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ME 347 Mechanical Vibrations Introduction to Vibrations Dr. Conchúr Ó Brádaigh January 2012 [email protected] College of Engineering & Informatics

Lecture 1 - Introduction to Vibrations

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Page 1: Lecture 1 - Introduction to Vibrations

ME 347 Mechanical Vibrations Introduction to Vibrations

Dr. Conchúr Ó Brádaigh

January 2012

[email protected]

College of Engineering & Informatics

Page 2: Lecture 1 - Introduction to Vibrations

Basic Concepts of Vibration

ME 347 Mechanical Vibrations - Introduction to Vibrations

Any motion that repeats itself after an interval of time is called vibration or oscillation. Examples are the swinging of a pendulum or the vibration of a plucked string. The theory of vibration deals with the study of oscillatory motions of bodies and the forces associated with them.

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Page 3: Lecture 1 - Introduction to Vibrations

Basic Concepts of Vibration

ME 347 Mechanical Vibrations - Introduction to Vibrations

A vibratory system, in general, includes a means for storing potential energy (spring or elasticity); a means for storing kinetic energy (mass or inertia); and a means by which energy is gradually lost (damper) The vibration of a system involves the transfer of its potential energy to kinetic energy, and of kinetic energy to potential energy. If the system is damped, some energy is dissipated in each cycle of vibration and must be replaced by an external source if steady-state vibration is to be achieved

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Page 4: Lecture 1 - Introduction to Vibrations

Example System – Simple Pendulum

ME 347 Mechanical Vibrations - Introduction to Vibrations

1-2: Potential energy converted to kinetic energy (max. at 2) 2-3: Kinetic energy converted to potential energy (max. at 3 & 1) Damping from air resistance means that pendulum will eventually stop.

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Page 5: Lecture 1 - Introduction to Vibrations

Number of Degrees of Freedom

ME 347 Mechanical Vibrations - Introduction to Vibrations

The minimum number of independent co-ordinates required to determine completely the positions of all parts of a system at any instant in time defines the number of degrees of freedom of the system.

Single degree of freedom systems

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Page 6: Lecture 1 - Introduction to Vibrations

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2-Degree of Freedom Systems

ME 347 Mechanical Vibrations - Introduction to Vibrations

(c) θ & X or x, y & X (note x2 +y2 = l2)

(a) x1 & x2 (b) θ1 & θ2

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School Institute Name to go here

3-Degree of Freedom Systems

ME 347 Mechanical Vibrations - Introduction to Vibrations

(a) x1, x2 & x3

(c) θ1, θ2 & θ3

(b) θ1, θ2 & θ3 or x1, x2, x3 & y1, y2, y3 (note xi

2 +yi2 = li2, i = 1,2,3)

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Some systems, especially those involving continuous elastic members, have an infinite number of degrees of freedom (DOF), e.g. the cantilever beam shown. Systems with a limited number of DOF are called discrete or lumped systems, those with an infinite number of DOF are called continuous or distributed systems.

Infinite Degree of Freedom Systems

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Page 9: Lecture 1 - Introduction to Vibrations

Vibration Analysis Procedure

ME 347 Mechanical Vibrations - Introduction to Vibrations

1. Mathematical Model of System

2. Derivation of Governing equations

3. Solution of the Governing Equations

4. Interpretation of the Results

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Page 10: Lecture 1 - Introduction to Vibrations

Mathematical Model of a Motorcycle

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Simplest model considers one equivalent mass, spring and damping constants

More refined model separates out the mass of each wheel from that of the vehicle and rider, and gives stiffness and damping properties to each strut, and stiffnesses to each wheel

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Mathematical Model of a Motorcycle (cont.)

ME 347 Mechanical Vibrations - Introduction to Vibrations

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The model can be refined further by providing for elasticity & damping of the rider/seat.

This model could then be simplified by combining the strut and wheel properties to make a simpler 2 DOF system.

Page 12: Lecture 1 - Introduction to Vibrations

Spring Elements

ME 347 Mechanical Vibrations - Introduction to Vibrations

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A spring is said to be linear if the elongation or reduction in length x is related to the applied force, F as:

where k is the spring constant, rate or stiffness The work done in deforming a spring is stored as strain or potential energy in the spring:

Page 13: Lecture 1 - Introduction to Vibrations

Example: Spring Constant of a Rod

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.3 (Rao). Find the equivalent spring constant of a uniform rod of length l, cross-sectional area A, and Young’s Modulus E, subjected to an axial tensile or compressive force, F as shown:

Page 14: Lecture 1 - Introduction to Vibrations

Example: Spring Constant of a Rod

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Page 15: Lecture 1 - Introduction to Vibrations

Example: Spring Constant of a Cantilever Beam

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.4 (Rao). Find the equivalent spring constant of a cantilever beam subjected to a concentrated load F at its end, as shown below

k = ?

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Example: Spring Constant of a Cantilever Beam

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Solution:

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Combinations of Springs

ME 347 Mechanical Vibrations - Introduction to Vibrations

Case 1. Springs in Parallel

2 springs in parallel:

n springs in parallel: College of Engineering & Informatics

Page 18: Lecture 1 - Introduction to Vibrations

Combinations of Springs

ME 347 Mechanical Vibrations - Introduction to Vibrations

Case 2. Springs in Series For 2 springs in series: For n springs in series:

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Page 19: Lecture 1 - Introduction to Vibrations

Example: Torsional Spring Constant of a Propellor Shaft

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.6 (Rao). Determine the torsional spring constant of the steel propeller shaft shown below

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Example: Equivalent Spring Constant of Hoisting Drum

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.7 (Rao). Determine the equivalent spring constant of the system shown below (do yourselves)

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Example: Equivalent Spring Constant of a Crane (do yourselves)

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Page 22: Lecture 1 - Introduction to Vibrations

Example: Equivalent Spring Constant of a Rigid Bar Connected by Springs

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Page 23: Lecture 1 - Introduction to Vibrations

Combinations of Masses

ME 347 Mechanical Vibrations - Introduction to Vibrations

In many practical applications, several masses appear in combination. For a simple analysis, we can replace these masses by a single equivalent mass. Case 1: Translational Masses Connected by a Rigid Bar

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Combinations of Masses

ME 347 Mechanical Vibrations - Introduction to Vibrations

Case 2: Translational and Rotational Masses Coupled Together

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Page 25: Lecture 1 - Introduction to Vibrations

Equivalent Mass of a System

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.11 (Rao). Find the equivalent mass of the system shown below, where the rigid link 1 is attached to the pulley and rotates with it.

Page 26: Lecture 1 - Introduction to Vibrations

Equivalent Mass of a System

ME 347 Mechanical Vibrations - Introduction to Vibrations

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Example 1.12 (Rao). A cam-follower mechanism is used to convert the rotary motion of a shaft into the oscillating notion of a valve. The system comprises:

Pushrod of mass mp Rocker arm of mass mr and mass moment of inertia Jr about its CG Valve of mass mv and a valve spring of negligible mass

Find the equivalent mass of the system at (i) point A and (ii) point C