Collecting and Analyzing Data

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Page 24: Lecture 17

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Collecting and Analyzing Data

Page 25: Lecture 17

Normal Pentane Octane Number = 62Iso-Pentane Octane Number = 95

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Catalytic Reformers

Page 26: Lecture 17

n-pentanei-pentane

0.75 wt% Pt

Al2O3

n-pentenei-pentene

Al2O3

N

I

n-pentane n-pentene -H2

Pt

Al2O3i-pentene

+H2

Pti-pentane

Catalytic Reformers

26

Page 27: Lecture 17

Isomerization of n-pentene (N) to i-pentene (I) over alumina

N I

Al2O3

1. Select a mechanism (Mechanism Single Site)

Adsorption on Surface: SNSN Surface Reaction: SISN Desorption: SISI

Treat each reaction step as an elementary reaction when writing rate laws.

Catalytic Reformers

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Page 28: Lecture 17

2. Assume a rate-limiting step. Choose the surface reaction first, since more than 75% of all heterogenous reactions that are not diffusion-limited are surface-reaction-limited. The rate law for the surface reaction step is:

S

SISNSS

'IN K

CCkrrr

28

SSISSN

Catalytic Reformers

Page 29: Lecture 17

3. Find the expression for the concentrations of the adsorbed species CN.S and CI.S. Use the other steps that are not limiting to solve for CN.S and CI.S. For this reaction:

CKPC NNSN:0kr

A

AD From

CPKKCPC II

D

ISI:0

kr

D

D From

Catalytic Reformers

29

SNSN

SISI

Page 30: Lecture 17

4. Write a Site Balance.

SISNt CCCC

5. Derive the rate law. Combine steps 2, 3 and 4 to arrive at the rate law :

IINN

PINSN

IINN

PIN

k

NtsSN

PKPKKPPkrr

PKPKKPPKCkrr

1

1

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Catalytic Reformers

Page 31: Lecture 17

CO NO CO2 12

N2

1994 2004 2008HC 0.41 0.125 0.10CO 3.4 3.4 3.4NO 0.4 0.4 0.14

Catalytic Conversion of Exhaust Gas

Page 32: Lecture 17

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222 NNVS•N

2VNN

2S•NDD2

S•NOS•COSS2

VCOCOS•COCO

S•COVCOCOACO

VNONOS•NONO

S•NOVNONOANO

PKCCCPKCkrS2gNS•NS•N

CCkrSS•NCOS•NOS•CO

CPKCKC

CPkrS•COS•CO

CPKCKC

CPkrS•NOSNO

Catalytic Conversion of Exhaust Gas

Page 33: Lecture 17

33

rS kS CNO•SCCO•S

rS kSKNOKCOPNOPCOCV2

CT CV CNO•S CCO•S CN•S

CV CVKNOPNO CVKCOPCO CV KN 2PN 2

Catalytic Conversion of Exhaust Gas

Page 34: Lecture 17

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2NNCOCONONO

CONONO

2

NNCOCONONO

CONO

k

2tCONOS

SNO

NNCOCONONO

tV

22

22

22

PKPKPK1

PkPr

PKPKPK1

PP CKKkrr

PKPKPK1C

C

Catalytic Conversion of Exhaust Gas

Page 35: Lecture 17

Neglect

KN2PN 2

r NO kPNOPCO

1 KNOPNO KCOPCO 2

r NO kPNOPCO

1 KNOPNO KCOPCO KN 2PN2 2

Catalytic Conversion of Exhaust Gas

Page 36: Lecture 17

Find optimum partial pressure of CO

r NO kPNOPCO

1 KNOPNO KCOPCO 2

d rNO dPCO

0

PCO 1 KNOPNOKCO

Catalytic Conversion of Exhaust Gas

Page 37: Lecture 17

End of Web Lecture 17

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