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Structural dynamics-Introduction
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1
SD 421
Dynamics of Structures
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1.0 Introduction1.1 Objective
The objective of structural dynamics is to predict the behavior of structures under dynamic loads
This is done with a help of a mathematical model for the structural system.
For problems involving complex material properties, loading and boundary conditions, the engineer has to introduce assumptions and idealizations, which will make the problem manageable.
A mathematical model is a symbolic designation for the substitute idealized system including all assumptions imposed on the physical problem.
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1.0 Introduction1.2 Significance
There are cases whereby a structure has to be designed to resist dynamic loads such as gusty winds, earthquakes or other dynamic disturbances. under those circumstances it is important to
determine :
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1.0 Introduction1.2 Significance
The natural frequencies of vibration of the structure the purpose of estimating the likelihood of resonance due to the dynamic disturbances
The maximum displacements, stresses and acceleration the structure may experience when it is subjected to the dynamic disturbances.
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1.0 Introduction1.3 Degrees of Freedom
Degrees of Freedom is the number of independent coordinates or measurements required to define completely the configuration of the structure at any instant
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1.0 Introduction1.3 Examples: One Degrees of Freedom Systems
Simple Pendulum. Configuration is defined fully by angle
L
o(t)
M
o(t)
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1.0 Introduction1.3 Examples: One Degrees of Freedom Systems
Configuration is defined fully by displacement x(t)
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1.0 Introduction1.3 Examples: Two Degrees of Freedom Systems
Configuration is fully defined by the displacements x1(t) and x2(t)
Therefore the system has 2 degrees of freedom
m2
m1
m2
m2
m1 m1h2
h2
h 1 h 1
x1x1
x2x2
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1.0 Introduction1.3 Degrees of Freedom (cont.)
In general a continuous structure has an infinite number of degrees of freedom.
Nevertheless the process of idealization permits the reduction in the number of degrees of freedom to a discrete number and in some cases to just a single degree of freedom .
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1.0 IntroductionExamples of structural systems that can be modeled as one degree of freedom systems
Mass of the columns can be neglected
Mass of the beam can be neglected
F(t)
F(t)
m
m
X(t)
X(t)
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1.0 Introduction1.4. Dynamic Models
One degree of freedom systems may be described conveniently by one of the following models
m
m
kkc
c
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1.0 Introduction1.4. Dynamic Models
Each model has following elements:1) A mass element (m) representing the mass
and inertial characteristics of the structure2) A spring element (k) representing the
stiffness characteristics of the structure. (The stiffness of the structure describes the restoring force and the potential energy characteristics of the structural system.)
3) A damping element (c) representing the frictional characteristics and energy loses of the structure
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2.0 Free Vibrations of Un-damped Single
Degree of Freedom Oscillator2.1 Equation of Motion
Fig. 2.1 Shows un-damped single degree of freedom system, in which the mass has been displaced and then suddenly released
Position of static equilibrium Position of the mass t sec. After being
displaced and released suddenly
Figure 2.1 Un-damped Single Degree of freedom system
kk
m
m
X(t) X
(t)
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using Newton’s 2nd Law of Motion
Fig. 2.2 Shows a free body diagram of the oscillator displaced in the positive direction and acted upon by the spring force F = k∙x
k∙x
Positive Direction of motion
Fig. 2.2: Free body Diagram of the mass
m
k
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using Newton’s 2nd Law of Motion
From Newton’s 2nd Law of Motion:
F = m∙a
i.e.
Thus [2.1]
Equation [2.1] is the equation of motion of afreely vibrating one degree of freedom oscillator
xmxk masstheofonaccelerati
dtdxxwhereby
2
2
0 xkxm
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using D’Alembert’s Principle
It is difficult to use Newton’s 2nd Law of motion to derive the equations of motions of complex structural systems.
In those cases D’Alembert’s principle, in conjunction with the principle of virtual work is widely used
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using D’Alembert’s Principle
D’Alembert’s Principle states that a system may be set in a state of dynamic equilibrium by adding to the external forces a fictitious force which is commonly known as inertia force.
The inertia force is equal to mass multiplied by the acceleration and it is always directed NEGATIVELY with respect to the corresponding coordinate
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using D’Alembert’s Principle
Application of the Principle to a single degree of freedom system is illustrated in Fig. 2.3 below
Note that in Fig. 2.3 is the inertia Force
k∙x
Fig. 2.3: Free body Diagram of the mass
m
k
xm Positive Direction of motion
xm
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.1 Derivation Using D’Alembert’s Principle
The requirement that the two forces must be in equilibrium gives the equation of motion as follows:
00 xkxmFx [2.1]
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
The Equation of motion is given by equation
[2.1] i.e.0 xkxm
The equation is of
2nd ORDER,
LINEAR,
HOMOGENEOUS and has
CONSTANT COEFFICIENTS
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
To solve the equation one can start by assuming a trial solution given by
tBxor
tAx
cos
sin
[2.2]
[2.3]
Substituting Eq. [2.2] into Eq. [2.1] gives 02 tAkm sin [2.4]
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
If Eq. [2.4] is to be satisfied at any time (-m∙ω2 + k) must be equal to zero
i.e. -m∙ω2 + k =0 [2.5]
i.e.
The quantity is known as the
NATURAL FREQUENCY of the system
mkor
mk 2
mk
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
Similarly substituting x=B cosωt into gives:
i.e. -m∙ω2 + k =0 i.e.
mkor
mk 2
0 xkxm
02 tAkm cos
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
Since either x=Asinωt or x=Bcosωt is a solution of the differential equation and since this equation is linear, the superposition
of these two is also a solution. Thus the solution of the
equation of motion is given by
x=Asinωt + Bcosωt [2.6] Where A and B are constants of integration which are determined from the initial conditions.
0 xkxm
0 xkxm
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
The velocity is given by
Let xo = Displacement of the mass at time t=0
vo = Velocity of the mass at t=o.
Substituting x(t=0 )=xo into Eq. [2.6] gives
xo=B i.e. B=xo [2.8]
Substituting v(t=0)= vo into Eq. [2.7] gives
vo= Aω i.e. [2.9]
tBtAdtdxxv sincos [2.7]
ovA
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2.0 Equation of Motion Un-damped Single Degree of Freedom Oscillator
2.2 Solution of the Differential Equation of Motion
Finally substitution of A and B from Eqs.[2.8] and [2.9] gives the displacement of the mass as a function of time:
txtvtx
cossin)( 00 [2.10]
Where xo = Displacement of the mass at time t=0 vo = Velocity of the mass at t=o. ω = natural frequency of the system
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2.3 Springs in Parallel or in Series
Sometimes it is necessary to determine the equivalent spring constant for a system in which two or more springs are arranged in parallel or in series.
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2.3.1 Springs in Parallel
Fig. 2.4: Two Springs in Parallel
k1 k2 k1 k2m
m x
F
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2.3.1 Springs in Parallel
Fig. 2.5: Free Body Diagrams
k1
xk2x
kex
F F(a) Actual System (b) Equivalent
System
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2.3.1 Springs in Parallel
Equilibrium requirements for the actual system (fig. 2.5(a)) and of the equivalent system (Fig. 2.5(b)) gives
F = kex= k1x+k2x=(k1+k2)x Thus The Equivalent spring constant is given
by: ke=(k1+k2)In general the equivalent spring constant for n Springs in parallel is given by
n
i
ie kk1
[2.11]
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2.3.2 Springs in Series
k1
k2
k2
k1
m
F
x
m
Let:
x1= Change in length of 1st Spring
x2=Change in Length of 2nd Spring
Displacement of the mass is
given by:
x=x1+x2
Fig. 2.6: Spring In Series
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2.3.2 Springs in Series
k1x1
F F
k2x2
Fig. 2.7: Free Body Diagrams
(a) (b)
Equilibrium Requirements give
2222
kFxorxkF
and
1111
kFxorxkF
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2.3.2 Springs in Series
If ke is the equivalent spring constant the Displacement of the mass is given by
ekFx
2121
kF
kFxxx
21
21
111
11
kkkei
kkF
kF
e
e
..
But
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2.3.2 Springs in Series
In general the equivalent spring constant for n Springs in series is given by
n
iie kk
1
11 [2.12]
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2.4 Frequency and Period
Equation [2.10] shows that the motion of a freely oscillating mass can be expressed by a sine or cosine function of same frequency ω. Since both cosine and sine functions have a period of 2the period T of the motion is given by
ωT= 2
2TOr
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2.4 Frequency and Period
The period is usually expressed in seconds per cycle or simply in seconds with the understanding that it is per cycle.
The value of the reciprocal to the period is the natural frequency f
2
1 T
fi.e.
The natural frequency is usually expressed in HERTZ or CYCLES PER SECOND
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2.4 Frequency and Period
The quantity ω is sometimes referred to as the natural frequency. To distinguish between ω and f, ω is sometimes called CIRCULAR or ANGULAR natural frequency. The circular frequency is is given in RADIANS PER SECOND