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Le Chatelier's Principle
Use Le Chatelier’s Principle to explain the effects on the position of a system at equilibrium from:
· Changing concentration
· Changing temperature
· Changing pressure
· Adding a catalyst
Le Chatelier's Principle (1884)
When a system at equilibrium is subjected to a stress, the system will adjust so as to
relieve the stress.
Remember: Kc value is constant. BEFORE the stress, and AFTER the reaction
adjusts to the stress.
Types of Stress
1. Concentration stress
Any change in concentration of products or reactants from equilibrium values.
[increase] System will react by consuming the excess.
[decrease]System will react by producing to replace the loss.
• More C means increased rate of reverse reaction.
Kc =
[C] [A][B]
CBA +
Kc = 1.35
Increase [C] - the reaction shifts left to use it up.
• Excess C used up until ratio of product to reactant concentrations is equal to Kc once again.
Kc =
[C] [A][B]B CA +
Kc = 1.35
Forward reaction rate increases (favored) and Kc is reestablished.
Removing a particle is like decreasing [ ]. Reaction will shift to replace the loss.
Increase [B] - the reaction shifts right to use it up.
2 NO2 (g) N2O4 (g) car exhaust smog
Huge spike indicates that [ ] was changed by adding more particles.
2 NO2 (g) N2O4 (g) car exhaust smog
A huge spike indicates that [ ] was changed by removing particles.
2 NO2 (g) N2O4 (g) car exhaust smog
Temperature
The system relieves the stress by either replacing lost heat or consuming added heat.
Reaction reestablishes new eqlbm (with new [ ]s) at new temperature – BUT also changes the Kc.
Consider heat a component of the system:
Exothermic A B (- ∆H )
Endothermic A B (+ ∆H)HEAT +
+ HEAT
2. Temperature stress
Temperature increase / add heat • Reaction shifts left to use up the heat.• Endothermic reaction (reverse) favored.
Temperature decrease / removing heat• Reaction shifts right to produce more heat.• Exothermic reaction (forward) favored.
+ heat
heat
A B
+A B
Kc = [B] [A]
Kc = [B] [A]
∆H = -58 kJ2 NO2 (g) N2O4 (g) car exhaust smog
∆H = -58 kJ2 NO2 (g) N2O4 (g) car exhaust smog
Volume/Pressure
Changing the pressure of a system only affects those equilibria with gaseous reactants and/or products.
3. Volume stress
Shifts to compensate pressure changes will effect all concentrations – BUT, Kc value will return as equilibrium reestablishes.
A + 2 B C
A + 2 B C
Volume decrease – (↑P )
AB
BC
Reaction shifts to decrease total number of gas particles – reduces pressure.
C
A + 2 B C
Volume increase– (↓P )
A
B
B
C
Reaction shifts to increase total number of gas particles – increase pressure.
BBA
1. IF the size of the container is cut in half?
Increases pressure reduce pressure by reducing the number of molecules in the container.
Reverse reaction favoured. The equilibrium shifts left.
2 NH3(g) N2(g) + 3 H2(g)
2. IF the reaction chamber is increased in volume?
Increasing volume, reduces pressure increase pressure by increasing number of molecules in container.
Reverse reaction is favoured.The equilibrium shifts left.
2 NO2 (g) N2O4 (g) car exhaust smog
Therefore, in response to pressure changes, the equilibrium position remains unchanged.
H2(g) + I2(g) 2 HI(g)
3. Increase container OR increase the pressure?1 + 1 : 2
Pressure changes have NO effect on this eqlbm – same # of particles regardless of shift (stoich).
Factors (stresses) that do not affect
Equilibrium Systems
Catalysts
Lowers activation energy for both forward and reverse reaction equally.
Equilibrium established more quickly, but position and ratios of concentrations will remain the same.
K value remains the same.
Inert Gases (noble gases)
Unreactive – are not part of a reaction, therefore can not affect [ ], pressure or volume of a equilibrium system.
Catalysts, inert gases, pure solids or pure liquids do NOT appear in the mass action expression - so they
cannot have an effect if altered.
Le Chatelier's AND
life
Haemoglobin protein used to transport O2 from lungs to body tissue.
Lungs - [O2] is high - forward reaction favored Haemoglobin binds to the excess O2. Tissue - [CO2] is high and [O2] is low - reverse reaction favored. Hb releases O2.
Hb (aq) + O2 (g) HbO2 (aq)
Haemoglobin Production and Altitude
Hb (aq) + O2 (g) HbO2 (aq)
High altitudes - [O2] is very low - reverse reaction favored. Hb release O2, fewer Hb bind oxygen. Result in exaggerated lack of oxygen to the tissues, resulting in headache, nausea and fatigue.
Over time, body adjusts by producing more haemoglobin molecules.
Increases [Hb] in the blood stream shifts equilibrium right - more O2 bound and transported to the tissue.
Appliance - NO energy - forward reaction favored Energy release to run appliance.
Outlet (recharge) - high energy - reverse favoredReforming the reactants, storing the energy for use.
Rechargable Batteries
Lead-acidPbO2 + Pb + 4 H+ + 2 SO4
2- 2 PbSO4 + 2 H2O + energy
Nickel-cadmium Cd + 2 NiO(OH) + 2 H2O 2 Ni(OH) + Cd(OH)2 + energy
Electrical energy (like heat) is written in the reaction.
THE HABER PROCESS
N2(g) + 3H2(g) 2NH3(g)
ΔH = -92.4 kJ mol-1
· high pressure· medium temperature - catayst· remove ammonia· high reactant
concentrations