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Lecture 15 Induction Machines: Principle of
Operation and Equivalent Circuit Model
ECE 492/592 Electric Motor Drives
Introduction to Induction Machines
•
Induction Machines are also called–
Asynchronous machines
–
Rotating transformer•
Main properties–
90% of industrial motor drives
–
Rugged and reliable–
Low maintenance (no brushes)
–
Inexpensive–
Relatively high power density
Induction motor construction
•
Stator construction (same as for the synchronous machine)–
Three windings spatially removed 120 degrees from each other–
Excited by a balanced three phase voltage
•
Rotor construction–
Rotor consists of a winding wound in the rotor slots–
The current in the rotor is induced from the stator winding
Introduction to Induction Machines•
Induction Machine types–
Squirrel cage: rotor winding are shorted; rotor windings are typically copper bars
–
Wound rotor: a winding on the rotor that can be accessed externally through the slip rings
–
We will investigate the squirrel cage induction machine
Squirrel cage (source: daviddarling.info) Wound rotor (source: tpub.com)
Review of Rotating Magnetic Field of the Stator
•
The diagram illustrates how the stator circuit (stator windings) sits on the stator of a simple two pole motor.
•
Each phase winding is capable of producing flux as defined by the right hand rule. If we excite the windings with a 3-phase voltage source, the resulting current through the coils will produce a time varying flux (vectors) by each phase.
c
b
a
The flux vector’s magnitude will be sinusoidal. The sum of the three flux vectors will result in a Net Flux ΦN
. As an example lets examine the flux at time t1
.
max( ) sin 0a t t
max( ) sin( 120 ) 240b t t
max( ) sin( 240 ) 120c t t
( ) ( ) ( ) ( )N a b ct t t t
1 1 1 1 max3( ) ( ) ( ) ( ) 302N a b ct t t t
2 max3( ) 302N t
2 max3( ) 902N t
What results is a rotating magnetic field with a constant magnitude which produces a rotating flux ΦN
.
Review of Rotating Magnetic Field of the Stator (cont)
Rotor Behavior
•
When we excite the stator with a balanced current, a current will be induced in the rotor
•
As a result of the interaction between the two currents, a force will be produced in the motor
Faraday's EMF Lawe Blu
Lorent's ForceF Bli
•
Look back to example from lecture 1
Transformer Model•
Since the induction machine at zero speed (locked rotor condition) is a form of a three-phase transformer with a shorted secondary we will review the transformer model
•
We will assume that both the primary (stator) and the secondary (rotor) are Y-connected
•
We will then investigate a single phase of the motor and realize the other two phases will behave identically with a 120 degrees offset
Ideal Transformer Model
V
+
-
R’
I1
V
+
-
E2
+
-
R
I2
+
-
E1
I1
N1 N2
Ideal Transformer
1 1
2 2
N VN V
1 2
2 1
N IN I
21
2'
NR RN
Practical Transformer Model
R1
: winding resistanceX1
: winding inductive reactance (leakage)RC
: core loss (eddy currents, hysteresis)Xm
: magnetizing reactance of entire transformerIm
: magnetizing current
Primary circuit model Secondary circuit model
E2
: Induced voltage X2
: inductive reactance (leakage)R2
: winding resistance
Developing the Induction Motor Model from the Transformer Model
•
Looking at the rotor circuit, we see that the induced emf
is a function of the rate of change of flux seen be the rotor winding
•
If the rotor is moving at some speed in the same direction as the flux vector, the speed of change in flux will be reduced
2
For stationary rotor 0
where is the synchronous electrical speed
The frequency of the induced voltage is
For moving rotor 0
where is the induced voltage on the
r
e e
e
r
r e r r
dEdt
dE Edt
rotor winding
The frequency of the induced voltage is e r
Developing the induction motor model from the transformer model
•
We want to find the relation between E2 and Er
Er=sE2
sX2
R2
Ir+
-
2
2
,
The parameter is defined as the motor slip
e r e r
e rr
e
d dE Edt dt
E sE
s
Developing the induction motor model from the transformer model
2 2 2
2 2
2 2 2 2
r r
r
E sE I jsX RsE EI
jsX R jX R s
Er=sE2
sX2
R2
Ir+
-
Induction Motor Equivalent Circuit
V
+
-
R1 X1
I1
E2
+
-
X2
R2/sIr
Rc
+
-
E1Xm
I
Im
2' 12 2
2
NR RN
Reflected rotor circuit parameters
2' 12 2
2
NX XN
' 22
1r
NI IN
Assumption: Im
<<I1
, then I1
≈I’2
and the stator and rotor windings are now in series.
'1 2eqR R R
'1 2eqX X X
V
+
-
R1 X1I1
E1=E’2
X’2 R’2
I’2
Rc
+
-
Xm
Im
R’2 (1-s)s
Rewrite the reflected stator resistance: this is done to ease power flow computation.
' ''2 22 (1 )R RR s
s s
Induction Motor Equivalent Circuit
Component related to the rotating rotor