34
FST 4822 LABORATORY FOR CHEMISTRY AND TECHNOLOGY OF PLANT AND ANIMAL PRODUCTS SEAFOOD BASED LAB: SENSORY EVALUATIONS OF FOOD PRODUCTS GROUP : GROUP 6 GROUP MEMBERS : TEY CHEE SENG 137999 SITI FARHIAH BINTI ABDUL MANAN 136430 FARHANA YUSOF 136499 NUR BAITI SOFYUDDIN 136786 AMINAH LET 137176 FARHAH IZZATI SHUKOR 137259 YONG XIANGPEI 138713 SEE HUI YONG 138835 PROGRAM : BACHELOR OF FOOD SCIENCE &TECHNOLOGY LAB : MAKMAL PEMPROSESAN & MAKMAL BIOKIMIA DATE : 30 TH JULY 2008

LAB 4 - Sensory Evaluation of Food Products

Embed Size (px)

DESCRIPTION

A lab report on previously minced meat in sensory evaluation-under food science and technology of Universiti Putra Malaysia

Citation preview

Page 1: LAB 4 - Sensory Evaluation of Food Products

FST 4822LABORATORY FOR CHEMISTRY AND

TECHNOLOGY OF PLANT AND ANIMAL PRODUCTS

SEAFOOD BASED LAB:SENSORY EVALUATIONS OF FOOD

PRODUCTS

GROUP : GROUP 6GROUP MEMBERS :TEY CHEE SENG 137999SITI FARHIAH BINTI ABDUL MANAN 136430FARHANA YUSOF 136499NUR BAITI SOFYUDDIN 136786AMINAH LET 137176FARHAH IZZATI SHUKOR 137259YONG XIANGPEI 138713SEE HUI YONG 138835

PROGRAM : BACHELOR OF FOOD SCIENCE &TECHNOLOGYLAB : MAKMAL PEMPROSESAN & MAKMAL BIOKIMIADATE : 30TH JULY 2008LECTURER: PROFESSOR MADYA DR. AZIS ARIFFIN

Page 2: LAB 4 - Sensory Evaluation of Food Products

Introduction:

According to Elizabeth (1977), a sensory evaluation was made by senses of taste, smell,

touch, and hearing when the food product was consumed. The complex sensation from the

interaction of our senses was used to measure the food quality and for new product development.

Many developments and advances in this area have been made since Methods for Sensory

Evaluation of Food was published in 1967 (Elizabeth, 1977). Research, product development,

and quality control are the three main areas that sensory testing is being utilized (Meilgaard et

al., 1991).

There are many different types of sensory tests. Attribute difference tests usually

determine in what sense a certain quality or trait differ between samples. Meanwhile, affective

sensory tests evaluate the consumer acceptance of products. Overall difference tests determine

the sensory difference which may exist between samples. A triangle test is a type of difference

test to determine if there is a sensory difference between two products. For example, a researcher

may want to see if changing one ingredient to make a food product will affect the taste of the

final product. (Meilgaard et al., 1999). The sensory test measures if any differences detected are

truly significant by analyzing the sensory data for statistical significance. After statistical

analysis, the researchers can make a meaningful interpretation from the results of the sensory

data (Meilgaard et al., 1999).

The simplest form of sensory evaluation that can be performed is the evaluation that is

done at the bench by research worker who develops the new food products. The research worker

usually relies on his or her own evaluation to determine the differences in the food products. The

more formal manner of sensory evaluation is conducted by laboratory and consumer panels.

Sensory evaluation that is performed in the presence of large scale panelists can give clear

prediction of consumer reactions.

Different food products have different composition and ratio of ingredients used in them.

In order to determine the best composition and ratio that suits the consumer needs, sensory

evaluation is done so that food industry can improvise their products to be sold to the consumers.

For this experiment, we were asked to prepare three fish-based products which are fish ball, fish

cake and fish finger. All of these were made using surimi block into different end products. The

final products were then undergone sensory test to determine the acceptance among us.

During the preparation of the products, different processing methods were used although

the ingredients added to make up the mixture was similar. For fish ball, the mould machine was

used to shape the fish ball into round shape before boiling it in a boiler. On the other hand, fish

Page 3: LAB 4 - Sensory Evaluation of Food Products

cake was cut into shape by using cutting utensils before putting it into steamer and followed by

frying. While for fish finger, it was also put into steamer followed by battered and coated with

breadcrumbs before frying it.

These different processing methods gave various sensory evaluations on the products

although the basic ingredients were the same. The processing methods give effects on the end

products in terms of texture, overall appearance and also acceptability among consumers. As for

fish cake and fish finger, both of them were fried in hot oil temperatures. Frying operations that

are actually applied to dry the food and to increase shelf life may finally cause losses of

nutrients, especially fat soluble vitamins. For example vitamin E which is absorbed from oil by

crisps during frying, is oxidized during storage. Bunnell et al. (1965) found that 77% loss of

vitamin E after eight weeks at ambient temperature. As mentioned above, fish cake and fish

finger were fried in hot oil which will produce crust formation and seal the food surface.

The objective of the experiment was to introduce the students the proper method to

evaluate the product characteristics which have undergone different processing methods. Apart

of that, this experiment was also allow the students to learn more about hypothesis testing and

statistical significance and to determine the most important sensory attributes for fried products.

Equipments and Utensils:

Cooking oil

Cutting utensils

Frying pan

Serving plates

Moulding machine

Bowl cutter mixer

Ingredients

Ingredient Formulation

Surimi 6 kg

Salt 50g

MSG 30g

Wheat flour 600g

STPP (Sodium Tripolyphosphate) 120g

Fish Flavour 40g

Ice 300g

Page 4: LAB 4 - Sensory Evaluation of Food Products

Batter ingredient

Water 300g

Wheat flour 150g

Corn starch 50g

Procedure

a) Preparation of food product (fish ball, fish cake and fish finger)

All the ingredients were weighed accurately

Surimi and salt were mixed by using bowl cutter mixer for 5 minutes

Wheat flour, fish flavour, salt, MSG and ice were added. The mixture was mixed for 10 minutes

The mixture was divided into three parts

1) Fish Ball 2) Fish Cake 3) Fish Finger

1) Fish Ball

The mixture was extruded in the moulding machine

Fish ball

Boiled in boiling water

*until the fish balls were floating

The fish ball was cooled for 20 minutes

2) Fish Cake

The mixture was compressed into sheets by using fish cake Molding

The compressed mixture was steamed by using steamer for 20minutes

After that, the steamed sheets was cut into a uniform pieces

Page 5: LAB 4 - Sensory Evaluation of Food Products

Fish cake

3) Fish finger

The mixture was compressed into sheets by using fish cake moulding

The compressed sheets was steamed by using steamer for 20 minutes

After that, the steamed sheets was cut into a uniform pieces

Fish finger

All the ingredients were weighed accurately for the preparation of batter

The fish finger was coated with the batter and bread crumb

b) Preparation for the sensory analysis

The prepared foods were cooked

*fish ball-boiling method

*fish cake and fish finger

-deep frying method

The cooked samples were cut into bite size and placed them on the serving plates

To ensured that product identity was not disclosed, the cooked samples were coded with 3 digit

random code such as 123, 456 etc

Each product was evaluated by each group. The average and standard deviation of the results

was computed by combining the results of evaluations from the other groups in the session

The texture, taste, color, odor, overall appearance and overall acceptability were evaluated

according to the scale provided below:

a) Texture- very hard-1; slight hard-2; soft-3

b) Taste- not acceptable-1; moderately acceptable-2; very acceptable-3

c) Color- not acceptable-1; moderately acceptable-2; very acceptable-3

d) Odor- not acceptable-1; moderately acceptable-2; very acceptable-3

e) Overall appearance- not acceptable-1; moderately acceptable-2; very acceptable-3

Page 6: LAB 4 - Sensory Evaluation of Food Products

f) Overall acceptability- not acceptable-1; moderately acceptable-2; very acceptable-3

Figure 1: Operating mixer with ingredient inside Figure 2: Operating fish ball

Making

Figure 3: Fish ball

Page 7: LAB 4 - Sensory Evaluation of Food Products

Results and analysis:

Sensory Attributes ANOVA Test Tukey’s Test

Texture No significant different at 1%

level.

-

Taste Significant different at 5%

level.

Fish cake is significantly more acceptable compared to fish ball and fish finger at 5% level.

Color No significant different at 1%

level.

-

Odor Significant different at 1%

level.

Fish ball is significantly unacceptable than fish cake and fish finger at 5% level.

Overall Appearance Significant different at 1%

level.

Fish ball is significantly unacceptable than fish cake and fish finger at 5% level.

Overall Acceptability Significant different at 1%

level.

Fish cake is significantly more acceptable than fish ball at 5% level.

Discussion :

Beef balls and fish fingers are both categorized as meat products. To make meat products

to be consumable, various methods of cooking have been developed. With the application of

different cooking methods, such as boiling, frying, steaming, grilling or baking, an internal

altering of texture, taste, odor, flavor have resulted. Even though both are meats, the cooking

methods can have different effect on both these meat products. The beef balls can have a more

distinct effect as rather than the fish fingers.

At cooking temperature, proteins and sugars of meat products can produce brown

pigments. This is the result of interaction of deposits from smoke on the meat surfaces and the

endogenous compounds. On heating, lipid in meat can undergo thermally induced oxidation,

where a range of volatiles which contribute to the formation of flavor. In experiment, we had

steamed fish fingers and also fish cakes. Steaming did not change the color of both the end

products much and remained in their almost natural color. Since steaming is a wet heat and water

is available, steaming makes the fish fingers and fish cake even tender. The tenderness of fish

increases as the temperature increases. This effect also happens on the beef balls.

Page 8: LAB 4 - Sensory Evaluation of Food Products

Frying is a way of cooking. By frying, a considerable amount of oils can be migrated to

fried food. This has indirectly contributed to the absorption of oil by food and caused a change in

the flavor of meat. The meats which have been fried usually absorb the fatty acid profile of the

oil, which act as the frying medium. The fatty acid which acts as the flavor carrier allows the

solubility of the fat soluble compound, such as flavor and thus enhances the flavor of the fried

foods. Hence, frying increases the adsorption of fat content on foods and the higher contents of

fats or oils on the fried foods can enhance the flavor better. Moreover, the fried foods are oily

and give us a smooth and oily mouth feel. Upon frying, protein, carbohydrates and fats also

undergo changes. Maillard reaction (browning and caramelization) takes place in the fried food

due to the reaction of amino acid as well as sugars to give a desirable brown color. This reaction

also contributes the fried foods a richer flavor. A golden brown color can be formed on the

surface of the meat. As for texture, frying impart crispiness on the fried foods. Nonetheless,

frying makes the fried foods softer if the foods are kept and stored for a longer period of time. In

terms of taste, the deep-fried foods are less palatable if the deep-fried foods are soaked in the oil

for a period of time. Moreover, the oil used in deep frying has an effect on the sensory attributes

of fried foods. The age and thermal history of oil can affect the sensory attributes of fried foods.

The prolonged frying at high temperature can cause the oxidation of oil to form unpleasant

flavors and odors, such as volatile carbonyls, hydroxyl acid, keto acid and epoxy acid. The

formation of these unpleasant flavors and odors are the results of oxidation of the oil when it is

exposed to long time frying. Apart from that, prolonged frying also allows the formation of dark

color oil and this indirectly will affect the fried food to obtain a darker and undesirable color.

The above discussed attributes are the effects of frying on meat products. When comparing meat

products, such as fish fingers and meat balls, meat balls have the more distinct effects as

compared to the fish fingers. Fish finger obtains a lesser effect and color of fish meat does not

change after frying.

For fried products, the most important sensory attributes of fried breaded fish fingers are

texture, flavor and appearance. Breading is a system where it provides a coating and protection

to the meat products. This system can prevent the moisture inside the meat to be lost in the form

of water vapor. With the presence of this coat, the moisture contents of the meat continue to

retain inside meat and thus free from water diffusion. As a result, fried meat product becomes

juicier and do not harden or toughen during deep frying. The deep-fried breaded fingers also

have enhanced flavours. This is because, in frying, the bread coating carries flavor as well as

seasonings added. Thus, this has enhanced the sensory characteristics of the particular products

and also the acceptability of consumers. Apart from that, texture of the breaded fingers is also

important. With the suitable temperature and also pressure, softness and crispiness can result.

Page 9: LAB 4 - Sensory Evaluation of Food Products

The bread coating can impart crispiness on the fried product when atmospheric pressure is

applied. On the other hand, the breaded fingers can be soft when the positive pressure is used.

Smoking is also another type of way of cooking meat. Smoked meat can be eaten straight

without cooking. Smoking can preserve the meat and thus extend the shelf life of meat products.

By smoking, varieties of meat products in market can be achieved. With the smoking of meat, a

desirable color can be developed. As a result, smoking has enhanced the brown color of the meat

surface and it gives a more acceptable and desirable color to consumers. Furthermore, the

smoked meats also possess a developed aroma and flavor. The Phenols from the wood smoke,

which is used in smoking has an effect on flavor and aroma development of smoked meat. Two

of the examples of phenols in wood smoke are guaiacol and syringol with the former has more

contribution on flavor and the latter enhances the aroma.

Sensory attributes of a food item are typically perceived in the following order such as

appearance, odor/ aroma/ fragrance, consistency and texture, and flavor. In this experiment, we

have done the sensory evaluation of the fish surimi which we had previously processed. Through

this experiment, the sensory evaluation of fish balls, breaded fish fingers and fish cake had been

done. Based on the Results and Analysis, there was no significance difference among the three

samples in terms of texture, odor and color. These three samples have similar acceptable

appearance. However, fish cake has the best taste as compared to the breaded fish fingers and

fish balls. The delicious taste of fish cake could be due to the proper frying temperature and time

had been carried out. The breaded fingers had a lesser preference amongst the judges could be

due to the lack of frying time on the minced fish meat. People handled the frying of the breaded

fish fingers might be affected by the colour of the golden orange of the crumb. This is because

the crumbs which acted as the coat were fried completely, whereas the minced fish meats inside

were blocked by the bread system. As a result, softer texture of minced fish meats was formed

inside and affected the sensory evaluation of judges. Fish ball has the most unacceptable overall

appearance after frying. This could be due to the fish balls were too soft and not elastic. Besides

that, the fish ball also had an undesirable smell which decreased the appetite of judges. Hence,

with all the results above, it can be concluded that fish cake had the highest overall acceptability.

Inferences:

1. There are many type of fish product that is available in the market which is differing in

their sensory characteristics.

2. Different types of processing equipment, yielding products with different quality

parameters.

Page 10: LAB 4 - Sensory Evaluation of Food Products

3. The sensory evaluation is crucial since the determination cannot be duplicated in any other

analysis.

4. The results of sensory evaluation can be analyzed mathematically.

5. The sensory evaluation can be used to identify consumer’s preference.

6. The sensory evaluation is important in evaluating the characteristic of the product.

Conclusion

Based on the results, fish cake is the most preferable product compared to fish balls and

breaded fish fingers. This is due to the type of cooking that have been conducted to the three

types of products which are frying, boiling and steaming and is much affected by the time and

temperature of cooking.

References:

1. Elizabeth L., Laboratory Methods for Sensory Evaluation of Food, Ottawa, Canada, 5 & 6,

1977.

2. P. J. Fellows, Food Processing Technology: Principles and Practice, 362, 1999

3. Meilgaard, M., Civille, G.V., and Carr, B.T., Sensory Evaluation Techniques, 3rd Edition,

CRC Press LLC, Boca Raton, FL, 1999

4. Pearson, A.M. and Gillett, T.A. (1999). Meat Cookery and Cooked Meat Products. In

Processed Meats.( pp. 111).Maryland : An Aspen Publication, Aspen Publishers, Inc.

Galthersburg.

5. Toldra, F., Meat: Chemistry and Biochemistry. In Y. H., Hui. (2006). Handbook of Food

Science, Technology, and Engineering (pp 28-3). New York: CRC Press.

6. FST 4822 Laboratory Manual

7. FST 4822 Lecture Note-Meat Technology

8. FST 4829 Sensory Evaluation Lecture Note

9. http://food.oregonstate.edu/sensory/theresa.html (accessed: 15 August 2008)

10. http://www.dietriot.com/stories/fry-light-qa.asp (accessed: 15 August 2008)

Page 11: LAB 4 - Sensory Evaluation of Food Products

Index:

Results:

a) Texture Group Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 2 2 2 63 3 2 2 74 2 2 3 75 2 3 3 86 2 2 3 7

Total 14 14 15 43Mean 2.33 2.33 2.50

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the texture attribute of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 43 2 / (3 × 6)= 1849 / 18= 102.72

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / number of judgments for each sample) − CF

= (152 + 142 + 142) / 6 − 102.72= 617 / 6 – 102.72= 0.11

Sum of squares, judges = (Sum of the squares of the total for each judge / number of judgments by each judge) − CF

= (82 + 62 + 72 + 72+ 82 + 72) / 3 − 102.72= 311 / 3 − 102.72= 0.95

Sum of squares, total = Sum of the squares of each judgment − CF= (22 + 22 + …..32 + 22) − 102.7= 107 − 102.72= 4.28

Page 12: LAB 4 - Sensory Evaluation of Food Products

Sum of squares, error = ss total − ss judges − ss samples= 4.28 – 0.11 - 0.95= 3.22

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Mean square, ms ms, samples = 0.11/2 = 0.06ms, judges = 0.95/5 = 0.19ms, error = 3.22/10 = 0.32

Variance ratio, F F, samples = 0.06/0.32 = 0.19F, judges = 0.19/0.32 = 0.59

Analysis of variance table (ANOVA table):Source of variation Df ss ms FSamples 2 0.11 0.06 0.19Judges 5 0.95 0.19 0.59Error 10 3.22 0.32Total 17 4.28

1% level of significance 5% level of significance

Samples:F calculated (0.19) < F table (7.56) F calculated (0.19) < F table (4.10)

Conclusion: There is no significant difference in the texture attribute between the samples at both 5% level and 1% level.

Judges:F calculated (0.59) < F table (5.64) F calculated (0.59) < F table (3.33)

Conclusion: There is no significant difference in the texture attribute between the samples at both 5% level and 1% level.

b) Taste Group Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 2 3 2 73 2 3 3 84 2 2 1 55 2 3 2 76 2 3 2 7

Page 13: LAB 4 - Sensory Evaluation of Food Products

Total 13 17 12 42Mean 2.17 2.83 2.00

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the taste attribute of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 42 2 / (3 × 6)= 1764 / 18= 98.00

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / number of judgments for each sample) − CF

= (132 + 172 + 122) / 6 − 98.0= 602 / 6 – 98.0= 2.33

Sum of squares, judges = (Sum of the squares of the total for each judge / number of judgments by each judge) − CF

= (82 + 72 + 82 + 52+ 72 + 72) / 3 − 98.0= 300 / 3 − 98.0= 2.00

Sum of squares, total = Sum of the squares of each judgment − CF= (32 + 32 + …..32 + 22) − 98.0= 104 − 98.0= 6.00

Sum of squares, error = ss total − ss judges − ss samples= 6.00 − 2.00 − 2.33= 1.67

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Mean square, ms ms, samples = 2.33/2 = 1.17ms, judges = 2.00/5 = 0.40ms, error = 1.67/10 = 0.17

Variance ratio, F F, samples = 1.17/0.17 = 6.88F, judges = 0.40/0.17 = 2.35

Page 14: LAB 4 - Sensory Evaluation of Food Products

Analysis of variance table (ANOVA table):Source of variation df ss ms FSamples 2 2.33 1.17 6.88Judges 5 2.00 0.40 2.35Error 10 1.67 0.17Total 17 6.00

1% level of significance 5% level of significance

Samples:F calculated (6.88) < F table (7.56) F calculated (6.88) > F table (4.10)

Conclusion: There is significant difference in the taste attribute between the samples at 5% level.

Judges:F calculated (2.35) < F table (5.64) F calculated (2.35) < F table (3.33)

Conclusion: There is no significant difference among the judges at both 5% level and 1% level.

Since there is a significant difference among the samples at 5% level, Tukey’s Test is used to determine which sample are significant different from the others.

The standard error of the sample mean is calculated.

For 3 samples and 10 degrees of freedom, the value obtained from table is 3.88Least significant difference = 3.88 × 0.17 = 0.66

Any two sample means that differ by 0.66 or more are significantly different at the 5% level.

Sample scores : Fish Finger Fish Cake Fish Ball13 17 12

Sample means : 2.17 2.83 2.00

The sample means are arranged according to magnitude:Fish Cake Fish Finger Fish Ball

2.83 2.17 2.00

Each mean is compared with the others to see if the difference is 0.66 or moreFish Cake – Fish Finger = 2.83 – 2.17 = 0.66 = 0.66Fish Cake – Fish Ball = 2.83 – 2.00 = 0.83 > 0.66Fish Finger – Fish Ball = 2.17 – 2.00 = 0.17 < 0.66

Page 15: LAB 4 - Sensory Evaluation of Food Products

The results are shown using letters to indicate differences:Fish Cake Fish Finger Fish Ball

2.83a 2.17b 2.00b

Any two values not followed by the same letter are significantly different at the 5% level.

Conclusion: Fish cake is significantly more acceptable in taste attribute compared to fish ball and fish finger at 5% level.

c) Color Group Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 3 2 2 73 3 3 2 84 3 2 3 85 3 3 3 96 3 2 2 7

Total 18 15 14 47Mean 3.00 2.50 2.33

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the color attribute of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 47 2 / (3 × 6)= 2209 / 18= 122.72

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / number of judgments for each sample) − CF

= (182 + 152 + 142) / 6 − 122.72= 745 / 6 – 122.72= 1.45

Sum of squares, judges = (Sum of the squares of the total for each judge / number of judgments by each judge) − CF

= (82 + 72 + 82 + 82+ 92 + 72) / 3 − 122.72= 371 / 3 − 122.72= 0.95

Sum of squares, total = Sum of the squares of each judgment − CF= (32 + 32 + …..22 + 22) − 122.72= 127 − 122.72

Page 16: LAB 4 - Sensory Evaluation of Food Products

= 4.28

Sum of squares, error = ss total − ss judges − ss samples= 4.28 − 0.95 − 1.45= 1.88

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Mean square, ms ms, samples = 1.45/2 = 0.73ms, judges = 0.95/5 = 0.19ms, error = 1.88/10 = 0.19

Variance ratio, F F, samples = 0.73/0.19 = 3.84F, judges = 0.19/0.19 = 1.00

Analysis of variance table (ANOVA table):Source of variation df ss ms FSamples 2 1.45 0.73 3.84Judges 5 0.95 0.19 1.00Error 10 1.88 0.19Total 17 4.28

1% level of significance 5% level of significance

Samples:F calculated (3.84) < F table (7.56) F calculated (3.84) < F table (4.10)

Conclusion: There is no significant difference in the color attribute between the samples at both 5% level and 1% level.

Judges:F calculated (1.00) < F table (5.64) F calculated (1.00) < F table (3.33)

Conclusion: There is no significant difference among the judges at both 5% level and 1% level.

Page 17: LAB 4 - Sensory Evaluation of Food Products

d) Odor Group Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 2 3 1 63 2 3 1 64 3 3 1 75 3 3 1 76 2 2 1 5

Total 15 17 7 39Mean 2.50 2.83 1.17

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the odor attribute of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 39 2 / (3 × 6)= 1521 / 18= 84.50

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / Number of judgments for each sample) − CF

= (152 + 172 + 72) / 6 − 84.50= 563 / 6 – 84.50= 9.33

Sum of squares, judges = (Sum of the squares of the total for each judge / Number of judgments by each judge) − CF

= (82 + 62 + 62 + 72+ 72 + 52) / 3 − 84.5= 259 / 3 − 84.50= 1.83

Sum of squares, total = Sum of the squares of each judgment − CF= (32 + 32 + …..22 + 12) − 84.5= 97 − 84.5= 12.50

Sum of squares, error = ss total − ss judges − ss samples= 12.50 − 1.83 − 9.33= 1.34

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Page 18: LAB 4 - Sensory Evaluation of Food Products

Mean square, ms ms, samples = 9.33/2 = 4.67ms, judges = 1.83/5 = 0.37ms, error = 1.34/10 = 0.13

Variance ratio, F F, samples = 4.67/0.13 = 35.92F, judges = 0.37/0.13 = 2.85

Analysis of variance table (ANOVA table):Source of variation df ss ms FSamples 2 9.33 4.67 35.92Judges 5 1.83 0.37 2.85Error 10 1.34 0.13Total 17 12.50

1% level of significance 5% level of significance

Samples:F calculated (35.92) > F table (7.56) F calculated (35.92) > F table (4.10)

Conclusion: There is significant difference in the odor attribute between the samples at 1% level.

Judges:F calculated (2.85) < F table (5.64) F calculated (2.85) < F table (3.33)

Conclusion: There is no significant difference among the judges at 1% level.

Since there is a significant difference among the samples at 1% level, Tukey’s Test is used to determine which sample are significant different from the others.

The standard error of the sample mean is calculated.

For 3 samples and 10 degrees of freedom, the value obtained from table is 3.88

Least significant difference = 3.88 × 0.15 = 0.58

Any two sample means that differ by 0.58 or more are significantly different at the 5% level.

Sample scores : Fish Finger Fish Cake Fish Ball15 17 7

Sample means : 2.50 2.83 1.17

Page 19: LAB 4 - Sensory Evaluation of Food Products

The sample means are arranged according to magnitude:Fish Cake Fish Finger Fish Ball

2.83 2.50 1.17

Each mean is compared with the others to see if the difference is 0.66 or moreFish Cake – Fish Finger = 2.83 – 2.50 = 0.33 < 0.58Fish Cake – Fish Ball = 2.83 – 1.17 = 1.66 > 0.58Fish Finger – Fish Ball = 2.50 – 1.17 = 1.33 > 0.58

The results are shown using letters to indicate differences:Fish Cake Fish Finger Fish Ball

2.67a 2.17a 1.67b

Any two values not followed by the same letter are significantly different at the 5% level.

Conclusion: Fish ball is significantly unacceptable in odor attribute than fish cake and fish finger at 5% level.

e) Overall Appearance Group Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 2 2 1 53 3 3 2 84 3 2 2 75 3 3 3 96 3 3 2 8

Total 17 16 12 45Mean 2.83 2.67 2.00

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the overall appearances of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 45 2 / (3 × 6)= 2025 / 18= 112.50

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / number of judgments for each sample) − CF

= (172 + 162 + 122) / 6 − 112.5= 689 / 6 – 112.5= 2.33

Sum of squares, judges = (Sum of the squares of the total for each judge / number of judgments by each judge) − CF

= (82 + 52 + 82 + 72+ 92 + 82) / 3 − 112.5= 347 / 3 − 112.5

Page 20: LAB 4 - Sensory Evaluation of Food Products

= 3.17

Sum of squares, total = Sum of the squares of each judgment − CF= (32 + 32 + …..22 + 22) − 112.5= 119 − 112.5= 6.50

Sum of squares, error = ss total − ss judges − ss samples= 6.50 – 3.17 - 2.33= 1.00

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Mean square, ms ms, samples = 2.33/2 = 1.17ms, judges = 3.17/5 = 0.63ms, error = 1.00/10 = 0.10

Variance ratio, F F, samples = 1.17/0.10 = 11.70F, judges = 0.63/0.10 = 6.30

Analysis of variance table (ANOVA table):Source of variation Df ss ms FSamples 2 2.33 1.17 11.70Judges 5 3.17 0.63 6.30Error 10 1.00 0.10Total 17 6.50

1% level of significance 5% level of significance

Samples:F calculated (11.70) > F table (7.56) F calculated (11.70) > F table (4.10)

Conclusion: There is significant difference in the overall appearance between the samples at 1% level.

Judges:F calculated (6.30) > F table (5.64) F calculated (6.30) > F table (3.33)

Conclusion: There is significant difference among the judges at 1% level.

Since there is a significant difference among the samples at 1% level, Tukey’s Test is used to determine which sample are significant different from the others.

Page 21: LAB 4 - Sensory Evaluation of Food Products

The standard error of the sample mean is calculated.

For 3 samples and 10 degrees of freedom, the value obtained from table is 3.88

Least significant difference = 3.88 × 0.13 = 0.50

Any two sample means that differ by 0.50 or more are significantly different at the 5% level.

Sample scores : Fish Finger Fish Cake Fish Ball17 16 12

Sample means : 2.83 2.67 2.00

The sample means are arranged according to magnitude:Fish Cake Fish Finger Fish Ball

2.83 2.67 2.00

Each mean is compared with the others to see if the difference is 0.66 or moreFish Cake – Fish Finger = 2.83 – 2.67 = 0.16 < 0.50Fish Cake – Fish Ball = 2.83 – 2.00 = 0.83 > 0.50Fish Finger – Fish Ball = 2.67 – 2.00 = 0.67 > 0.50The results are shown using letters to indicate differences:

Fish Cake Fish Finger Fish Ball2.67a 2.17a 1.67b

Any two values not followed by the same letter are significantly different at the 5% level.

Conclusion: Fish ball is significantly unacceptable (overall appearance) than fish cake and fish finger at 5% level.

f) Overall AcceptabilityGroup Products Total

Fish Finger Fish Cake Fish Ball1 3 3 2 82 2 3 1 63 2 3 2 74 2 2 1 55 2 3 2 76 2 2 2 6

Total 13 16 10 39Mean 2.17 2.67 1.67

Page 22: LAB 4 - Sensory Evaluation of Food Products

Since there are three samples used in this test, the statistical analysis to determine whether there

is significant difference between the overall acceptability of the three samples is done by using

ANOVA:

Analysis of variance (ANOVA):Correction factor (CF) = Total 2 / number of responses

= 39 2 / (3 × 6)= 1521 / 18= 84.50

Sum of squares, ss Sum of squares, samples = (Sum of the squares of the total for each sample / number of judgments for each sample) − CF

= (132 + 162 + 102) / 6 − 84.50= 525 / 6 – 84.50= 3.00

Sum of squares, judges = (Sum of the squares of the total for each judge / number of judgments by each judge) − CF

= (82 + 62 + 72 + 52+ 72 + 62) / 3 − 84.50= 259 / 3 − 84.50= 1.83

Sum of squares, total = Sum of the squares of each judgment − CF= (32 + 32 + …..22 + 22) − 84.50= 91 − 84.50= 6.50

Sum of squares, error = ss total − ss judges − ss samples= 6.50 − 1.83 − 3.00= 1.67

Degrees of freedom, df df, samples = 3 – 1 = 2df, judges = 6 – 1 = 5df, total = 18 – 1 = 17df, error = 17 – 2 – 5 = 10

Mean square, ms ms, samples = 3.00/2 = 1.50ms, judges = 1.83/5 = 0.37ms, error = 1.67/10 = 0.17

Variance ratio, F F, samples = 1.50/0.17 = 8.82F, judges = 0.37/0.17 = 2.18

Page 23: LAB 4 - Sensory Evaluation of Food Products

Analysis of variance table (ANOVA table):Source of variation df ss ms FSamples 2 3.00 1.50 8.82Judges 5 1.83 0.37 2.18Error 10 1.67 0.17Total 17 6.50

1% level of significance 5% level of significance

Samples:F calculated (8.82) > F table (7.56) F calculated (8.82) > F table (4.10)

Conclusion: There is significant difference in the overall acceptability between the samples at 1% level.

Judges:F calculated (2.18) < F table (5.64) F calculated (2.18) < F table (3.33)

Conclusion: There is no significant difference among the judges at 1% level.

Since there is a significant difference among the samples at 1% level, Tukey’s Test is used to determine which sample are significant different from the others.

The standard error of the sample mean is calculated.

For 3 samples and 10 degrees of freedom, the value obtained from table is 3.88

Least significant difference = 3.88 × 0.17 = 0.66

Any two sample means that differ by 0.66 or more are significantly different at the 5% level.

Sample scores : Fish Finger Fish Cake Fish Ball13 16 10

Sample means : 2.17 2.67 1.67

The sample means are arranged according to magnitude:Fish Cake Fish Finger Fish Ball

2.67 2.17 1.67

Each mean is compared with the others to see if the difference is 0.66 or moreFish Cake – Fish Finger = 2.67 – 2.17 = 0.50 < 0.66Fish Cake – Fish Ball = 2.67 – 1.67 = 1.00 > 0.66Fish Finger – Fish Ball = 2.17 – 1.67 = 0.50 < 0.66

Page 24: LAB 4 - Sensory Evaluation of Food Products

The results are shown using letters to indicate differences:Fish Cake Fish Finger Fish Ball

2.67a 2.17ab 1.67b

Any two values not followed by the same letter are significantly different at the 5% level.

Conclusion: Fish cake is significantly more acceptable (overall acceptability) than fish ball at 5% level.