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8/17/2019 Lect01-6P-C
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8/17/2019 Lect01-6P-C
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Linear Amplifiers (2)
• Symbol for a single-ended
input linear voltage amplifier.
• Ideally provides linearvoltage gain regardless of
the amplitude of the input
signal
• Real amplifiers have power
supplies that limit the
amplitude of the output
• If input is too large, output
clamps
Transfer Characteristics (1)
Plot of amplifier output versus amplifier input
Transfer Characteristics (2)
• Gain = Slope
• To operate amplifier in its linear region, the inputmust be kept small enough
Real Transfer Characteristics
• Each circle represents
a different DC
component for the
input and output
signals – called an
operating point
• Location of operating
point has an effect on
• input signal range
• amplifier gain magnitude
• amount of distortion
Operating Point (1)
Voltage gain, output DC voltage, allowable input
magnitude range are affected
Operating Point (2)
Derivative of
transfercharacteristic
gives measure
of amplifier gain
linearity (and
distortion)
Input and output signal amplitude ranges are
maximized when operating point is near middle of
linear region
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Signal Convention (1)
• DC magnitudes in uppercase symbol and
subscript
– Example: ID, VD
• Ac signal quantities in lowercase symbol &
subscript
– Example: id(t), vd(t)
• Total DC + ac signal quantities in lowercase
symbol, uppercase subscript
– Example: iD(t), vD (t)
Signal Convention (2)In general
vD(t) = VD + vd(t)
iC(t) = IC + ic(t)
Superposition
• If the amplifier is linear, superposition can be
applied. Each component can be determined
seperately.
• Determine the DC magnitude of the output using
DC model (i.e capacitors are open circuited,
inductors are short circuited)
– Example: IO, VO
• Determine the ac signal component of the output
using the ac model (i.e., DC sources are killed and
capacitors are short circuited, inductors are open
circuited) as
– Example: vo(t) = Av vi(t)
Amplifier Classification
CurrentCurrentCurrent
TransresistanceVoltageCurrent
TransconductanceCurrentVoltage
VoltageVoltageVoltage
TypeOutputInput
+
vi
-
+
vo
-
Ideal Voltage Amplifier
Avi
+
R oAvi
+
vi-
+
vo-
R i
+
Real Voltage Amplifier
Loaded Ideal Voltage Amplifier
Avi
+
vi-
+
vo-
+
R LR s
vs
+
Av
v
s
o=
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Loaded Voltage Amplifier
R o
Avi
+
vi-
+
vo-
R i
+
R L
R s
vs
+
Lo
L
is
i
s
o
R R
R
R R
R A
v
v
++=
Ideal Current Amplifier
Real Current Amplifier
Aii
ii io
Aiiii io
R i R o
Loaded Ideal Current Amplifier
Ai
i
s
o=
Aii R Lii
R sisio
Loaded Current Amplifier
Aii R Lii
R Sisio
R i R o
Lo
o
is
s
s
o
R R
R
R R
R A
i
i
++=
To determine Input Resistance R i
R oAvi
+
vi-
+
vo-
R i
+
• Apply input voltage vi(or input current ii)
• Determine the input
current ii (or inputvoltage vi)
Then
R i = vi / iiAiiii io
R i R o
ii
+
vi-
Voltage Amplifier
Current Amplifier
To determine Output Resistance R o
R oAvi
+
vi-
+
vx-
R i
+
• Kill the input signal
(set vi or ii to zero)
• Apply a test voltage
vx to the output node• Determine the current
ix that the source
delivers to the circuit
Then
R o = vx / ix
Aiiii ix
R i R o
ii
+
vi-
Voltage Amplifier
Current Amplifier
+
vx-
ix