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ECE 583Lecture 10
Errors in Langley method; temporal effects, absorption
10-1 Langley method
Consider all of the assumptions that are inherent in theLangley method
PBiggest assumption is that the optical depth is constant with timePOther assumptions are
• Atmospheric composition is horizontally homogeneous• Airmass is known
PAssumes Beer’s law and voltage relationship is valid• Small wavelength interval (Beer’s law is monochromatic)• Responsitivity is relatively constant over the bandpass• Optical depth is relatively constant over the bandpass
P Instrument is not contributing to errors• Stable with time• Response is linear (or can be corrected)• Field of view effects are minimal• Digitization of the output
PAlso assumes that the attenuation is linear with airmass
10-2
VV
VV
m m0
0
VV
VV
m m0
0
VV
VV
m
m
0
0
Errors in Langley method
Analyze the sensitivity of the results with respect to each ofthe parameters in the voltage relation
PDifferentiation by parts gives
PSolving for the percent error in intercept
PSolving for the optical depth error gives
10-3
V V e m0
ii
i
V Vm
ln ln0
Regression “errors”
One issue that should be clear is that a standard linearregression will be biased
PTypical method is to find the “best” fit straight line through themeasurements via linear regression
PErrors depend on the airmass leading to more weight being given tovariations in optical depth at large airmass
ln(V)=-m given only errors are due to random atmosphericfluctuations
PDevelop a technique that does not suffer from this issue• Define
• Then
• Where i is the ith measurement
10-4
1
1N ii
N
i i
( )ii
N
1
2
dd V i
i
N
ln ( )0 1
2 0
Regression errors
The least squares fit minimizes the squared deviations fromthe averages
PAverage optical depth is
PFluctuation in optical depth is
PWant the V 0 such that this intercept for a straight line minimizes
PThus want,
10-5
dd V
dd V
dd Vi
i
N
ii
Ni
ln( ) ( )
ln ln0 1
2
1 0 02 0
ii
i
ii
i
Ni
ii
N
ii
NV Vm
ddV m N N
V Vm
ddV N m
ln ln ln ln0
0 1
0
1 0 1
1 1 1 1 1
ln
ln ln
VN
Vm
Vm m
Nm m
i
ii
Ni
ii
N
ii
N
ii
N
ii
N0
21 1 1
21 1
2
1
1 1
ln ln1 1
1 11
21
21 1
21 1
2
mVm m
Vm
Nm m
ii
Ni
ii
N
ii
Ni
ii
N
ii
N
ii
N
Unweighted fit
Taking the derivative with respect to the intercept voltage
P
PUsing the relationships for i and the average optical depth it can beshown that
PThen the best estimate of the intercept and optical depth are
10-6
ln
( )( )
V
ii
N
ii
N
ii
N
ii
N
ii
N
N
Nm m
m
Nm m
02
2
21 1
22
21
2
21 1
21 1
1
1 1
(ln ) ( )V0 113
Uncertainties are really what is of interest
Evaluate the uncertainties by using the standard deviation ofthe fit - (lnV 0 ) and ( )
PThen the variance on the intercept and optical depth estimates are
• Where is the standard deviation of the optical depth based on i
PThe unweighted case provides an improved estimate of the standarddeviation of the intercept and optical depth estimates
PFor the case of a large number of measurements
10-7 Renormalized example10-8
VV
VV
m m0
0
VV
m
Airmass limitations
Assume that the dominant errors are due to errors in theairmass
PErrors in airmass can be due to• Choice of airmass model• Errors in refraction computation (uncertainty in profiles)• Location error• Timing errors
PAssume that the errors are caused by timing uncertaintyPRecall
PThen in this case
• Want a limit of 0.1% in measurement error• Means that airmass error should be less than 0.002 for a clear sky case
10-9
VV
m
m dmdt
t
Airmass limitations
Modeling efforts show that it is straightforward to meet the0.1% error for m<5.0
PErrors in airmass can be reduced by • Precisely recording time to better than 1 second• Spherical geometry must be taken into account• Refraction must be included• Vertical distribution of atmospheric attenuators must be reasonably
modeledPWhere does the 1 second requirement come from?
• Recall
• Write the error in airmass as that due to an error in time
10-10
dmdt
smax
.0 0015 1
t smax.
..0 001
0 00150 67
Airmass timing
Analysis of airmass as a function of time for standard casesusing solar ephemeris shows
Pdm/dt is a maximum at high solar zenith angles (surnrise, sunset)PFurther, it can be shown that the error is largest in spring and fall
PThe 0.1% error/change in measurments due to timing error for a largeoptical depth of 1.0 means
PConclusion is that a 1 s accuracy is needed• Requirement is looser for smaller optical depths• Requirement is less for longer wavelengths (lower optical depths)
10-11
V V e V V VV V DD
DDVV
diff direct diff
direct
diff
direct
0
1, ,
,
,
,
( )
DDVV
m Pdiff
directaerosol aerosol aerosol( ) cos( )0
Diffuse light redux
The finite field of view of the sensor means that there is adiffuse light component in the measurement
PRecall the diffuse-to-direct ratio introduced previously
• Varies with FOV of the sensor• Also varies with wavelength, solar zenith (airmass), and optical depth
• P is the phase function• 0 is the single scatter albedo
10-12
DDVV Km Pd
a a1
2( )
Diffuse-light effects
Diffuse light causes two primary effects - added light andtemporal variations
PBoth effects can modeled reasonably well• Recover optical depth from the Langley method• Remove molecular optical depth and determine aerosol optical depths
(we’ll discuss this more later)• Compute the diffuse contribution from assumed aerosol model• Correct for diffuse effects to iterate on optical depth and intercept
PTemporal variations can be measured• Measure direct signal with one channel• Measure diffuse light with another channel• Develop a factor K that accounts for differences in center wavelength,
responsivities, and aerosol effects
10-13 Error in from Langley method
Plot here shows theoptical depth errordue to diffuse light
PModel-base resultsPVariety of Junge
exponents (recall thatlarge Junge values implysmaller particles)
PResults as a function ofFOV
10-14
Diffuse-light and Langley plots
Generate a model-basedLangley data set
PWavelength of 400 nm withmoderate aerosol amount
P4-degree full-field FOVPRetrieved intercept is 0.6% too lowPRetrieved optical depth to low by
0.013 in optical depth (4.3% inaerosol optical depth)
PThis assumed no temporalvariability in the aerosol content
10-15 Langley methodThe langley method requires that the optical depth not vary as
a function of timePGraph below shows the results from a day for which the Langley method
does not work wellPThis gives an incorrect value for the intercept and for optical depthPTucson from October 30, 2001
0 1 2 3 4 5 6 7Airmass
3
4
5
6
10-16
Not so good Langley plot
One of the biggest error source in the Langley method istemporal variations in atmospheric composition
Langley Plot
0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0Airmass
-3.0
-2.0
-1.0
0.0
1.0 June 23, 2001Ivanpah Playa
400 nmLangley fit
870 nmLangley fit
10-17 Variation in optical depth
Can still determine an average optical depth as well asinstantaneous values
Optical Depth vs. Time
6.0 7.0 8.0 9.0 10.0 11.0 12.0Mountain Standard Time
0.0
0.2
0.4
0.6
0.8
1.0
1.2 Ivanpah PlayaJune 23, 2001
400 nm870 nm
10-18
Variation in Langley plot
Typically the varibility seen in a Langley plot is caused byvariations in atmospheric conditions
P Instrumental effects can play a role• Noise in the measurement• Temperature/thermal effects in the detectors
PAtmospheric variability can be caused by• Clouds• Wind conditions• Convection• Pollutants
PBest measurements take place• On mountaintops where lower aerosol loading means lower aerosol
variability• Mornings which are cooler and more stable with less convective mixing• Low wind conditions• Away from pollution sources
10-19 Residual optical depth
Examine the difference between the instantaneous opticaldepth and regression average
PGood day will showsmall randomvariations in theresidual
PAirmass effect cancause larger errors atsmaller airmass
PConvection alsomore prevalent atsmall airmass for amorning collection
PLarger number ofpoints at smallairmass also affectsthe regression
10-20
Residual plots
Residual optical depth plot shown here is still from a not sobad day
PAirmass range onthe regressionwas limited tobetween 2.0 and6.5
PShould haveconfidence thatthis is valid beforeblindly attemptingto restrict airmassrange
PMay date fromTucson shownhere correspondsto a hot daysusceptible toconvective effects
10-21 Residual plots
Plot here is one for which the Langley assumptions are notvery valid
PCould stillprovide areasonableestimate ofintercept but notlikely
PThis was a“clear” day in thesummer
10-22
( )( )
tm t
VV
1 0
0
Cm
VV
1 0
0
( ) ( ) ( ) ( )t t m t m tVV1 2
1 2
0
0
1 1
Residual plots
The only foolproof means of detecting temporal variations is toknow the interecpts ahead of time
PHowever, errors in the voltage intercept will cause an error in the retrievedoptical depth
PThe correct instantaneous optical depth is related to the computed opticaldepth by
P If the error in intercept is small the changes in optical depth will still beapparent
P Inverse airmass difference typically <0.1 for about 30 minutes difference• Assume 2% uncertainty in intercept• Changes greater than 0.002 in optical depth are discernible
10-23 Temporal variationsin optical depth
PDifficult to see the slowlyvarying atmospheric trends• High frequency atmospheric
changes• Sensor noise
PTemporal averaging allows theslowly varying effects to bedetermined
PSlowly-varying atmosphericchanges are more problematicfor the Langley retrievals
10-24
Temporal variationin optical depth
PSame data set as previousviewgraph except for shorterwavelength
PPlotted versus airmass andtime
PNote that there are similarfeatures between this bandand the longer wavelength
10-25
V V ei imi i
0
Q V Vii
N
0 02
1
*
i ii
i
i
ii
N
where N mVV1
1 1 0
1ln
*
Intercept correction method
Improved intercept retrieval can be obtained with informationon the change in optical depth over the measurements
PDefine an instantaneous intercept as
PGoal is to retrieve an optimal intercept V*0 that minimizes a performancefunction Q
PThis requires the instantaneous optical depth as
• V*0 can be found if the residual optical depth can be modeled ordetermined
• This information can be obtained from the diffuse component
10-26
d Vdm
cons tln( ) tan
ln( ) ln( )( )
V Vm t
0 0
Residual plot failure
There is an interesting result for which an optical depth thatvaries with time will still provide a good Langley plot
PConsider the case where the log of measurement is linear in airmassPThen
P “It can be shown” that the optical depth that satisfies this condition is
PWhere the primed quantities are the difference between the actual and theerroneous intercepts and optical depths
10-27 Intercept determination
The question then becomes what is the best way to determinethe intercepts for a given sensor
PThe intercepts are needed to allow determination of instantaneous opticaldepths
PFirst step is to find dates that are good for Langley analysis• No apparent variations in the Langley plot• Scatter is small at high airmass• No curvature to data at high airmass• All wavelengths without absorption have small standard deviations• Low optical depths at long wavelengths (<0.05 for Tucson)• Residuals at long wavelengths are small (<0.002)• Residuals show random scatter• Intercepts show reasonable agreement with past results
PCompute average of selected dates
10-28
Determination of InterceptTypically, several days of data are used to calibrate the solar
radiometerPGraph below shows results from several datesPDifferences can be caused be instrumental effects and atmospheric
variability
Band 1 Band 2 Band 3 Band 4 Band 5 Band 6 Band 7 Band 8 Band 10350
400
450
500
550
600
650
700
Oct. 28 Oct. 29 Oct. 30Nov. 1 Nov. 5
10-29 Determination of interceptGraphs below summarize the variability on the dates shown in
the previous graph
November 1 November 5
October 28 October 29 October 30
10-30
Interceptdetermination
POne mechanism forevaluating a good Langleyday is comparisons betweendays
PCompare retrieved interceptwith standard deviation ofthe intercept (these areweighted results)
PCompare the retrievedintercept with the opticaldepths on the date
10-31 Interceptdetermination
PSelected dates fromprevious data set
PUpper graph spans a 16-month period
P Is the 7% decrease real oran artifact of the Langleyresults?
PLower results are for a 6-month period
10-32
Intercept vs. TimeThe whole reason for all of this work is to ensure that we can
track changes in instrument response over time
Band 1 Band 2 Band 3 Band 4 Band 5 Band 6 Band 7 Band 8 Band 10350
400
450
500
550
600
650
700
April 02 August 02 Nov. 02
10-33 Intercept versus time10-34
Interceptversus time
PScale the intercepts byband for easiercomparison
PNote that many of thedays produce similarchanges in interceptsrelative to other dates
PBand 8 results areanomalous indicating aninstrumental change
10-35 How well can we do?10-36
How well can we do?10-37 Comparisons between sensors10-38